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education
Department:
Education
PROVINCE OF KWAZULU-NATAL
NATIONAL
SENIOR CERTIFICATE
GRADE 12
q MATHEMATICAL LITERACY t
| b COMMON TEST X
m MARCH 2020 :
MARKS: 100
TIME: 2 hours
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Mathematical Literacy · Grade 12 · KZN March · 2020. Memorandum, 16 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2020
- Exam period
- KZN March
- Pages
- 16
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Mathematical Literacy 2 March 2020 Common Test
NSC
INSTRUCTIONS AND INFORMATION
. This question paper consists of FOUR questions. Answer ALL the questions.
2 Number the answers correctly according to the numbering system used in this
question paper.
ay Start EACH question on a NEW page.
4. You may use an approved calculator (non-programmable and non-graphical), unless
stated otherwise.
5 Show ALL calculations clearly.
6. Round off ALL final answers appropriately according to the given context, unless
stated otherwise.
ie Indicate units of measurement, where applicable.
8. Diagrams and graphs are NOT necessarily drawn to scale, unless stated otherwise.
a. Write neatly and legibly.
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Mathematical Literacy 3 March 2020 Common Test
NSC
QUESTION 1
lel
Mrs Molefe buys raw mealies from the farmer at R7,00 each. The farmer delivers
mealies to her home for free at 06:00. She cooks the mealies for one hour fifty
minutes. She sells them at the taxi rank for R13,00 each. She sells on Monday to
Saturday. A single trip to the taxi rank costs R15,00.
Use the information above and the February calendar below to answer the questions
that follow.
FEBRUARY CALENDAR 2020
Source: www.shutterstock.com
1.1.1. Determine the number of days that Mrs Molefe sold mealies at the taxi
rank in February 2020.
1.1.2. After the delivery, it takes Mrs Molefe 20 minutes to prepare raw mealies for
cooking. At what time will the mealies be ready for eating?
1.1.3 Calculate the monthly taxi fare for February 2020.
1.1.4 Calculate the profit from the sale of one mealie.
1.1.5 Define the term break-even.
1.1.6 Write down the formula for calculating the cost per day in the form:
1.1.7 Write down the formula for calculating the income per day in the form:
Income = ...... * ......
1.1.8 Calculate the profit made if she bought 70 raw mealies and only sells 40.
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SUN | MON | TUE | WED | THU | FRI | SAT
1
2 ] 4 5 6 cd 8
9 10 7 12 13 14 15
16 a 18 19 20 21 ee
23 24 25 26 27 —
(2)
(3)
(4)
(2)
(2)
(2)
(2)
(6)
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March 2020 Common Test
NSC
rs
Mr Molefe is a fisherman. Before he goes to the sea shore to fish, he studies the
tide table. Below are the two tide tables for Durban showing tides for Tuesday
28/01/2020 and Wednesday 29/01/2020.
Use the information above and TABLE 1 below to answer the following questions.
TABLE 1: Showing Durban tide tables for 28/01/2020 and 29/01/2020
28/01/2020 29/01/2020
Tide Time Height Tide Time Height
High tide 5:44 am 191m High tide 6:13 am 1,86m
Low tide 11:49 am 0,43 m Low tide 12:18 pm 0,50 m
High tide 5: 49 pm 18m High tide 6:17 pm 1,76 m
Low tide 11:59 pm 0,35 m Low tide = -
Sunrise Sunset | Moonrise | Moonset | Sunrise | Sunset | Moonrise | Moonset
5:20am | 6:56 pm | 8:17am 9:21pm | 5:21am | 6:55pm | 9:10am 9:51pm
Source: www.tide-forecast.com
1.2.1 Calculate the difference in time between the high tide and low tide in the
morning on 28 January 2020.
1.2.2 Write down the time for a low tide in the afternoon of 29 January 2020 in a
24-hour format.
1.2.3. Convert the height of the high tide to feet (ft) on 28 January 2020 in the
morning.
Note: 1 foot = 30,48 cm
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Mathematical Literacy
QUESTION 2
6]
NSC
March 2020 Common Test
2)
neighbour.
The Du Toit family stays in Newcastle. They decided to change the electricity
from the metered one to domestic prepaid. Below is a table of the Newcastle
electricity tariffs for 2017/2018 and 2018/2019. Mr van Zyl is the Du Toit’s
Note: The municipality financial year of services starts on 1 July of the current
Use the information above and TABLE 2 below to answer the questions that
follow.
