Physical Sciences Grade 10 Free State June 2025 Paper & Memo

Testpapers.co.za Se ee education Department of Education FREE STATE PROVINCE TIME: 3 HOURS This paper consists of 12 pages and two information sheets. Copyright reserved Please turn over

Grade 10 Testpapers.co.za FS/June 2025 INSTRUCTIONS AND INFORMATION 1. 10. 11. 12. Write your name and other information in the appropriate spaces on the ANSWER BOOK. This question paper consists of NINE questions. Answer ALL questions in the ANSWER BOOK. Start EACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. . Leave one line 2.1 and QUES questions, for example between QUESTION mable pocket calculator. iets | atnematcal instruments. You are advised to use the attached DATA SHEETS. You may use approp Show ALL formulae and substitutions in ALL calculations. Round off your FINAL numerical answers to a minimum of TWO decimal places where applicable. Give brief motivations, discussions, et cetera where required. Write neatly and legibly. Copyright reserved Please turn over

Testpapers.co.za FS/June 2025 Grade 10 as QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the answer and write down only the letter A, B, C or D next to the question number (1.1—1.10) in your ANSWER BOOK. 1.1. Time taken for one complete wave cycle to pass a point is known as ... of a wave. A wavelength. B frequency. F Cc D period. (2) 1.2. When the period ¢ es, the frequency ... A increases. B decreases. Cc becomes zero. D stays the same. (2) 1.3. How does the SPEED of a wave of a red light compare to that of an ultraviolet light in a vacuum? A Equal to. (2) 14 gained protons. lost electrons. 0 O DB lost protons. (2) Copyright reserved Please turn over

Testpapers.co.za FS/June 2025 Grade 10 as 1.5 _ Which one of the following is the equivalent unit for potential difference? A W.h B JC Cc ed D os (2) 1.6 Abattery witha connected in serie Asecond resistor of the SAME RESISTANCE is now connected in parallel with resistor R. (See the diagram on the right.) How will the voltmeter and ammeter readings change when the second resistor is connected in the circuit? VOLTMETER READING | AMMETER READING A Decreases Increases B Increases Increases Cc Stay the same Decreases D Stay the same Increases (2) Copyright reserved Please turn over

Testpapers.co.za FS/June 2025 Grade 10 7S 1.7 What happens to the average kinetic energy of particles when the temperature of the substance increases? A Increases B Decreases Cc Becomes zero D Remains constant (2) 1.8 The atomic number of an element is determined by the number of... A neutrons. — B electrons. c nucleons. © D protons. : (2) 1.9 When a metal atom bonds with a non-metal, the non-metal atom will ... A lose electrons and decrease in size. B gain electrons and decrease in size. Cc lose electrons and increase in size. D gain electrons and increase in size. (2) 1.10 Which ONE of the following is a physical change ? A Iron and sulphur are melted together. B A piece of magnesium burns in air. Cc Wood turns into ash. D Gold melts. (2) [20] Copyright reserved Please turn over

Testpapers.co.za Grade 10 QUESTION 2 FS/June 2025 The frequencies and the corresponding energy of electromagnetic waves are given in the table below. 2:1 2:2 2.3 2.4 2.5 TYPE OF WAVE Microwaves Infrared Visible light Ultraviolet 2,01*1019 X- rays Define freque: Give one use of tt 2.2.1 Infrared - 2.2.2 X-rays - Calculate the: 2.3.1 Frequency of visible light 2.3.2 Wavelength of ultraviolet. Which type of waves has the lowest penetrating ability? (2) (1) (1) (3) (3) Refer to the either frequency or the energy to explain your answer. (2) Determine the energy of gamma ray with a wavelength of 1,24 x 10°! m. (3) Copyright reserved [15] Please turn over

Testpapers.co.za Grade 10 QUESTION 3 FS/June 2025 In the diagram below a wave passes a point every 0,5 seconds. The total length of the waves shown below is 6 m. 3.1 3.2 3.3 Define the term Calculate: 3.2.1 the speed of the wa 3.2.2 how far is the wave after 3 minutes. A wave is generated using a slinky is shown below. R 3.3.1 What type of wave is represented in the diagram above? 3.3.2 What is represented by the following: (a) letter P (b) letterR (c) distance PQ Copyright reserved (2) (3) (3) (2) (1) (1) (1) Please turn over

