Mathematical Literacy Grade 12 P2 NSC November 2026 Memo (Eng)

UNOFFICIAL Copyright reserved Please turn over Unofficial memo hlayiso mock exams Practice Series: Grade 12 NSC Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P2 NOVEMBER 2026 — UNOFFICIAL MARKING GUIDELINES MARKS: 150 These marking guidelines consist of 14 pages.

UNOFFICIAL Mathematical Literacy/P2 2 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 IMPORTANT: These are unofficial marking guidelines prepared by Hlayiso for revision. They are not the DBE’s official memorandum; the official marking guidelines may differ in mark allocation and accepted alternatives. SYMBOL AND EXPLANATION Symbol Explanation Symbol Explanation M Method A Accuracy MA Method with accuracy CA Consistent accuracy C Conversion D Definition F Choosing the correct formula SF Substitution in a formula J Justification O Opinion/Reason/Example P Penalty (e.g. no units, incorrect rounding) R Rounding RT/RG/RM Reading from a table/graph/map, plan or diagram S Simplification MM Measuring (ruler) NPR No penalty for rounding NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out an attempt of a question and not redone the question, mark the crossed-out version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines. Stop marking at the second calculation error in the same item. • Answers only, without working, are awarded full marks unless stated otherwise in the row. For “show that” and “verify” items, the working must be shown. • Units: penalise missing or incorrect units (mm, cm, m, m2, ℓ, kg, ◦F, £, %) ONCE per question (1P), not per item, unless the unit is the mark being tested. • Rounding: penalise incorrect rounding ONCE per question (1P). Money is rounded to TWO decimal places; counts of rolls, bins, springs and metres of fencing that must be bought are whole numbers. • A justification (J) mark is awarded only if it follows from the candidate’s own (correct or CA) calculations. • Measuring items (MM): the values below were estimated from photographs of the answer book and are given with a tolerance. Markers must use measurements taken on the printed ANSWER BOOK and award CA marks from the candidate’s own measurements within the tolerance. • Accept a full stop or a comma as the decimal sign and either a space or no separator for thousands. Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 3 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 QUESTION 1 1.1.1 F ✓✓D F (2) 1.1.2 D ✓✓D D Note: I is a floor plan (top view); do not accept I. (2) 1.1.3 H ✓✓D H Note: C is a number (ratio) scale; do not accept C. (2) 1.1.4 B ✓✓D B Note: G is a two-way (contingency) table; do not accept G. (2) 1.1.5 J ✓✓D J Note: E is the circumference.(2) 1.2.1 Triangular (prism) ✓✓A triangular (2) 1.2.2 Container A : Container B 450 g : 1800 g = 1 : 4 ✓RT 450 and 1 800 ✓M correct order ✓S 1 : 4 Note: 4 : 1: max 2/3. (3) 1.2.3 Mass = 450 g÷60 = 7,5 g ✓M dividing by 60 ✓A 7,5 g (2) 1.2.4 365÷7 = 52,14 weeks ≈52 weeks ✓C dividing by 7 ✓R 52 weeks Note: Answer only: full marks. (2) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 4 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 1.2.5 Impossible ✓✓A impossible Note: Neither container is a cylinder: A is a triangular prism and B is a rectangular prism (box). (2) 1.3.1 June: 30−11+1 = 20 days; July: 19 days Total = 20+19 = 39 days ✓M counting both 11 June and 19 July ✓A 39 days Note: The first and last days are both match days, so the count is inclusive. 