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Maths-Grade-11-SEPT-2022-QP-and-Memo.pdf
Mathematics · Grade 11 · NSC Prelim Exam · 2022. Question paper and memorandum, 16 pages. Read online or download the PDF.
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- Mathematics
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- Grade 11
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- Question paper and memo
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- 2022
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- NSC Prelim Exam
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Matlaganealoaded From Stanmorephysics. COM Common Test September 2022
Grade 11
INSTRUCTIONS AND INFORMATION
Read the following instructions carefully before answering the questions.
2.
10.
This question paper consists of 6 questions.
Answer ALL the questions.
Number the answers correctly according to the numbering system used in this
question paper.
Clearly show ALL calculations, diagrams, graphs, etc. which you have use@®
determining your answers. rey
Answers only will NOT necessarily be awarded full marks. a
ani
You may use an approved scientific calculator (non-program: Ne
d
non-graphical), unless stated otherwise. XN
If necessary, round off answers correct to TW! imal places, unless stated
otherwise.
Diagrams are NOT necessarily drawn to sa
A DIAGRAM SHEET for QUESTION 33.1 and QUESTION 4.1 is attached at the
end of this question paper. Detachthe DIAGRAM SHEET and hand it in together
with your ANSWER BOOK. e)
Write neatly and legibly
Copyright Reserved Please turn over
Matlagunealoaded from Stanmorephysics. Com Common Test September 2022
Grade 11
QUESTION 1
1.1 A survey was conducted among 560 drivers about the number of accidents they were
involved in during one calendar year. The results are summarised in the table below.
a 4 Number of accidents
wey Of driver Two or fewer More than two Total
30 years and younger 157 51 208
Older than 30 years 304 48 352
Total 461 99 SAO
1.1.1 Use the information in the table to calculate the probability that a driver
selected at random from this group:
oy
CO
(a) is older than 30 years. (2)
(b) was involved in more than two sei the year. (1)
(c) is older than 30 years and wonifiSer in more than two
accidents in the year. & (2)
1.1.2 Are the events “being invo w more than two accidents in the year”
and “being older than 3 rs” independent of each other? Motivate
your answer by “oo ‘vant calculations. (3)
1.2 For two events, A and B se sample space §S, it is given that:
e P(A) =0,55
° P(B)=0,6 g@
e P(Aand 25
1.2.1 aw a Venn diagram to represent this information. (4)
(@) Determine P[not(A or B)]. dd)
1.2.3 Determine P[A and (not B)]. qd)
1.3 During a virus pandemic Khanyi decides to visit her friend Nozipho. Neither of them
knew that Nozipho had contracted the virus.
e The probability that both of them will be wearing masks during the visit is 82%.
e Ifthey are wearing masks during the visit, the probability that Khanyi will
contract the virus is 8%.
e Ifthey are not wearing masks during the visit, the probability that Khanyi will not
contract the virus is 27%.
What is the probability that Khanyi will contract the virus because of the visit to
Nozipho? (5)
[19]
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Matlpganeloaded From Stanmorephysics. COM Common Test September 2022
Grade 11
QUESTION 2
A tyre manufacturer collected data on how far cars could travel using one set of tyres. The
distances, in 1000’s of kilometres, covered by cars using one set of tyres are shown in the ogive
(cumulative frequency curve) below.
Ogive (cumulative frequency curve) showing the distances
travelled by cars using one set of tyres
120
110
100
B90
5
3. 80 5
oO
& 70
oO
= 60
8
=I
2 50
5 40
30
20
10
0 t
10 615) «6©200«25 80's 8S Oss SZ 5855S CSC CS 8
Distance travelled in 1000's of kilometres
2.1 What is the total number of Cars’on which data was collected?
= ie
2.2 Write down the modal class of the data.
2.3 Use the ogive to determine the median number of kilometres travelled before new
tyres were required.
2.4 In the survey, what percentage of the cars travelled more than 50 000 km with one set
of tyres?
Copyright Reserved Please turn over
()
(2)
(2)
(3)
[8]
Matixeaiwaloaded from Stanmorephysics. CoM Common Test September 2022
Grade 11
QUESTION 3
The data listed below shows the distance (in kilometres) travelled by cyclists on each day of a
twelve day cycle tour:
3.1
3.2
3.3
3.4
82 89 94 100 113 121
123 128 128 132 135 140
Determine
3.1.1 the mean distance travelled per day
3.1.2 the standard deviation of the data
On how many days do the cyclists travel a distance that is outside of one standard
deviation from the mean? Show all your calculations.
The 5-number summary for the data is as follows:
(82 ; 97 ; 122 ; 130 ; 140).
3.3.1 Use the scaled line on the DIAGRAM SHEET to draw a box-and-whisker
diagram for this set of data.
