Limpopo Maths Literacy Grade 12 March 2023 QP and Memo

Downloaded from Stanmorephysics.com pine 3riy on NS A. REPUBLIC OF SOUTH AFRICA ST DEPARTMENT OF EDUCATION SEKHUKHUNE EAST DISTRICT — DISTRICT ON THE RISE MATHEMATICAL LITERACY 2023 TERM:1, TEST GRADE 12 DATE: 07 MARCH 2023 MARKS: 100 DURATION: 2 HOURS This paper consists of TEN pages including Annexures and Answer Sheet

Downloaded from Stanmorephysics.com INSTRUCTIONS AND INFORMATION 1. The paper consists of FOUR questions. Answer ALL questions. 2. Number your answers according to the numbering system in the paper. 3. There are THREE Annexures as follows 3.1. Use ANNEXURE A for QUESTION 1. 3.2. Use ANNEXURE B for QUESTION 2. 3.3. Use ANNEXURE C for QUESTION 4 4, Use the ANSWER SHEET for QUESTION 4.2.7 5. You may use an approved calculator, non-programmable and non-graphical. 6. Show all calculations clearly. 7. Indicate units of measurements, where applicable. 8. Round all answers according to the contexts, unless specified otherwise. 9. Maps and diagrams are not necessarily drawn to scale.

Downloaded from Stanmorephysics.com Question 1 Ms Abraham is 35 years old and earns a monthly salary of R27 500. She contributes 7.5% of her annual gross income towards her pension fund. ANNEXURE A shows the tax rates for 1 March 2019 to 29 February 2020 Use ANNEXURE A and the information above to answer the questions that follow. 1.1. Explain the word gross income as it was used in this context. (2) 1.2. Show how the value of R35 253 was calculated. (4) 1.3. Determine Ms Abraham’s annual taxable income for the year 2020. (5) 1.4 Ms Abraham indicated that she should not pay more than R 50 000 towards tax during 2020. Calculate her annual tax to verify whether she is correct. (6) 1.5 Due to COVID-19, her monthly salary was reduced from R27 500 to R24 800 in 2021.Calculate the percentage decrease(convert the answer to one decimal place). (4) /21/ Question 2 ANNEXURE B shows an adapted version of an electricity account statement for Meso High School received from Eskom. Some of the information has been omitted. Interest is charged on accounts in arrears (unpaid on the date payable) at rate of 12.5% per annum, compounded monthly. All amounts exclude 15% of VAT. Use ANNEXURE B and the information above to answer the questions that follow. 2.1 Show that the missing value A is 2678 Kwh. (2) 2.2 Calculate the value of B. (2) 2.3 Determine the value of C, the VAT amount charged. (2) 2.4 Calculate the total amount due (D), including interest. Show all calculations. (5) AW

Downloaded from Stanmorephysics.com Question 3 3.1 Mrs Lediga from Meso High School decided to sell sandwiches during lunch breaks asa fundraising project. The cost price of making one sandwich is R8.50 and the daily fixed cost is R70.00.The intended profit margin is 35%. A sandwich is a food item consisting of two slices of bread with a filling between them, eaten as a light meal. TABLE 1: INCOME RECEIVED FROM THE SALE OF SANDWICHES Number of sandwiches (n) 0 10 20 30 70 100 Income in rand(R) 0 115 230 345 805 1150 TABLE 2: COST PRICE OF SANDWICHES Number of sandwiches(n) 0 10 20 30 n 100 Cost price in rand(R) 70 155 240 325 750 920 Mrs Lediga used the following formula to calculate the cost price of the Sandwiches: Cost = R70 + R8.50 xn where n is the number of sandwiches Use the information above to answer the questions that follow. 3.1.1 3.1.2 3.1.3 Determine the selling price of ONE sandwich (to the nearest 10 cents), if Mrs Lediga’s intended profit margin is 35%. (4) TABLE 1 shows the income received from the sale of sandwiches Write down an equation that can be used to calculate the income. (2) Calculate the value of n in Table 2, where n is the number of sandwiches (3)

