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Math L3 Module 1

Level 3 Mathematics study guide, 49 pages. Read online or get the free PDF download.

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Mathematics NQF Level 3 *see terms and conditions Downloaded from hlayiso.com Mathematics NQF Level 3
Complex numbers Topic 1 Downloaded from hlayiso.com Mathematics NQF Level 3
Represent complex numbers in a form appropriate to the context Module 1 Downloaded from hlayiso.com Mathematics NQF Level 3
Writing imaginary numbers in i-notation Figure 1.4: A graphical representation of the number system with complex number Downloaded from hlayiso.com Unit 1.1
Click above to play this video. Downloaded from hlayiso.com Unit 1.1
Learning activity 1.1 Downloaded from hlayiso.com Mathematics NQF Level 3
8 4 20 2. Simplify 60 j + 10 j − 20 j and write in the rectangular form a ± bi: Remember, i and j are both used to 60 j 8 + 10 j 4 − 20 j 20 represent imaginary numbers = 60( j 4 ) 2 + 10( j 4 ) − 20( j 4 )5 2 2 2 2 2 2 2 5 = 60( j j ) + 10( j j ) − 20( j j ) 2 5 = 60[(−1)(−1)] + 10[(−1)(−1)] − 20[(−1)(−1)] Substitute j 2 = −1 Downloaded from hlayiso.com Learning activity 1.1
2. Continued = 60[(−1)(−1)]2 + 10[(−1)(−1)] − 20[(−1)(−1)]5 = 60(1) 2 + 10(1) − 20(1)5 = 60 + 10 − 20 = 50 Downloaded from hlayiso.com Learning activity 1.1
4. Solve for x and write the answers in i- notation: 1) −3 − 81 −1 Subsitute i 2 = −1 = 3 3 (−1 − 3i ) = 3 =−1 − 3i Downloaded from hlayiso.com Learning activity 1.1
Learning activity 1.2 Downloaded from hlayiso.com Mathematics NQF Level 3
Simplify: 6) 3 2i × i 7 13) = 2i10 = 2(i 2 )5 2 5 = = 2(−1) −1 = −2 Subsitute i 2 = −1 Subsitute i 2 = −1 Downloaded from hlayiso.com Learning activity 1.2
Learning activity 1.3 Downloaded from hlayiso.com Mathematics NQF Level 3
Click above to play this video. Downloaded from hlayiso.com Learning activity 1.3
The relationship between the rectangular and polar forms Figure 1.11: The relationship between the rectangular and polar forms Downloaded from hlayiso.com Unit 1.4
Learning activity 1.4 Downloaded from hlayiso.com Mathematics NQF Level 3
Click above to play this video. Downloaded from hlayiso.com Learning activity 1.4
1. Write the following complex number in polar form: 1.3) Modulus = r a 2 + b2 Argand diagram Figure 1.9 Downloaded from hlayiso.com Learning activity 1.4
1. Write the following complex number in polar form: a and b without signs 1.3) 2 − 2i b Acute angle α = tan −1 a Figure 1.9 Downloaded from hlayiso.com Learning activity 1.4
1. Write the following complex number in polar form: 4th 1.3) quadrant Figure 1.9 Downloaded from hlayiso.com Learning activity 1.4
1. Write the following complex number in polar form: 1.3) Polar form: z = r cis θ or r θ Figure 1.9 Downloaded from hlayiso.com Learning activity 1.4
2. Write the following complex number in rectangular form (a + bi): 2.5) 5 [cos 240° + i sin 240°] = 5 [−0,5 + i (−0,866)] Rectangular form: z = r cis θ z= a + bi =z r (cos θ + i sin θ ) Downloaded from hlayiso.com Learning activity 1.4
Summative assessment Module 1 Downloaded from hlayiso.com Mathematics NQF Level 3
1. Simplify the following to the a + bi form 17 16 1.1) i 1.2) i 2 8 2 8 = (i ) i = (i ) 8 = (−1) i 8 = (−1) =i =1 Subsitute i 2 = −1 Subsitute i 2 = −1 Downloaded from hlayiso.com Summative assessment – Module 1
1. Simplify the following to the a + bi form ( 3i ) × i 3 6 1.3) 1.4) i 2 + 3i 3 – 2i 4 = 27i × i 3 6 =−1 + 3(i 2 )i − 2(i 2 ) 2 9 = 27i =−1 + 3(−1)i − 2(−1) 2 2 4 = 27(i ) i =−1 − 3i − 2 = 27(−1) 4 i =−3 − 3i = 27i Downloaded from hlayiso.com Summative assessment – Module 1
1. Simplify the following to the a + bi form 1.5) 3i 4 1.6) i ÷ 2i 6 3 9i 1 = ( i ) 2 2 = 2 2 (i )2 3 3i 1 1 = = 3(−1) 2(−1)3 1 1 = − = − 3 2 Downloaded from hlayiso.com Summative assessment – Module 1
2. Simplify without using a calculator and write in standard form: 2.1) = 2i (2 − i + 3i ) = 2 2i − 2i 2 + 6i 2 = 2,828i − 2 (−1) + 6 (−1) = 2,828i + 1, 414 − 2, 449 = −1, 035 + 2,828i Downloaded from hlayiso.com Summative assessment – Module 1
2. Simplify without using a calculator and write in standard form: 2.2) 6−4 j = 2 10 j + 6 j − 15 − 9 j 6−4 j = j + 6(−1) − 15 6 − 4 j −21 − j = × −21 + j −21 − j Downloaded from hlayiso.com Summative assessment – Module 1
2. Simplify without using a calculator and write in standard form: 2.2) Continued −126 − 6 j + 84 j + 4 j 2 = 441 + 21 j − 21 j − j 2 −126 + 78 j + 4(−1) = 441 − (−1) −130 + 78 j = 442 = −0, 294 + 0,176 j Downloaded from hlayiso.com Summative assessment – Module 1