Testpopers.co.za FS/June 2025 Grade 10 7 3.4 _ A truck moves with a constant velocity towards a building. When the truck is at position 1 which is x-metres aN from the buildiaes, the.driver sounds the siren and receives the echo vat positio losition 1 and 2 are 400 m apart. Calculate the distat tween the truck and the building when the truck is at position 2. T! S in air is 340 m- s*. (5) [20] QUESTION 4 Two small identical spheres R and S placed on insulated stands, as shown in the sketch below. The spheres carry charges of +2x10°C and -4x10°C respectively. +2x10°C ® -4x10°°C 4.1 State the principle of conservation of charge. (2) 4.2 Which sphere has an excess of electrons? Explain the answer. (2) 4.3. The two spheres are brought into contact. Calculate: 4.3.1. the new charge on sphere R. (3) 4.3.2 the number of electrons transferred. (3) 4.4 It is observed that the spheres move apart after contact. Briefly explain this observation. (3) [13] Copyright reserved Please turn over

Testpapers.co.za FS/June 2025 Grade 10 as QUESTION 5 The diagram shows the three resistors connected to the battery, the ammeter and high resistance voltmeters, V1 and V2. The regiaia e of the ammete wires and the battery is negligible. ? s 5.1. State Ohm’s law (2) When the switch S is closed, the current passing through 6 © resistor is 0,8 A. 5.2 Calculate the: 5.2.1 effective resistance of parallel combination. (3) 5.2.2 reading on V2. (3) 5.2.3. reading on the ammeter. (3) 5.2.4 amount of charge passing through the ammeter in 10 seconds. (3) 5.2.5 reading on V1. (4) 5.3. Define potential difference across the ends of a conductor. (2) 5.4 Calculate work done in moving charge of 9,6 C through the 5 Q resistor (3) [23] Copyright reserved Please turn over

Testpopers.co.za FS/June 2025 Grade 10 QUESTION 6 The graph below shows a heating curve of a pure substance. 6.1 6.2 6.3 6.4 6.5 6.6 Graph of temperature vs time gas = = N Temperature (°C) = N > Time (s) Define the term boiling point. (2) Using the graph, write down the: 6.2.1 boiling point of the pure substance. (1) 6.2.2 phase of the pure substance at 60 °C. (1) How many phase changes are represented on the graph? (1) What happens to the temperature while the substance undergoes a phase change? Choose from INCREASES, DECREASES or REMAINS THE SAME. (1) How do we know that this substance is not water? (2) In which phase of matter is the average kinetic energy of the particles the highest? (2) [10] Copyright reserved Please turn over

Grade 10 QUESTION 7 7. Ta. Copyright reserved Consider the electron configuration of the three elements given below: ELEMENT ELECTRON CONFIGURATION P 1s?2s?2p®3s?3p° Q 1s22s22p® R 18?2s?2p%3s73p%4s2 —_ 7.1.2 Write down ORMULA of element represented by Q belongs. 7.1.4 Which element isin g (VII), period 3. 7.1.5 Write down the chemical formula of the compound that is formed when P reacts with R. A certain element, T, is in group 18(VIII) and period 2 of the periodic table. For this element, write down the: 7.2.1 name of group 18(VIII) elements. 7.2.2 number of valence electrons. 7.2.3 valency. Testpapers.co.za FS/June 2025 (2) (1) (1) (1) (2) (1) (1) (1) [10] Please turn over

Testpapers.co.za FS/June 2025 Grade 10 as QUESTION 8 The table below shows the first ionisation energies of some elements in group one. ELEMENT FIRST IONISATION ENERGIES (kJ-mo!") Lithium 520 Sodium 496 Potassium 419 8.1 Define the term i (2) 8.2. Which one of the | easily lose its outer electron? (1) 8.3 Explain the trend of tion energies down the group. (3) Naturally occurring eleme re of their isotopes. 8.4 From the above statement, which atomic particle is responsible for the occurrence of isotopes? (1) 8.5 The element neon is found in nature in the form of three isotopes, with their percentages as indi 8.5.1. Which on SO the heaviest? Give a reason for (2) 8.5.2 Us Ss C } ne the relative atomic mass of neon, using the information above. (3) [12] Copyright reserved Please turn over