38 days: max 1/2. (2) 1.3.2 Radius = 13 cm÷2 = 6,5 cm ✓M dividing by 2 ✓A 6,5 cm (2) 1.3.3 BBVA ✓✓RT BBVA (2) 1.3.4 22:00−15:00 = 7 hours (South Africa is 7 hours ahead of Dallas) ✓M subtracting the times ✓A 7 hours Note: Not the 6 hours of Atlanta: Dallas is in a different time zone. (2) 1.3.5 04:00 South African time Morning ✓RT 04:00 ✓A morning (2) [31] Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 5 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 QUESTION 2 2.1.1 Rosemary Road ✓✓RM Rosemary Road Note: Basil Road is exit only. (2) 2.1.2 North-east ✓✓RM north-east Note: The park is above and to the right of John’s house (14). The north arrow on the plan leans slightly to the left, which moves the bearing further towards the east, so NE is the best fit. Accept NNE. (2) 2.1.3 (a) TRUE ✓✓A true Note: Reading: the numbers increase clockwise round the outer ring (1 is north of the entrance; 3 is in the north-west, 14 in the south, 19 in the south-west) and then continue in the inner block. (2) 2.1.3 (b) 27 ✓RM reading the inner block ✓CA 27 Note: Reading: outer ring 1–19 (park skipped; 18 is the triangle south-east of 19), inner top row 20–23 from west to east (22 is the third), inner bottom row 24–28 from east to west, so A = 27. CA from 2.1.3(a). (2) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 6 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 2.1.4 Bordered by 4 houses: 21, 22, 25, 26, 27 ⇒5 houses Bordered by 2 houses: 2, 3, 4, 5, 6, 9, 12, 13, 14, 15, 16, 17, 18, 24, 28 ⇒15 houses Ratio = 5 : 15 = 1 : 3 John is CORRECT. ✓A 5 houses ✓A 15 houses ✓M ratio in the correct order ✓S 1 : 3 ✓J correct Note: “Bordered” means sharing a boundary line with another house. The park, the guard station and roads are not houses. Houses 1, 7, 8, 10, 11 and 19 border one house, and 20 and 23 border three. Reading: 23 just overlaps 25 on the plan. If 23 and 25 are read as not touching, 4 : 16 = 1 : 4 (NOT correct): award CA. (5) 2.1.5 House 19 is a triangle. Fence the west side and the diagonal side (shared with house 18), not the north side facing Nita’s Crescent. West side ≈1,8 cm; diagonal ≈2,4 cm Total on plan = 1,8+2,4 = 4,2 cm Actual = 4,2 cm×550 = 2310 cm = 23,1 m ≈24 m of fencing ✓MM west side ✓MM diagonal side ✓M adding ✓M multiplying by 550 ✓C dividing by 100 ✓R 24 m Note: The lengths were estimated from a photograph. The printed 3,5 cm arrow on Annexure E is 129 px wide and both annexure photos have the same scale (header 589 vs 591 px), so 1 cm ≈36,9 px. West side 68 px ≈1,8 cm; diagonal 88 px ≈2,4 cm. Scaling to the A4 width instead (210 mm = 720 px) gives 2,0 cm and 2,6 cm, i.e. 25,1 m. Note: Accept west side 1,6–2,0 cm and diagonal 2,2–2,6 cm, i.e. 21,5 m to 25,3 m, rounded up to 22–26 m. Markers measure on the actual answer book. Fencing is sold per running metre, so round UP. North side also fenced (≈33 m): max 5/6. (6) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 7 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 2.2.1 R91,50 ✓✓RM R91,50 Note: The Vaal toll (95 km) comes before Grasmere (140 km). (2) 2.2.2 Diepkloof ✓✓RM Diepkloof (2) 2.2.3 West ✓✓A west Note: The opposite of east (E). (2) 2.2.4 Oak Avenue: 188 km; Vaal River: 105 km Distance = 188−105 = 83 km 83 km > 80 km ∴her statement is VALID ✓RM 188 and 105 ✓M subtracting ✓A 83 km ✓J valid (4) [29] QUESTION 3 3.1.1 7 tubes A above B Height = 220 mm−10 mm 7 = 210 7 = 30 mm ✓M subtracting 10 mm ✓RM 7 tubes ✓A 30 mm Note: Reading: the roll in the diagram is divided into 7 equal tubes A and the short piece