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Mathematical Literacy Grade 11 P1 2017 Memo (Eng)

MemorandumMathematical LiteracyGrade 1120177 pages

Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2017 (English), 7 pages. Read online or download the free PDF.

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Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2017 MATHEMATICAL LITERACY P1 MARKING GUIDELINE MARKS: 100 Symbol Explanation M Method M/A Method with Accuracy A Accuracy CA Consistent accuracy RT/RG/RM Reading from a table/Reading from a graph/Read from map SF Substitution in a formula P Penalty, e.g. for no units, incorrect rounding off etc. NP No Penalty S Simplification R Rounding/Reason This marking guideline consists of 7 pages.
Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017) QUESTION 1 Quest. Solution Explanation Marks AWARD FULL MARKS FOR ANSWER ONLY 1.1.1 January 2017  2RT Correct L1 month (2) 1.1.2 R258,20 + R4 956,38 + R2 582 + R1 956,20  1M Count L1 = R9 753,08  correct values 1CA Total deductions (2) 1.1.3 Unemployment Insurance Fund  2A Write in L1 full (2) 1.1.4 3 1M Correct L1 𝑥 1 290  ratio 5 = R774,00  1 CA Amount (2) 1.2 Perimeter 1M/A correct L1 4 cm x 2 + 2 cm + 3 cm + 6 cm + 7 cm  values =26 cm  1A Perimeter (2) 1.3.1 North East  2A Direction L1 (2) 1.3.2 1 cm on the map represents 250 000 cm on the ground/in 2A Explanation L1 reality.  (2) 1.4.1 17, 19, 21, 23, 25, 26, 26, 27, 28, 29  2A L1 Arrangement (12) 1.4.2 7  2A Minimum L1 temperature (2) 1.4.3 Number appearing most frequently.  2A explanation L1 (2) [20] Copyright reserved Please turn over
Downloaded from hlayiso.com (EC/NOVEMBER 2017) MATHEMATICAL LITERACY P1 3 QUESTION 2 Quest. Solution Explanation Marks 2.1.1 R1 450,00  2RT amount L1 (2) 2.1.2 1 450  1M Correct values L1 x 100  1 495 1M (x100) = 96,98  = 97,0%  (4) 2.1.3 Total amount to be paid per day. L1 R1 400 x 3 = R4 200,00  1A 6 sleeper R1 035 x 2 = R2 070,00  1A 4 sleeper R1 495 x 1 = R1 495,00  1A 8 sleeper Total = R7 765,00  1A Total (4) 2.1.4 Total cost for 4 days = R7 765 x 4  CA from 2.1.2 L3 = R31 060,00  1M multiplying by 4 31 060 x 14% 1M R7 765 = R4 348,40  1CA Cost without R31 060 + R4 348,40  VAT = R35 408,40  OR 1M x 14% R7 765 x4  1CA = R31 060  R31 060 x 114%  R35 408,40  (5) 2.2.1 Deposit = 12,5%  x R31 060  CA from 2.1.2 2M L1 = R3 882,50  Multiplying by 12,5% and 31 060 1CA (3) 2.2.2 Balance = R35 408 – R3 882,50  CA from 2.1.2 and L1 = R31 525,90  2.2.1 OR 1M Subtraction VAT on Deposit = 3 882,50 x 0,14 1CA Balance = R543,55 Balance including VAT R27 177,50 x 1,14 = R30 982,35 + 543,55 = R31 525,90 (2) Copyright reserved Please turn over
Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017) Quest. Solution Explanation Marks 2.2.3 Thirty one thousand five hundred twenty five rands (2) and ninety cents  2.2.4 Donation = 20 x R14,2058  2M Multiplying L3 = R284,116  1S = R284,12  1A Donation (Accept R284,10) (3) 2.3. Cost of parking = 4 x R12,00  1M/A L1 = R48,00  (Multiply 4 days by 12) 1CA Parking fees (2) [27] Copyright reserved Please turn over
Downloaded from hlayiso.com (EC/NOVEMBER 2017) MATHEMATICAL LITERACY P1 5 QUESTION 3 Quest. Solution Explanation Marks 3.1.1 Minimum daily food = 250g + 500 g  1M Addition L1 750 g  1M Division cups = 125 g = 6 cups  1CA Cups (3) 3.1.2 10 000 𝑔 1SF, L2 Number of days =  750 𝑔 1 C ( kg to g) 1S Division = 13,3  1CA Days - = 13 days  (4) 3.1.3 42 1C L1 Tommy’s weight = 1 000  1A Ton = 0,042 tons  (2) 3.2.1 43 1MA L1  = 0,43  1A 100 (2) 3.2.2 Area of a main bedroom = 3 m x 3,5 m  1M L2 = 10,5 m2  1CA Area (2) 3.2.3 10,5 m2 1SF and 1C Number of boxes of tiles = (0,43 x 0,43) m 2 x 13  L2 10,5 m2 =  0,1849 m2 x 13 56,79 1S = 1CA 13 = 4,37  1CA (rounding upward for = 5 boxes  boxes) (5) [18] Copyright reserved Please turn over
Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017) QUESTION 5 Quest. Solution Explanation Marks ANSWER ONLY (FULL MARKS) 5.1.1 445 million cubic metres  1A Maximum L2 Heyshope dam  1A units (2) 5.1.2 Difference = 445 – 180,9  1A Correct values L1 = 246,1  1M subtraction 1CA Difference (3) 5.1.3 57,9+36,3+71,5+20,8+57+18,9+13,5+18,1+180,9 9 L2 1M division by 9 Mean = 474,9  1S 9 = 52,77 million cubic metres  1CA (3) 5.1.4 (i) Klipfontein  2 RT L1 (ii) Ohrigstad  any two dams (iii) Glen Alpine  identified (2) 5.1.5 Range = 445 – 10  1M L2 = 435  1CA (using values from a wrong column ) (2) Copyright reserved Please turn over
Downloaded from hlayiso.com (EC/NOVEMBER 2017) MATHEMATICAL LITERACY P1 7 Quest. Solution Explanation Marks 5.2.1 Absentees Week1 = 47 M/A Absentees Week 2 = 42 A Therefore Week 1 had most absentees  (2) 5.2.2 Each bar correctly plotted -allocate 1 mark [5x 1= 5] L2 (5) 5.3.1 5 1M numerator P(Green ball) = 18  L2 1M denominator (Allow answer in % or decimal and no penalty for rounding) Accept 0,278 OR 27,8%. (2) 5.3.2 10 1M numerator P( Blue ball)= 18  × 100  L2 1M multiplication = 55,56%  by 100 1CA Percentage to 2 decimal places (3) [24] TOTAL: 100 Copyright reserved Please turn over

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