Physical Sciences Grade 10 P1 Eastern Cape November 2019 Memo

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 10 NOVEMBER 2019 PHYSICAL SCIENCES (PHYSICS) P1/ FISIESE WETENSKAPPE (FISIKA) V1 MARKING GUIDELINE/NASIENRIGLYN EXEMPLAR/EKSEMPLAAR MARKS/PUNTE: 150 This marking guideline consists of 12 pages./ Hierdie nasienriglyn bestaan uit 12 bladsye.

Downloaded from hlayiso.com 2 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2019) QUESTION 1/VRAAG 1 1.1 B ✓✓ (2) 1.2 D ✓✓ (2) 1.3 B ✓✓ (2) 1.4 B ✓✓ (2) 1.5 B ✓✓ (2) 1.6 D ✓✓ (2) 1.7 A ✓✓ (2) 1.8 A ✓✓ (2) 1.9 C ✓✓ (2) 1.10 B ✓✓ (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/NOVEMBER 2019) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 3 QUESTION 2/VRAAG 2 2.1 A single vector having the same effect as two or more vectors acting together. ✓✓ ʼn Enkele vektor wat dieselfde effek het as twee of meer vektore wat saamwerk. (2) 6 cm 2.2 ✓ ✓ Displacement /verplasing 4 cm 2 cm ✓ Displacement/Verplasing = 4× 20/1 =80 m ✓east ✓ (5) 2.3 2.3.1 Total distance/Totale afstand = 160 m ✓✓ (2) 2.3.2 Positive marking from 2.2/Positiewe nasien vanaf 2.2. total distance/𝑡𝑜𝑡𝑎𝑙𝑒 𝑎𝑓𝑠𝑡𝑎𝑛𝑑 Average speed/gemiddelde spoed = ✓ total time/𝑡𝑜𝑡𝑎𝑙 𝑡𝑦𝑑 160 = 300 ✓ v = 0,53 m·s-1 ✓ (3) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 4 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2019) QUESTION 3/VRAAG 3 3.1 Acceleration is the rate of change of velocity. ✓✓ Versnelling is die tempo van verandering in snelheid. (2) 3.2 3.2.1 v = 0 m·s-1 ✓ (1) 3.2.2 SOUTH/Suid ✓ (1) 3.2.3 a=0✓ (1) 3.3 3.3.1 ∆𝑣 Acceleration/versnelling = gradient/gradiënt = ✓ ∆𝑡 𝑣(𝑓)−𝑣(𝑖) 𝑡(𝑓)−𝑡(𝑖) 30−0 ✓✓ 3−0 a = 10 m·s-2 ✓ (4) 3.3.2 Total displacement = total area under the graph Totale verplasing = totale area onder die grafiek ∆X = A1 + A2 + A3 + A4 ∆X = (1/2 b x h) + (l x b) + (1/2 b x h) + (1/2 b x h) ✓ ∆X = (1/2 x 3 x 30) ✓ + (4x30) ✓ + (1/2 x 2 x 30) ✓ + (1/2 x 1 x -20) ✓ ∆X = 45 + 120 + 30 – 10 ∆X = 185m ✓ (in the direction of motion/in die rigting van beweging) (6) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/NOVEMBER 2019) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 5 QUESTION 4/VRAAG 4 4.1.1 Vf = vi + a∆t ✓ Vf = 0 + (2)(10) ✓ Vf = 20m·s-1 ✓ (3) 4.1.2 Option 1/Opsie 1 Option 2/Opsie 2 Option 3/Opsie 3 Positive marking Positive marking from 4.1/Positiewe from 4.1/Positiewe ∆x = vi∆t + ½ a∆t2 ✓ nasien vanaf 4.1 nasien vanaf 4.1 vf2 = vi2 + 2a∆x✓ ∆x = (0)(10) + ½ (2)(10)2 ✓ v f + vi ∆x = ( )∆t✓ 202 =02 + 2(2)∆x✓ 2 ∆x = 0 + 100 20 + 0 ∆x = 100 m✓ ∆x = ( )10✓ 2 ∆x = 100m ✓ ∆x = 100 m✓ (3) 4.2 V2f = v2f + 2a∆x ✓ (2vi)2 ✓ = v2i + 2(5)(3500) ✓ 4v2i = v2i + 35 000 3v2i = 35 000 V2i = 11 666.67 Vi = 108,01 m·s-1 Vf = vi + a∆t 216,02 ✓ = 108,01 + (5)∆t ✓ 5∆t = 108,01 ∆t = 21,60 s ✓ (6) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 6 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2019) QUESTION 5/VRAAG 5 5.1 Mechanical energy/Meganiese energie ✓ (1) 5.2 Em (A) = Ek(A) + Ep(A) = ½ mv2 + mgh ✓ = ½ (2)(10) ✓ + (2(9,8)(30) ✓ 2 = 149,6 J ✓ (4) 5.3 Em (A) = Em (B) (½ mv2 + mgh)A = (½ mv2 + mgh)B ✓ 149,6 ✓ = ½ (2)v2 + (2)(9,8)(0) ✓ v = 12,23 m·s-1 ✓ (4) 5.4 The principle of conservation of mechanical energy ✓ states that the total mechanical energy in an isolated system remains constant. ✓✓ Die beginsel van die behoud van meganiese energie stel dat die totale meganiese energie in ʼn geïsoleerde stelsel konstant bly (3) 5.5 Marking guide/Nasienriglyn Correct shape (STRAIGHT LINE)/Korrekte vorm (REGUIT LYN) ✓ All points plotted correctly/Al die punte korrek aangedui ✓✓ If at least 2 points plotted correctly/As ten minste 2 punte korrek aangedui is 1/2 Graph of height vs Kinetic energy/ Grafiek van hoogte vs Kinetiese energie Kinetic Energy/ Kinetiese energie 300 200 100 10 20 30 Height/Hoogte (m) (3) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/NOVEMBER 2019) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 7 QUESTION 6/VRAAG 6 6.1 Pulse is a single disturbance in a medium ✓✓ / Pols is ʼn enkele steuring in ʼn medium. (2) 6.2 Up/Af ✓ (1) 6.3 6.3.1 T = 1/f ✓ = 1/30 ✓ = 0,033 ∆t = 0,033 x 3 ✓ ∆t = 0,10 s ✓ (4) 6.3.2 Wavelength/Golflengte(m) = 12/3 ✓ =4m ✓ (2) 6.3.3 Option 1/Opsie 1 Option 2/Opsie 2 Option 3/Opsie 3 Positive marking from ∆x = v∆t ✓ Positive marking 6.3.2/Positiewe nasien 12 = v(0.10) ✓ from 6.3.1 and 6.3.2/ vanaf 6.3.2 V = 120 m·s-1 ✓ Positiewe nasien v = fλ ✓ vanaf 6.3.1 en 6.3.2 = (30)(4) ✓  V= V = 120 m·s-1 ✓ T✓ 4 V= 0,033 ✓ V=121, 21 m·s-1 ✓ (3) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 8 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2019) QUESTION 7/VRAAG 7 7.1 7.1.1 ∆x = v∆t ✓ 85 = v(0,25) ✓ v = 340 m·s-1 ✓ OR / OF ∆x = v∆t ✓ 170 = v(0,5) ✓ V = 340 m·s-1 ✓ (3) 7.1.2 Positive marking from 7.1.1/ Positiewe nasien vanaf 7.1.1. v= f  ✓ 340 = (100)  ✓  = 3,40 m ✓ (3) 7.2 7.2.1 Ultrasound refers to sound with a frequency of 20 kHz to 100 kHz ✓✓/ Ultraklank verwys na klank met 'n frekwensie van 20 kHz tot 100 kHz (2) 7.2.2 • Detecting invisible cracks in the wings of aircraft ✓ • Opsporing van onsigbare krake in die vlerke van vliegtuie. OR / OF • Determining the thickness of metals/plastic ✓ • Bepaal die dikte van metale/plastiek OR / OF • Cleaning delicate mechanisms of old-fashioned clocks ✓ • Om delikate meganismes van outydse horlosies skoon te maak (1) 7.2.3 Ultrasound does not damage the soft tissue of human organs. ✓✓/ Ultraklank beskadig nie die sagte weefsel van menslike organe nie. (2) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/NOVEMBER 2019) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 9 QUESTION 8/VRAAG 8 8.1 8.1.1 Infra-red/infrarooi ✓ (1) 8.1.2 Sun/Son ✓ OR/OF Gas discharge tube/Gasafvoerbuis ✓ (1) 8.2 c E= h ✓  3×108 ✓ 𝐸 = (6.63 × 10−34 ) 4×10−5 ✓✓ E = 4.97 × 10−28 𝐽 ✓ (5) 8.3 8.3.1 B, ✓ • B has a highest energy/frequency than ultraviolet ✓✓/ B, • B het die hoogste energie/frekwensie as ultraviolet (3) 8.3.2 Type of (electromagnetic) radiation ✓ Tipe (elektromagnetiese) straling OR/OF Frequency (of electromagnetic radiation) ✓ Frekwensie (van elektromagnetiese straling (1) 8.3.3 Fair test ✓✓ OR fair investigation OR to have one independent variable/ Billike toets OF billike ondersoek OF om een onafhanklike veranderlike te hê. (2) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 10 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2019) QUESTION 9/VRAAG 9 9.1 Poles are correctly labelled/Pole is korrect ✓ Field lines with arrows/Veldlyne met pyle ✓ Correct pattern/Korrekte patroon ✓ (3) 9.2 ATTRACTION/AANTREKKINGKRAG ✓ (1) 9.3.1 YES/JA ✓ (1) 9.3.2 NO, ✓ They repel each other or same poles of magnet ✓/ NEE, hulle stoot mekaar of dieselfde magneetpole. (2) 9.4 Earth’s magnetic field deflects charged particles ✓ which would harm the ozone layer./ Die Aarde se magnetiese veld reflekteer gelaaide deeltjies af wat die osoonlaag kan benadeel. Ozone layer protects Earth from ultraviolet strays. ✓/ Osoonlaag beskerm die Aarde teen ultravioletstrale. (2) [9] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/NOVEMBER 2019) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 11 QUESTION 10/VRAAG 10 10.1 A✓ (1) 10.2 ELECTRIC/ELEKTRIES ✓ (1) 10.3 To prevent charge leakage/Om ladinglek te voorkom ✓✓ (2) 10.4 10.4.1 States that the net charge of an isolated system remains constant (2) during any physical process. ✓✓/ Stel dat die netto lading van ʼn geïsoleerde stelsel gedurende enige fisiese proses konstant bly. 10.4.2 B✓ (1) 10.4.3 (4.4×10−9 )+(−2×10−9 ✓ 2 Q = +1.2 x10-9 C ∆Q n= ✓ q (1.2×10−9 )−(4.4×10−9 ) (1.2×10−9 )−(−2×10−9 ) n= ✓✓ OR = ✓✓ −1.6 ×10−19 1.6 ×10−19 n = 2x1010 electrons/elektrone ✓ (5) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 12 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2019) QUESTION 11/VRAAG 11 11.1 Electric current is the rate of flow of charges ✓✓/ Eletriesestroom is die tempo waarteen lading vloei Accept/Aanvaar Electric current is the amount of charge passing a point per unit time. ✓✓/ Elektriesestroom is die hoeveelheid lading wat deur ʼn punt gaan per eenheidstyd (2) 11.2 11.2.1 Potential difference/Potensiaalverskil ✓ (1) 11.2.2 Electric current/Elektriesestroom ✓ (1) 11.3 11.3.1 𝑅 = 𝑅1 ×𝑅2 ✓ 𝑙𝑙 𝑅1 +𝑅2 6×12 = ✓ 6+12 = 4Ω✓ OR/OF 1/Rp = 1/R1 + 1/R2 = 1/6 +1/12 Rp = 4 Ω (3) 11.3.2 Positive marking from 11.3.1/Positiewe nasien vanaf 11.3.1. Rll = Rs + Rll = 18 + 4 = 22 Ω ✓✓ (2) 11.3.3 Option 1/Opsie 1 Option 2/Opsie 2 I12 Ω = 0,5 A✓ V = IR V = (1)(6) ✓ I A2 = 1 + 0,5 V=6V = 1,5 A✓ V I= R I = Q /Δt✓ 6 1,5 = Q/5 ✓ I= ✓ Q = 7,5 C ✓ 4 I =1,5 A I = Q /Δt ✓ 1,5 = Q/5 ✓ Q = 7,5 C ✓ (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/NOVEMBER 2019) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 13 11.4 EQUAL TO ✓ /GELYK AAN Resistors in parallel work under the same potential difference ✓✓/ Weerstande in parallel werk onder dieselfde potensiële verskil. (3) 11.5 INCREASE/TOENEEM ✓✓ (2) [19] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief