MATHS LIT P1 ENG MEMO SEPT 2012 hlayiso.com

Downloaded from hlayiso.com Province of the EASTERN CAPE EDUCATION NATIONAL SENIOR CERTIFICATE GRADE 12 SEPTEMBER 2012 MATHEMATICAL LITERACY P1 MEMORANDUM MARKS: 150 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table/Reading from a graph/Read from map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason O Opinion This memorandum consists of 12 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (SEPTEMBER 2012) QUESTION 1 Question Solution Explanation LO+AS 1.1 1.1.1 x 100 = 76,6 = 77% √ MA 1MA Correct method and 12.1.1 accuracy x 100 = 74,6 = 75% √ MA 1MA Correct method and accuracy x 100 = 92,5% = 93% √ MA 1MA Correct method and accuracy (3) 1.1.2 1M Correct method used 12.1.1 Average = √M = √M 1MA Method and accuracy = 81,6% √ CA 1Ca Consistent accuracy (3) 1.2 1.2.1. x 100 = 77,142.. = 77% √ MA 1MA Correct method and 12.1.1 accuracy x 100 = 90% √ MA 1MA Correct method and accuracy x 100 = 90% √ MA 1MA Correct method and accuracy (3) 1.2.2 Average = √M 1M Correct method used 12.1.1 = √ MA 1MA Method and accuracy = 85,6% √ CA 1Ca Consistent accuracy (3) 1.2.3 John, because his average is 1O Correct person and 12.1.1 higher than mine. √ O reasoning valid Accept any valid reason (1) 1.3 1.3.1 Milk = 540 ÷ 560 √ M 1M Correct method used 12.3.2 = 0,96428…. ≈ 0,96 pints √ CA 1CA Consistent accuracy (2) Margarine = 30 ÷ 25 √ M 1M Correct method used = 1,2 oz √ CA 1CA Consistent accuracy (2) Flour = 85 ÷ 25 √ M 1M Correct method used = 3,4 oz √ CA 1CA Consistent accuracy (2) Sugar = 100 ÷ 25 √ M 1M Correct method used = 4 oz √ CA 1CA Consistent accuracy (2)

Downloaded from hlayiso.com (SEPTEMBER 2012) MATHEMATICAL LITERACY P1 3 1.3.2 1SF Correct values used 12.3.2 √ SF = 396 + 32 1CA Consistent accuracy = 428 √ CA (2) 1SF Correct values used √ SF = 360 + 32 1CA Consistent accuracy = 392 √ CA (2) 1.4 1.4.1 Deposit = 6 573 x 10% √ SF √ M 1SF Correct values used 12.1.1 = R657, 30 √ CA 1M correct method 1CA Consistent accuracy (3) OR Deposit = 6 573 x √ SF √ M 1SF Correct values used 1M correct method = R657,30 √ CA 1CA Consistent accuracy (3) OR Deposit = 6 573 x 0,1 √ SF √ M 1SF Correct values used = R657,30 √ CA 1M correct method 1CA Consistent accuracy (3) 1.4.2 A = ? P = 6 573 – 10% 1CA Correct calculation of 12.1.1 r = 15% n = 2 yrs principle value = 5 915,70 √ CA = 0,15 Using A = P(1 + rt) = 5 915,70 (1+ 0,15 x 2) √ SF 1SF Correct values substituted = 5 915,70 (1,3) √ M 1M Correct method used = R7 690,41 √ CA 1CA Consistent accuracy (4) OR A = ? P = 6573 – 10% 1CA Correct calculation of r = 15% n = 2 yrs principle value = 5 915,70 √ CA = 0,15 Using A = P + (P x r x t) = 5 915,70 + (5 915,70 1SF Correct values x 0,15 x 2) √ SF substituted = 5915,70 + 1774,71 √M = R7 690,41 √ CA 1M Correct method used OR 1CA Consistent accuracy Other variations can use 15% or in place of 0,15 (4)

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (SEPTEMBER 2012) 1.4.3 Monthly Payment = 7 690,41 ÷ 24 12.1.1 √ SF √ M 1SF Correct values used 1M Correct method used = 320,43375… = R 320,43 per month √ CA 1CA Correct answer (3) 1.4.4 Save up, do part time work etc. 1O Any valid suggestion 12.1.1 accept any reasonable accepted here suggestion here. √ O (1) 1.5 Amount needed = 500 x 12,56 √ M 1M Correct method used 12.1.1 = R6 280,00 √ A 1A Correct answer (2) [38]

Downloaded from hlayiso.com (SEPTEMBER 2012) MATHEMATICAL LITERACY P1 5 QUESTION 2 Question Solution Explanation LO+AS 2.1 BEAD PARADISE: for all the beads, string and material you will ever need…. Invoice No. 23521 Date: 18/3/12 (1) 2.1.3 Quantity Description Unit Price 6 kg Glass beads R56,00/kg 6 x 56 R336,00 √ CA 100 Clay Beads R1,80 ea. 100 x 1,80 R180,00 150 Wooden R1,85 ea. 150 x 1,85 R277,50 √ CA Beads 175 Brass R2,50 ea. 175 x 2,50 R437,50 √ CA Beads 2 Rolls String R45,00/ 2 x 45 R90,00 roll 20 metres Linen R57,00/m 20 x 57,00 R1 140,00 √ CA Odds and R48,00 1 x 48 R48,00 Ends 336+180+277, 50+437,50+90 Sub-Total R2 509 √ CA + 1 140 + 48 √M 2 509 x 14% or using 0,14 14% VAT R351,26 √ CA or for 14% √M 2509 + 351,26 Total √ M R2 860,26 √ CA 1CA x 7 for accurate calculations 1M x 3 for correct methods used. (10)

