Physical Sciences Grade 10 Paper 1 KZN June 2023 Memo

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com . ea , 8 ” aN KWAZULU-NATAL PROVINCE Pd el | = EDUCATION ease REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE ets se seseeaaees : Beeese eee ES. ‘a : PHYSI . a a a " . 0 2 1 a “ Seeseseseesess oTrrrrirtt ttt MARKS: 75 DURATION: 1,5 hours This questio' 5 and a data sheet.

Downloaded from hlayiso.com Prysicallensslaasiadfirom Stanmorephysics.com June 2023 Common Test INSTRUCTIONS AND INFORMATION 1. This question paper consists of SIX questions. Answer ALL the questions in the ANSWER BOOK. 2 Start EACH:auestion on a NEW paae in the ANSWER BOOK. 3. Number the answers correctly according to the numbering system used in this question paper. 4. Leave ONE line between two sub-questions, for example between QUESTION 2.1 and QUESTION 2.2. 5. You may use a non-programmable calculator. 6. You may use appropriate mathematical instruments. 7. You are advised to use the attached DATA SHEETS. 8. Show ALL formulae and substitutions in ALL calculations. 9. Round off your final numerical answers to a minimum of TWO decimal places. 10. Give brief motivations, discussions et cetera where required. as Write neatly and legibly. Copyright reserved Please turn over

Downloaded from hlayiso.com Downloaded from Stanmore i Physical Science P1 (Grade 10) phy: ane en June 2023 Common Test 3 QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the answer and write only the letter (A-D) next to the question number (1.1-1.5) in the ANSWER BOOK, for example 1.11 E. 4.1 Which of the following indicates a wave in which the particles of the medium vibrate parallel to the direction of motion of the wave? A Water waves B ‘Transverse waves C Light waves D Sound waves (2) a2 Which graph represents the relationship between the frequency and the speed of LIGHT waves in a vacuum? A B Cc D = 7 % a S — E Ss i i i i 3 3 a | a o a frequency (Hz) frequency (Hz) frequency (Hz) frequency (Hz) (2) Copyright reserved Please turn over

Downloaded from hlayiso.com — Downloaded from Stanmorgghysics.com june 2023 Common Test 4 1.3 Consider the circuit diagram below. Which is the correct relationship between the voltmeter readings? A V2=V3 B V3=0,5V2 Cc V2=0.5V3 D W1=V2+V3 (2) 1.4 Which ONE of the following is equivalent to 1 Volt? A 1sC B 1A‘s Cc 1c D 1A-s* (2) 15 A perspex rod is rubbed on a woollen cloth, and becomes negatively charged. Which ONE of the following explains why the perspex rod becomes negatively charged? A __ Itloses electrons. B__ It gains electrons. Cc It gains protons. D It loses protons. (2) 2x5=10 Copyright reserved Please turn over

Downloaded from hlayiso.com Physical Ronn oa (eae fom Stanmorepitysics.com June 2023 Common Test QUESTION 2 (Start on a new page.) : The diagram below represents a transverse wave moving from left to right. Ls d= 13,5 cm ST The time taken for 3 consecutive crests to pass a given point is 2,5 seconds. 2.1 Write down the amplitude of the wave. (1) 2.2 Define the term wavelength in words. (2) 2.3 For the above wave, calculate: 2.3.1 The wavelength. (2) 2.3.2 The period of the wave. (2) 2.3.3 The wave speed. (3) 2.4 Determine the distance between six consecutive crests in this wave pattern. (3) [13] Copyright reserved Please turn over

Downloaded from hlayiso.com PRYSICESSWIICA GES Flom Stanmorepifysics.com June 2023 Common Test QUESTION 3 (Start on a new page.) 3.1. Aninvestigation was conducted to determine the relationship between the energy and frequency of a photon of light. The results obtained are shown in the graph belo [aYaYay h of Frequency and Energy of a photon > Energy (x10) J Nn 0 1 2 3 4 5 6 7 8 9 Frequency (x 1024) Hz 3.1.1. Write a suitable investigative question. (2) 3.1.2 What is the mathematical, relationship between the energy of a photon and its frequency? (1) 3.1.3. Explain your answer to Question 3.1.2 by referring to the shape of the graph. (2) 3.1.4. Determine the wavelength of the photon associated with point P on the graph. (3) Copyright reserved Please turn over

