Mathematics
NQF Level 4
*see terms and conditions
Downloaded from hlayiso.com
Mathematics NQF Level 4
Skip to contentStudy guide View all
Maths Level 4 Module 13
Level 4 Mathematics study guide, 23 pages. Read online or get the free PDF download.
Subject: MathematicsMultiple grades23 pages
Mathematics. Study guide, 23 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Multiple grades
- Document type
- Study guide
- Curriculum
- TVET
- Pages
- 23
- File size
- 645.3 KB
Loading document…
Loading document…
1 of 23
Document textSearch extracted text and jump to a page.
Data handling and
probability models
Topic 4
Downloaded from hlayiso.com
Mathematics NQF Level 4
Use experiments, simulations
and probability distribution
to set and explore probability
models
Module 13
Downloaded from hlayiso.com
Mathematics NQF Level 4
Learning activity 13.2
Downloaded from hlayiso.com
Mathematics NQF Level 4
Venn diagram – vid 24
Downloaded from hlayiso.com
Learning activity 13.2
Learning activity 13.3
Downloaded from hlayiso.com
Mathematics NQF Level 4
Tree diagram – vid 23
Downloaded from hlayiso.com
Learning activity 13.3
Summative assessment
Module 13
Downloaded from hlayiso.com
Mathematics NQF Level 4
1) There are 450 boys in a school. 250 play
soccer and 90 play cricket. 50 play cricket
and soccer.
1.1) Draw a Venn diagram of the information.
Figure 13.8
Downloaded from hlayiso.com
Summative assessment – Module 13
1.2 Determine:
a) P(soccer)
250
p(s) =
450
= 0,556
b) P(soccer and cricket)
50
p(s and c) =
450
= 0,111
Downloaded from hlayiso.com
Summative assessment – Module 13
1.2 (Continued)
c) P(soccer or cricket)
290
p(s or c) =
450
= 0, 644
d) P(not playing soccer)
1 200
p(s ) =
450
= 0, 444
Downloaded from hlayiso.com
Summative assessment – Module 13
2) A box contains 12 identical balls, of which
four are white and eight are red.
The sample space is S
S = {W1 ; W2 ; W3 ; W4 ; R1 ; R 2 ; R 3 ; R 4 ; R 5 ; R 6 ; R 7 ; R 8 }
Calculate the probability of drawing:
2a) A white ball
n(W)
p (W) =
n(S)
4
=
12
= 0,333
Downloaded from hlayiso.com
Summative assessment – Module 13
2b) A red ball
n( R )
p( R) =
n(S)
8
=
12
= 0, 667
Downloaded from hlayiso.com
Summative assessment – Module 13
3) A box contains six balls: two white ones,
three red ones and one blue one.
Two balls are drawn from the box.
From a tree diagram
n(S) = 30;
n(r and r) = 6;
n(b and b) = 0;
n(W) = 18;
n(w and r) = 12
Downloaded from hlayiso.com
Summative assessment – Module 13
3) Continued
Determine the probability of the following:
3a) Both balls being red
6
p (r and r ) =
30
2
=
10
= 0, 2
3b) Both balls being blue
0
p (b and b) =
30
=0
Downloaded from hlayiso.com
Summative assessment – Module 13
3) Continued
3c) One ball being white
18
p ( w) =
30
3
=
5
= 0, 6
3d) One white and one red ball being drawn
12
p ( w and r) =
30
2
=
5
0.4
=Downloaded from hlayiso.com
Summative assessment – Module 13
4) A coin is tossed and a die is rolled.
4.1) Show this event on a tree diagram.
Figure 13.9
Downloaded from hlayiso.com
Summative assessment – Module 13
4.2) Determine the probability of obtaining
“heads” and an even number.
3
p (H; even) =
12
= 0, 25
4.3) Determine the probability of obtaining
“heads” and a 4.
1
p (H; 4) =
12
= 0, 0833
Downloaded from hlayiso.com
Summative assessment – Module 13
4.4) Determine the probability of obtaining
“tails” and an uneven number.
3
p (T ; uneven) =
12
= 0, 25
Downloaded from hlayiso.com
Summative assessment – Module 13
5) The following two-way table contains results
of a survey investigating the effect of
smoking on lung cancer:
Effect on lung cancer Male (M) Female (F) Total
Positive result (P) 70 60 130
Negative result (N) 42 49 91
Total 112 109 221
Downloaded from hlayiso.com
Summative assessment – Module 13
5a) Use the original table and calculate
P(M) × P(P).
112 130
p (male) ⋅ p (pos) = ×
221 221
14 560
=
48 841
= 0, 298
5b) Calculate P(M and P).
70
p (male and pos) =
221
= 0,317
Downloaded from hlayiso.com
Summative assessment – Module 13
5c) Change the expected numbers in the cells
for the data to be more independent. The
totals must stay the same.
Ratio 112:109
112
∴ The positive male result must be ×130
221
14 560
=
221
Male Female Total = 65,88 (66)
Positive result 66 64 130
No positive result 46 45 91
Total 112 109 221
Downloaded from hlayiso.com
Summative assessment – Module 13
Mathematics NQF Level 2
Downloaded from hlayiso.com
Mathematics NQF Level 4
Study this subject
Notes, quizzes and topic questions for this subject.
Recommended for this subject
More papers and memos for this grade and subject.

















