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NATIONAL
SENIOR CERTIFICATE
GRADE 11
NOVEMBER 2020
MATHEMATICAL LITERACY P1
EXEMPLAR
MARKS: 100
TIME: 2 hours
*Imlit1*
This question paper consists of 9 pages, including an answer sheet.
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Mathematical Literacy Grade 11 P1 2020 Memo (Eng)
Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2020 (English), 24 pages. Read online or download the free PDF.
Mathematical Literacy · Grade 11 · Eastern Cape November · 2020. Memorandum, 24 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 11
- Document type
- Memorandum
- Year
- 2020
- Exam period
- Eastern Cape November
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 24
- File size
- 991.7 KB
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This exam
Eastern Cape November 2020
Questions in this paper
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2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020)
INSTRUCTIONS AND INFORMATION
1. This question paper consists of FOUR questions. Answer ALL the questions.
2. 2.1 Use the ANSWER SHEET for QUESTION 4.3.2.
2.2 Write your NAME and GRADE in the spaces provided on the ANSWER
SHEET for QUESTION 4.3.2.
Hand in the ANSWER SHEET with your ANSWER BOOK.
3. Number the answers correctly according to the numbering system used in this
question paper.
4. Maps and diagrams are not necessarily drawn to scale, unless stated otherwise.
5. Round off ALL final answers according to the context used, unless stated otherwise.
6. Indicate units of measurement, where applicable.
7. Start EACH question on a NEW page.
8. You may use an approved calculator (non-programmable and non-geographical),
unless stated otherwise.
9. Show ALL calculations clearly.
10. Write neatly and legibly.
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(EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 3
QUESTION 1
1.1 Moses earns a gross salary of R10 500 per month. The basic monthly expenses used
from the income are as follows:
Housing expense 21%; Food 36%, Transport 10%; Cellphone bills 1,9%. The rest is
for savings.
Use the above information to answer the following questions.
1.1.1 Calculate the total gross salary per annum. (2)
1.1.2 Determine the amount of the monthly food expense. (2)
1.1.3 Write down the ratio of the housing percentage to the food percentage in the
simplest form. (2)
1.1.4 Calculate Moses’s percentage for savings from his salary. (3)
1.2 Thando, a Mathematical Literacy teacher, collected and analysed test results of his
class. The test was marked out of a total mark of 50. The results of the learners are
indicated below:
38 21 12 18 41
28 24 34 10 35
Use the above information to answer the questions that follow.
1.2.1 Is the above data primary or secondary? (2)
1.2.2 Write down the highest mark obtained in the test. (2)
1.2.3 Explain the meaning of the term ‘median’. (2)
1.2.4 Write down the mark out of 50 for a learner who achieved 70% in the test. (2)
1.2.5 Write down the number of learners who failed the test, if the pass mark is 20
out of 50. (2)
1.3 A shopkeeper bought a dress for R750 and sold it, making a loss of R50.
1.3.1 Explain the meaning of the term ‘loss’ in this context. (2)
1.3.2 Calculate the percentage loss made on the sale. (2)
[23]
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4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020)
QUESTION 2
2.1 Mrs Rogue invested money monthly from 2016 to 2020 at Company A. She terminated her
investment and received the statement below from Old Mutual:
Contract number Contracting Name of Start date Last
party Investment plan of contract premium
due date
Smart MAX
17801249 R. Rogue Focused 01/07/2016 30/06/2031
Education Plan/1
Fund value as at 23 March 2020
Investment fund Unit price (cents) Number of Fund value
units
Allan Gray Balanced Fund C Class 8 266,470 A R8 038,07
Total R8 038,07
Difference between fund value and termination value
Fund value R8 038,07
Reduction fees and transaction charges B
Termination value R6 995,25
Withdrawals up to 23 March 2020 R765,57
Expected premium details as at 23 March 2020
Current Annual Next New premium Investment Premium
premium Increase premium fund(s) Split
rate increase
Allan Gray
R332,75
… 01/07/2020 R366,02 Balanced Fund 100%
monthly
C Class
Total contributions since contract start date
Total premiums paid R12 924,75
2.1.1 Write down the name of the investment plan that Mrs Rogue has. (2)
2.1.2 Calculate the value of A, the number of units earned from the given fund value. (4)
2.1.3 Show by means of calculations that Mrs Rogue lost 45,88% of the total premiums she
contributed towards the fund by terminating her investment before the last premium. (4)
2.1.4 Calculate the value (in Rands) of B, the reduction fees and transaction charges. (2)
2.1.5 Write down the withdrawal value as at 23 March 2020. (2)
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(EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 5
2.1.6 Calculate the percentage increase on the monthly premium. Give your final answer
to the nearest percentage.