Downloaded from Stanmorephysics.com 3.2 Maranatha Metal Polishing Company is based in Durban. Given below is the company’s income and expenditure statement for December 2020. [ INCOME (R) EXPENDITURE (R) | National Products (Local) 1984 609 | | Salaries 1 362 912 International Products (Exports) | 3055 713 | | Overtime 187 427 Fuel [191 102 Repairs & Services 115 346 Office Supplies | 1891 Cleaning Materials 5.007 Water & Electricity 18 238 Rent 47311 TOTAL: | 5 040 322 TOTAL: | 1 929 234 Use the information above to answer the questions that follow. 3.2.1 What percentage of total income is total expenditure? (3) 3.2.2 Due to Covid-19, the export earnings for the company fell by 75% in January 2021 and local earnings decreased by 47%. Calculate the profit/ loss for the company in January 2021. (7) 3.3 Mrs Lediga has planned a family (her husband and two daughters aged 7 and 10) 7 night stay holiday in Tokyo, Japan. At the end of November 2020 the average price of dinner per adult was $13.50 and half of the price per child. She estimated that the inflation rate (percentage price increase) should not be more than 10%by June 2021. The exchange rate as at 2 march 2021 was ¥ 1= RO.1404 ¥ = Japanese Yen $ 1= ¥ 106.86 $= US Dollar [Sources: www.transferwise.com and MP 2019] Use the information above to answer the questions that follow. 3.3.1 Mrs Lediga said that the total cost for their dinner would not exceed R3 000.00 for the duration of their stay. Verify whether she is correct. (9) 3.3.2 Which is the weaker currency between the South African and the Japanese Yen? (2) /30/

Downloaded from Stanmorephysics.com Question 4 4.1 4.2 A statistician wants to check the trends of the number of tourists who visited South Africa from SADC countries and overseas in 2015. The information is displayed in ANNEXURE C. Use ANNEXURE C and the information above to answer the questions that follow: 4.1.1 Determine the total number of tourists from overseas countries who visited South Africa in 2015. Write your answer in words 4.1.2 Calculate the mean number of tourists from SADC countries. 4.1.3 Determine the probability ( as a percentage) of randomly selecting a SADC country with the number of tourists not more than 1 million 4.1.4 Write down the ratio of the number of tourists from Canada to the number of tourists from Mozambique in form 1: ............ 4.1.5 Calculate the inter-quartile range of tourists from overseas countries (4) (3) (2) (3) (2) The data below represent the percentage marks achieved by Grade 12 learners in Life Sciences. The class consists of 20 learners. 64 57 58 62 59 A 60 61 62 71 62 65 66 64 75 80 B B 92 85 A is the lowest percentage mark Use the information above to answer questions that follow: 4.2.1 Determine the percentage of data values that lies between the lower quartile and the upper quartile. 4.2.2 Calculate the value of A, if the range of the marks obtained by the learners is 36. 4.2.3 Write down the modal percentage. 4.2.4 Determine the value of B, given that the mean mark obtained by the learners is 48. 4.2.5 Calculate the median percentage mark. 4.2.6 Determine the probability (as common fraction in simplified form) of randomly selecting a learner who achieved more than 80%. 4.2.7. Complete the histogram of the number of learners obtaining the given mark intervals in ANSWER SHEET. (2) (3) (2) (3) (3) (3) (8) /38/

Downloaded from Stanmorephysics.com ANNEXURE A Question 1 INCOME TAX RATES FOR INDIVIDUALS FOR THE FINANCIAL YEAR 1 MARCH 2019 TO 28 FEBRUARY 2020 Tax bracket | Taxable income Rates of Tax (R) 1 0— 195 850 18% of taxable income 2 195 851 — 305 850 35 253 + 26% of taxable income above 195 850 3 305 851 — 423 300 63 853 + 31% of taxable income above 305 850 4 423 301 — 555 600 100 263 + 36% of taxable income above 423 300 5 555 601 — 708 310 147 891 + 39% of taxable income above 555 600 6 708 311 — 1500 000 | 207 448 + 41% of taxable income above 708 310 7 1500 001 and above | 532 041+ 45% of taxable income above 1 500 000 TAX REBATES Primary rebate (under 65) R14 220 Secondary rebate (persons 65 and R22 014 older Tertiary (persons 75 and older) R24 615 TAX THRESHOLD Persons under 65 R79 000 Persons 65 and under 75 R122 300 Persons 75 and older R136 750 Adapted from: www.sars.gov.za