Testpapers.co.za FS/June 2025 Grade 10 QUESTION 9 9.1 9.2 9.3 9.4 Chemical bonding leads to the formation of molecules such as NH3 and F2. 9.1.1 Define the term chemical bonding. (2) 9.1.2 Draw the Aufbau diagram to represent the element fluorine. (3) 9.1.3 Write down the type of chemical bond found in fluorine molecule (F2). (1) Draw the Lewis structu of NHsmolecule. (3) ion below represents chemical change Cu + NazSO4 9.3.1 Define chem alehange. (2) 9.3.2 Balance the above equation. (2) 9.3.3. Write word equation for the chemical equation above. (3) 9.3.4 In what phase is Cu ? (1) 9.3.5 Use the relative atomic masses to prove that the mass is conserved in the above chemical equation. (5) Consider the change represented below: CO2(s) > CO2(g) 9.4.1 Define sublimation. (2) 9.4.2 Is the above an example of chemical or physical change? (1) 9.4.3. Give a reason for the answer in QUESTION 9.4.2. (2) [27] GRAND TOTAL: 150 Copyright reserved Please turn over

Testpapers.co.za Grade 10 FS/June 2025 DATA FOR PHYSICAL SCIENCES GRADE 10 JUNIE-EKSAMEN GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 10 JUNIE-EKSAMEN TABLE 1: PHYSICAL CONSTANTS / TABEL 1: FISIESE KONSTANTES NAME / NAAM SYMBOL/ SIMBOOL_ | VALUE / WAARDE Speed of light ina vacuum » » . Spoed van lig in 'n vakuum 3,0 x 10° m:s” Planck's constant = x 10s: Planck se konstante poe : Charge on electron 3 Lading op elektron “1,6 x 10°C Electron mass ae | - Elektronmassa 9,11 x 10 kg TABLE 2: FORMULAE / TABEL 2: FORMULES WAVES, SOUND AND LIGHT / GOLWE, KLANK EN LIG v=fa =+ offorT == f =F offor =F Ax / v= of/or At Q = nq _@ f stand +i he spoed = tyd of/or E=hf=> distance speed =—— time ELECTROSTATICS / ELEKTROSTATIKA _a+Q Q 2 ELECTRIC CIRCUITS/ ELEKTRIESE STROOMBANE Q=IAt V =IR W ee Rs = Ry + Rp + R3 1_ijt Rp Ry Ro Copyright reserved Please turn over

Dourloaded.teansialieorlysics. com FS/June 2025 Grade 10 TABLE 3: we pemone asi OF ELEMENTS/TABEL 3: DIE PERIODIEKE TABEL VAN ELEMENTE 1 2 3 4 } il Z 8 9 10 11 12 13 14 15 16 17 18 (I) (Il) Atoomgetal (Il) (IV) (V) (VI) (VII) (VIII) 4 KEY/ SLEUTEL Atomic number 2 aw H i He 1 29 4 3 4 goa i 5 6 7 8 9 10 4 Elektronegatiwiteit o Simbool = Lil? Be Electronegativity >| — Cu Symbol a B a Cc |S N |S = F Ne 7 9 63,5 11 12 14 16 19 20 o "1 Nn 12 Benaderde reiatiowe atoommassa ie) % © ¥ 18 rr) 16 [—) 7 18 o Nal= Mg i i ‘ ~ ACIS SIG P lai S le Ce Ar 23 24 Approximate relative atomic mass 27 28 34 32 35,5 40 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 1,6 SKIS Ca |S Sc TiS Vv Cr | Mn |& Fe |2Co|2 Ni |2 Cu |S Zn Ga |% Ge = Se |S Br Kr 39 40 45| 48| 51 52 55| 56| 59| 59| 63,5| 65 70 73 75 79 80 84 1,5 1,6 2,0 > o 4 2, 37|_ 38 39/_ 40| 41 42| 43| 44] 45| 46| 47 48 49 50 51 52 53 54 SRb/2 sr |S Zr) Nb|2 Mo |@ Te |& Ru |S Rh|G Pd|@ Ag [= Cd |= In |S Sn N Te |g | Xe 86| 88 89| 91) 92 96 101| 103| 106) 108; 112| 115| 119| 122| 128| 127| 134 oe < 14 1,8 1,9 n ow 55 56 57 72| 73 74 75 76 77| 78 79 80 81 82 83 84 85 86 n. Cs|x> Ba La\o Hf} Ta Ww Re Os Ir Pt; Au Hg jo Te jo Pb jn Bi jo Po |m At Rn °133/° 137 | 139)" 17| 181) 184) 186) 190) 192) 195) 197| 201 |= 204 |= 207 |* 209 |“ ~ 9 87 88 89 S Fr/Z Ra Ac 58 59 60 61 62 | 63 64 65 66 67 68 69 70 71 226 Ce Pr Nd Pm | Sm | Eu Gd Tb Dy Ho Er Tm Yb Lu 140 | 141 | 144 150 | 152 | 157 | 159 | 163 | 165 | 167 | 169 | 173 | 175 90 91 92 93 94 | 95 96 97 98 99 100 | 101 102 | 103 Th Pa U Np Pu | Am | Cm Bk Cf Es Fm Md No Lr 232 238 Copyright reserved Please turn over