You may use the following formula:
ࢋ࢝ ࢘ࢋ࢛ ି ࢉ࢛࢘࢘ࢋ࢚ ࢘ࢋ࢛
Percentage increase = × %
ࢉ࢛࢘࢘ࢋ࢚ ࢘ࢋ࢛ (4)
2.2 Alice sells food from a kiosk that she rents in a township. The expenses associated with
ingredients and labour for a plate amount to R30.
The formula for expenses: Expenses = R500 + R30 × Number of plates
She sells food per plate. The graph below shows her expenses and income for a month.
ALICE’S EXPENSES AND INCOME FROM SALES
1800
1600
1400
Amount in Rands(R)
1200
1000
800 Expenses
600
Income
400
200
0
0 5 10 15 20 25 30 35
Number of plates
Use the above information and the graph to answer the questions that follow.
2.2.1 Write down the independent variable in the above context. (2)
2.2.2 Determine the amount Alice pays as fixed expenses. (2)
2.2.3 Write down the formula for the income if a plate is sold at R50, in the form of:
Income = … (2)
2.2.4 Determine the profit at the break-even point. (2)
2.2.5 Determine the loss when 8 plates are sold. (4)
[30]
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6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020)
QUESTION 3
The Global Wellness Institute did research about the amount of spa revenue generated in
different regions of the world in 2017.
TABLE 1: NUMBER OF SPAS, REGIONS AND THE REVENUE
GENERATED
Regions Names of Regions Number of Revenue in
Spas Billion dollars ($b)
P North America 30 394 22,9
Q Latin America-Caribbean 13 856 6,6
R Sub-Saharan Africa 3 984 …
S Middle East – North Africa 6 057 2,8
T Europe 46 282 33,3
V Asia – Pacific 48 679 26,5
TOTAL … …
[Source: globalwellnessinstitute.org]
Use the information above to answer the questions that follow.
3.1 Calculate the total number of spas used for the research in 2017. (2)
3.2 Calculate the mean number of spas used. Give your final answer to the nearest whole
number. (2)
3.3 Express the number of spas in Europe as a percentage of the total number of spas. (2)
3.4 Determine the number of regions that lies above the range number of spas. (2)
3.5 Write down the unit ratio of spas in regions P and V. (3)
3.6 Calculate the total revenue in billion dollars for the spas if sub-Saharan Africa’s
revenue is $5,0 billion less than Latin America-Caribbean’s revenue. (4)
3.7 Calculate the median revenue of the regions. (3)
3.8 Determine the probability (as a percentage) of randomly selecting a region with more
than 40 000 spas. (3)
[21]
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(EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 7
QUESTION 4
4.1 GOOD BOYS CAR WASHING BAY is in an area where water is charged according
to the water tariffs structure shown in TABLE 2 below.
TABLE 2: WATER TARIFF STRUCTURE
Block Usage in Normal Charge per kilolitre
kilolitre (kƐ) (kƐ) (Excluding VAT)
1 0–6 R0,00
2 +6 – 15 R9,35
3 +15 – 30 R11,16
4 +30 – 45 R12,53
5 +45 – 60 R13,98
6 60+ R15,34
NOTE: VAT is Value Added Tax. The VAT rate is 15%.
Use TABLE 2 above to answer the question that follow.
Calculate how much GOOD BOYS CAR WASHING BAY pays a month including
VAT when they use 25 kƐ of water and give a reason why a step up (increasing block
rate) system of water tariffs is used to charge water consumption other than a flat
single rate. (6)
4.2 Andile received a donation from his brother who works in Rwanda. The donation was
745 614,04 Rwanda Francs (RWF). The bank deducted 10% for bank charges. Andile
states that he will receive R12 750. Verify the statement with the necessary
calculations.
Use the exchange rate R 0,019 = 1 RWF (6)
4.3 Ibanda High School recorded absentees in the Grade 11 Mathematical Literacy class
during the first week when schools reopened after the COVID-19 pandemic break.