TABLE 2: Showing Newcastle electricity tariffs for domestic in 2017/2018 and
2018/2019.
Block
Tariff/ kWh in cents
excluding 15% VAT
2017/2018
Tariff/ kWh in cents
excluding 15% VAT
2018/2019
Block 1: ( 0-50 kWh ) 96,93 cents 104,68 cents
Block 2: (from 50 ~ 350 kWh ) 116,88 cents 126,53 cents
Block 3: ( from 350 - 600 kWh) 124,92 cents 134,91 cents
Block 4: (> 600 kWh)
131,57 cents
142,10 cents
Source: www.newcastlemunicipality.gov.za
2.1.1 Determine the number of kilowatt hours (Kwh) in block 1 and block 2.
2.1.2 Write the ratio of kilowatt hours of block | to block 2 in simplest form .
2.1.3. In May 2018, the family bought electricity for R600,00 including VAT.
(a) Calculate the VAT amount.
(b) Determine the number of kilowatt hours (kWh) they received.
2.1.4 In May 2019, Mr van Zyl’s family consumed 503 kWh of electricity.
Calculate the total amount including VAT that this family will pay.
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(2)
(2)
(3)
(6)
(6)
[19]
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Mathematical Literacy
QUESTION 3
3.1
6 March 2020 Common Test
NSC
Lindani who is 45 years old, is married with 3 children. He earns a monthly taxable
income of R32 500. He contributes to a medical aid scheme for him and his family.
The Adapted Tax table for 2019/2020 is shown below.
TABLE 3: TAX RATES FOR INDIVIDUALS FOR THE 2019/2020 TAX YEAR
Taxable Income
Rates of tax
0-195 850
18 % of taxable income
195 851 - 305 850
35 253 + 26% of taxable income above 195 850
305 851 - 423 300
63 853 + 31% of taxable income above 305 850
423 301 - 555 600
100 263 + 36% of taxable income above 423 300
Rebates
Primary Rebate R14 220
Secondary (Persons
65 and older) ta
7 : a.
Tertiary (Persons 75 R2601
and older)
Medical Aid Tax Credits per month
Main member R310
First dependant R310
Each additional R209
dependant
[Adapted source: www.sars.org]
Use TABLE 3 and the information above to answer the questions that follow.
3.1.1 Calculate Lindani’s annual taxable income. (2)
3.1.2 Determine Lindani’s total medical aid tax credit for the year. (3)
3.1.3 Hence, calculate his monthly income tax for the year 2019/2020. (8)
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Mathematical Literacy 7 March 2020 Common Test
NSC
3.2
The graph below shows the 2020 Bank withdrawal fees for R500 charged by the different
Banks in South Africa.
Withdrawal fee (R500, Other banks ATM)
R25,00
R21,50
R20,00
R20,00 R19,50 “
R18,50
R15,00 R14,50
R12,00 oe
R10.00 as og :
= ;
R0,00
Capitec Discovery Finbond StandardBank Fnb Nedbank Absa
Banks in South Africa
[Adapted source: www.busstech.co.za]
Use the graph and the information above to answer the questions that follow:
3.2.1 Identify the price difference between the most expensive and the least expensive
withdrawal fee. Give a reason for this price difference. (3)
3.2.2. FNB charges a fixed bank fee plus R1,90 for every R100 withdrawn. Use the
graph to calculate the fixed bank fee. (4)
3.2.3 Determine the percentage change in the withdrawal fee for Capitec bank, if the
cost to withdraw R500 in 2019 was R8,75.
You may use the formula:
New - original .
original
% change = 100 (3)
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Mathematical Literacy
8
NSC
March 2020 Common Test
3.2.4 Absa charges R11,50 + R2 for every R100 withdrawn. A customer withdrew
R2 000. Explain why the calculation below is incorrect. Hence provide the correct
calculation.
Total withdrawal fee for Absa Bank = R2000 + 500
=4
=4x R21,50
= R86
(4)
[27]
QUESTION 4
4.1 | the Survey conducted by Statistics South Africa indicate specific types of crime committed
from 2014 to 2019.
TABLE 4: NUMBER OF INDIVIDUALS AGED 16 AND OLDER THAT
EXPERIENCED THE FOLLOWING CRIMES FROM 2014 TO 2019.
