MATHS LIT P1 GR11 MEMO NOV2020 ENG D_hlayiso.com_.pdf

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2020 MATHEMATICAL LITERACY P1 MARKING GUIDELINE EXEMPLAR MARKS: 100 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table/Reading from a graph/Read from map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason AO Answer only NPR No penalty for rounding This marking guideline consists of 8 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020) MARKING GUIDELINES NOTE: x If a candidate answers a question TWICE, only mark the FIRST attempt. x If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled version) x Consistent accuracy (CA) applies in ALL aspects of the marking guidelines, however it stops at the second calculation error. x If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra incorrect item presented. LET WEL: x As ʼn kandidaat ʼn vraag TWEE keer beantwoord, merk slegs die EERSTE poging. x As ʼn kandidaat ʼn antwoord van ʼn vraag doodtrek (kanselleer) en nie oordoen nie, merk die doodgetrekte (gekanselleerde) poging. x Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyn toegepas, maar dit hou by die tweede berekeningsfout op. x Wanneer ʼn kandidaat aflesings vanaf ʼn grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item. Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 3 QUESTION 1 [23 marks] Ques. Solution Explanation T&L 1.1.1 Annual gross salary = R10 500 × 12 9 M 1M Multiply by 12 F = R126 000 9A 1A Gross per annum (2) L1 1.1.2 Monthly food expense = R10 500 × 36% 9M 1M % Calculation F = R3 780 9CA 1CA Amount (2) L1 1.1.3 Housing % : Food % F = 21% : 36% 9M 1M Correct values and order L1 = 7 : 12 9CA 1CA Simplest form (2) 9M 1.1.4 Savings % = 100% – (21% +36% +10% + 1,9%) 1M Adding correct values F = 100% – 68,9%9M 1M Subtracting from 100 L1 = 31,1% 9CA 1CA Percentage (3) 1.2.1 Primary data 99A 2A Correct data type D (2) L1 1.2.2 41 99 RT 2RT Highest mark D (2) L1 1.2.3 Median is the middle value of a set of data which is arranged 2A Explanation D from small to big. 99A (2) L1 1.2.4 35 99 A 2A Correct mark D (2) L1 1.2.5 3 99 RT 2RT No. of learners failed D (2) L1 1.3.1 Loss is when the cost is more than the income. 99 A 2A Correct explanation F OR L1 Loss incurred when selling price is less than cost price of an item. 99 A (2) 1.3.2 ହ଴ % loss = ଻ହ଴ × 100% 9M 1M Fraction multiplied by F 100% L1 = 6,67% 9 CA 1CA Percentage NPR (2) [23] Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020) QUESTION 2: FINANCE [30 marks] Ques. Solution Explanation Topic /Level 2.1.1 SmartMAXFocussed Education Plan 1 99 RT 2A Correct investment plan F (2) L1 2.1.2 8266 ,470 1C Converted to Rands F Number of units = 9C 1CA Value L2 100 = R82,6647 9 CA 8038 ,07 1M Division = 9M 82 ,6647 1CA No. of units = 97,23703104 9 CA (4) 2.1.3 % loss = 12 924,75 – 6 995,25 9 M 1M Subtraction of values F = R5 929,50 9 S 1S Simplification L3 5929 ,50 9 M 1M Dividing correct values = u 100 9 M 1M Multiply by 100% 12924 ,75 = 45,88% OR OR 6995 ,25 9 M Percentage loss = u 100 9 M 1M Dividing correct values 12924,75 1M Multiply by 100% = 54,12% 9S 1S Simplification = 100% – 54,12% 9M 1M Subtraction of % = 45,88% (4) 2.1.4 B = R8 038,07 – R6 995,25 9 MA 1MA Subtraction F = R1 042,82 9C A 1CA Correct answer (2) L2 2.1.5 R765,57 99RT 2RT Correct value F (2) L2 9RT 2.1.6 366 ,02  332 ,75 1RT Correct values F % increase = u 100 9 SF 1SF Substitution 332 ,75 L2 = 9,998% 9 S 1S Simplification = 10% 9 R 1R Nearest % (4) 2.2.1 Number of plates 99 RT 2RT Number of plates F (2) L2 2.2.2 Fixed expenses = R500 99 RT 2RT Fixed expenses F (2) L2 2.2.3 Income = R50 × Number of plates sold 9 M 9 A 1M Multiplication with R50 F 1A Correct formula (2) L2 2.2.4 R0 OR (No Profit) 99 RT 2RT No profit F (2) L2 Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 5 2.2.5 Loss for 8 plates = Expenses – Income 1RT R740 F 9RT 9 RT 1RT R400 L3 = 740 – 400 9M 1M Subtraction = R340 9A 1A Loss OR (From graph allow 340±10) OR Expenses = 500 + 8 × 30 = R740 9M IM for R740 