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Physical Sciences Grade 10 Paper 1 KZN November 2023 Memo

MemorandumPhysical SciencesGrade 10202318 pages

Grade 10 Physical Sciences Paper 1 memorandum from the KZN November Exam 2023, 18 pages. Read online or download the free PDF.

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KZN November Exam 2023

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Downloaded from hlayiso.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE ,,�-------------- _________ � _,, 11 II ,1 II II II II ,, -----------��., II �.!!�!!!!!!�!!!!!!!!!�!! - MARKS: 100 DURATION: 2 hours Stanmorephysics This question paper consists of 11 pages and a data sheet.
Downloaded from hlayiso.com Physiewslanderdann) Stanmorerbysics.com November 2023 2 INSTRUCTIONS AND INFORMATION i This question paper consists of EIGHT questions. Answer ALL the questions in the ANSWER BOOK. —= H question on a NEW page in the ANSWER BOOK. 3 Numb r the answers correctly according to the numbering system used in this question paper. 4. Leave ONE line between two sub-questions, for example between QUESTION 2.1 and QUESTION 2.2. 5. You may use a non-programmable calculator. 6. You may use appropriate mathematical instruments. G You are advised to use the attached DATA SHEET. 8. Show ALL formulae and substitutions in ALL calculations. 9: Round off your final numerical answers to a minimum of TWO decimal places. 10. Give brief motivations, discussions et cetera where required. 11. Write neatly and legibly. Copyright reserved
Downloaded from hlayiso.com Physiewshance aan) Stanmorepbysics.com November 2023 3 QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the answer and write only the letter (A—D) next to the questionAuimber (1.1-1.5) in the ANSWER BOOK, for example 1.6 E. 1.1 If th distance between two consecutive compressions in a wave is decreased, which-ONE of the following will INCREASE when the wave speed is kept constant? A Amplitude B_ Period C Frequency D Wavelength (2) 1.2 The position-time graph for a car travelling along a straight horizontal surface is shown below. GRAPH OF POSITION VERSUS TIME Position (m) 0 t Time (s) Line PQ is a tangent to the curve at time t1. Which ONE of the following is equal to the gradient of PQ? A __ Average velocity over the period 0 to t1 B Instantaneous velocity at t1 C Average acceleration over the period 0 to t: D Instantaneous acceleration at ti (2) Copyright reserved
Downloaded from hlayiso.com PhysiewebandeGranom) Stanmorerbysics.com November 2023 4 1.3 The kinetic energy of a trolley is E. What will the kinetic energy of the trolley be if its velocity is tripled? A B Cc D 9E (2) 1.4 The table below shows the changes in the velocity of a car in intervals of 4 seconds. Time (s) 0 4 8 12 16 20 24 28 32 Velocity (m.s“) ie} 7 14 21 28 28 28 28 28 Which ONE of the following is CORRECT for the acceleration of the car? The acceleration of the car ... A _ increases initially for 16 s then remains constant. B _ is initially constant for 16 s then becomes zero. C _ is initially constant for 16 s and then decreases. D _ increases initially for 16 s and then becomes zero. (2) Copyright reserved