Downloaded from hlayiso.com Physica Sipptidd deeetPom Stanmorephf¥sics. com June 2023 Common Test 3.2 The table below displays data for different types of-electromagnetic radiation in order of increasing energy. TYPE OF RADIATION Energy (J) Radio waves Jay 2,65 x 10°27 Microwaves nl 1,99 x 10°28 Infrared (IR) (200) 3,99 x 1022 Visible light 1,33 x 10°79 Ultraviolet (UV) light 4,64 x 10-8 X-rays 9,95 x 10°77 Radiation Y 2:32 x.10-4 3.2.1 Identify the type of radiation represented by Radiation Y. (1) 3.2.2 Write down the energy value for the type of radiation with the highest wavelength. (1) 3.2.3 Determine the frequency of ultraviolet light. (3) [13] QUESTION 4 (Start on a new page.) Aman standing between 2 buildings, as shown in the diagram below, sounds a siren. He hears the echo of the sound produced by the siren from building 1 after 8 seconds, and the echo from building 2 after 6 seconds. 4 1366 m = fs Building 2 Building 1 X The distance between the man and building 1 is 1366 m.’ The man and both buildings are on the same plane and in a straight line. 4.1 Calculate the speed of sound in air. fat (3) 4.2 Determine the distance “X” between both buildings. (4) [7] Copyright reserved Please turn over

Downloaded from hlayiso.com PrvsicahSSMMougEes from Stanmorepfiysics.com ee QUESTION 5 (Start on a new page.) Two small identical spheres, P and R, are suspended on long silk threads, as shown in the sketch below. Sphere P is initially neutral and the initial charge of R is unknown cloar Sphere P is rubbed with a cloth and gains 2x10" electrons. 5.1 Determine the new charge of sphere P. (3) 5.2 State the principle of conservation of charge in words. (2) 6.3 Sphere P, is now brought into contact with Sphere R and the two spheres are then separated. Both spheres have a charge of 6,4 uC after they are separated. Calculate: 5.3.1 The initial charge on Sphere R. (4) 5.3.2 The number of electrons transferred from sphere P to sphere R. (4) 5.4 Your hand feels a small sharp electric shock when you touch a metal doorknob, after walking on carpet on a dry day. Explain this phenomenon. (3) [16] Copyright reserved Please turn over

Downloaded from hlayiso.com PUYSIASGWISATER Mom Stanmorephiysics.com QUESTION 6 (Start on a new page) A battery with an emf of 18V is connected to four resistors as shown. fy EMF =18V jaa @ Ome 10 “A 6Q M4 ® 180 C of charge passes through the 20 resistor in 1,5 minutes. 6.1 Define current in words. 6.2 Calculate the reading on ammeter Az. 6.3 Determine the: 6.3.1 Effective resistance of the parallel combination 6.3.2 The reading on voltmeter V1 6.3.3 Energy transferred to the 20 resistor in 1,5 minutes 6.4 Awire of negligible resistance is connected from point X to reading on Ai INCREASE, DECREASE OR REMAIN THE Explain the answer. Copyright reserved June 2023 Common . Will the TOTAL: Please turn over (2) (3) (2) (2) (4) (3) [16] 75

Downloaded from hlayiso.com Prysical Sippitdd deererPom Stanmorepiffsics.com dune 2023 Common Test DATA FOR PHYSICAL SCIENCES GRADE 10 PAPER 1 (PHYSICS) TABLE 1: PHYSICAL CONSTANTS NAME! SYMBOL VALUE Speed of light inajvacuum c 3,0 x 108 m-s* Planck's constant h 6,63 x 10% J-s Charge on electron qe -1,6 x 107°C Electron mass Me 9,11 x 10°" kg TABLE 2: FORMULAE WAVES, SOUND AND LIGHT v=fa or c=fa rat f he E=hf Sito oe ELECTROSTATICS 1+Q2 Q=nxq qul =2 ELECTRIC CIRCUITS Sow Sip dei Q=Ix At ip ht R Ww Rs = Ry +R, + rae Copyright reserved