The data is shown in the table below.
Monday Tuesday Wednesday Thursday Friday
Girls 4 6 8 7 10
Boys 5 3 8 9 7
Use the above information to answer the questions that follow.
4.3.1 Determine the probability that a learner chosen at random was absent on
Wednesday. (3)
4.3.2 Complete the double bar graph on the ANSWER SHEET provided by plotting
the missing bars for the number of boys and girls absent. (5)
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8 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020)
4.4 A Grade 11 Mathematical Literacy class at Ibanda High wrote an examination
marked out of 100 marks. The results arranged in ascending order are shown below.
23 41 42 50 50 51 54 55 56 57
60 61 65 66 66 67 68 69 70 70
70 72 C 74 76 79 82 85 86 88
Use the above information to answer the questions that follow.
4.4.1 The mean of the above data is equal to 64,2. A learner calculated that the
value of C in the above data is 74. Verify, with the necessary calculations,
whether the answer is valid. (4)
4.4.2 The frequency table of the above data is shown below.
Class interval Frequency
20–29 1
30–39 D
40–49 2
50–59 7
60–69 8
70–80 8
80–89 4
Determine the value of D and give a reason for your answer. (2)
[26]
TOTAL: 100
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(EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 9
ANSWER SHEET
QUESTION 4.3.2
NAME OF LEARNER:
GRADE 11:
Number of absent learners during the week
12
10
8
Number of absent learners
6
4
2
0
Monday Tuesday Wednesday Thursday Friday
Days of the week
Girls Boys
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NATIONAL
SENIOR CERTIFICATE
GRADE 11
NOVEMBER 2020
MATHEMATICAL LITERACY P1
MARKING GUIDELINE
EXEMPLAR
MARKS: 100
Symbol Explanation
M Method
MA Method with accuracy
CA Consistent accuracy
A Accuracy
C Conversion
S Simplification
RT/RG/RM Reading from a table/Reading from a graph/Read from map
F Choosing the correct formula
SF Substitution in a formula
J Justification
P Penalty, e.g. for no units, incorrect rounding off etc.
R Rounding Off/Reason
AO Answer only
NPR No penalty for rounding
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2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020)
MARKING GUIDELINES
NOTE:
x If a candidate answers a question TWICE, only mark the FIRST attempt.
x If a candidate has crossed out (cancelled) an attempt to a question and NOT redone
the solution, mark the crossed out (cancelled version)
x Consistent accuracy (CA) applies in ALL aspects of the marking guidelines,
however it stops at the second calculation error.
x If the candidate presents any extra solution when reading from a graph, table, layout
plan and map, then penalise for every extra incorrect item presented.
LET WEL:
x As ƌ kandidaat ƌ vraag TWEE keer beantwoord, merk slegs die EERSTE poging.
x As ƌ kandidaat ƌ antwoord van ƌ vraag doodtrek (kanselleer) en nie oordoen nie,
merk die doodgetrekte (gekanselleerde) poging.
x Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyn toegepas,
maar dit hou by die tweede berekeningsfout op.
x Wanneer ƌ kandidaat aflesings vanaf ƌ grafiek, tabel, uitlegplan en kaart geneem
en ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item.