education Department of Education FREE STATE PROVINCE JUNE EXAMINATION/JUNIE EKSAMEN GRADE/GRAAD 10 PHYSICAL SCIENCES FISIESE WETENSKAPPE MEMORANDUM UPDATED/OPGEDATEER JUNE/JUNIE 2025 MARKS/PUNTE: 150 TIME: 3 HOURS TYD: 3 URE This marking guideline consists of 12 pages. Hierdie nasienriglyn bestaan uit 12 bladsye. Copyright reserved Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 1s QUESTION 1/VRAAG 1 11° Dvv 1.2. BYvY 13. Avv 14. Cvv 15 Cvv 16 Dvv 1.7 Avv 18 Dvv 19 Dvv 1.10 Dvv [20] QUESTION 2/VRAAG2 2.1. The number of wave pulses/waves/vibrations per second. / Die getal golfpulse/ golf/ vibrasies per sekonde. v ¥ (2) 2:2.4 (anyone/enigeen)Y¥ (1) (anyone/enigeen)Y (1) Copyright reserved Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 2.3.1 Option/ Opsie 1 = hf VF 2,11 x 10-?° = 6,63 x 1073+ f VS vs f = 3,18 x 10% HzVA (3) 23:2 Option/ Opsie 1 Option/ Opsie 2 c= fa VF E=“vF 3x 10° =2,01x10%.4 VS a = 149x107? m/149nm VA 1,33 x 10-18 = a 0x108) vs = 149 x 10-m/149mm vA MARKING GUIDELINE/MERKRIGLYN YF Formula (any one correct) / Formule (enige korrekte een) YS Full substitution (into one correct formula)/ Volledige Invervanging (in een korrekte formule in) YA Final answer + unit / Finale antwoord + eenheid RANGE/GRENS: (1,47 > 1,50) x 10-7 Copyright reserved (3) Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 as 2.4 microwaves/radio waves / mikrogolwe/radiogolwe ¥ lower frequency/lower energy~ laer frekwensie/laer energie (2) 25 Es"“v a _ (6,63x10734)(3x108) ¥ 5 1,24x10711 = 1,60 x 10724) v (3) [15] QUESTION/ VRAAG 3 — 3.1. A wave in which at right angle/ perpendicularv to the direction of the p th ‘n Golf waarin die vi ¢ rigting van die voo ) (2) - ALLOW/AANVAAR: 3.2.1 ve ma v= Distance = speed x time $ Afstand = spoed x tyd el ef so P og’ ORIOF 5 ORIOF v=~ =6m:s-lv¥ ig (3) OR/IOF v=- 300 t =3 x 60=180s¥ a Distance = speed ev Afstand = spoed x tyd ¥ (4) 3.3.1 Long 2 if vale (golwe) vv (2) 3.3.2 (a) ¢ er erdikkings. ¥ (1) : (1) (1) Copyright reserved Please turn over