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (SEPTEMBER 2012) Question Solution Explanation LO+AS 2.2 2.2.1 12.2.2 Sivu's Business 3500 3000 2500 Expenses/ Income 2000 Expenses Income 1500 1000 500 0 0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 180 190 200 Number of Items Correct spacing between units on both axes √ Two points plotted correctly on each graph √√√√ Correct Y-intercept for each graph √√ (7) 2.2.2 38 items to be sold √ RG √ M 1RG Correct reading from 12.2.1 Accept 38 – 39 items depending the graph 1M correctly using the graph on graph. and has indicated with lines on the graph (2) 2.2.3 Profit = 3 000 – 1 375 √ SF 1SF correct values used 12.2.2 = R1 625 √ CA 1CA Correct answer (2) 2.2.4 1 800 income = 120 items √ RG √ 1RG Correct reading from 12.2.1 M the graph 1M correctly using the graph and has indicated with lines on the graph (2)

Downloaded from hlayiso.com (SEPTEMBER 2012) MATHEMATICAL LITERACY P1 7 Question Solution Explanation LO+AS 2.2.5 180 items = R1 275 √ RG √ M 1RG Correct reading from the 12.2.1 graph 1M correctly using the graph Accept R1 200 – R1 350 and has indicated with lines on depending on plotting on graph the graph (2) [25]

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P1 (SEPTEMBER 2012) QUESTION 3 Question Solution Explanation LO+AS 3.1 Eastern Cape = 9 449 1R correct value rounded off 12.4.4 = 9 000 GWh √ R (1) 3.2 3.2.1 Gauteng √ RT 1RT correct reading from 12.4.4 table (1) 3.2.2 28% √ RT 1RT correct reading from 12.4.4 table (1) 3.3 Northern Cape √√ RT 2RT correct reading from pie 12.4.4 graph (2) 3.4 25 983 + 9 449 + 4 724 + 1M Correct method used 12.4.4 10 054 + 47 243 + 25 984 + 66 140 + 35 432 + 11 811 √ M 1CA Consistent accuracy = 236 820 GWh √ CA (2) 3.5 Difference = 4 7243 – 25 983 √M 1M Correct method 12.4.4 = 21 260 GWh √ CA 1CA Consistent accuracy (2) 3.6 More industries 2R accept any 2 good 12.4.4 reasons here. Richer province More people Mines etc. √√ R (2) 3.7 3.7.1 Cost = 49,5 x 60,80 + 228 x 30 12.2.1 √ SF 1SFCorrect substitution 1CA Correct method and = 3 009,60 +6 840 √ CA accuracy = 9 849,6 cents = R98,495 = R98,50 √ A 1A Correct answer (3) 3.7.2 Cost = 50 x 60,80 + 15,75 x 2SF Correct substitutions 12.2.1 64,39 + 228 x 31 √√ SF 1CA Correct Method and accuracy = 3 040 + 1 014,1425 + 7 068 √ CA = 11122,1425 = R111, 22 √ A 1A Correct answer (4) 3.7.3 Accept any reasonable answer 1O own opinion 12.2.1 here so long as it is connected to being environmentally friendly. √O (1) [19]

Downloaded from hlayiso.com (SEPTEMBER 2012) MATHEMATICAL LITERACY P1 9 QUESTION 4 Question Solution Explanation LO+AS 4.1 4 metres √ C 1C Correct calculation (1) 12.3.1 4.2 2SF correct substitution of 12.3.1 Perimeter = 2 x 6 + 4 + √ SF values = 16 x 6,28 √ MA 1MA Method and accuracy = 22,28 m √ CA 1CA Correct answer (4) 4.3 2SF correct substitution of 12.3.1 Area = (4 x 6) + √√ SF values = 24 + 6,28 √ MA 1MA Method and accuracy = 30,28 √ CA 1CA Correct answer (4) 4.4 Wood, sanding and varnishing costs 1Sf correct substitution of 12.2.1 values = 30,28 x 265 √ SF = R8 024,20 √ CA 1CA correct answer and accuracy (2) 4.5 Skirting Board costs 12.2.1 = 22,28 x 55 √ SF 1SF correct values used 1CA correct calculation and = R1 225,40 √ CA accuracy (2) 4.6 Labour costs 2SF correct substitution of 12.2.1 = 3 x 15 h x R65 √√ SF values required CA Correct answer and = R2 925 √ CA accuracy (3) 4.7 Total cost = 8 024,20 + 1 225,40 + 2 925 12.2.1 √√√ SF 3SF correct values used = R 12 174,60 √ CA 1CA Correct answer and accuracy (4) 4.8 Profit = 12 174,60 x 65% √ M 1M correct method and 12.1.1 values 1CA correct answer and = R7 913,49 √ CA accuracy (2) OR 1M correct method and Profit = 12 174,60 x √M values 1CA correct answer and = R7 913,49 √ CA accuracy (2)