Income = 50 × 8 = R400 9M 1M for R400 Loss = 740 – 400 = R340 9A 1M subtraction 1A for R340 exact answer (4) [30] Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020) QUESTION 3: DATA HANDLING (18 marks) AND PROBABILITY (3 marks) Ques. Solution Explanation T/L 3.1 Total number of spas = 30 394 + 13 856 + 3 984 + 6 057 + 46 282 + 48 679 1M Adding correct values D =149 252 9M 9A 1A Total (2) L1 3.2 Mean = ଵସଽ ଶହଶ 9M CA from 3.1 D ଺ 1M Division L2 = 24 875,33 1R Whole number = 24 875 9 R (2) 3.3 European spas as a % = ସ଺ ଶ଼ଶ ×100 9M 1M Fraction with correct D ଵସଽ ଶହଶ values and L2 = 31% 9CA multiplication by 100 1CA Percentage (2) 3.4 Range = 48 679 – 3 984 D = 44 695 9S 1S Calculate range L3 Number of regions above range = 2 CA9 1CA Number of regions (2) 3.5 ସ଼ ଺଻ଽ 30 394 : 48 679 = 1 : ଷ଴ ଷଽସ 9M 9M 1M Ratio D 1M Fraction L3 1CA Unit ratio =1 : 1,60 9 CA NPR (3) 3.6 Revenue in sub-saharan Africa = 6,6 – 5,0 9M 1M Subtraction D = 1,6 9S 1S Simplification L3 Total revenue for spas 1M Addition = 22,9 + 6,6 + 1,6 + 2,8 + 33,3 + 26,5 9M 1CA Total revenue = $93,7 billion 9CA Penalise 1 mark if not in billions (4) 3.7 1,6; 2,8; 6,6; 22,9; 26,5; 33,3 9M CA the value $1,6 from 3.6 D included in the data L3 Median revenue = ଺,଺ ା ଶଶ,ଽ 9M 1M Arranging in order of ଶ descending or ascending = $14,75 billion 9CA 1M Concept of median 1CA Answer in billions (3) 3.8 P (Regions with more than 40 000 spas) 1RT Correct numerator and P 9RT denominator L2 ଶ = × 100 9M 1M Multiplication by 100 ଺ 1CA Percentage = 33,33% 9CA NPR (3) [21] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 7 QUESTION 4: FINANCE (12 marks), DATA HANDLING (11 marks) AND PROBABILITY (3 marks) Ques. Solution Explanation T/L 4.1 Cost = Kilolitre Cost 6 6 × 0 = 0 9M 1M Cost of first 6 kℓ F L4 9 9 × 9,35 = R84,15 1M Cost for both 9 and 10 9M kilolitres 10 10 × 11,16 = R111,6 1CA Total cost Total = 25 litres 84,15 + 111,60 = R195,75 9M 9M 1M Multiply by 15% R195 ×115% = R225,11 9CA 1CA Cost including VAT OR 9M 9M Cost = (6 × 0) + (9 × 9,35) + (10 × 11,16) = R84,15 + R111,60 = R195,75 9CA Including VAT = R195,75 × 15% 9M = R29,3625 = R195,75 + R29,3625 = R225,119CA Increased block rate tariffs to encourage saving of water 9A OR 1A Reason Also assist small businesses or families with free water 9A Accept any other sound reason. (6) 4.2 R0,019 = 1 RWF 1M Concept of ratio F R? = 745 614,04 RWF 9M L4 R? = 0,019 × 745 614,04 9M 1M Multiplication = R14 166,66676 9S 1S Simplification value in R ଵ଴ Bank charges = 14166,66676×ଵ଴଴ 9M 1M Multiplication of 10% 1A Value of 10% = R1 416,666676 9A 1M Subtraction Andile received = R14 166,66676 – 1 416,66676 9 M = R12 750 1A Valid Statement is valid. 9A OR OR ଵ଴ 1M Multiplication of 10% Bank charges = × 745 614,04 RWF 9M 1A Value of 10% ଵ଴଴ = 74 561,404 9A 1M Subtraction Andile received in RWF = 745 614,04 – 74 561,404 9M 1S Simplification value = 671 052,636 9S In Rands: R0,019 = 1 RWF 1M Concept of ratio R? = 671 052,636 RWF 9M 1M Multiplication Andile received = R0,019 × 671 052,636 9M = R12 750 Statement is valid 9CA 1CA Valid (6) Copyright reserved Please turn over

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020) 4.3.1 Total absentees = 67 9 M 1M Addition to 67 P Absentees on Wednesday =16 9A 1A Absentees on Wed L2 P(absent on Wed) = ଵ଺ 9CA 1CA Fraction ଺଻ (3) 4.3.2 1A for Monday boys at 5 D Number of absent learners during the week 1A for Tuesday girls at 6 L2 12 1A for Thurs for girls at 7 1A for Thurs for boys at 9 10 1A for Fri for boys at 7 Number of absent learners 9A 8 9A 9A 6 9A 9A 4 2 0 Monday Tuesday Wednesday Thursday Friday Days of the week Girls Boys (5) 4.4.1 Value of C: D 64,2 = 9M ஼ ା ଵ ଼ହଷ 1M Addition (1 853) and L4 ଷ଴ division by 30 64,2 × 30 = C + 1 853 1M Subtraction C = 1 926 – 1 853 9M 1CA Value of C = 73 9CA Answer invalid 9O 1A Invalid (4) 4.4.2 D = 0 9A 1A Value of D D No learners scored 30 – 39 marks 9A 1A Explanation L4 (CA value of D from 4.4.1 included in the data) (2) [26] TOTAL: 100 Copyright reserved Please turn over