Downloaded from Stanmorephysics.com ANNEXURE B QUESTION 2 ADAPTED ELECTRICITY ACCOUNT STATEMENT TAX INVOICE ESKOM VAT registration number: Not supplied Tel : 0860037566 Fax : 0862437566 PO Box 8610 JHB 200 Account month : February Billing date : 2020-02-26 2020 Tax invoice number : 599945472565 Account number : 5999481065 Name: Street address : Meso High School 34 President Street Rethusitswe Account Summary Amount in rand Balance brought forward R 2914.78 Electricity Kwh: Previous reading :112124 New reading : 114802 kwh used: A Energy charge(< 600 kwh) 600kwh @ R1.0566/kwh Energy charge(> 600 kwh) 2078kwh @ R1.7961 R 633.96 B Adjustment interest on overdue account VAT (5% eee Cc TOTAL AMOUNT DUE D DUE DATE : 2020-03-23 BANKING DETAILS : BANK: ABSA BRANCH CODE :745648 BANK ACCOUNT NUMBER : 73000000128 Source: www.eskom.co.za NOTE: e Accounts unpaid on the date payable are subject to interest at a rate of 12.5% Per annum, compounded monthly and services will be suspended. e Kwh (kilowatt hour) is the unit of three-phase

Downloaded from Stanmorephysics.com ANNEXURE C QUESTION 4.1 Tourist arrivals of Top 10 SADC countries" Tourist arrivals of Top 10 overseas countries" Visitor % Country of Visitor % Rankin arrivals Total Rankin origin arrivals Total 2015 arrival 2015 arrival g Country s 9 s of origin [==] 1900 [=] United 1 Zimbabwe 791 28.9 1 Kingdom 407 486 | 19.0 - 1394 [=| United 2 Lesotho [| 913 21.2 2 States 297 226 | 13.9 3 =| +200 18.3 3 G [==] 256 646 | 12.0 Mozambique 335 . ermany . 4 Eswatini ~~~] | 838006] 12.7 4 France | 128 438] 6.0 5 “1 |so3s14] 9.0 5 Netherland | 151 g83| 5.7 Botswana Ss 6 Namibia (| | 212514] 3.2 6 Australia [==] 99 205 4.6 7 Zambia |="| 161259] 2.5 7 China [>] 84691 3.9 8 Malawi || [135260] 2.1 8 India i 78 385 3.7 9 | 48 416 0.7 9 Canada [=| 56 224 2.6 Angola 10 re] 35 817 0.5 10 Italy [=] 52377 2.4 Tanzania

Downloaded from Stanmorephysics.com ANSWER SHEET A Name: Question 4.2.7 Intervals Frequency 50-59 60-69 9 70-79 80-89 90-100 LIFE SCIENCES MARKS 10 NUMBER OF LEARNERS - 50-59 60-69 80-89 90-100 MARK INTERVALS

Downloaded from Stanmorephysics.com REPUBLIC OF SOUTH AFRICA DEPARTMENT OF EDUCATION SEKHUKHUNE EAST DISTRICT — DISTRICT ON THE RISE NATIONAL SENIOR CERTIFICATE [ GRADE 12 MATHEMATICAL LITERACY 2023 TERM 1 TEST MEMORANDUM MARKS: 50 This memorandum consist of EIGHT pages.

Downloaded from Stanmorephysics.com Question 1 [21] 1.1 | The total earnings before taxes and other deductions. ~ ¥O 20 explanation (2) 1.2 18% of taxable income = = x R195850 “FY SF = R35 253,36 YS 1F choice of formula 1SF substitution = R35 253VR 1S simplification 1R rounding (4) 1.3 Taxable income = R27 500 — 7,5% of R27 500V™M M Maleply by 5% 7,9 = R27 500 — x R27 500“ SF 100 = R27 500 — R2 062,50 = R25 437,50 VCA Annual taxable income = R25 437,50 x 12¥M 1M Subtracting pension 1CA Answer 1M multiply by 12 = R305 250Y CA 1CA Answer OR Annual income = R27 500 x 12 1A Correct answer = R330 000VA Taxable income = R330 000 — 7,5% of R27 500” MY CA 1M Multiply by = R330 000- 2.x R27 500”M 73% 100 1CA pension amount = R330 000 — R24 750 1M Subtracting = R305 250WCA pension 1CA Answer (5) 1.4 | Annual tax = R35 253 + 26% of (R305 250 —R195 850) WSF 1SF Correct substitution = R35 253 + 26 R109 400 100 = R35 253 + R28 444VvM = R63 697V CA Payable tax = R63 697 — R14 220W MA = R49 477V CA She is correct. YO 1M Adding correct amounts 1CA simplification 1MA Subtracting rebates 1CA Answer 10 Conclusion (6)

Downloaded from Stanmorephysics.com 15 _ R24800— R27500 1SF Substituting Percentage decrease = a0 x 100% correct values 1M Calculating % vSFYM 1CA Answer =- wY 9,818181% VY CA IR Rounding = -9,8%YR (4) [21] Question 2 [11 Marks] 2.1 | A=114 802-112 124YRTYM 1RT reading = 2 678KWH correct values 1M subtraction (2) 2.2. | B=2078 Kwhx R1,7961/KwhY MA 1MA Multiply by R1.7961 = R3 732,30¥ CA 1A Correct Answer (2) 2.3. | VAT = 15% of R4 366,26 YMA 1MA Calculating VAT = R654,94VA 1A Correct answer (2) 2.4 | Monthly interest rate = 12.5% +12 YM 1M Dividing by 12 Amount of interest = R2 914.78 x 0.01041666667Y MA 1A Multiply by rate = R 30.36 Y¥CA 1CA Answer 1 MA Adding Total amount due (D) = R2 914.78 + R4 366.26 + R 654.94 + R30.36 ¥™MA =R7 966.77 VCA correct values 1CA Correct answer (5) [11]

Downloaded from Stanmorephysics.com Question 3 [30 Marks] 3.1.1 | Selling Price = R 8.50 + R 8.50 x 35% YM 1M 35% of R8.50 =R 8.50 + R 2.98 YM 1M Adding =R1148VCA 1CA Answer =R1150VR 1R Rounding OR Profit margin = R 8.50 x 35% YM 1M 35% Of R8.50 =R 2.98 1M Adding Selling price = R8.50 + R2.98 YM 1CA Answer =R1148VCA 1R Rounding =R1150YR OR Selling price = R 8.50 x 135% VA YM 1A 135% =R1148VCA 1M Multiply by =R1150VR 135% 1CA Answer 1R Rounding (4) 3.1.2 | Income in (R) = R11.50 x number of sandwiches ™A “CA CA from 3.1.1 OR 1CA R 11.50 Income in (R) = R11.50 x n where n is the number of 1AMultiply by n sandwiches ¥CA VA (2) 3.1.3 1M changing R750 = R 70 + R8.50 x P subject of the R750 — R70 = R8.50 x PYM formula R8.50 x P=R680 1S Simplification P = R680 + R8.50 WS 1CA Answer P=80“CA (3) 3.2.1 . _ R1929234 1MA dividing Total Expenditure = 5040329 x100% YMA YMA 1MA multiplying = 38,28%V A 1A correct answer (3)

Downloaded from Stanmorephysics.com 3.2.2 75% of R3 055 713 = R2 291 784,75” MA January export earnings = R3 055 713 — R2 291 784,75 = R763 928,25VA 47% of R1 984 609 = R932 766,23Y~M Local earnings = R1 984 609 — R932 766,23 = R1 051 842,77VA Total income for January = R1 051 842,77 + R763 928,25 =R1 815 771,02VA Loss for January = R1 815 771,02 — R1 929 234VM = R113 462,98V CA OR January export earnings = 0,25 x R3 055 713“ MA = R763 928,25V A Local earnings = 0,53 x R1 984 609V MA = R1 051 842,77VA Total income for January = R1 051 842,77 + R763 928,25 =R1 815 771,02VA Loss for January = R1 815 771,02 — R1 929 234YM = R113 462,98V“CA 1MA multiplying by 75% 1A answer 1M multiplying by 47% 1A answer 1A addition and answer 1M subtracting 1CA answer 1MA multiplying by 25% 1A answer 1MA multiplying by 53% 1A answer 1A addition and answer 1M subtracting 1CA answer (7) 3.3.1 | Price of dinner for 1 adult and 1 child in dollars =$13.50+$6.75 YMA 1MA Adding = $20.25 correct values Price of dinner for 2 adults and 2 children in dollars 1M Multiply by 2 =$20.25x2YM = $ 40.50 1C Converting to Price in Yen = $ 40.50 x 106.86 “C Yen =¥432783V A 1A Answer Price in Rand = ¥ 4 327.83 x 0.1404 =R607.63“C 1C Converting to Amount for 7 nights = R607.63 x 7 nights =R4253.41 VCA Total cost including 10% increase =R4 253.41 x 110% YM =R4678.75”¥ CA Mrs Lediga is incorrect YO Rand 1CA Cost for 7 nights IM Increase by 10% 1CA Answer 10 Conclusion