3.3.2 Comment on the skewness of the data.
Before the start of each day’s section of the tour, the cyclists had an additional warm-
up ride of x km. If this is also taken into account, write down, in terms of x (where
applicable)
3.4.1 the mean distance travelled per day
3.4.2 the standard deviation
Copyright Reserved Please turn over
(2)
(1)
(3)
(3)
(1)
(2)
(1)
[13]
Matineaiwaloaded from Stanmorephysics. CoM Common Test September 2022
Grade 11
QUESTION 4
41 Draw the graph of, vy =—2sinx, for x e[—90° ;270° ] on the set of axes provided on the
DIAGRAM SHEET. Clearly indicate all intercepts with the axes, turning points and
end points. (4)
4.2 In the diagram, the graphs of f(x)=tanbx and g(x) =cos(x—30°) are drawn on
the same set of axes for x €[—180° ;180°].
P(90°; 1) lies on f and Q lies on g, such that PQ is parallel to the y-axis.
A is a turning point of g.
cd
aq
a
\
2
S
/
ne, A ae
o
2
Use the diagram to answer the following questions:
4.2.1 Write down the value of b. ()
4.2.2 Write down the coordinates of A, the turning point of g. (2)
4.2.3 Write down the coordinates of Q. (2)
4.2.4 Write down the equation of the asymptote of y=tanb(x+20°) for
x €[-180° ;180°]. (1)
4.2.5 Determine the range of hif A(x) = g(x)+3. (2)
4.2.6 For which values of x, in the interval x €[0°,.:0u°y, will f(x).g(x) <0? (3)
[15]
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Matineaiwaloaded from Stanmorephysics. com Common Test September 2022
Grade 11
QUESTION 5
5.1 In the diagram below, F=35°, E=90°, GDF =14° and FG =7m.
D
2
LI 35°
E G Tm F
5.1.1 Write down the size of EGD. (1)
5.1.2 Calculate the length of DE. (5)
5.2 The diagram below shows a regular octagon inscribed in a circle of radius r cm and
with centre O. A and B are two vertices of the octagon. AO, BO and AB are drawn.
—
A
B
Se
5.2.1 Show that the area of the octagon is 2V27? cm’. (4)
5.2.2 If r=5 cm, calculate the perimeter of the octagon. (3)
[13]
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Matineawaloaded from Stanmorephiysics. COM Common Test September 2022
Grade 11
QUESTION 6
The solid below was made by drilling a right circular cone out of a right rectangular prism (i.e.
the cone is removed from the prism).
P, Q, Rand S are vertices of the prism such that PQ = 20 cm, QR = 15 cm, RS = 12 cm.
The radius of the cone, 7, is 4,5 cm and the height of the cone, A, is 6 cm.
The slant height ofthe cone is /.
Total surface area of a cone = zr? +r
S
|
|
|
|
|
| 12 cm
| N /
| \ ec M
| * “ 7 ‘
pot dt R
/ \ /
/ ys
/ \ if
\l/
/ v 15cm
/
/
/
/
P 20cm Q
Calculate the total surface area of the solid. [7]
TOTAL: 75
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Matineaiwaloaded from Stanmorephysics. com Common Test September 2022
Grade 11
NAME & SURNAME:
DIAGRAM SHEET
QUESTION 3.3.1
I T T T I T I T I y T 1 1
80 90 100 110 120 130 140
QUESTION 4.1
gle
3
2
1
—90° 0 ' 90° : j 180° : 270°
4 i i i i i i
~a'- ae ne ae
| ee
et nana
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Downloaded from Stanmorephysics.com
KWAZULU-NATAL PROVINCE
EDUCATION
REPUBLIC OF SOUTH AFRICA
NATIONAL
SENIOR CERTIFICATE
This marking guideline consists of 7 pages.
Mathefagwrdoaded from Stanmorephysics.com
GRADE 11
Marking Guideline
QUESTION 1
Common Test September 2022
P(older than 30 years) = 352
¥ 352 (as numerator)
. 560 ¥ 560 (as denominator)
a . :
(a) = 0,63 Answer only: full marks (2)
. 99
1.1.1 | P(more than 2 accidents) = —— 99
(b) 560 v answer (——or 0,18)
=0,18 560
0)
. 48
i P(older than 30 years and more than 2 accidents) = 560 Y 48 in numerator
fe = 0,09 v answer
(2)
1.1.2 P(older than 30 years) x P(more than 2 accidents)
2
= 352 x 2 Y calculating P(older than
560 560 30 years) x P(more than 2
_ 1089 or 0,11 accidents)
9800
.. P(older than 30 years) x P(more than 2 accidents) # V reasoning
P(older than 30 years and more than 2 accidents) v .
