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Physical Sciences Grade 10 Paper 2 KZN June 2024 Memo

MemorandumPhysical SciencesGrade 10202415 pages

Grade 10 Physical Sciences Paper 2 memorandum from the KZN June Exam 2024, 15 pages. Read online or download the free PDF.

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KZN June Exam 2024

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Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com NATIONAL SENIOR CERTIFICATE GRADE 10 PHYSICAL SCIENCES P2 COMMON TEST JUNE 2024 MARKS: 75 DURATION: 1 ½ hours This question paper consists of 8 pages and 2 data sheets. Copyright reserved Please turn over
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Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com
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Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com
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Downloaded from hlayiso.com Downloaded f rom St anmorephysics. Physical Sciences P2 NSC com Common Test June 2024 1 NATIONAL SENIOR CERTIFICATE GRADE 10 PHYSICAL SCIENCES P2 COMMON TEST MARKING GUIDELINE JUNE 2024 MARKS: 75 DURATION: 1½ hours This marking guideline consists of 5 pages. Copyright reserved Please turn over
Downloaded from hlayiso.com Downloaded f rom St anmorephysics. Physical Sciences P2 NSC com Common Test June 2024 2 QUESTION 1: 1.1 C  (2) 1.2 C  (2) 1.3 A  (2) 1.4 B  (2) 1.5 D  (2) [10] QUESTION 2 2.1 2.1.1 Oak (chip).  The density of oak is less than the density of water.  (2) 2.1.2 Aluminium.  Aluminium has a lower density than lead.  For a constant mass, the density is inversely proportional to the volume.  (3) 2.2 2.2.1 Pure Substance  (1) 2.2.2 4Al + 3O2  2Al2O3 LHS  RHS  Balancing  (3) 2.3 2.3.1 Physical (change)  (1) 2.3.2 Decomposition  A single reactant is broken down into multiple products.  (2) 2.4 Mass of reactants = 2(14 + 1x3) + 2x1 + 32 +16x4  = 132 g.mol-1 Mass of products = 2(14 + 4x1) + 32 + 16x4 = 132 g.mol-1 Mass of reactants is equal to the mass of products. Therefore mass is conserved.  (3) [15] Copyright reserved Please turn over
Downloaded from hlayiso.com Downloaded f rom St anmorephysics. Physical Sciences P2 NSC com Common Test June 2024 3 QUESTION 3 3.1 Melting.  (1) 3.2 Thermometer  (1) 3.3 Crushed ice allows for easier transfer of heat energy from one particle to the next.  or Use crushed ice because it is easier for the thermometer to measure the temperature (2) 3.4 The temperature of the substance increases.  The average kinetic energy of the particles increases.  Particles move faster.  (3) 3.5 The water has reached room temperature  and there isn’t an external heat source.  (2) 3.6 Liquid.  (1) [10] QUESTION 4 4.1 4.1.1 A larger atomic radius results in lower first ionisation energy.  (1) 4.1.2 As you move from left to right across a period the effective nuclear charge increase  The force of attraction between the nucleus and the outer orbital increases.  or Cl has a smaller atomic radius than Mg (2) 4.1.3 Decrease  As you move down the group the atomic radius increases.  The force of attraction between the nucleus and valence electrons decreases.  (3) 4.1.4 The outermost energy level is full in noble gases resulting in a stable electronic configuration  or Noble gases have the smallest atomic radius for the elements in the same period.  (2) 4.2 The energy released when an electron is attached to an atom or molecule to form a negative ion.  (2) Copyright reserved Please turn over
Downloaded from hlayiso.com Downloaded f rom St anmorephysics. Physical Sciences P2 NSC com Common Test June 2024 4 4.3 Halogen  (1) [11] QUESTION 5 5.1 5.1.1 18  (1) 5.1.2 3p  3s 2p  2s 1s sp-notation: 1s22s22p63s23p5  (3) 5.1.3 Ionic bonds (1) 5.1.4 OPTION 1 OPTION 2 -1 -1 -1 2+ 2+ Cl Ca Cl  Ca 2 Cl  (2) Copyright reserved Please turn over
Downloaded from hlayiso.com Downloaded f rom St anmorephysics. Physical Sciences P2 NSC com Common Test June 2024 5 5.2 Let the 2nd isotope be Copper – X % Copper – X = 100 – 25  = 75%    25 75 63,5 = 65× + X� � 100 100 x = 63 number of neutrons = 63 – 29  = 34  (6) 5.3 5.3.1 MgO  (2) 5.3.2 (NH4)2Cr2O7  (2) 5.4 Copper (II) nitrate  Note: Copper nitrate  (2) [19] QUESTION 6 6.1 6.1.1 M(CaCO3) = 40 + 12 + 16 x 3  = 100 g.mol-1  (2) Positive marking from 6.1.1 𝑚𝑚 n(CaCO 3) = 6.1.2 𝑀𝑀  50 n(CaCO3) = 100  n(CaCO3) = 0,5 mol 𝑁𝑁 n(CaCO3) = 𝑁𝑁𝐴𝐴  N 0,5 = 6,02 × 1023  N = 3,01 x 1023 molecules  (5) V n(CO2 ) = 6.2 Vm  V 0,5 = 22,4  V = 11,2 dm3  (3) [10] TOTAL: 75 Copyright reserved Please turn over

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