Downloaded from Stanmorephysics.com OR = $ 20.25 = $ 40.50 Price including 10% increase = $ 40.50 x 1.1 ¥™M =$44.55vY CA Amount for 7 nights = $ 44.55 x 7 nights = $311.85 ¥CA Amount in Yen = $ 311.85 x 106.86 “C = ¥ 33 324.29V A Amount in Rand = ¥ 33 324.29 x 0.1404 =R4678.73Y C Mrs Lediga is incorrect. ~ O Price of dinner for 1 adult and 1 child = $ 13.50 + $6.75 YM Price of dinner for 2 adults and 2 children = $ 20.25 x 2 ¥M 1M Adding correct values 1M Multiply by 2 1M Increase by 10% 1CA Answer 1CA Cost for 7 nights 1C Converting to Yen 1A Answer 1C Converting to Rand 10 Conclusion (9) 3.3.2 | YenvVvA OR Japanese Yen VV A 2A Correct Answer (2) [30] Question 4 [38 Marks] 4.1.1 | Total number of tourists . = 407 486 + 297 226 + 256 646 + 128 438 +121 883 + IMA Aging 99 205 + 84 691 + 78 438 + 56 244 + 52 377 YMA ICA A = 1582561 ¥CA DCA Comect One million five hundred and eighty two thousand five answer Hundred and sixty one YY CA (4) 4.1.2 | Mean =( 1 900 791 + 1 394 913 + 1 200 335 + 838 006 + 593 514 + 212 514 + 161 259 + 135 260 + 48 416+ 35 817) +10 WRT 1RT Correct values 1M Mean concept = 6520 825 +10 V M 1CA Answer (3) = 652 082 VY CA 4.1.3 | Probability = 710 x100 vMA 1A Correct method = 70% YCA 1CA Correct answer (2)

Downloaded from Stanmorephysics.com 4.1.4 56 224: 1200335 ¥ RT VY MA 1:21.35” CA 1RT both correct values 1MA ratio in correct order 1CA ratio unit Accept 1: 21 and 1:21.4 (3) IQR = 256 646 — 78 385 YW MA 2MA Correct = 178 261 CA Method and correct values 1CA Correct answer (2) 4.2.1 | 50% VVA 2A Correct Answer (2) 4.2.2 | Range = Maximum — Minimum ¥ M 1M Range concept 36 =92-AYRT 1RT Correct values A=92—36 1CA Answer 3 =56“ CA (3) 4.2.3 |62VVA 2A Correct Answer (2) 4.2.4 _ 1124+2B 1MA Mean 48 = 20 vMAVA concept 2B = 1124 —960 1A Adding correct 164 values B=-> ¥M 1M Dividing by 2 1CA Answer =82VCA (3) 4.2.5 . _ 64+64 CA from 4.2.4 Median = vRT YM 1RT Correct values =64VA 1M Dividing by 2 1A Correct answer (3) 4.2.6 1A Numerator Probability = a VYAVA = 1 vcA 2 1A Denominator 1CA Answer (3)

Downloaded from Stanmorephysics.com 4.2.7 Intervals Frequency 50-59 4 60-69 70-79 80-89 el BIN) oO 90-100 “A for 4 and 2 VA for 4 and 1 2A for 4 and 2 2A for 4 and 1 2A 2 Correct bars 2A 2 Correct bars LIFE SCIENCES MARKS 1 10 409 9 S08 8 (8) 207 7 = 06 6 $0.5 5 B04 4 203 3 “02 2 0.1 1 0 0 50-59 60-69 70-79 80-89 90-100 MARK INTERVALS vA for 2 bars (50-59 and 70-79) vA for 2 bars (80-89 and 90-100 [38]