Statistic 2014/15 | 2015/16 | 2016/17 | 2017/18 | 2018/19
Theft of personal property 2 095 571 | 1 894495 | 1 762 131 | 1 844 367 | 2 343 507
Street robbery 706 227 | 678 653 738 462 735 298 1125 972
Assault excluding sexual assault | 724 435 682 924 590 281 600 153 598 948
Consumer fraud 254 351 233 182 199 681 146 536 172 743
Hijacking 194 976 161 800 158 990 A 198 199
Sexual offences 127 935 117 282 134 134 126070 | 97938
1
[Adapted source: www.statssa.gov.za.]
Use TABLE 4 and the information above to answer the questions that follow:
4.1.1 Calculate the total number of individuals affected by assault including sexual
offences in 2018/019.
4.1.2 Determine the mean number of individuals affected by Theft of personal
property from 2014 to 2019.
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Mathematical Literacy 9 March 2020 Common Test
NSC
4.1.3 The range for individuals affected by hijackings is 46 169.
Determine A, the minimum number of individuals affected by hijacking
in 2017/18. (3)
4.1.4 Describe the trend in street robbery from 2014 to 2019. (2)
4.2
The box and whisker plot below shows the heights of Basketball players and Baseball players in inches.
9 4 o——— Basketball players
CT a eR
1
| ee ers eae JJ pn ae] a] ae FETA EL a ae FP)
rl
4
64 66 68 70 72 74 #76 78 80 82 84 86
Heights of Basketball and Baseball Players (in.)
[Adapted source: www.slideshow.net]
Use the information above to answer the following questions:
4.2.1 75% of the Baseball team’s height is the same as 50% of the Basketball team’s.
Determine the height of the players. (2)
4.2.2 One of the coaches claimed that the difference in the maximum heights of the
players is 3 times more than the difference in the minimum heights of the
players.
Verify, if this claim is correct, using a calculation. (5)
4.2.3 Determine the inter quartile range for the Baseball players. Explain the
significance of the IQR of the Baseball players. (3)
4.2.4 Which teams heights’ are more consistent and why? (3)
[23]
TOTAL: [100]
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NATIONAL
SENIOR CERTIFICATE
GRADE 12
MATHEMATICAL LITERACY
COMMON TEST
MARKING GUIDELINE
MARCH 2020
MARKS: 100
SYMBOL EXPLANATION
M Method
MA Method with accuracy
CA Consistent accuracy
A Accuracy
C Conversion
S Simplification
RT/RG/RD/RM Reading from a table/ graph/ diagram/Map
SF Correct substitution in a formula
O Opinion/ reason/deduction/example/Explanation
J Justification
R Rounding off
F deriving a formula
AO Answer only full marks
P Penalty e.g. for units, incorrect rounding off etc.
NPR No penalty for rounding / units
This marking guideline consists of 7 pages.
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Mathematical Literacy 2 March 2020 Common Test
NSC - Memorandum
QUESTION 1 [31 MARKS]
Ques Solution Explanation T&L
1.1.1 25 days RT 2 RT reading from the table M
(2) L1
1.1.2 Prep. Time: 06:00 + 20 minutes M 1M adding 20 minutes M
= 06:20 + 1 hour 50 minutes M 1M adding cooking time L1
Finishing time = 08:10 CA 1CA time
AO (3)
1.1.3 Return trip = R15,00 × 2 M 1M multiplying by 2 M
= R30,00 A 1A fare L1
Monthly fare = R30,00 × 25 days M 1M multiplication
= R750,00 CA 1CA monthly fare (4)
1.1.4 Profit = R13,00 – R7,00 M 1M subtraction F
= R6,00 A 1A profit L1
AO (2)
1.1.5 Break-even is when there is no profit and no loss. E 2E explanation F
OR OR L1
Break-even is when the cost is equal to the income. E 2E explanation
(2)
1.1.6 CA 1CA fixed taxi fare
Cost = R30,00 + R7,00 × number of raw mealies CA 1CA formula (2) F
L1
1.1.7 Income = R13,00 × number of raw mealies sold. F 2F formula (2) F
L1
1.1.8 Cost = R30,00 +( R7,00 × number of raw mealies)
= R30,00 + R7,00 × 70 CA 1CA substitution
= R520,00 CA 1CA cost F
Income = R13,00 × number of raw mealies L2
= R13,00 × 40 MA 1MA multiplying 40 by R13,00
= R520,00 A 1A income
Profit = R520,00 – R520,00 M 1M subtraction
= R0,00 CA 1CA no profit
Accept if profit is not
calculated award 2 marks for
no profit
(6)
1.2.1 Difference = 11:49 – 5:44 MA 1MA subtraction
= 6 hours 05 minutes A 1A difference M
OR OR L2
5:44 – 6:44 (1 hour)
6:44 – 7:44 (1 hour)
7:44 – 8:44 (1 hour) 1MA adding
8:44 – 9:44 (1 hour) MA
9:44 – 10: 44 (1 hour)
10:44 – 11:44 (1 hour)
11:44 = 11:49 (5 minutes)
Difference : 6 hours 05 minutes A 1A difference
AO (2)
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Mathematical Literacy 3 March 2020 Common Test
NSC - Memorandum
1.2.2 Time of low tide 12:18 A 2A time in 24-hour format M
(2) L2
1.2.3 Height = 1,91 m M 1M identifying correct height
1 foot = 30,48 cm ÷ 100 C 1C converting cm to m M
1 ft = 0,3048 m L2
ft = 1,91 m
1,91m
ft = M 1M dividing by 0,3048
0,3048 m
= 6,266……..