Downloaded from hlayiso.com 10 MATHEMATICAL LITERACY P1 (SEPTEMBER 2012) Question Solution Explanation LO+AS 4.9 Quote = 12 174,60 + 7 913,49 √ SF √ M 1Sf correct values used 12.2.1 1M method = R20 308,09 √ CA 1CA Correct answer (3) [25] QUESTION 5 Question Solution Explanation LO+AS 5.1 Joe’s Mean = 1M Correct method used 12.4.2 1MA Method and accuracy √M = √ MA = R 2 500,00 √ CA 1CA Correct answer and accuracy (3) AND Mpho’s Mean = 1M Correct method used 12.4.2 √M 1MA Method and accuracy = √ MA 1CA Correct answer and = R2 500,00 √ CA accuracy (3) 5.2 Joe’s Range = 2 800 – 2 200 √ M 1M Correct method used 12.4.2 1CA Correct answer and = 600 √ CA accuracy (2) AND Mpho’s Range = 3 500 – 1 500 √ M 1M Correct method used 12.4.2 1CA Correct answer and = 2 000 √ CA accuracy (2) 5.3 2 200; 2 200; 2 300; 2 400; 2 400; 1M Correct method used 12.4.2 2 500; 2 500; 2 600; 2 600; 2 700; 2 800; 2 800 1CA Calculation and Joe’s Median = √M accuracy = 2 500 √ CA (2) AND

Downloaded from hlayiso.com (SEPTEMBER 2012) MATHEMATICAL LITERACY P1 11 Question Solution Explanation LO+AS 1 500; 1 900; 2 000; 2 200; 2 300; 1M Correct method used 12.4.2 2 400; 2 600; 2 700; 2 800; 3 000; 3 100; 3 500 1CA Calculation and Mpho’s Median = √M accuracy = 2 500 √ CA (2) 5.4 2 200; 2 200; 2 300; 2 400; 2 400; 1M correct method used 12.4.2 2 500; 2 500; 2 600; 2 600; 2 700; 2 800; 2 800 Joe’s modes = 2 200, 2 400, 2 500, 1CA correct values given (2 2 600 and 2 800 √ M √ CA values per ½ mark max = 1) (2) AND 1 500; 1 900; 2 000; 2 200; 2 300; 1M correct method used 2 400; 2 600; 2 700; 2 800; 3 000; 3 100; 3 500 Mpho’s mode = nil √ M √ A 1A Correct answer (2) 5.5 Both Means and Medians are the same 2O learners observation of 12.4.5 for both √ O results for central tendencies correct Modes do not help at all – too common or nil Range is small for Joe’s Range for Mpho’s much larger √ O Choice = Joe’s – start at higher rate or √R 1R Accept learner’s choice Choice = Mpho’s – get more with more and any valid reason for responsibilities choice. (3) 5.6 Choice = Joe’s √ O 1O Correct choice/option 12.4.5 Because better starting pay i.e. Joe’s is R2 200 and Mpho’s only R1 500. √ R 1R logical reason given (2) 5.7 Choice = Mpho’s 1O Correct choice/option 12.4.5 Mpho’s has a better maximum pay. Mpho’s is R3 500 and Joe’s only R2 800. √ R 1R logical reason given (2) [25]

Downloaded from hlayiso.com 12 MATHEMATICAL LITERACY P1 (SEPTEMBER 2012) QUESTION 6 Question Solution Explanation LO+AS 6.1 Outside Height = 3,7 cm √ A 1A Accurately measured (1) 12.3.1 6.2 Scale = 3,7 cm : 1 m √ SF 1SFCorrect values used 12.3.3 1M Correct method = 3,7 : 100 √ M 1CA Correct answer and = 37 : 1 000 √ CA accuracy (3) 6.3 Inside volume = 0,95 x 0,9 x 0,4 √ M √ C 1M Method 12.3.1 1C Conversion to metres = 0,342 √ CA 1CA Consistent accuracy (3) 6.4 Concrete needed = Whole Volume – 2 SF 1 mark for each group 12.3.1 Inside Volume of correct values = (1 x 1 x 0,5) – (0,95 x 0,9 x 0,4) √√ SF 2MA 1 mark for method and 1 mark for accuracy = 0,5 – 0,342 √√ M A 1CA Correct answer and = 0,158 √ CA consistency (5) 6.5 Cost of Dustbin = 0,158 x R 255,50 √ M 1M Method used 12.3.1 = 40,369 √ MA 1MA Method and accuracy = R 40, 37 √ R 1R Rounded off correctly (3) 6.6 Cost of plastic dustbin = 0,158 x R185,95 √ M 1M Method used 12.3.1 = 29,3801√ MA 1MA Method and accuracy = R 29,38 √ R 1R Rounded off correctly (3) [18] TOTAL: 150