Therefore: the events are not independent conclusion G)
1.2.1 P(S)
P(A One mark each for the
(A) P(B) following values placed
correctly:
v 0,3
v 0,25
v 0,35
v0,1
0,1
(4)
1.2.2 | P[not(A omB)] = Ogi V0,1
Q)
1.2.3 | P[A and (not B)] =0,3 ¥0,3
Q)
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Mathehaowrdoaded from Stanmorephysics.com
Common Test September 2022
GRADE 11
Marking Guideline
1.3 A tree diagram may be drawn to represent all the possible outcomes
with their probabilities:
Contract
0,08
Masks
0,82 0,92
Not Contract
Contract
0,73,
0,18
No masks
0,27
Not Contract
P(mask and contract) + P(no mask and contract) ¥¥ 0,82 0,08
= 0,82 x 0,08 + 0,18 x 0,73 vv 0,18 0,73
=0,20 or 20% ¥ answer after addition
(accept 19,70%) (5)
[19]
QUESTION 2
2.1 120 cars v answer
Q)
2.2 45000 < x < 55000 vv answer
Y (2)
OR fr J
45000<x<55000 vv answer 0)
2.3 46 500 km vv answer
(accept from 46 000 to 47 000)
(2)
2.4 120 — 77 = 43 cars Y 77 (accept 76 to 78)
vo 9
Percentage: 8 = 35,83% 43 (accept 42 to 44)
120 VY 35,83% (accept 35,0% to
36,67%)
(3)
[8]
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Mathehaowrdoaded from Stanmorephysics.com
GRADE 11
Marking Guideline
Common Test September 2022
QUESTION 3
3.1.1 1385 vy 1385
12 12
= 115,42 v
Answer only: full marks answer (2)
3.1.2 | 18,67 km v answer
dQ)
3.2 | Interval: —(115,42—18,67 ; 115,42 +18,67)
= (96,75 ; 134,09) Y 96,75
Outside of this interval: (82; 89; 94; 135; 140) ¥ 134,09
Therefore: on 5 days Y answer
(3)
3.3.1 v whiskers
—______ |__1 ending at 82 and
82 97 722 730 140 ee
+ +‘ + + + box from 97
I q I T I T J I ' T 1 to 130
80 90 100 110 120 130 140 | Q, at 122
(3)
3.3.2 | The data is skewed to the left OR negatively skewed v answer
()
3.4.1
New mean = 1385+12x y 1385+ 12x
12 Answer only: full marks 12
=115,42+x Vv 115,42+x
(2)
3.4.2 | 18,67 km vv answer
dQ)
[13]
QUESTION 4
41 (-90°;2) (270°;2
v x-intercepts
t and y-intercept
Y turning point
Vv :
oD 0° x end points
an
(90°:-2)
v shape
(4)
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Mathefagwrdoaded from Stanmorephysics.com
Common Test September 2022
GRADE 11
Marking Guideline
1 Y answer
4.2.1 ==
2 Q)
42.2 | AGo':1) Y 30°
vor
(2)
423 (90:5) v .
vo
2
(2)
4.2.4 | x=160° v answer
dd)
42.5 | 2<y<4 ¥ endpoints
Y correct notation
OR (2)
ye[2; 4] Y¥ endpoints
Y correct notation (2)
4.2.6 | »=0° or 120° <x <180° VY x=0°
Y endpoints of interval
OR Y correct notation
G3)
x=0° or xe[120° ; 180°) vx=0
Y¥ endpoints of interval
Y correct notation
GQ)
[15]
QUESTION 5
5.1.1 | 49° v answer
dd)
s12| DG_ GF —
a“ sinF sinFDG Y applying sine rule in
triangle DGF
DG 7 ae
: =— Y substitution
sin35° sinl4°
DG= 7xsin35
sin 14°
_ 7xsin35°
sin 14° Vv
= 16,60 m length of DG
DE = sin EGD
DG
DE — . aoe Y substitution in correct trig
—— =sin 49 :
16,60 ratio
DE=16,60xsin 49°
-1253m ¥ answer
(5)
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Matheaowrdoaded from Stanmorephysics.com
Common Test September 2022
GRADE 11
Marking Guideline
A 360° ° . A
5.2.1 | AOB =—— = 45 [ Zs around a point] ¥v AOB=45°
AOQ=BO=r
Area of AAOB= 5AO-BOssin AOB
= 1 sins” Y substitution into area rule
-lp _ OR 1p ve vip? tL or 1? v2
2 \V2 2 (2 2 \W2 2 | 2
Area of the octagon = 8x Area of AAOB
1 2
-( 35) OR (2 )2 ¥ 8xArea of AAOB
= 4 2 2 2
-(4} OR (2v2)r cm
_| 2x V2xV/2 2
V2
=2/2r? cm?
(4)
5.2.2 | AB’ =AO’ +BO*=2.A0,BO.cos AOB
=57 +57 —2(5\(5)cos 45° Y substitution into cosine rule
=14,64
- AB=3,83 cm Y length of AB
.”. perimeter = 8 x 3,83 = 30,61 cm v answer
G)
[13]
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Mathefagwrdoaded from Stanmorephysics.com
GRADE 11
Marking Guideline
QUESTION 6
Common Test September 2022
TSA of prism = 2(12x20)+2(12x15)+2(15x 20)
=480+360+600
=1440cm?
Area of circular base of cone = 2x1?
=2x4,5°
= 63,62 cm?
Slant height of cone (@) = Vh? +r
= 6° +4,5°
=7,5cm
Lateral surface area of cone = 7 xrx
=71x4,5x7,5
= 106,03 em?
TSA of solid =1440 +106, 03 — 63, 62
=1482,41 cm?
¥ 2(12x 20) + 21215) +2(15x 20)
v answer
Y 63,62 cm?
Y using Theorem of Pythagoras
v¥ 7,5 cm
¥ 106,03 cm?
v answer
[7]
Copyright Reserved
TOTAL: 75
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