1CA height in ft
6,27 ft CA
OR
OR
Height = 1,91 m M
1M identifying correct height
1 foot = 30,48 cm
1,91 m × 100 C
1C converting m to cm
= 191 cm
191c m
ft = M 1M dividing by 30,48
30,48 c m
= 6,266……..
6,27 ft CA 1CA height in ft
(4)
[31]
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Mathematical Literacy 4 March 2020 Common Test
NSC - Memorandum
QUESTION 2 [19 MARKS]
2.1.1 No. of kWh in Block 1: 50 kWh – 0 kWh= 50 kWh A 1A correct no. of kWh F
No. of kWh in Block 2: 350 kWh – 50 kWh = 300 kWh A 1A correct no. of kWh L2
AO
Accept 350 kWh
(2)
2.1.2 Ratio 50 : 300 MA CA from 2.1.1 F
1 : 6 S 1MA ratio in correct L1
order
1S simplification
AO
(2)
2.1.3 R600,00 1M dividing by 1,15
Amount excluding VAT = M
(a) 1,15 F
= R521,74 L2
VAT amount = R600,00 – R521,74 M 1M subtraction
= R78,26 A 1A VAT amount
OR
15 OR
VAT amount = × R600,00 M 2M dividing &
115 multiplying
= R78,26 A 1A VAT amount
OR
OR
100
Amount excluding VAT = × R600,00 M
115 100
= R521,74 1M multiplying by
115
VAT amount = R600,00 – R521,74 M 1M subtraction
= R78,26 A 1A VAT amount
(3)
(b) No. of kWh = R521,74 – R48,465 (50 kWh) C 1C converting cents to
R473,275 – R350,64 (300 kWh) M rands F
R122,635 1M subtraction L2
M = 98,1708…..
1,2492 1M dividing by rate in
98,17CA block 3
Total no. of kWh = 50 + 300 + 98,17 M 1CA number of kWh
= 448,17 CA 1M adding
1CA no. of kWh
(6)
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Mathematical Literacy 5 March 2020 Common Test
NSC - Memorandum
2.1.4 104,68 126,53 1C converting cents to
Amount = ( 50 kWh × ) + ( 300 kWh × )
100 100 C rands F
A L2
+ 153 kWh ×
134,91
) 1A no. of kWh in block 3
100
= R52,34 + R379,59 + R206,4123 S
1S simplification
= R638,3423 A
1A amount
1M multiplying by 1,15
Amount including VAT = R638,3423 × 1,15 M
1CA amount
= R734,09 CA
OR
OR
104,68 126,53
Amount = ( 50 kWh × ) + ( 300 kWh × )+
100 100 C 1C converting cents to
rands
A 134,91
(153 kWh × ) 1A no. of kWh in block 3
100
= R52,34 + R379,59 + R206,4123 S
1S simplification
= R638,3423 A 1A amount
Amount including VAT = R638,3423 + (15% × R638,3423 ) M
= R734,09 CA 1M adding 15%
1CA amount
OR OR
104,68 126,53
Amount = ( 50 kWh × ) + ( 300 kWh × )+
100 100 C 1C converting cents to
rands
A 134,91
(153 kWh × )
100 1A no. of kWh in block 3
= R52,34 + R379,59 + R206,4123 S 1S simplification
= R638,3423 A 1A amount
VAT = 15% × R638,3423
= R95,75
Amount including VAT = R638,3423 + R95,75 M 1M adding VAT
= R734,09 CA 1CA amount
[maximum 3 marks if
used the wrong column
R678,41]
(6)
[19]
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Mathematical Literacy 6 March 2020 Common Test
NSC - Memorandum
QUESTION 3 [27 MARKS]
Ques Solution Explanation T &L
3.1.1 Annual Taxable income =R 32 500 × 12 MA 1MA multiplying by 12 F