Testpapers.co.za Grade/Graad 10 3.4 AFRIKAANS (t= 3 s) FS/June/VS/Junie 2025 Option/ Opsie 1 Option/ Opsie 2 At for sound to travel from position 1 to position 2/ At vir die klank om vanaf posisie 1 na posisie 2 te beweeg: distance = speed * Ti afstand = spoed x tyd 400 = 340xtvS At=1,176s At for sound to travel from pe ' the building / At vir die klank posisie 2 na die gebou te be Afstand = spoed x = 340 x 0,912VS =310,08 m v At for sound to travel from position 1 to position 2/ At vir die klank om vanaf posisie 1 na posisie 2 te beweeg:: distance = speed ~ time afstand = spoed ~ tyd 400 =340xtvS At=1,176s time from position 1 to the building: tyd vanaf posisie 1 na die gebou: =1,176+3v VF vs Distance/afstand x = 709,92 m Distance from position 2 to the building: Afstand van posisie 2 na die gebou = 709.92 — 400 = 309,92 mv Option/ Opsie 3 Pease g At 340v Ga- 100 1020 = 2x — 400 x = 710 = Position 1 from builing / Posisie 1 vanaf gebou Position 2 from builing / Posisie 2 vanaf gebou = x — 400 Iv = 710-400 v = 310 mv Copyright reserved (6) Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 3.4 ENGLISH (t=2s) Option/ Opsie 1 Option/ Opsie 2 At for sound to travel from position 1 to | At for sound to travel from position 1 to position 2/ At vir die klank om vanaf position 2/ At vir die klank om vanaf posisie 1 na posisie 2 te beweeg: posisie 1 na posisie 2 te beweeg:: distance = speed ~ time afstand = spoed x tyd distance = speed * Ti afstand = spoed x tyd 400 =340xtvS At=1,176s 400 = 340xtvS At=1,176s At for sound to travel fro! the building / At vir die posisie 2 na die geb time from position 1 to the building: tyd vanaf posisie 1 na die gebou: =1,176+2v Distance = spee VF Afstand = spoed x tyd vs = 340 x 0,411VS Distance/afstand x = 540 m =140 mv Distance from position 2 to the building: Afstand van posisie 2 na die gebou = 540 — 400 = 140 mv Option/ Opsie 3 eg At x = 540 = Position 1 from builing / Pt Position 2 from builing / Posisie 2 vanai — [20] Copyright reserved Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 as QUESTION/ VRAAG 4 4.1. The net charge of an isolated system remains the same./ Die netto lading van 'n geisoleerde sisteem bly konstant gedurende enige fisiese prosesv V OR/OF Charge cannot be destroyed nor created, only transferred from one object to another. / Lading kan nie geskep of vernietig word nie, maar slegs van een voorwerp na ‘n ander oorgedra word. VV (2) 4.2 $v the sphere / die sfeer is negatief gelaai.v (2) A311 Qnew (3) 4.3.2 -1x10~°-2x107? =1,6x10-19 n = 1,875 x 101° (electrons) W (3) n= 4.4 During contact, electrons are transferred from S to R. ¥ The spheres acquire equal charges. Vv Spheres thus repel each other. ¥ Tydens kontak word elektrone van S na R oorgedra. ~ Die sfere verkry gelyke ladings. ~ Sfere stoot mekaar dus af. (3) [13] QUESTION/ VRAAG 5 (One mark carried to 5.2.2 and 5.2.5 respectively./ Een punt is na vraag 5.2.2 en 5.3.5 onderskeidelik oorgedra.) (3) case Copyright reserved Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 as 5.2.2-R="v V; Bre = Vz = 4,8V¥ (4) 5.2.3. POSITIVE MARKING FROM 5.2.1 and 5.2.2 / POSITIEWE NASIEN VANAF 5.2.1 en 5.2.2 Option/ Opsie 1 Option/ Opsie 2 Vv Vv (3) (3) 2.3 AND 5.2.2 / 5.2.3 EN 5.2.2 Option/ Opsie 2 Riot = 3 +2,73” = 5,73 OY Viot = Imain X Rror™ = 1,76 x5,73¥ = 10,08 VY (5) 5.3. The energy transferred per unit electric charge flowing through it. vv Die energie oorgedra per eenheid elektriese lading wat daardeur vioei. — (2) 5.4 POSITIVE MARKING FROM 5.2.2 / POSITIEWE NASIEN VANAF 5.2.2 Is V= v ols Y=48= 2 a W = 46,08] ¥ (3) [23] Copyright reserved Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 QUESTION/ VRAAG 6 6.1 Boiling point is the temperature at which the vapour pressure of the liquid equals the atmospheric pressure. / Die temperatuur van 'n vioeistof waar sy dampdruk gelyk is aan die eksterne (atmosferiese) druk.v ¥ (2) 6.2.1. 117 (°C) v (1) 6.2.2.Liquid/ Vioeistof ¥ (1) 6.3 Two/Twee/ 2v (1) 6.4. REMAINS THE SAME/ iLFDEVY (1) 6.5 The boiling poi nt ° : ce is greater than / not equal to that of water. /Die kookpu stof is hoér as/ nie gelyk aan die kookpunt van wate | (117°C >100 °C). 100 °C).“ ¥ (Compare/vergelyk) The melting point of the substance is greater than / not equal to that of water./ Die smeltpunt van die suiwer stof is hoér as/ nie gelyk aan die kookpunt van water nie. (17°C > 0°C) OF/OR (17°C # 0 °C).~ v (Compare/vergelyk) (2) 6.6 Gaseous phase / Gasfase VY (2) [10] QUESTION/VRAAG 7 7.1.1. The number of protons in an atom of an element. Die aantal protone in ‘n atom van ‘n element. vv (2) 7.1.2 Calcium/ Kalsium/ Ca ¥ (1) (1) (1) (2) (1) (1) (1) [10] Copyright reserved Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 1% QUESTION/ VRAAG 8 8.1 8.2 8.3 8.4 8.5.1 8.5.2 lonisation energy is the amount of energy (per mol) required to remove the outermost electron Y from an atom in the gaseous phase. ¥ lonisasie-energie is die hoeveelheid energie benodig (per mol) om 'n buitenste elektron(e) uit 'n atoom in die gasfase te verwyderv . (2) Potassium/ Kalium ¥ (1) The distance between valence orbitals and the nucleus increases. v The force of ater between nucleus and outermost electrons decrease.v lonization energy | yf is, less energy is required to remove the Die afstand tusse isorbitale en die kern neem toe. ~ Die aantrekkings! in buitenste elektrone neem af.“ lonisasie-energié né minder energie is nodig om die buitenste elektron te area (3) Neutrons/ Neutrone ¥ (1) Ne-22 / Neon-22 v It has highest atomic mass/mass number ¥ Dit het ‘n hoér attoommassa/ massagetal. (2) Relative atomic mass/ Relatiewe attommassa _ (20 x 88,48)+(21 x 0,27 )+(22 x 11,25)” 100¥ = 20,23 v OR/ OF (20 x 0,8848) + (21 x 0,0027) + (22 x 0,1125)“v = 20,23V (3) [12] Copyright reserved Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 as QUESTION/ VRAAG 9 oO atoms resulting from the simultaneous nuclei and the outer electrons. g tussen twee atome wat die gevolg is van die ssen hulle kerne en die buitenste elektrone.“ VY (2) opposite spin/ pyltjies ways in elde spinrigting der of electrons/ korrekte aantal elektrone (3) 9.1.3 Covalent (bond)/ Kovalente (binding) ¥ (1) 9.2 8 electrons around N/ 8 elektrone rondom N v 3 bonding pairs of electrons/ 3 bindingspare elektrone v Single lone pair on N atom/ Een alleenpaar op N-atoom v (3) Copyright reserved Please turn over

