Mathematics Grade 8 Paper 1 November Mock 2026 Memo

Copyright reserved Please turn over Mock hlayiso mock exams Practice Series: Grade 8 Exam Preparation WWW.HLAYISO.COM SENIOR PHASE END-OF-YEAR EXAMINATION GRADE 8 MATHEMATICS P1 NOVEMBER 2026 (MOCK) MARKING GUIDELINES MARKS: 75 These marking guidelines consist of 7 pages.

Mathematics/P1 2 Senior Phase – Marking Guidelines Hlayiso/Mock 2026 NOTE: • If a learner answers a question TWICE, only mark the FIRST attempt. • If a learner has crossed out an attempt and not redone the question, mark the crossed-out version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines. Stop marking at the second calculation error. • Accept correct alternative methods. Answers only: award full marks ONLY where the guideline says so. • Do not penalise learners if units are omitted in final answers, unless the question asks for them. SECTION A QUESTION 1 1.1 B (−7 is a negative integer; natural numbers are 1 ; 2 ; 3 ; ...) ✓B (1) 1.2 A (3,6×105) ✓A (1) 1.3 C (highest exponent is 5) ✓C (1) 1.4 C (460×1,15 = R529) ✓C (1) 1.5 C (cube numbers: 53 = 125) ✓C (1) [5] SECTION B QUESTION 2 2.1 150 = 2×3×5×5 150 = 2×3×52 ✓prime factors ✓exponential form (2) 2.2 HCF = 2×3 = 6 LCM = 23 ×3×52 ×7 = 4200 ✓HCF = 6 ✓LCM = 4200 (CA from 2.1) (2) 2.3 = √ 25−(−4)+(−8) = 5+4−8 = 1 ✓ √ 25 = 5 ✓+4 and −8 ✓answer (3) Copyright reserved Please turn over

Mathematics/P1 3 Senior Phase – Marking Guidelines Hlayiso/Mock 2026 2.4 = 5 2 −6 12 = 5 2 −1 2 = 4 2 = 2 ✓5 2 ✓1 2 (multiplication first) ✓answer (3) [10] QUESTION 3 3.1 Total parts = 2+3+4 = 9 One part = 1350 9 = R150 Ayanda: R300; Bheki: R450; Zola: R600 OR 2 9 ×1350 = R300, 3 9 ×1350 = R450, 4 9 ×1350 = R600 ✓9 parts / R150 ✓any two shares ✓all three shares (3) 3.2 Time = distance speed = 270 90 = 3 hours Arrival: 07:45+3 h = 10:45 ✓3 hours ✓10:45 (CA) (2) 3.3 SI = 6500×4×0,075 SI = R1950 Amount = 6500+1950 = R8450 OR A = 6500(1+4×0,075) = R8450 ✓substitution ✓R1 950 ✓R8 450 (CA) (3) [8] QUESTION 4 4.1 = 4x6y2 ×3xy4 6x5y3 = 12x7y6 6x5y3 = 2x2y3 ✓4x6y2 ✓12x7y6 or coefficient 2 ✓x2y3 (3) 4.2 = 7a4 −2a4 = 5a4 ✓7a4 and 2a4 ✓answer (2) Copyright reserved Please turn over

Mathematics/P1 4 Senior Phase – Marking Guidelines Hlayiso/Mock 2026 4.3 = 34 ÷33 +1 = 3+1 = 4 OR 81÷27+1 = 4 ✓34 ÷33 or 81÷27 ✓answer (2) [7] QUESTION 5 5.1.1 1 ✓answer (1) 5.1.2 −7 ✓answer (1) 5.1.3 = −5(−2)3 +3(−2)2 +(−2)−7 = −5(−8)+3(4)−2−7 = 40+12−2−7 = 43 ✓substitution ✓40 and 12 ✓answer (3) 5.2.1 = 6a2 −3ab−2a2 −8ab = 4a2 −11ab ✓6a2 −3ab ✓−2a2 −8ab ✓answer (3) 5.2.2 = 12x3 4x −8x2 4x + 4x 4x = 3x2 −2x+1 ✓3x2 −2x ✓+1 (2) 5.2.3 (5p2 −3p+2)−(2p2 −p−6) = 5p2 −3p+2−2p2 + p+6 = 3p2 −2p+8 ✓correct order and signs ✓answer (2) [12] Copyright reserved Please turn over

Mathematics/P1 5 Senior Phase – Marking Guidelines Hlayiso/Mock 2026 QUESTION 6 6.1.1 5x−2x = 8+7 3x = 15 x = 5 ✓3x = 15 ✓answer (2) 6.1.2 3x−12−2x−2 = 6 x−14 = 6 x = 20 ✓3x−12 ✓−2x−2 ✓answer (3) 6.1.3 ×6: 2x+12 = 3x−6 12+6 = 3x−2x x = 18 ✓multiplying by LCD 6 ✓2x+12 = 3x−6 ✓answer (3) 6.1.4 5x = 125 5x = 53 x = 3 ✓5x = 125 or 53 ✓answer (2) 6.2 Kagiso: x Lerato: x+6 (x+4)+(x+6+4) = 40 2x+14 = 40 x = 13 Lerato is 13+6 = 19 years old. (Trial and improvement with a check: full marks) ✓equation ✓x = 13 ✓19 years (CA) (3) [13] Copyright reserved Please turn over

Mathematics/P1 6 Senior Phase – Marking Guidelines Hlayiso/Mock 2026 QUESTION 7 7.1.1 p = 10 q = 12 ✓p ✓q (2) 7.1.2 Constant difference = 2 Tn = 2n+2 ✓2n ✓+2 (2) 7.1.3 2n+2 = 64 2n = 62 n = 31 tables ✓equating to 64 ✓31 tables (CA) (2) 7.2.1 Constant difference = 3 y = 3x−4 ✓3x ✓−4 (2) 7.2.2 a = 3(4)−4 = 8 b = 3(10)−4 = 26 ✓a = 8 ✓b = 26 (CA) (2) [10] Copyright reserved Please turn over

Mathematics/P1 7 Senior Phase – Marking Guidelines Hlayiso/Mock 2026 QUESTION 8 8.1.1 12 km ✓answer (1) 8.1.2 From 08:45 to 09:30: 45 minutes ✓answer (1) 8.1.3 Distance = 12 km; time = 09:30 to 10:30 = 1 hour Speed = 12 1 = 12 km/h ✓12 km and 1 hour ✓12 km/h (2) 8.1.4 To the park: the graph is steeper from A to B (12 km in 45 min = 16 km/h, compared to 12 km/h on the way back). ✓to the park with reason (No mark for the answer without a reason) (1) 8.2.1 x −1 0 1 2 3 y −3 −1 1 3 5 ✓any three correct ✓all five correct (2) 8.2.2 x y (3 ; 5) (−1 ; −3) ✓at least three points plotted correctly ✓all five points plotted correctly ✓straight line drawn through the points (CA from 8.2.1) (3) [10] TOTAL: 75 Copyright reserved