L2
= R390 000 A 1A annual taxable income (2)
3.1.2 Total med aid tax credit= F
1MA adding correct values L3
R310+R310+R209+R209+R209MA
= R 1247
1MA multiplying by 12
= R 1247×12MA
1CA medical aid tax credit
= R 14 964CA
(3)
3.1.3 A 1A correct tax bracket F
Monthly tax = R63 853 + 0,31(R390 000 – R305 850)SF 1SF correct substitution L3
= R89 939,50S 1S simplification
= R89 939,50 – (R14 220) MA 1MA subtracting rebate
1CA answer
= R75 719,50CA
1CA subtracting medical credit
= R75 719,50 – (R14 964) CA from Q3.1.2
= R60 755,50
1MA dividing by 12
= R60 755,50 ÷ 12 MA
1CA monthly tax (8)
= R5062,96 CA
3.2.1 Difference in price = R21,50 – R8 RG 1RG subtracting correct values F
1A difference in price L4
= R13,50A
Capitec bank fee rates are lower than Absa. O 1O opinion (3)
3.2.2 Fixed bank fee = R500÷100 MA 1MA dividing by 100 F
L3
=5
1MA multiplying by R1,90
= 5 × R1.90MA
= R9.50
1CA subtracting answer
= R19,50 – 9.50CA
1CA fixed bank fee (4)
= R10CA
3.2.3 1RG 1RG and subtraction F
8,00 8,75 L2
% Change = × 100
8,75 MA 1MA dividing by 8,75
= – 8,57%CA
1CA % decrease (3)
3.2.4 Withdrawal fee has a fixed cost of R11,50 therefore F
method is incorrectO 1O opinion L4
Withdrawal fee = R2000 ÷ 100MA 1MA dividing by 100
= 20
= R11,50 + (R2×20) SF 1SF substitution into formula
= R51,50A 1A withdrawal fee (4)
[27]
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Mathematical Literacy 7 March 2020 Common Test
NSC - Memorandum
QUESTION 4 [23 MARKS]
4.1.1 Total number of individuals affected = 598 948 + 97 938RT 1RT correct values DH
= 696 886A 1A total (2) L2
4.1.2 Mean DH
=2 095 571+1 894 495+1 762 131+1 844 367+2 343 507MA 1MA adding correct values L2
=9 940 071
=9 940 071 ÷ 5MA 1MA dividing by 5
=1 988 014,20
1 988 014 CA 1CA mean (3)
4.1.3 Range = Max - MinMA 1MA concept of range DH
46 169 = 198 199 – ASF 1SF correct substitution L3
198 199 – 46 169 =152 030A 1A value of A (3)
4.1.4 It is fluctuating over a period of timeO 2O opinion DH
L4
OR OR
Increasing and decreasing over a period of timeO 2O opinion
(2)
4.2.1 74 inchesRG 2RG reading correct value DH
(2) L2
4.2.2 Difference in Max heights = 85 - 76 1RG difference in DH
= 9 inchesRG maximum heights L3
Difference in Min heights = 67 -64
= 3 inchesRG 1RG difference in
minimum heights
Max height is 3 times more = 9 ÷ 3MA 1MA dividing by 3
=3CA 1CA max height
Claim is correct. O 1O opinion (5)
4.2.3 IQR = 74 – 66 RG 1RG subtracting correct DH
values L4
= 8 inches CA 1CA IQR
The middle 50% of player’s heights are concentrated between
66 and 74 inchesO 1O opinion (3)
4.2.4 Baseball A 1A correct team DH
L4
IQR and range for baseball team is smaller than that of 2O opinion (3)
basketball teamO
[23]
TOTAL: [100]
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