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(EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 3
QUESTION 1 [23 marks]
Ques. Solution Explanation T&L
1.1.1 Annual gross salary = R10 500 × 12 9 M 1M Multiply by 12 F
= R126 000 9A 1A Gross per annum (2) L1
1.1.2 Monthly food expense = R10 500 × 36% 9M 1M % Calculation F
= R3 780 9CA 1CA Amount (2) L1
1.1.3 Housing % : Food % F
= 21% : 36% 9M 1M Correct values and order L1
= 7 : 12 9CA 1CA Simplest form (2)
9M
1.1.4 Savings % = 100% – (21% +36% +10% + 1,9%) 1M Adding correct values F
= 100% – 68,9%9M 1M Subtracting from 100 L1
= 31,1% 9CA 1CA Percentage (3)
1.2.1 Primary data 99A 2A Correct data type D
(2) L1
1.2.2 41 99 RT 2RT Highest mark D
(2) L1
1.2.3 Median is the middle value of a set of data which is arranged 2A Explanation D
from small to big. 99A (2) L1
1.2.4 35 99 A 2A Correct mark D
(2) L1
1.2.5 3 99 RT 2RT No. of learners failed D
(2) L1
1.3.1 Loss is when the cost is more than the income. 99 A 2A Correct explanation F
OR L1
Loss incurred when selling price is less than cost price of an
item. 99 A (2)
1.3.2 % loss =
ହ
× 100% 9M 1M Fraction multiplied by F
ହ
100% L1
= 6,67% 9 CA
1CA Percentage
NPR (2)
[23]
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4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020)
QUESTION 2: FINANCE [30 marks]
Ques. Solution Explanation Topic
/Level
2.1.1 SmartMAXFocussed Education Plan 1 99 RT 2A Correct investment plan F
(2) L1
2.1.2 8266 ,470 1C Converted to Rands F
Number of units = 9C 1CA Value L2
100
= R82,6647 9 CA
8038 ,07 1M Division
= 9M
82 ,6647
1CA No. of units
= 97,23703104 9 CA (4)
2.1.3 % loss = 12 924,75 – 6 995,25 9 M 1M Subtraction of values F
= R5 929,50 9 S 1S Simplification L3
5929 ,50 9 M 1M Dividing correct values
= u 100 9 M 1M Multiply by 100%
12924 ,75
= 45,88%
OR OR
6995 ,25 9 M
Percentage loss = u 100 9 M 1M Dividing correct values
12924,75 1M Multiply by 100%
= 54,12% 9S 1S Simplification
= 100% – 54,12% 9M 1M Subtraction of %
= 45,88% (4)
2.1.4 B = R8 038,07 – R6 995,25 9 MA 1MA Subtraction F
= R1 042,82 9C A 1CA Correct answer (2) L2
2.1.5 R765,57 99RT 2RT Correct value F
(2) L2
9RT
2.1.6 366 ,02 332 ,75 1RT Correct values F
% increase = u 100 9 SF 1SF Substitution
332 ,75 L2
= 9,998% 9 S 1S Simplification
= 10% 9 R 1R Nearest % (4)
2.2.1 Number of plates 99 RT 2RT Number of plates F
(2) L2
2.2.2 Fixed expenses = R500 99 RT 2RT Fixed expenses F
(2) L2
2.2.3 Income = R50 × Number of plates sold 9 M 9 A 1M Multiplication with R50 F
1A Correct formula (2) L2
2.2.4 R0 OR (No Profit) 99 RT 2RT No profit F
(2) L2
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(EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 5
2.2.5 Loss for 8 plates = Expenses – Income 1RT R740 F
9RT 9 RT 1RT R400 L3
= 740 – 400 9M 1M Subtraction
= R340 9A 1A Loss
OR (From graph allow 340±10)
OR
Expenses = 500 + 8 × 30 = R740 9M IM for R740
Income = 50 × 8 = R400 9M 1M for R400
Loss = 740 – 400 = R340 9A 1M subtraction
1A for R340 exact answer (4)
[30]
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6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020)
QUESTION 3: DATA HANDLING (18 marks) AND PROBABILITY (3 marks)
Ques. Solution Explanation T/L
3.1 Total number of spas
= 30 394 + 13 856 + 3 984 + 6 057 + 46 282 + 48 679 1M Adding correct values D
=149 252 9M 9A 1A Total (2) L1
3.2 Mean =
ଵସଽ ଶହଶ
9M CA from 3.1 D
1M Division L2
= 24 875,33
1R Whole number
= 24 875 9 R
(2)
3.3 European spas as a % =
ସ ଶ଼ଶ
×100 9M 1M Fraction with correct D