B. Accept 3 cm. (3) 3.1.2 Length = 130 mm+2×5 mm = 140 mm Perimeter = 2(140 mm+30 mm) = 340 mm = 34 cm ✓M adding two overlaps ✓A 140 mm ✓SF substitution ✓CA 340 mm ✓C 34 cm Note: Length 130 mm (no overlaps), giving 32 cm: max 3/5. One overlap only (135 mm, 33 cm): max 4/5. (5) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 8 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 3.1.3 ONE piece has 4 tubes and 3 strips. Tubes needed = 68×4 = 272 Rolls = 272÷7 = 38,86 ≈39 rolls 39 < 40 ∴her statement is VALID ✓RM 4 tubes per piece ✓M multiplying by 68 ✓M dividing by 7 (CA from 3.1.1) ✓R 39 rolls ✓J valid Note: Reading: the picture shows the reindeer-face tube, three more tubes and three paper strips. Reading 3 tubes per piece gives 30 rolls (VALID): max 4/5. Reading 5 tubes gives 49 rolls (NOT valid): max 4/5. (5) 3.1.4 Total strips = 8+6+10+7+22 = 53 P(white) = 22 53 ×100% = 41,51% ✓M adding ✓A 53 ✓M dividing (×100%) ✓CA 41,51% Note: Accept 41,5% or 42%. 22 53 not as a %: max 3/4. (4) 3.2.1 17 panels, 2 screws per panel Screws = 17×2 = 34 ✓RM 17 panels ✓A 34 screws Note: Count the panels in the completed top diagram (17). (2) 3.2.2 Length = 17×110 mm+16×10 mm = 1870+160 = 2030 mm (= 2,03 m) ✓M panels × 110 mm ✓M 16 spaces × 10 mm ✓CA 2 030 mm Note: 17 spaces (2 040 mm): max 2/3. CA from 3.2.1. (3) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 9 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 3.2.3 Panel: ℓ= 30 cm, w = 110 mm = 11 cm, h = 3,5 cm TSA = 2(30×11)+2(30×3,5)+2(11×3,5) = 660+210+77 = 947 cm2 17 panels: 947×17 = 16099 cm2 3 coats: 16099×3 = 48297 cm2 Spread rate: 11 m2 = 110000 cm2 per litre Paint = 48297 110000 = 0,439 ℓ≈439 mℓ Half a tin = 500 mℓ÷2 = 250 mℓ 439 mℓ> 250 mℓ ∴his statement is NOT VALID ✓C 11 cm ✓SF substitution ✓A 947 cm2 ✓M ×17 panels ✓M ×3 coats ✓C 110 000 cm2 ✓M dividing ✓CA 439 mℓ ✓J not valid Note: Working in m2 (4,8297 m2 ÷11 = 0,439 ℓ): full marks. One coat only (146 mℓ, “valid”): max 7/9. CA from 3.2.1. (9) [31] QUESTION 4 4.1.1 Carolina deck ✓✓RM Carolina deck (2) 4.1.2 Staterooms with a window: 106–110 (5) and 201–206 (6) = 11 11 28 = 0,392857... ≈0,393 ✓RM 11 staterooms ✓M dividing by 28 ✓A 0,3928… ✓R 0,393 Note: The key lists rooms 103–105 separately as “single room with window”. Check of the total: main deck 8, lounge deck 6 + 6, Carolina deck 8, which is 28. Including 103–105 (14 28 = 0,500): max 3/4. (4) 4.1.3 −7 = (◦F−32)× 5 9 ◦F = −7× 9 5 +32 = −12,6+32 = 19,4 ◦F ✓SF substitution ✓M changing the subject ✓A 19,4 ◦F Note: −7×1,8+32: full marks. (3) 4.1.4 The observation deck is the open top deck, exposed to the sun. The other decks are covered by the deck above them. ✓✓O valid reason (2) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 10 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 4.1.5 Stairs; lift ✓A stairs ✓A lift (2) 4.1.6 (a) They are staterooms with a balcony, so they need extra space for the balcony. (They are more luxurious and more expensive.) ✓✓O valid reason (2) 4.1.6 (b) 34,34 m = B + 3 staterooms (C) + A + 4 internal walls 34,34−13,65−6,825 = 13,865 m Walls = 4×0,045 = 0,18 m 13,865−0,18 = 13,685 m C = 13,685 3 = 4,56 m ✓RT 13,65 and 6,825 ✓M subtracting B and A ✓A 4 walls ✓M 4×0,045 ✓M subtracting walls ✓M dividing by 3 ✓CA 4,56 m Note: Reading: the 34,34 m arrow runs from the wall of the midship lounge to the stern. It covers B, staterooms 208, 210 and 212, and the open space A, with internal walls at B|208, 208|210, 210|212 and 212|open space. The window-stateroom size (2,8 m) is not