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Mathematical Literacy Grade 11 P1 2018 Memo (Eng)

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Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2018 (English), 6 pages. Read online or download the free PDF.

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Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2018 MATHEMATICAL LITERACY P1 MARKING GUIDELINE MARKS: 100 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table/Reading from a graph/Reading from map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason AO Answer only NPR No penalty for rounding This marking guideline consists of 6 pages.
Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018) QUESTION 1 [21] Ques Solutions Explanation T&L 1.1.1 R2 578 799 F Two million, five hundred and seventy eight thousand seven L1 hundred and ninety nine rand A 2A Write in words (2) F M 1.1.2 386 819,85 1M Correct values L1 % Deposit =  100 M 1M Multiply by 100 2 578 799 = 15% A 1A Answer in % (3) F 1.1.3 R386 819,85 A 1A Correct value L1 386 819,85 Transaction Cost = R5,75 + R1,10 × 100 M 1M Dividing by 100 = R5,75 + R4 255,02 1CA Transaction cost (3) = R4 260,77 CA NPR M 1.2.1 Distance = 82,3 – 26,9 MRT 1RT Correct distances L1 = 55,4 km  CA 1M Subtraction 1CA Distance (3) M 1.2.2 Time taken = 04:54:45 – 03:05:14 M 1MA Subtracting correct L1 = 01:49:31 CA times 1CA Time (2) M 1.2.3 Distance in metres = 68,9 × 1 000 C 1C Multiply by 1 000 L1 = 68 900 m A 1A Distance in metres (2) D 1.3.1 12, 8, 7, 5, 2, RG M 1RG Correct values L1 1M Descending order (2) D 1.3.2 Bar graph OR Column graph  A 2A Correct graph (2) L1 CA from 1.3.1 D 1.3.3 Total number of houses = 12 + 8 + 7 + 5 + 2 RG 1RG Values from the L1 = 34 A graph 1A Number of houses (2) [21] Copyright reserved Please turn over
Downloaded from hlayiso.com (EC/NOVEMBER 2018) MATHEMATICAL LITERACY P1 3 QUESTION 2 [29] Ques Solution Explanation T&L F 2.1.1 R2 250  RT 2RT Break-even L1 amount (2) F 2.1.2 Cost of A = R1 500 + R5,00(50) SF 1SF Substitution L1 = R1 500 + R250  S 1S Simplification = R1 750 CA 1CA Answer (3) F 2.1.3 Income = R15,00 × 250  1RT Correct values L1 = R3 750,00 1M Multiplication (2) F 2.1.4 Profit = Income – Expenses 1RT Correct values L1 = R5 250 – R3 250 RT M 1M Subtraction = R2 000 A 1M Profit (3) F 2.2.1 1st year = R60 000 × 8,5% M 1M Multiplication L2 = R5 100 A 1CA Interest (2) CA from 2.2.1 F 2.2.2 st 1 year total amount = R5 100 +R60 000 M 1M Adding interest L2 = R65 100  CA 1CA Amount 2nd year total amount = R65 100 × 8,5 % 1CA % calculation = R5 533,50 CA 1M Adding interest Total at the end of 2 years = R65 100 + R5 533,50 M 1CA Total amount = R70 633,50 CA (5) Water used = 587-561 1M Water used F 2.3.1 = 26 kℓ M 1RT Free kℓ L2 Cost = (0 × 6 kℓ) A + (20 × R10,02)  M 1M Multiplying by = R200,40 CA R10,02 Total cost = 200,40 + 80,70 1CA Water cost = R281,10 CA 1CA Cost including additional charge (5) F 2.3.2 VAT amount = R80,70 × 15% M 1M Multiplying L1 = R12,105 S 1S Simplification = R12,10 R 1R Rounding (Accept R 12,11)(3) Copyright reserved Please turn over
Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018) F 2.4.1 Inflation rate is a measure of inflation expressed in % showing the 2A Explanation L1 increase in price of goods and services. A OR The rate at which price increases over time if there is a decline in the purchasing value of money A (2) F 2.4.2 Price of brown bread in 2017 1M Multiply L1 = (1 + 6,59 %) × R9,99  M correct values = R10,65  A 1A Cost (2) [29] QUESTION 3 [17] Ques Solution Explanation T&L M 3.1.1 12 miles  RT 1RT Correct value L1 Distance = 12 × 1,609 1A Answer in km = 19,308 km A NPR (2) M 3.1.2 68 1RT Correct value Humidity of Cape Town =  RT L1 100 17 = 25  A 1A Simplified fraction (2) M 3.1.3 Time of sunset in Cape Town = 17:27 L1 12-hour format = 05:27 pm  A 2A Correct time (2) M 3.1.4 ℉ = (℃ × 1,8) + 32 L2 = (17 × 1,8) + 32  SF 1SF Correct value = 62,6  S 1S Simplification = 63 ℉  R 1R Rounding (3) M 3.2.1 Volume = Length × Width × Height 1SF Substitution L2 = 30 in × 12 in × 7,1 in  SF 1S Simplification = 2 556 in3 S A 1A Correct unit (3) Copyright reserved Please turn over
Downloaded from hlayiso.com (EC/NOVEMBER 2018) MATHEMATICAL LITERACY P1 5 CA from 3.2.1 M 3.2.2 Volume of the tank = 2 556 in × 85% M 3 1M Multiply by L3 = 2 172,6 in3 CA 85% 1CA Volume Increased volume after stones added = 2556 × 97% = 2479,32 in3 CA 1CA Volume Volume of stones = 2479,32 – 2 172,6 M 1M subtraction = 306,72 in3 CA 1CA Volume OR Volume of stones = 97% - 85% M M 1M Using correct = 12% × 2556 M M values = 306,72 in3 CA 1M Subtraction 2M Multiplication by 12% and 2556 1CA Volume of stones (5) [17] QUESTION 4 [13] Ques Solutions Explanation T&L M&P 4.1 Hartford RM 2RM Correct city L1 (2) 4.2 Distance on the map = 7,5 cm 2,5 cm = 100 miles M 1M Scale measure M&P 7,5 (use the scale as L2 = 3 cm S from actual map) 2,5 1S Division 3 × 100 = 300 miles CA 1CA Multiply by 100 (3) M&P 4.3 84and 87  RG 2RG Combination L1 OR of roads 81,88 and 90 RG (2) M&P 4.4 North East A 2A Correct direction L1 (2) M&P 4.5 Road 80  RG 2RG Correct road L1 (2) P 4.6  RG 𝟖 1A Numerator L2 Probability =  RG 𝟏𝟔 1A Denominator (2) [13] Copyright reserved Please turn over
Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018) QUESTION 5 [20] Ques Solutions Explanation T&L 1M Subtracting correct D 5.1 Poults not hatched in December = 28 795 – 25 422 M values L1 = 3 373 CA 1CA Not hatched (2) D 5.2 Mean L2 = 28 927 + 28 409 + 27 179 + 28 795 + 29 961 + 29 906 + 30 030 + 1M Adding 28 597 + 28 825 + 29 441 + 29 271 + 29 725  M 1M Dividing by 12 349 066 1CA Mean = M 12 NPR (3) = 29 088,93 CA D 5.3 No modal value A 2A Modal value (2) L1 D 5.4 Range = highest value – lowest value 1MA Subtracting L2 = 25 719 – 22 782 MA correct values = 2 937 CA 1CA Range (2) D 5.5 25 719, 25 422, 25 332, 25 075, 24 786, 24 616, 24 067, 23 645, 1M Arranged L2 23 598, 23 572, 23 179, 22 782 A 1MA Median concept with correct values 24 616  24 067 1CA Median (3) Median = 2 MA = 24 341  CA 5.6 Total hatched during 2016-2107= 291 7893 M 1M Addition Hatched in March= 25 719  RT 1RT D Ratio. 25 719 : 29 1793  CA 1CA Express a ratio. (3) L2 CA from 5.1.2 P 5.7 29 271 1M Fraction L2 P(July eggs) = × 100 M M 349 066 1M Multiplying by 100 = 8,39 % CA 1CA % (3) NPR D 5.8 Compound bar graph A 2A Type of graph L1 OR Bar graph A OR Line graph A (2) [20] TOTAL: 100 Copyright reserved Please turn over

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