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NATIONAL
SENIOR CERTIFICATE
GRADE 11
NOVEMBER 2017
MATHEMATICAL LITERACY P1
MARKING GUIDELINE
MARKS: 100
Symbol Explanation
M Method
M/A Method with Accuracy
A Accuracy
CA Consistent accuracy
RT/RG/RM Reading from a table/Reading from a graph/Read from map
SF Substitution in a formula
P Penalty, e.g. for no units, incorrect rounding off etc.
NP No Penalty
S Simplification
R Rounding/Reason
This marking guideline consists of 7 pages.
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Mathematical Literacy Grade 11 P1 2017 Memo (Eng)
Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2017 (English), 7 pages. Read online or download the free PDF.
Mathematical Literacy · Grade 11 · Eastern Cape November · 2017 · English. Memorandum, 7 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 11
- Language
- English
- Document type
- Memorandum
- Year
- 2017
- Exam period
- Eastern Cape November
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 7
- File size
- 904.2 KB
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This exam
Eastern Cape November 2017
Questions in this paper
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2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017)
QUESTION 1
Quest. Solution Explanation Marks
AWARD FULL MARKS FOR ANSWER ONLY
1.1.1 January 2017 2RT Correct L1
month (2)
1.1.2 R258,20 + R4 956,38 + R2 582 + R1 956,20 1M Count L1
= R9 753,08 correct values
1CA Total
deductions (2)
1.1.3 Unemployment Insurance Fund 2A Write in L1
full (2)
1.1.4 3 1M Correct L1
𝑥 1 290 ratio
5
= R774,00
1 CA Amount (2)
1.2 Perimeter 1M/A correct L1
4 cm x 2 + 2 cm + 3 cm + 6 cm + 7 cm values
=26 cm 1A Perimeter (2)
1.3.1 North East 2A Direction L1
(2)
1.3.2 1 cm on the map represents 250 000 cm on the ground/in 2A Explanation L1
reality. (2)
1.4.1 17, 19, 21, 23, 25, 26, 26, 27, 28, 29 2A L1
Arrangement (12)
1.4.2 7 2A Minimum L1
temperature (2)
1.4.3 Number appearing most frequently. 2A explanation L1
(2)
[20]
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(EC/NOVEMBER 2017) MATHEMATICAL LITERACY P1 3
QUESTION 2
Quest. Solution Explanation Marks
2.1.1 R1 450,00 2RT amount L1
(2)
2.1.2 1 450 1M Correct values L1
x 100
1 495 1M (x100)
= 96,98
= 97,0% (4)
2.1.3 Total amount to be paid per day. L1
R1 400 x 3 = R4 200,00 1A 6 sleeper
R1 035 x 2 = R2 070,00 1A 4 sleeper
R1 495 x 1 = R1 495,00 1A 8 sleeper
Total = R7 765,00 1A Total (4)
2.1.4 Total cost for 4 days = R7 765 x 4 CA from 2.1.2 L3
= R31 060,00 1M multiplying by 4
31 060 x 14% 1M R7 765
= R4 348,40 1CA Cost without
R31 060 + R4 348,40 VAT
= R35 408,40
OR 1M x 14%
R7 765 x4 1CA
= R31 060
R31 060 x 114%
R35 408,40 (5)
2.2.1 Deposit = 12,5% x R31 060 CA from 2.1.2 2M L1
= R3 882,50 Multiplying by 12,5%
and 31 060
1CA (3)
2.2.2 Balance = R35 408 – R3 882,50 CA from 2.1.2 and L1
= R31 525,90 2.2.1
OR 1M Subtraction
VAT on Deposit = 3 882,50 x 0,14 1CA Balance
= R543,55
Balance including VAT
R27 177,50 x 1,14
= R30 982,35 + 543,55
= R31 525,90 (2)
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4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017)
Quest. Solution Explanation Marks
2.2.3 Thirty one thousand five hundred twenty five rands
(2)
and ninety cents
2.2.4 Donation = 20 x R14,2058 2M Multiplying L3
= R284,116 1S
= R284,12 1A Donation
(Accept R284,10) (3)
2.3. Cost of parking = 4 x R12,00 1M/A L1
= R48,00 (Multiply 4 days by
12)
1CA
Parking fees (2)
[27]
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(EC/NOVEMBER 2017) MATHEMATICAL LITERACY P1 5
QUESTION 3
Quest. Solution Explanation Marks
3.1.1 Minimum daily food = 250g + 500 g 1M Addition L1
750 g 1M Division
cups =
125 g
= 6 cups 1CA Cups (3)
3.1.2 10 000 𝑔 1SF, L2
Number of days =
750 𝑔 1 C ( kg to g)
1S Division
= 13,3 1CA Days -
= 13 days (4)
3.1.3 42 1C L1
Tommy’s weight = 1 000
1A Ton
= 0,042 tons
(2)
3.2.1 43 1MA L1
= 0,43 1A
100
(2)
3.2.2 Area of a main bedroom = 3 m x 3,5 m 1M L2
= 10,5 m2 1CA Area (2)
3.2.3 10,5 m2 1SF and 1C
Number of boxes of tiles = (0,43 x 0,43) m 2 x 13 L2
10,5 m2
=
0,1849 m2 x 13
56,79 1S
= 1CA
13
= 4,37 1CA
(rounding upward for
= 5 boxes boxes) (5)
[18]
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6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017)
QUESTION 5
Quest. Solution Explanation Marks
ANSWER ONLY (FULL MARKS)
5.1.1 445 million cubic metres 1A Maximum L2
Heyshope dam 1A units (2)
5.1.2 Difference = 445 – 180,9 1A Correct values L1
= 246,1 1M subtraction
1CA Difference (3)
5.1.3 57,9+36,3+71,5+20,8+57+18,9+13,5+18,1+180,9 9 L2
1M division by 9
Mean = 474,9 1S
9
= 52,77 million cubic metres 1CA (3)
5.1.4 (i) Klipfontein 2 RT L1
(ii) Ohrigstad any two dams
(iii) Glen Alpine identified (2)
5.1.5 Range = 445 – 10 1M L2
= 435 1CA (using
values from a
wrong column ) (2)
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(EC/NOVEMBER 2017) MATHEMATICAL LITERACY P1 7
Quest. Solution Explanation Marks
5.2.1 Absentees Week1 = 47 M/A
Absentees Week 2 = 42 A
Therefore Week 1 had most absentees (2)
5.2.2
Each bar correctly plotted -allocate 1 mark [5x 1= 5] L2 (5)
5.3.1 5 1M numerator
P(Green ball) = 18 L2
1M denominator
(Allow answer in % or decimal and no penalty for
rounding) Accept 0,278 OR 27,8%. (2)
5.3.2 10 1M numerator
P( Blue ball)= 18 × 100
L2
1M multiplication
= 55,56%
by 100
1CA Percentage to
2 decimal places (3)
[24]
TOTAL: 100
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