in this span. Note: 3 walls (4,58 m) or 5 walls (4,55 m): max 6/7. Walls ignored (4,62 m): max 5/7. Accept 4,562 m. (7) 4.2.1 Springs used in Diagram C = 16 Remaining = 72−16 = 56 ✓RM 16 springs ✓M subtracting from 72 ✓CA 56 (3) 4.2.2 B ✓✓A B Note: Springs go in diagonally opposite pairs: 1/2, 3/4, 5/6, 7/8. Spring 9 (between 1 and 7) is paired with spring 10 between 2 and 8. Then 11 is between 3 and 5 and its opposite, 12, between 4 and 6. Only option B keeps every pair opposite. (2) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 11 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 4.2.3 26,5 = mass (1,65)2 Mass = 26,5×2,7225 = 72,146 kg ≈72 kg ✓SF substitution ✓M changing the subject ✓A 72,146 kg ✓R 72 kg (4) [31] QUESTION 5 5.1.1 Gate One ✓✓RM Gate One (2) 5.1.2 Grandstand (C) ✓✓RM Grandstand Note: Reading: from P12 he walks north between the parking area and LAWN TWO, then west along its northern edge. At the north-western corner he turns south past A (Pearson Pagodas), then B (Lawn Enclosure), then C, the third area. (2) 5.1.3 Adults: 2×£42,50 = £85,00 Daughter (17): £21,25; son (11): free Total = £85,00+£21,25+£0+£30,00 = £136,25 ✓M 2×42,50 ✓RT 21,25 and free ✓M adding parking ✓A £136,25 Note: Charging the son as a child aged 13–18 (£157,50): max 3/4. (4) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 12 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 5.1.4 Playing time = 6×7,2 = 43,2 min 5 breaks between 6 chukkas; one is the half-time break, so 4 chukka breaks Chukka breaks = 4×4 = 16 min Total = 43,2+16+10 = 69,2 min = 1 h 9,2 min 0,2×60 = 12 s Duration = 1 h 9 min 12 s ✓M 6×7,2 ✓A 43,2 min ✓M 4×4 min ✓M adding 10 min ✓CA 69,2 min ✓C 0,2 min = 12 s ✓CA 1 h 9 min 12 s Note: The breaks fall between the chukkas, and the half-time break after chukka 3 replaces one chukka break. Also accept 5 chukka breaks plus half-time (43,2+20+10 = 73,2 min = 1 h 13 min 12 s): full marks. One 4-min break only (57,2 min = 57 min 12 s): max 5/7. (7) 5.2.1 Volume = 1,370×1,050×1,385 = 1,9923225 m3 = 1992,32 ℓ Difference = 1992,32−1100 = 892,32 ℓ ✓SF substitution ✓C ×1000 ✓M subtracting 1 100 ✓CA 892,32 ℓ Note: Accept 892 ℓor 892,3 ℓ. (4) 5.2.2 18+13+11+11 = 53 1 large, 1 medium and 2 small bins (4 bins) ✓M combination totalling 53 ✓A 1 large and 1 medium ✓A 2 small Note: This is the only combination of FULL bins that gives 53. No 3-bin combination works (3 large = 54). (3) Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 13 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 5.2.3 Option 1 (front 1,375 m along the 4,13 m side): 4,13÷1,375 = 3,004 →3 2,17÷1,085 = 2 3×2 = 6 bins Option 2 (side 1,085 m along the 4,13 m side): 4,13÷1,085 = 3,81 →3 2,17÷1,375 = 1,58 →1 3×1 = 3 bins Maximum = 6 small bins ✓M dividing the length ✓M dividing the width ✓R 3 and 2 ✓CA 6 bins ✓M testing the other orientation ✓CA maximum 6 bins Note: Bins stand upright, so the height (1,340 m) is not used. Only one orientation tested, giving 6: max 4/6. (6) [28] TOTAL: 150 Copyright reserved Please turn over