Downloaded from hlayiso.com Physiewslandedrdaom) Stanmorerbkysics.com November 2023 5 1.5 Four identical resistors are connected as shown in the circuit diagram below. Which ONE of the following relationships is correct for the readings on the voltmeters? © Ra Ri R3 -©- Bo VrHVi+V2+V3 + V4 A M=V2=V3 C Vr=V3 + V4 D Wt=V3 (2) [2X 5=10] Copyright reserved
Downloaded from hlayiso.com PhysiewebandeGranom) Stanmorerbysics.com November 2023 6 QUESTION 2 (Start on a new page.) 21 A section of a wave is represented below. time = x seconds The frequency of the wave is 2,5 Hz. 2414 Is the above wave TRANSVERSE or LONGITUDINAL? (1) 21:2 Calculate the speed of the wave. (3) 2.1.3 Determine the time, “x”, between point A and point B on the graph. (3) 22 Ships use Sonar (Sound Navigation and Ranging) to map and measure the depth of the ocean at different points. This is achieved by emitting sound waves into the sea and detecting the reflected sound. The sound wave emitted by the Sonar on a ship takes 0,8 seconds to reach point P, which is on the seabed 1200 m below the ship. Q is a second point on the seabed, as shown in the diagram below. O*K Copyright reserved
Downloaded from hlayiso.com Physiewslandedrdaom) Stanmorerbysics.com November 2023 az 2.2.1 Calculate the speed of sound in seawater at point P. (3) It is estimated that the speed of sound in seawater increases by 4,5 m.s“ for every me increase in temperature. The temperature of the seawater at point Q is 2°C higher than at point P. When a sound wave is emitted directly above point Q, the reflected sound wave is detected 2,5 seconds later. Determine the depth of the sea at point Q. (4) [14] QUESTION 3 (Start on a new page.) A photon of wavelength 2 x 10” m is located within the x-ray range of the electromagnetic spectrum. 3.1 Write down the speed of this photon in a vacuum. (1) 3.2 Calculate: 3.2.1 The frequency of the photon. (3) 5:3:2 The energy of the photon. (3) 3.3 The wavelength of the photon is doubled. Will the penetrating ability of this photon INCREASE, DECREASE or REMAIN THE SAME? Explain the answer. (3) [10] Copyright reserved
Downloaded from hlayiso.com Physiewebanderaaom) Stanmorerbysics.com November 2023 8 QUESTION 4 (Start on a new page.) Two small identical Spheres, X and Y, carrying charges of — 6 x 10 8Cand8x10°C respectively, afeSuspended from a ceiling by means of light, insulated strings. Qx =-6x10°C Qy =8 x10°C 4.1 State the principle of quantization of charge. (2) 4.2 Calculate the difference between the number of protons and electrons in Sphere X. (3) The spheres are brought into contact and are then separated. 4.3 State the principle of conservation of charge. (2) 4.4 Calculate the new charge on Sphere Y. (3) [10] Copyright reserved
Downloaded from hlayiso.com Physiewslandedrdaom) Stanmorerkysics.com November 2023 9 QUESTION 5 (Start on a new page) A battery consisting of 3 identical cells of unknown emf is connected to four resistors, as shown in the diagram below. 120 R2 The voltmeter reads 12 V, while ammeter A2 reads 2 A. 51 Define the emf of a battery in words. (2) a2 Calculate the: 5.2.1 Effective resistance of the parallel combination (3) 5.2.2 The reading on ammeter Ai: (3) 5.2.3 Energy transferred to the resistor R3 in 2 minutes (5) 5.2.4 EMF of each cell (3) 5.3 A fifth resistor, Rs, is now connected in parallel to Ra. 5.3.1 Will the emf of the battery INCREASE, DECREASE OR REMAIN THE SAME? (1) 5:3:2 Will the reading on Ai INCREASE, DECREASE SAME? L Give a reason for the answer. (2) [19] REMAIN THE Copyright reserved