ଵସଽ ଶହଶ
values and L2
= 31% 9CA
multiplication by 100
1CA Percentage (2)
3.4 Range = 48 679 – 3 984 D
= 44 695 9S 1S Calculate range L3
Number of regions above range = 2 CA9 1CA Number of regions (2)
3.5 ସ଼ ଽ
30 394 : 48 679 = 1 : ଷ ଷଽସ 9M 9M 1M Ratio D
1M Fraction L3
1CA Unit ratio
=1 : 1,60 9 CA
NPR (3)
3.6 Revenue in sub-saharan Africa = 6,6 – 5,0 9M 1M Subtraction D
= 1,6 9S 1S Simplification L3
Total revenue for spas 1M Addition
= 22,9 + 6,6 + 1,6 + 2,8 + 33,3 + 26,5 9M 1CA Total revenue
= $93,7 billion 9CA Penalise 1 mark if not in
billions (4)
3.7 1,6; 2,8; 6,6; 22,9; 26,5; 33,3 9M CA the value $1,6 from 3.6 D
included in the data L3
Median revenue =
, ା ଶଶ,ଽ
9M 1M Arranging in order of
ଶ descending or ascending
= $14,75 billion 9CA 1M Concept of median
1CA Answer in billions (3)
3.8 P (Regions with more than 40 000 spas) 1RT Correct numerator and P
9RT denominator L2
ଶ
= × 100 9M 1M Multiplication by 100
1CA Percentage
= 33,33% 9CA NPR (3)
[21]
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(EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 7
QUESTION 4: FINANCE (12 marks), DATA HANDLING (11 marks) AND
PROBABILITY (3 marks)
Ques. Solution Explanation T/L
4.1 Cost =
Kilolitre Cost
6 6 × 0 = 0 9M 1M Cost of first 6 kƐ F
L4
9 9 × 9,35 = R84,15 1M Cost for both 9 and 10
9M kilolitres
10 10 × 11,16 = R111,6
1CA Total cost
Total = 25 litres 84,15 + 111,60 = R195,75 9M
9M 1M Multiply by 15%
R195 ×115% = R225,11 9CA 1CA Cost including VAT
OR
9M 9M
Cost = (6 × 0) + (9 × 9,35) + (10 × 11,16)
= R84,15 + R111,60
= R195,75 9CA
Including VAT = R195,75 × 15% 9M
= R29,3625
= R195,75 + R29,3625
= R225,119CA
Increased block rate tariffs to encourage saving of water 9A
OR 1A Reason
Also assist small businesses or families with free water 9A
Accept any other sound reason. (6)
4.2 R0,019 = 1 RWF 1M Concept of ratio F
R? = 745 614,04 RWF 9M L4
R? = 0,019 × 745 614,04 9M 1M Multiplication
= R14 166,66676 9S 1S Simplification value in R
Bank charges = 14166,66676×
ଵ
9M 1M Multiplication of 10%
ଵ
1A Value of 10%
= R1 416,666676 9A
1M Subtraction
Andile received = R14 166,66676 – 1 416,66676 9 M
= R12 750
1A Valid
Statement is valid. 9A
OR
OR
ଵ 1M Multiplication of 10%
Bank charges = × 745 614,04 RWF 9M 1A Value of 10%
ଵ
= 74 561,404 9A 1M Subtraction
Andile received in RWF = 745 614,04 – 74 561,404 9M 1S Simplification value
= 671 052,636 9S
In Rands: R0,019 = 1 RWF 1M Concept of ratio
R? = 671 052,636 RWF 9M 1M Multiplication
Andile received = R0,019 × 671 052,636 9M
= R12 750
Statement is valid 9CA 1CA Valid (6)
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8 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020)
4.3.1 Total absentees = 67 9 M 1M Addition to 67 P
Absentees on Wednesday =16 9A 1A Absentees on Wed L2
P(absent on Wed) =
ଵ
9CA 1CA Fraction
(3)
4.3.2 1A for Monday boys at 5 D
Number of absent learners during the week 1A for Tuesday girls at 6 L2
12 1A for Thurs for girls at 7
1A for Thurs for boys at 9
10 1A for Fri for boys at 7
Number of absent learners
9A
8
9A 9A
6 9A
9A
4
2
0
Monday Tuesday Wednesday Thursday Friday
Days of the week
Girls Boys
(5)
4.4.1 Value of C: D
64,2 = 9M
ା ଵ ଼ହଷ 1M Addition (1 853) and L4
ଷ division by 30
64,2 × 30 = C + 1 853
1M Subtraction
C = 1 926 – 1 853 9M 1CA Value of C
= 73 9CA
Answer invalid 9O 1A Invalid (4)
4.4.2 D = 0 9A 1A Value of D D
No learners scored 30 – 39 marks 9A 1A Explanation L4
(CA value of D from 4.4.1
included in the data) (2)
[26]
TOTAL: 100
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