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Math L2 Module 7

Level 2 Mathematics study guide, 21 pages. Read online or get the free PDF download.

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Mathematics NQF Level 2 Downloaded from hlayiso.com *see terms and conditions Mathematics NQF Level 2
Calculating perimeter, surface area and volume in 2D and 3D geometrical shapes Module 7 Downloaded from hlayiso.com Mathematics NQF Level 2
Learning activity 7.1 Downloaded from hlayiso.com Mathematics NQF Level 2
5. Calculate the perimeter and area of a trapezium with parallel sides of 2 m and 2,8 m and perpendicular height 1,8 m. 1 area = (sum of sides   height ) 2 1 area = (AB + CE) × AE 2 1 area  (2  2,8)  1, 8 2 2 area = 4,32 m LG Figure 7.1 Downloaded from hlayiso.com Learning activity 7.1
5. Calculate the perimeter and area of a trapezium with parallel sides of 2 m and 2,8 m and perpendicular height 1,8 m. Perimeter  sum of sides Perimeter  AB + BC + CE + AE 1,97 m BC 2  DC 2  BD 2 BC 2  (2,8  2) 2  (1,8) 2 BC 2  (0,8) 2  (1,8) 2  0, 64  3, 24  3,88  BC  3,88 LG Figure 7.1  1, 97 m Downloaded from hlayiso.com Learning activity 7.1
5. Calculate the perimeter and area of a trapezium with parallel sides of 2 m and 2,8 m and perpendicular height 1,8 m. Perimeter  sum of sides 1,97 m Perimeter  AB + BC + CE + AE Perimeter  2  1,97  2,8  1,8 = 8,57 m LG Figure 7.1 Downloaded from hlayiso.com Learning activity 7.1
Learning activity 7.3 Downloaded from hlayiso.com Mathematics NQF Level 2
2. Calculate the volume of a triangular prism if its base is a right-angled triangle with the sides adjacent to the 90° angle 8 cm and 6 cm and its perpendicular height 12 cm. 1 2 Area of base  (8)(6)  24 cm 2 Volume = area of base   height  24  12 3  288 cm Downloaded from hlayiso.com Learning activity 7.3
Click above to play this video. Downloaded from hlayiso.com Unit 7.4
Summative assessment Module 7 Downloaded from hlayiso.com Mathematics NQF Level 2
1. Calculate the perimeters and areas of the following laminas: 1.1 A triangle of sides 12 cm, 14 cm and 16 cm Perimeter = a  b  c  12  14  16 = 42 cm Downloaded from hlayiso.com Summative assessment – Module 7
1. Calculate the perimeters and areas of the following laminas: 1.1 A triangle of sides 12 cm, 14 cm and 16 cm (cont.) Area  s ( s  a )( s  b)( s  c ) Semi-perimeter (s)  21(21  12)(21  14)(21  16) abc s 2  21(9)(7)(5) 42 s  6 615 2  81, 333 cm 2 s  21 Downloaded from hlayiso.com Summative assessment – Module 7
1. Calculate the perimeters and areas of the following laminas: 1.2 A circle of radius 4 cm Circumference  2 r  2 (4) 2  8 cm  25,133 cm2 Downloaded from hlayiso.com Summative assessment – Module 7
1. Calculate the perimeters and areas of the following laminas 1.2 A circle of radius 4 cm (continued) 2 Area   r 2   (4) 2  16 cm 2  50, 265 cm Downloaded from hlayiso.com Summative assessment – Module 7
2. A cube of dimensions 7 cm is melted into a hexagonal prism with a base length of 4 cm. Calculate the height of the prism. 2 Volume of cube  l 3 7 3  343 cm Downloaded from hlayiso.com Summative assessment – Module 7
2. (continued) 3 3 2 Volume of prism  ah 2 V (2) h  2 3 3a 343(2) h 2 3 3(4)  8, 251 cm Downloaded from hlayiso.com Summative assessment – Module 7
3.1 Calculate the area of a parallelogram with a side of 12 cm and perpendicular height 7 cm. Ab h  12  7  84 cm2 Downloaded from hlayiso.com Summative assessment – Module 7
Click above to play this video. Downloaded from hlayiso.com Summative assessment – Module 7
Click above to play this video. Downloaded from hlayiso.com Summative assessment – Module 7
4. Calculate the surface area of a cylinder of base diameter 20 cm and perpendicular height 30 cm. 2 A  2 rh  2 r 2  2 (10)30  2 (10)  1 884,956 + 628,319 2 = 2 513,275 cm Downloaded from hlayiso.com Summative assessment – Module 7
Downloaded from hlayiso.com Mathematics NQF Level 2

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