Downloaded from hlayiso.com Phyiewshanceraani) Stanmorepbysics.com November 2023 10 QUESTION 6 (Start on a new page) A forklift startingfrom Point X needs to pick up a package from Point Y, which is due east from Point. The package! is)/thereafter transported to a table, which lies 350 metres due west of Point X. The-entire trip takes the driver 2 minutes to complete. N — |_ : > 350m X Y 6.1 Define the term average velocity in words. (2) 6.2 Calculate the average velocity of the forklift for the entire motion. (3) 63 The average speed of the forklift is 3,75 m-s". Determine the position of Point Y relative to Point X. (4) [9] QUESTION 7 (Start on a new page) 7.1 Acar C and a van V are both travelling at a constant velocity of 25 m.s“' east, on different lanes along the same horizontal road. The driver of the car follows the van, keeping a distance of 5 metres between them. Seeing a box on his lane, the driver of the van brakes and slows down uniformly to stop in 5 seconds. N Ds Box E OO Ss iI 7.1.1 Calculate the acceleration of the van whilst slowing down. (3) fAZ If the car continued at its original motion, how far ahead of the van will the car be when the van stops? (5) Copyright reserved
Downloaded from hlayiso.com Physiewslandedr dam) Stanmorerbysics.com November 2023 11 7.2 After passing the box, the van takes off from rest and accelerates uniformly at 4m-s* for 8 seconds. It thereafter travels at a constant velocity of X m-s" for a further 4 seconds as shown in the graph below. Velocity (m-s) Cg ee = Roaftsescnsnoeasew: Time (s) 2a USE THE GRAPH to determine the value of X. 7.2.2 Sketch the acceleration vs time graph for the 12 seconds represented in the graph above. Indicate the relevant time and acceleration values on the graph. QUESTION 8 (Start on a new page) A 4kg steel ball is pushed from rest from the top of a frictionless ramp of unknown height, h at point A. It passes point B, which is 1 metre above the ground at a velocity of 5,422 m-s". The ball eventually reaches the ground at point C. Cc 8.1 Calculate the mechanical energy of the ball. The magnitude of the velocity doubles as the ball rolls from Point A to Point C. 8.2 State the principle of conservation of mechanical energy in;words. | T 8.3 Determine the height h of the ramp. TOTAL: 100 Copyright reserved (3) (3) (3) [17] (4) (2) (5) [11]
Downloaded from hlayiso.com Physiewsdeddadraieom Kitanmorapstysics.com November 2023 12 DATA FOR PHYSICAL SCIENCES GRADE 10 PAPER 1 (PHYSICS) TABLE 1: PHYSICAL CONSTANTS NAME SYMBOL VALUE Acceleration dué+to gravity g 9,8 m.s2 Speed of lightifla vacuum Cc 3,0 x 108 m-s* Planck's constant h 6,63 x 10 J-s Charge on electron de -1,6 x 1019C Electron mass Me 9,11 x 10° kg TABLE 2: FORMULAE WAVES, SOUND AND LIGHT 1 v=fa or c=fa T= ig he E=hf E=— a ELECTROSTATICS 1+ Q2 Q=n XG = a 2 ® ELECTRIC CIRCUITS =1xA poe gern’ Rp Ri’ Re Ww R, = Ry +Ro te Vom Q MOTION zg 1.2 Vy = vi + aAt Ax=viAt+ Sat +y. v2 = v2 + 2aax AK= (SS )at WORK, ENERGY AND POWER U=mgh or E,= mgh K= yp, mv? or Ex = Vy, mv2 Copyright reserved
Downloaded from hlayiso.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 10 MARKS: 100 DURATION: 2 hours Copyright reserved
Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 1: ni Cvv (2) nd Byv (2) 13 Dvv (2) 14 BYY . (2) 15 Cv% (2) i [10] QUESTION 21 PA Transverse wave ¥ (1) 2.1.2 v=f xh v =2,5*0,3 v =0,75ms' v (3) 24.3 OPTION 1 OPTION 2 _4_ erent ee T= F565 pee c= time y = 0:825% =04s QS = time =0,4V x1,75v x = 0,7 (s)¥ time = 0,7 (s) ¥ (3) 2.2 distance 2.21 speed = : ¥ time _ 1200 ff ~ 0,8 = 1500 m-s! ¥ (3) 2.2.2 POSITIVE MARKING FROM QUESTION 2.2.1 speed = 1500+ 2x4,5” speed = 1509 m.s* d= distance speed = ime distance v =——_— 1509 1257 Distance = 1886,25 m V a (4) [14] Copyright reserved
Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 3 a 3x 10®mst v¥ 32 3.2.1 c=fxA v. [nat 3 x 108=fx2x107 v. f=1,5x 10 Hz v 3.2.2 » OPTION 1 OPTION 2 E=hxf ¥. ne v a 6,63 x 10734 x 3 x 10° v = 6,63 x 1034x 15x10 v.|~ 9x 40-7 =9,945x1079J v. =9,945x1019J v. 33 Decrease. ¥ The energy of the photon will decrease OR Energy of the photon is inversely proportional to the wavelength. ” A decrease in the energy of the photon decreases the penetrating ability “ QUESTION 4 41 All charges in the universe consist of an integer multiple Y of the charge of one electron ¥ 4.2 Q=nxq,¥% 6x10° =n x 1,610"? v n=3,75x 10%v 4.3 The net charge of an isolated systemY remains constant” (during any physical process). 44 a= Q1+Q2 x 2 Q= - 6x10 + 8x10? v 2 =1x10°Cv Copyright reserved (1) (3) (3) (3) [10] (2) (3) (2) (3) [10]
Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 5 5.1 The work done per unit charge Y by the source (battery) ¥ 5.2 5.2.2 5.2.3 5.2.4 5.3 5.3.1 5.3.2 Copyright reserved Using Ratio liza = % len =%(2)v =1A ltot = 1 + 2¥ =3AV POSITIVE MARKING FROM 5.2.2 Using Ohms Law V=IR 12=1x12v I=1A ltot = 1 + 2¥ =3AV OPTION 1 Vr3=%(12)¥ OR V=IR =6V =3x2v =6V Q=lIAt =3x120vV = 360 C W=VQv =6 x 360 ¥ = 2160 Jv EMF of Battery =12+6+6VvV =24V EMF of ONE CELL = 24+3 ¥ =8VV Remain the same Vv Increase ¥ The total resistance decreases. ¥ OPTION 2 W =I? RAt ¥ =32Vx2Vx120V =2160 Jv (2) (3) (3) (5) (3) (1) (2) [19]
Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 6 6.1 The rate of change of position VW (2) 6.2 ¥ (3) v= Ber Vv v= 2:92m.s* west V 6.3 distance speed = — time distance = v 3,75 120 distance = 450 m 450 = 2XY + 350V Distance from point X to Point Y = 50 m Position of Point Y = 50 m v east ¥ (4) [9] QUESTION 7 TAA OPTION 1 OPTION 2 Av =— ¥ Ve = vi + adtv¥ a At f i = SR v 0 = 25 + a(5)v =-5m.s? a = -5ms2 = 5 ms? west ¥ = 5ms? west ¥ (3) 71.2 Van POSITIVE MARKING FROM Q7.1.2 _ (“Atv AE ( 2 atv OR) ax = viAt + %adt? ¥ _ (0425). ax=(—=)xs = 25(5) + %(-5)(5) ¥ Ax = 62,5 m = 62,5m Car = 1 2 Ax=viAt+ aA OR Ax =viAt AX = 25x 5 + 30x57 v Ax = 25x 5 vt =125m =125m Distance between vehicles = 125 —62,5-5 ¥ =57,5m v (5) Copyright reserved
Downloaded from hlayiso.com Downloaded from Stanmorephysics.com 2A ae Ve Va 4v =f v7 8-0 X=32m-stv Acceleration (m. bh ——— 8 12.‘ Time(s) Marking Criteria 1 Mark — Horizontal line at 4 m.s? from 0 to 8 seconds 1 Mark — Horizontal line at 0 m.s? from 8 to 12 seconds 1 Mark — Shape (2 parallel horizontal lines that are disjointed) QUESTION 8 8.1 Er = mgh + “mv? v =4x98x1V%+%x4x (5.422) Vv =98 Jv 8.2 The total mechanical energy in an isolated system remains constant. Vv 8.3 POSITIVE MARKING FROM 8.1 Point C Er =mgh + “mv? 98 VY =0+%x4xv2v v=7m-s" Point A V=7+2=35msiv Er = mgh + “%mv2 98 =4x98xh+%x4x352V h=1,875 mv Copyright reserved TOTAL: (3) (3) (3) [17] (4) (2) (5) [11] 100

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