Mathematical Literacy Grade 11 P2 2020 Memo (Eng)

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2020 MATHEMATICAL LITERACY P2 MARKING GUIDELINE (EXEMPLAR) MARKS: 100 Symbol Explanation M Method M/A Method with Accuracy MCA Method with Consistent Accuracy CA Consistent Accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table OR Reading from a graph OR Read from map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off OR Reason AO Answer only NPR No penalty for rounding This marking guideline consists of 5 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2020) QUESTION 1 [21 MARKS] Ques. Solution Explanation Topic & Level 1.1.1 Temperature reading = 30 °C A 2A Correct reading M (2) L1 1.1.2 °F = 100 °F A 2A °F (2) M L1 1.1.3 Minimum °Fahrenheit = minus 42°F OR -42°F A 2A Min °F (2) M L1 1.1.4 Thermometer 1 : Thermometer 2 1RD Both values M RD correct L1 = 90 : 20 M 1M Correct order = 9 : 2 CA 1CA Simplified ratio (3) 1.2.1 Number of houses = 18 A 2A Correct number M of houses (2) L1 1.2.2 HospitalA 2A Correct building M (2) L1 1.2.3 Café A 2A Correct business M (2) L1 1.2.4 Length of the bar = 1,5 cm A 2A Correct length M (2) L1 1.2.5 1,5 cm on the map represents 50 yards in realityA CA from 1.2.4 M 2A Explanation (2) L1 1.2.6 3 houses A 2A Number of M houses more (2) L1 [21] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2020) MATHEMATICAL LITERACY P2 3 QUESTION 2 [26 MARKS] Ques. Solution Explanation Topic & Level 2.1.1 Circumference is the distance or length around the lamp 2A Explanation (2) M shade A L1 200 2.1.2 Radius = 10 C 1C mm to cm M 20 L2 = 2 M 1M Divide by 2 = 10 cm CA 1CA Radius (3) 2.1.3 Circumference of lamp shade = 𝜋 × diameter CA from 2.1.1 M = 3,142 × 20 cm SF 1SF Substitution L2 = 62,84 cm MCA 1MCA Circumference (2) 2.1.4 Height of lamp shade = 20 cm × 1,65 M 1M Multiply by M = 33 cm A 1,65 L4 Statement invalid O 1A Height 1O Invalid (3) 2.1.5 Area of lampshade = 𝜋 × radius × radius CA from 2.1.1 M = 3,142 × 10 cm × 10 cmSF 1SF Substitution L3 = 314, 2 cm2 MCA 1MCA Area of Area including wastage = 314, 2 cm2 × 1,0425 M lamp shade = 327,5535 cm2 CA 1M Multiply by ≈ 328 cm2 R 1,0425 1CA Area including wastage 1R Nearest cm2 (5) 2.2.1 Number of parts = 22 parts A 2A Number of parts M&P (2) L2 P(set screw) = 22A 2.2.2 2 CA from 2.2.1 P MCA 1A Number of set L2 = 0,090909…. screws ≈ 0,091 R 1MCA 1R 3 dec places (3) 2.2.3 To prevent shocking R 2R Reason (2) M&P OR L4 For safety purposes Accept any other relevant reasons 2.2.4 Bulbs can break/damage R 2R Explanation (2) M&P L4 2.2.5 To connect Stem 2 with Stem 3 A 2A Explanation (2) M&P L4 Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2020) QUESTION 3 [33 MARKS] Ques. Solution Explanation Topic & Level 3.1.1 Southwest A 2A Southwest M&P North A 1A North (4) L2 3.1.2 Scale refers to the relationship (ratio) between distance on a map 2A Definition (2) M&P and the corresponding distance on the ground (reality) A L1 3.1.3 Measure bar = 1,8 cm A (Accept 1,7 cm to 1,9 cm) 1A Measure bar M&P 1,8 cm = 2 km 1C km to cm L3 1,8 cm = 200 000 cm C ⸫ 1 cm = 111 111, 111 S 1S Simplification ⸫ 1 : 111 000 R 1R Nearest ‘000 (4) 3.1.4 𝑫𝒊𝒔𝒕𝒂𝒏𝒄𝒆 M&P Speed = 𝑻𝒊𝒎𝒆 1SF Substitution L3 𝟏𝟖,𝟐 𝒌𝒎 65 km/h = 𝑻𝒊𝒎𝒆 M 1M Changing 18,2 𝑘𝑚 subject of formule Time = 65 𝑘𝑚/ℎ M 1A Time in hours = 0,28….h A 1CA Time in min = 16,8 min C 1M Add times = 17 minutes 1CA Arrival time Time of arrival = 14:53 + 17 minutes M (6) = 15:10 CA 3.1.5 Because of the (Indian) ocean R 2R Reason (2) M&P L4 M 3.2.1 Steak = 0,454 kg A 2A Kilogram (2) L1 3.2.2 Salt = 0,5 × 5 ml M = 2,5 ml MA 1MA Millilitres L2 Black pepper = 0,25 × 5 ml = 1,25 ml CA 1CA Millilitres Total = 2,5 ml + 1,25 ml = 3,75 ml CA 11CA Total (3) 3.2.3 1 cup broth = 250 ml MA 1MA 250 ml M 3 L4 cup whipping cream = 0,75 × 250 ml 4 1MA 187,5 ml = 187,5 ml MA 1 cup sour cream = 0,25 × 250 4 = 62,5 ml MA 1MA 62,5 ml Total = 250 ml + 187,5 ml + 62,5 ml = 500 ml = 0,5 litres CA 1CA Litre Statement is valid O 1O Valid (5) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2020) MATHEMATICAL LITERACY P2 5 3.2.4 Cooking timeM MCA 1M Multiply by 2 M = (3 min × 2) + 8 min + 1 min + 1 min + 2 min + 20 min + 2 1MCA Adding all L2 min times = 40 minutes CA 1CA Total time (3) M 3.2.5 Time for preparation should also be considered. A 2A Reason (2) L4 QUESTION 4 [20 MARKS] Ques. Solution Explanation Topic & Level 4.1.1 6 seats A 2A No of seats M&P (2) L1 4.1.2 Raised Seating Area = 112 seats A 1A Seats in RSA M&P Flat Seating Area = 85 seats A 1A Seats in FSA L3 Difference = 112 – 85 M 1M Subtract = 27 seats CA 1CA Difference (4) P(L-row) = 197 A 4.1.3 12 1A Numerator M&P MCA 1MCA L2 Denominator (CA from 4.1.2) (2) 4.1.4 Walk to A5, then turn right A 1A Straight M&P Walk straight pass the Row D A 1A Turn right L4 Third Row (G) third seat A 1A 3rd row, 3rd seat Accept any other relevant responses (3) 4.2.1 Volume of drum = 𝜋 × radius × radius × height M C A 1C mm to cm L3 = 3,142 × 29 cm × 29 cm × 93 cm SF 1A Radius = 245 745, 246 cm3 CA 1SF Substitution Litres = 245 745, 246 cm3 ÷ 1 000 cm3 1CA Volume = 2 45,745 litres CA 1CA Litres (5) 4.2.2  The volume of advertisement refers to the maximum the 2A 1st Reason M drum can hold. A L4  The calculated volume refers to the entire drum. A 2A 2nd Reason (4) TOTAL: 100 Copyright reserved Please turn over