Physical Sciences Grade 10 Paper 1 KZN June 2024 Memo

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com NATIONAL SENIOR CERTIFICATE GRADE 10 PHYSICAL SCIENCES P1 COMMON TEST JUNE 2024 MARKS: 75 DURATION: 1,5 hours Copyright reserved

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Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com NATIONAL SENIOR CERTIFICATE GRADE 10 PHYSICAL SCIENCES P1 COMMON TEST MARKING GUIDELINE JUNE 2024 MARKS: 75 DURATION: 1,5 hours Copyright reserved

Downloaded from hlayiso.com Downloaded Physical Sciences P1 f rom St anmorephysics. com NSC –Grade 10 June 2024 Common Test 2 QUESTION 1: 1.1 D ✓✓ (2) 1.2 B ✓✓ (2) 1.3 C ✓✓ (2) 1.4 B ✓✓ (2) 1.5 B ✓✓ (2) [10] QUESTION 2 2.1 A wave in which the particles of the medium vibrate at right angles ✓ to the direction of the motion of the wave. ✓ (2) 2.2 2.2.1 Wavelength ✓ (1) 2.2.2 Amplitude ✓ (1) 2.3 2.3.1 v=f ×λ ✓ 10 = 20 x λ ✓ λ = 0,5 m ✓ (3) 2.3.2 POSITIVE MARKING FROM QUESTION 2.3.1 OPTION 1 OPTION 2 1 Distance = 3 ✓ x 0,5✓ T= ✓ f = 1,5 m 1 distance = ✓ speed = ✓ 20 time 1,5 10 = ✓ = 0,05 s time time = 3✓ x 0,05✓ time = 0,15 s ✓ = 0,15 s ✓ OPTION 3 distance speed = ✓ time 0,05 10 = ✓ time time for 1 wave = 0,05 s time = 3✓ x 0,05✓ = 0,15 s ✓ (5) [12] Copyright reserved Please turn over

Downloaded from hlayiso.com Downloaded Physical Sciences P1 f rom St anmorephysics. com NSC –Grade 10 June 2024 Common Test 3 QUESTION 3 3.1 3.1.1 What is the relationship between frequency and wavelength of (2) sound waves (in air)? ✓✓ 3.1.2 Frequency is inversely proportional to wavelength ✓ OR Inverse proportion ✓ (1) 3.1.3 The speed of sound in air depends on temperature ✓ (1) 3.1.4 v=f ×λ ✓ = 10 000 x 0,034 ✓ OR = 5000 x 0,068 ✓ = 340 m.s-1 ✓ (3) 3.1.5 POSITIVE MARKING FROM QUESTION 3.1.4 v=f ×λ 340 = 1000 (X) ✓ X = 0,34 m ✓ (2) 3.2 3.2.1 distance speed = time distance 340 ✓ = 0,074 ✓ Distance = 25,16 m ✓ (3) 3.2.2 POSITIVE MARKING FROM QUESTION 3.2.1 Distance = 100 – 25,16 ✓ = 74,84 m distance speed = time 74,84✓ 340 ✓ = time time = 0,22 s ✓ (4) [16] Copyright reserved Please turn over

Downloaded from hlayiso.com Downloaded Physical Sciences P1 f rom St anmorephysics. com NSC –Grade 10 June 2024 Common Test 4 QUESTION 4 4.1 4.1.1 Radio waves ✓ (1) 4.1.2 Ultraviolet ✓ (1) 4.2 Gamma rays have the highest energy. ✓ This allows it to easily penetrate through medical equipment ✓ and kill viruses and bacteria ✓. (3) OPTION 1 OPTION 2 4.3 hc E=hxf ✓ E= ✓ λ 6,79 x10-23 = 6,63 x10-34 x f ✓ -34 8 -23 6,63×10 × 3×10 ✓ 6,79×10 ✓= f = 1,024 x1011 Hz λ λ = 2,93 x 10-3 m ✓ c=fxλ 3 x 108 = 1,024 x1011 x λ ✓ λ = 2,93 x 10-3 m ✓ (4) [9] QUESTION 5 5.1 All charges in the universe consist of an integer multiple ✓ of the charge of (2) one electron ✓ 5.2 Q = n x qe ✓ = 1,25×1013 x -1,6×10-19 ✓ = - 2 x 10-6 C ✓ (3) 5.3 POSITIVE MARKING FROM QUESTION 5.2 ∆𝑄 5.3.1 𝑛 = ✓ 𝑞𝑒 -2 ×10-6 - (- 8 × 10-6 ) ✓ = -19 1,6 × 10 ✓ = 3,75 x 1013 e- ✓ (4) Q1 + Q2 5.3.2 Q= ✓ 2 -6 - 8×10 + QB ✓ - 2×10-6 ✓ = 2 QB = 4 x 10-6 C ✓ (4) [13] Copyright reserved Please turn over

Downloaded from hlayiso.com Downloaded Physical Sciences P1 f rom St anmorephysics. com NSC –Grade 10 June 2024 Common Test 5 QUESTION 6 6.1 The rate of flow of charge. ✓✓ (2) 6.2 V = IR ✓ =2x4✓ =8V✓ (3) 6.3 POSITIVE MARKING FROM QUESTION 6.2 6.3.1 V8Ω = IR I8Ω = ½ I4Ω OR 8 = I8Ω x 8 ✓ = 0,5(2) ✓ I8Ω = 1A IT = 1A + 2A ✓ = 3A OPTION 1 OPTION 2 VBulb = 14 – 8 ✓ VT = IR = 6V 14 = 3 x RT ✓ VBulb = IR RT = 4,67 Ω 6 = 3 x RBulb ✓ 1 1 1 = + RBulb = 2Ω ✓ RP R 1 R2 1 1 1 = + RP 4 8 RP = 2,67 Ω RBulb = 4,67 – 2,67Ω ✓ =2Ω✓ (5) 6.3.2 RT = 2 + 4 + 8 ✓ = 14 Ω VT = IR 14 = IT x 14✓ IT = 1A Q = I ∆t ✓ = 1 x 180 ✓ = 180 C ✓ (5) [15] TOTAL: 75 Copyright reserved Please turn over