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE MARKS: 75 DURATION: 1,5 hours

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 1 1.1 Dvv (2) 1.2 (2) 1.3 (2) 1.4 (2) 15 (2) [10] QUESTION 2 2.1 4cm or 0,04 mv (1) 2.2 The distance between two successive/consecutive points in phase. VW (2) 2.3 POSITIVE MARKING FOR QUESTION 2.3 231 4-135 2,25 =6cmor0,06m ¥ (2) 2.3.2 -75 y 2 =1,25s v (2) 2.3.3 OPTION 1 OPTION 2 — 1 _ distance f= T Speed = me” = 1 = O12 / 1.25 2,5 = 0.8 Hz = 0,048 ms? v v=f xA v =0,8 x 0,06 v = 0,048 m.s? ¥ (3) vv 2.4 Distance =5x6 =30cmor0,3m ¥ (3) [13]

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 3 3.1 3.1.1. What is the relationship between the frequency and energy of a photon? vv (2) 3.1.2 y of a photon is directly proportional to the frequency ¥ Or (1) portion ¥ con] 3.1.3 Thelgrath is a straight line Y starting from the origin v. (2) Or As the frequency increases the energy increases v proportionally v. 3.14 cH=fxXAv. 3x108=3x10%xA Vv. A= 1x10%m Vv. (3) 3.2 3.2.1 Gamma rays v. (1) 3.2.2 2,65x 1077J v. (1) 3.2.3 E=hxf v. 4,64 x 10°78 =6,63x 10% xf v. f= 7x10'%Hz v. (3) [13] QUESTION 4 ds distance 4.1 SPeel™ “time v _ 1366 = y =341,5ms' v (3) distance I 4.2 speed= ti Ica? . ime an v _ distance fam 341,5= 3 v = Distance = 1024,5 m X= 1024,5+ 1366 v = 2390m ¥ (4) [7]

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 5 5.1 Q=nxq, v =2 x {0% x (1,6x 10%) v = 3,2) SC Vv Thereféte charge on sphere P is -3,2 x 10° C. (3) — 5.2 The net charge of an isolated system remains constant during any physical process V¥ (2) 5.3 POSITIVE MARKING FROM QUESTION 5.1 5.3.1 _ Q1+Q2 Q= 2 v -3,2 x10°+Q, 6 , R Vv 6,4 x10° = rr v Qr=1,6x 10°C v (4) 53.2 n= 42 qe v _ 6,4 x10° — 1,6 x 10° _ 64x10°— (-3.2x10%) ¥ 1,6 x 10° OR “1,6 x 10° v =6x 10'S electrons ¥ (4) 5.4 Whilst walking on the carpet, electrons are transferred to you. W You pick up a negative charge, v due to the excess electrons. When you touch the doorknob (a conductor) , the quick movement of electrons ¥ from you to the doorknob results in the sudden shock. (3) [16]

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 6 6.1 6.3 The rate of flow of charge V¥ 6.3.1 6.3.2 6.3.2 6.3.3 v v 1. 1~,1 Rp Ry Ro _1 al ~3°6 v Rp=20V¥ POSITIVE MARKING FROM QUESTION 6.3.1 Using Ratios Vie - x18 v =6V v¥ OR Using Ohms Law Vi=IxR =2x3 v =6V v¥ POSITIVE MARKING FROM QUESTION 6.3.2 Using Ratios Vog= 2 x6 v 20= 3 =4V W=VxQ v =4x 180 Vv =720J v Using Ohms Law V2a=1xR =2x2v =4V W=VxQ v =4x 180 v =720J ¥ (2) (3) (2) (2) (4)

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com 6.4 Increase. ¥ The total resistance decreases. ¥ (3) Current is inversely proportional to resistance. ¥ [16] TOTAL: 75