3. Write the following complex numbers in polar form: Rectangular form 3.1) −2 + 4i z= a + bi z =−2 + 4i 2 2 Modulus = r a +b ∴ a =−2 ; b =4 ( ) 2 2 = −2 + 4 Argand diagram = 20 = 4, 472 Figure 1.13 Downloaded from hlayiso.com Summative assessment – Module 1
3. Write the following complex numbers in polar form: a and b 3.1) −2 + 4i without signs b Acute angle α = tan −1 a −1 4 = tan 2 = 63, 435° Figure 1.13 Downloaded from hlayiso.com Summative assessment – Module 1
3. Write the following complex numbers in polar form: 2nd 3.1) −2 + 4i quadrant = 180° − 63, 435° = 116,565° Figure 1.13 Downloaded from hlayiso.com Summative assessment – Module 1
3. Write the following complex numbers in polar form: 3.1) −2 + 4i Polar form: z = r cis θ or r θ =∴ z 4, 472 cis 116,565° = 4, 472 116,565° Figure 1.13 Downloaded from hlayiso.com Summative assessment – Module 1
3. Write the following complex numbers in polar form: 3.2) 4 − 7i =r a 2 + b2 4 + ( −7 ) 2 2 = = 8, 062 b α = tan −1 a 7 −1 = tan 4 Figure 1.14 = 60, 255° Downloaded from hlayiso.com Summative assessment – Module 1
3. Write the following complex numbers in polar form: 3.2) 4 − 7i = 360° − α θ = 360° − 60, 255° = 299, 745° z = r cis θ =∴ z 8, 062 cis 299,745° = 8, 062 299, 745° Figure 1.14 Downloaded from hlayiso.com Summative assessment – Module 1
3. Write the following complex numbers in polar form: 3.3) −1 − 3i =r a 2 + b2 ( −3) + ( −1) 2 2 = = 10 = 3,162 b α = tan −1 a −1 3 = tan 1 Figure 1.15 = 71,57° Downloaded from hlayiso.com Summative assessment – Module 1
3. Write the following complex numbers in polar form: 3.3) −1 − 3i = 180° + α θ = 180° + 71,57° = 251,57° z = r cis θ =∴ z 3,162 cis 251,57° = 3,162 251,57° Figure 1.15 Downloaded from hlayiso.com Summative assessment – Module 1
4. Write the following complex numbers in rectangular form: 4.1) 2 cis 100° 2(cos 100° + i sin 100°) 2(− = 0.173648.... + i 0.9848....) = −0,347 + 1,97i Rectangular form: z = r cis θ z= a + bi =z r (cos θ + i sin θ ) Downloaded from hlayiso.com Summative assessment – Module 1
4. Write the following complex numbers in rectangular form: 4.2) 4 cis 300° 4(cos 300° + i sin 300°) 4(cos 300° + i sin 300°) = 2 − 3, 464i Downloaded from hlayiso.com Summative assessment – Module 1
4. Write the following complex numbers in rectangular form: 4.3) 12 30° 12[cos 30° + i sin 30°] 12(0.866 + 0.5i ) = 10,392 + 6i Downloaded from hlayiso.com Summative assessment – Module 1
4. Write the following complex numbers in rectangular form: 4.4) 12 40° 12(cos 40° + i sin 40°) 12(0, 766 + i.0, 643) = 9,192 + 7, 716i Downloaded from hlayiso.com Summative assessment – Module 1
5. Represent z = −2 + 4i on an Argand diagram Figure 1.16: Argand diagram of z = −2+ 4i Downloaded from hlayiso.com Summative assessment – Module 1
6. Given z = 2 + 3i: 6.1) Represent z graphically in an Argand diagram. Figure 1.17: Argand diagram of z = 2 + 3i Downloaded from hlayiso.com Summative assessment – Module 1
6. Given z = 2 + 3i: 6.2) Calculate the modulus (r) and the argument (θ) of z The modulus ( r ) : The argument (θ ) : 2 r= 22 + 32 Downloaded from hlayiso.com Summative assessment – Module 1
6. Given z = 2 + 3i: 6.3) Express z in polar form Polar form Downloaded from hlayiso.com Summative assessment – Module 1
7. Study the argand diagram and answer the questions that follow: 7.1) The rectangular form of the complex number z z= a + bi z=−2 + 4i Figure 1.19: Argand diagram for Question 7 Downloaded from hlayiso.com Summative assessment – Module 1
7. Given the diagram below determine: 7.2) The modulus (r) =r a 2 + b2 ( ) 2 2 r= −2 + 4 = 20 = 4, 472 Figure 1.19: Argand diagram for Question 7 Downloaded from hlayiso.com Summative assessment – Module 1
7. Given the diagram below determine: 7.3) The value of the argument (θ) 4 tan α = 2 4 ∴α =tan −1 2 = 63, 43° θ = 180° − 63, 43° = Figure 1.19: Argand diagram for Question 7 116,57° Downloaded from hlayiso.com Summative assessment – Module 1
7. Given the diagram below determine: 7.4) Write the answer in polar form z=r θ =z 20 116,57° = 4, 472 116,57° Figure 1.19: Argand diagram for Question 7 Downloaded from hlayiso.com Summative assessment – Module 1
Mathematics NQF Level 2 Downloaded from hlayiso.com Mathematics NQF Level 3

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Math L3 Module 1 | Hlayiso