Testpapers.co.za FS/June/VS/Junie 2025 Grade/Graad 10 9.3.1 9.3.2 9.3.3 9.3.4 9.3.5 9.4.1 9.4.2 9.4.3 Change in which new chemical substances are formed/ Energy changes are much larger than those of the physical change/Mass and atoms are conserved, but the number of molecules is not. vv Verandering waarin nuwe chemiese stowwe gevorm word / Energieveranderinge is baie groter as dié van die fisiese verandering / Massa en atome word behou, maar die aantal molekules is nie.” ¥ (2) 2Na + CuSO, > Cu+Na,SO, Vv (2) Sodium + Copper(Il)¥ sulphate + Copper + Sodium sulphate V Natrium + koper(Ii)¥ sulfaat V =» koper + natriumsulfaat v (3) (1) 2Na + Cu + Na2SO4 a= F =i 2x23 | + to aaieram asc e 63,5 + (2 x 23) =46 V (16x +32+ (16x4) ¥ 205,5 ¥ 2) 205,5 W's awarded for comparing/verifying that the total mass of reactant and total mass of products are equal, not just copying the value left and right. Dis toegeken vir die vergelyking/bevestiging van die totale massa van reaktante teenoor totale massa van produkte, nie net eenvoudig die kopiéring van die waarde links en regs nie. (5) The process during which a solid change directly into a gas without passing through an intermediate liquid phase. / Die proses waartydens 'n vaste stof direk in 'n gas verander sonder om deur ‘n intermediére vioeistoffase te gaan. VV (2) Physical (change) / Fisiese (verandering)¥ (1) Because no new substance is formed; v the CO, remains chemically the same, YOR only its physical state changes. Omdat geen nuwe stof gevorm word nie; Y die CO, bly chemies dieselfde, VY OF slegs die fisiese toestand daarvan verander. (2) [27] GRAND TOTAL/ GROOTTOTAAL: 150 Copyright reserved Please turn over