UNOFFICIAL Mathematical Literacy/P2 14 NSC – Unofficial Marking Guidelines Hlayiso/November 2026 HOW DID OUR PREDICTION DO? The real November 2026 P2 compared with the Hlayiso 2026 Maths Literacy P2 Prediction paper Q Topic Real paper asked Our closest prediction item(s) Verdict Covered 1.1 Terminology A–J Metric system, elevation plan, bar scale, tree diagram, diameter 1.1: the same A–J matching format; we also asked bar scale (plus imperial system, radius, outcome)  10/10 1.2 Biscuit containers Name the prism, mass ratio 1 : 4, mass of one biscuit, days →weeks, probability scale 5.3 ratio, 1.2.1 unit conversion, 2.1.4 probability; no prism-naming or probability-scale item ≈ 9/11 1.3 World Cup Inclusive days, radius, table reading, time-zone difference, morning/evening 4.1.1 radius, 1.2.3 12-hour time, 5.2.2 day/date/time; our 5.2 said “ignore time zones” ≈ 8/10 2.1 Housing layout plan Entrance road, direction, house-numbering pattern, “bordered by” ratio, fencing by measuring (1 : 550) 3.1 floor plan (direction, measure + scale), 2.1.2 direction; no numbering or neighbour-count item ≈ 12/19 2.2 Strip map N1 First toll, interchange, opposite direction, verify > 80 km 2.2 strip/elevation chart, 2.1.1–2.1.2 map reading, 2.1.7 distance verify  10/10 3.1 Paper decoration Height of a tube, perimeter with overlaps, verify < 40 rolls, probability as % 3.2.2/4.1.3 how many to buy (round up), 2.1.4 probability as %, cylinder context (Q4.1)  14/17 3.2 Bench assembly Screws, cushion length (panels + gaps), TSA of a prism + spread rate verify (9) 1.3 braai-stand assembly; spread rate flagged “due” on the board but not set in our paper; TSA only for a cylinder label ≈ 9/14 4.1 Cruise-ship plan Deck reading, fraction to 3 d.p., ◦C→◦F, reasons, stairs/lift, missing dimension C with walls (7) 1.2.5 and 4.1.6 temperature, 3.1 plan reading and reasons; no “missing dimension from a plan” item ≈ 15/22 4.2 Trampoline; BMI Springs left, spring-installation pattern, BMI 1.3.1 counting parts only; BMI was on our “unlikely” list  3/9 5.1 Polo grounds Gate, route on a plan, family entry cost, duration in h/min/s 2.1.5 route description, 2.2.3 elapsed time, 5.2.2 time to the minute  13/15 5.2 Wheelie bins Volume vs capacity (m3 →ℓ), combination of bins, packing bins on a trailer 4.1.2 volume, 5.1.2 pallets in a container, 4.3 packing in a box (verify)  11/13 Marks of the real paper covered by our prediction 114/150 A learner who mastered our prediction could have answered about 114/150 (76%) of this paper with confidence. Most of that comes from the format and the standard M/MP/P skills; the plan-logic items (numbering, neighbours, spring pattern, missing dimension) and BMI were not practised. What we got right • The Q1.1 A–J matching table, in exactly our format, and bar scale was one of the terms in both. • Assembly diagrams for a sixth November in a row (bench and trampoline), as forecast. • A strip map (our “elevation profile / strip chart” call), route descriptions and compass directions. • The even-year ◦C↔◦F call, a spread-rate item (“due” after 2025), and packing items into a space. • “Buy whole units” rounding, probability as a %, ratio, time, the Special Answer Book with annexures, and four verify/show items (23 marks). What we missed • BMI (4 marks), which we rated unlikely, and time-zone differences. • Logic on plans: the house-numbering pattern, the “bordered by” ratio and the spring sequence (11 marks). • TSA of a rectangular prism with paint, and a missing dimension from a plan with wall thicknesses (16 marks together). • Several of our big calls did not appear: cylinder volume, density, composite circles, tree-diagram probability, scaled drawing and number-scale determination. That is about 60 of our 150 marks. Rating: 6/10. The format and most of the skills landed (matching table, assembly, strip map, ◦F, spread rate, packing), but none of our contexts matched, BMI caught us out, and our cylinder, density and circle items were not set. Copyright reserved