Mathematical Literacy Grade 11 P1 2020 Memo (Eng)

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2020 MATHEMATICAL LITERACY P1 MARKING GUIDELINE EXEMPLAR MARKS: 100 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table/Reading from a graph/Read from map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason AO Answer only NPR No penalty for rounding This marking guideline consists of 8 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020) MARKING GUIDELINES NOTE:  If a candidate answers a question TWICE, only mark the FIRST attempt.  If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled version)  Consistent accuracy (CA) applies in ALL aspects of the marking guidelines, however it stops at the second calculation error.  If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra incorrect item presented. LET WEL:  As ʼn kandidaat ʼn vraag TWEE keer beantwoord, merk slegs die EERSTE poging.  As ʼn kandidaat ʼn antwoord van ʼn vraag doodtrek (kanselleer) en nie oordoen nie, merk die doodgetrekte (gekanselleerde) poging.  Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyn toegepas, maar dit hou by die tweede berekeningsfout op.  Wanneer ʼn kandidaat aflesings vanaf ʼn grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item. Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 3 QUESTION 1 [23 marks] Ques. Solution Explanation T&L 1.1.1 Annual gross salary = R10 500 × 12  M 1M Multiply by 12 F = R126 000 A 1A Gross per annum (2) L1 1.1.2 Monthly food expense = R10 500 × 36% M 1M % Calculation F = R3 780 CA 1CA Amount (2) L1 1.1.3 Housing % : Food % F = 21% : 36% M 1M Correct values and order L1 = 7 : 12 CA 1CA Simplest form (2) M 1.1.4 Savings % = 100% – (21% +36% +10% + 1,9%) 1M Adding correct values F = 100% – 68,9%M 1M Subtracting from 100 L1 = 31,1% CA 1CA Percentage (3) 1.2.1 Primary data A 2A Correct data type D (2) L1 1.2.2 41  RT 2RT Highest mark D (2) L1 1.2.3 Median is the middle value of a set of data which is arranged 2A Explanation D from small to big. A (2) L1 A 1.2.4 35  A 2A Correct mark D (2) L1 1.2.5 3  RT 2RT No. of learners failed D (2) L1 1.3.1 Loss is when the cost is more than the income.  A 2A Correct explanation F OR L1 Loss incurred when selling price is less than cost price of an item.  A (2) 1.3.2 50 1M Fraction multiplied by F % loss = 750 × 100% M 100% L1 = 6,67%  CA 1CA Percentage NPR (2) [23] Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020) QUESTION 2: FINANCE [30 marks] Ques. Solution Explanation Topic /Level 2.1.1 SmartMAXFocussed Education Plan 1  RT 2A Correct investment plan F (2) L1 2.1.2 8266 ,470 1C Converted to Rands F Number of units = C 1CA Value L2 100 = R82,6647  CA 8038 ,07 1M Division = M 82 ,6647 1CA No. of units = 97,23703104  CA (4) 2.1.3 % loss = 12 924,75 – 6 995,25  M 1M Subtraction of values F = R5 929,50  S 1S Simplification L3 5929 ,50  M 1M Dividing correct values =  100  M 1M Multiply by 100% 12924 ,75 = 45,88% OR OR 6995 ,25  M Percentage loss =  100  M 1M Dividing correct values 12924,75 1M Multiply by 100% = 54,12% S 1S Simplification = 100% – 54,12% M 1M Subtraction of % = 45,88% (4) 2.1.4 B = R8 038,07 – R6 995,25  MA 1MA Subtraction F = R1 042,82 C A 1CA Correct answer (2) L2 2.1.5 R765,57 RT 2RT Correct value F (2) L2 RT 2.1.6 366 ,02  332 ,75 1RT Correct values % increase =  100  SF 1SF Substitution F 332 ,75 L2 = 9,998%  S 1S Simplification = 10%  R 1R Nearest % (4) 2.2.1 Number of plates  RT 2RT Number of plates F (2) L2 2.2.2 Fixed expenses = R500  RT 2RT Fixed expenses F (2) L2 2.2.3 Income = R50 × Number of plates sold  M  A 1M Multiplication with R50 F 1A Correct formula (2) L2 2.2.4 R0 OR (No Profit)  RT 2RT No profit F (2) L2 Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 5 2.2.5 Loss for 8 plates = Expenses – Income 1RT R740 F RT  RT 1RT R400 L3 = 740 – 400 M 1M Subtraction = R340 A 1A Loss OR (From graph allow 340±10) OR Expenses = 500 + 8 × 30 = R740 M IM for R740 Income = 50 × 8 = R400 M 1M for R400 Loss = 740 – 400 = R340 A 1M subtraction 1A for R340 exact answer (4) [30] Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020) QUESTION 3: DATA HANDLING (18 marks) AND PROBABILITY (3 marks) Ques. Solution Explanation T/L 3.1 Total number of spas = 30 394 + 13 856 + 3 984 + 6 057 + 46 282 + 48 679 1M Adding correct values D =149 252 M A 1A Total (2) L1 3.2 149 252 CA from 3.1 D Mean = 6 M 1M Division L2 = 24 875,33 1R Whole number = 24 875  R (2) 3.3 46 282 1M Fraction with correct D European spas as a % = 149 252×100 M values and L2 = 31% CA multiplication by 100 1CA Percentage (2) 3.4 Range = 48 679 – 3 984 D = 44 695 S 1S Calculate range L3 Number of regions above range = 2 CA 1CA Number of regions (2) 3.5 48 679 1M Ratio D 30 394 : 48 679 = 1 : 30 394 M M 1M Fraction L3 1CA Unit ratio =1 : 1,60  CA NPR (3) 3.6 Revenue in sub-saharan Africa = 6,6 – 5,0 M 1M Subtraction D = 1,6 S 1S Simplification L3 Total revenue for spas 1M Addition = 22,9 + 6,6 + 1,6 + 2,8 + 33,3 + 26,5 M 1CA Total revenue = $93,7 billion CA Penalise 1 mark if not in billions (4) 3.7 1,6; 2,8; 6,6; 22,9; 26,5; 33,3 M CA the value $1,6 from 3.6 D included in the data L3 6,6 + 22,9 1M Arranging in order of Median revenue = M 2 descending or ascending = $14,75 billion CA 1M Concept of median 1CA Answer in billions (3) 3.8 P (Regions with more than 40 000 spas) 1RT Correct numerator and P RT denominator L2 2 1M Multiplication by 100 = × 100 M 6 1CA Percentage = 33,33% CA NPR (3) [21] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2020) MATHEMATICAL LITERACY P1 7 QUESTION 4: FINANCE (12 marks), DATA HANDLING (11 marks) AND PROBABILITY (3 marks) Ques. Solution Explanation T/L 4.1 Cost = Kilolitre Cost 1M Cost of first 6 kℓ F 6 6 × 0 = 0 M L4 9 9 × 9,35 = R84,15 1M Cost for both 9 and 10 M kilolitres 10 10 × 11,16 = R111,6 1CA Total cost Total = 25 litres 84,15 + 111,60 = R195,75 M M 1M Multiply by 15% R195 ×115% = R225,11 CA 1CA Cost including VAT OR M M Cost = (6 × 0) + (9 × 9,35) + (10 × 11,16) = R84,15 + R111,60 = R195,75 CA Including VAT = R195,75 × 15% M = R29,3625 = R195,75 + R29,3625 = R225,11CA Increased block rate tariffs to encourage saving of water A OR 1A Reason Also assist small businesses or families with free water A Accept any other sound reason. (6) 4.2 R0,019 = 1 RWF 1M Concept of ratio F R? = 745 614,04 RWF M L4 R? = 0,019 × 745 614,04 M 1M Multiplication = R14 166,66676 S 1S Simplification value in R 10 1M Multiplication of 10% Bank charges = 14166,66676×100 M 1A Value of 10% = R1 416,666676 A 1M Subtraction Andile received = R14 166,66676 – 1 416,66676  M = R12 750 1A Valid Statement is valid. A OR OR 10 1M Multiplication of 10% Bank charges = × 745 614,04 RWF M 1A Value of 10% 100 = 74 561,404 A 1M Subtraction Andile received in RWF = 745 614,04 – 74 561,404 M 1S Simplification value = 671 052,636 S In Rands: R0,019 = 1 RWF 1M Concept of ratio R? = 671 052,636 RWF M 1M Multiplication Andile received = R0,019 × 671 052,636 M = R12 750 Statement is valid CA 1CA Valid (6) Copyright reserved Please turn over

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2020) 4.3.1 Total absentees = 67  M 1M Addition to 67 P Absentees on Wednesday =16 A 1A Absentees on Wed L2 16 1CA Fraction P(absent on Wed) = CA 67 (3) 4.3.2 1A for Monday boys at 5 D Number of absent learners during the week 1A for Tuesday girls at 6 L2 12 1A for Thurs for girls at 7 1A for Thurs for boys at 9 10 1A for Fri for boys at 7 Number of absent learners A 8 A A 6 A A 4 2 0 Monday Tuesday Wednesday Thursday Friday Days of the week Girls Boys (5) 4.4.1 Value of C: D 𝐶 + 1 853 1M Addition (1 853) and L4 64,2 = M 30 division by 30 64,2 × 30 = C + 1 853 1M Subtraction C = 1 926 – 1 853 M 1CA Value of C = 73 CA Answer invalid O 1A Invalid (4) 4.4.2 D = 0 A 1A Value of D D No learners scored 30 – 39 marks A 1A Explanation L4 (CA value of D from 4.4.1 included in the data) (2) [26] TOTAL: 100 Copyright reserved Please turn over