Physical Sciences Grade 10 Paper 2 KZN November 2023 Memo

Downloaded from hlayiso.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE ,. /# �-------------- -----------�., PHYSICAL SC II II II II ,1 NO EMBER 2 2 II II II II II � � �-------------------------------------�� /1 �� MARKS: 100 DURATION: 2 hours This question paper consists of 10 pages and 2 data sheets.

Downloaded from hlayiso.com Physiew stasnde (6riao m0) Sfanmorepbgsics.com November 2023 2 INSTRUCTIONS AND INFORMATION 1. This question paper consists of EIGHT questions. Answer ALL the questions in the ANSWER BOOK. — 2. StartEACH question on a NEW page in the ANSWER BOOK. 3. uel e answers correctly according to the numbering system used in this question paper. 4. Leave ONE line between two sub-questions, for example between QUESTION 2.1 and QUESTION 2.2. 5. You may use a non-programmable calculator. 6. You may use appropriate mathematical instruments. 7. You are advised to use the attached DATA SHEETS. 8. Show ALL formulae and substitutions in ALL calculations. 9. Round off your final numerical answers to a minimum of TWO decimal places. 10. Give brief motivations, discussions et cetera where required. 11. Write neatly and legibly. Copyright reserved

Downloaded from hlayiso.com Phypiawstasnde (6rfao m0) SLanmorepbesics.com November 2023 3 QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the answer and write only the letter (A-D) next to the question number (1.1—1.5) in the ANSWER BOOK, for example 1.6 D. 1.1 Whi the following is not a property of a metal? A ny B Ductile and malleable C Thermal conductor D Insulator of electricity (2) 1.2 An investigation is conducted to study the effect of temperature on the conductivity of a substance. The results are represented in the graph below. Which ONE of the following is the substance being investigated? A Copper B Aluminium C__ Silicon D~ Zinc (2) Copyright reserved

Downloaded from hlayiso.com Physiew stasnde (6riao m0) Sfanmorepbgsics.com November 2023 4 1.3 Which one of the following is an example of a chemical change? A __ Separating oil and water mixture using a decanter. QD a /Gendensation of water vapour. Cc Magnesium burning in air. B D___Dissolving sugar in water. (2) 1.4 Consider the balanced chemical equation below: AALS) + 302(g) — 2At20a(s) Which one of the following is the correct number of oxygen atoms required to form 4 moles of aluminium oxide (AtzO3z)? A 6x6,02 x 107 B 12x 6,02 x 1073 C 3x6,02 x 10? D 36x6,02 x 10? (2) 1.5 Consider the unbalanced chemical equation below: NH3 + O2 > NO + H2O Which ONE of the sets of coefficients will balance the equation? A 2,2,2,3 B 2,3,2,3 C 5,4,5,6 D 4,5,4,6 (2) [10] Copyright reserved

Downloaded from hlayiso.com Physiew stasnde (6riao m0) Sfanmorepbgsics.com November 2023 5 QUESTION 2 (Start on a new page.) Four different substances, W, X, Y and Z are represented in the table below. Substance W Substance X KEY CO CO O - Hydrogen CO - Lithium Substance Y Substance Z &Y - Nitrogen NW 2.1 Is Substance X an ELEMENT or a COMPOUND? Give a reason for the answer. (2) 2.2 Write down the LETTER of the substance that represents a mixture. (1) 2.3 Write down the COMMON NAME of Substance Y. (1) 2.4 Draw the Lewis structure of Substance Y. (2) 2.5 Identify the type of chemical bond between atoms in Substance W. (1) 2.6 Hydrogen gas and Nitrogen gas reacts to produce Substance Y. 2.6.1 Write down a BALANCED chemical equation for the reaction that (3) takes place. 2.6.2 Is this a synthesis or decomposition reaction? Give a reason for the answer. (2) 2.6.3 Use the balanced chemical equation from Question 2.6.1 to prove the law of conservation of mass in this reaction. (3) [15] Copyright reserved

Downloaded from hlayiso.com Physiew stasnde (6riao m0) Sfanmorepbgsics.com November 2023 6 QUESTION 3 (Start on a new page.) 3.1 3.1 3.2 3.3 3.4 3.5 3.6 3.7 The cooling curve of ETHANOIC ACID is represented in the graph below. The grap! ot drawn to scale. ira C The Cooling Curve of Ethanoic Acid B Temperature (°C) 10 20 _. . 80 90 95 Time (min) Define the term melting point in words. (2) What is the melting point of ethanoic acid? (1) Are the forces between particles stronger in ETHANOIC ACID or in WATER? (2) Give a reason for the answer. Write down the phase of ethanoic acid at 5 minutes. (1) Write down the name given to the phase change occurring between 10 and 20 minutes. (1) Explain why the change referred to in QUESTION 3.5 is a Physical Change. (2) At which points, A, B or C are the following statements applicable? 3.7.1 The forces between particles are the strongest. (1) 3.7.2 The spaces between the particles are the largest (1) 3.7.3 The kinetic energies of the particles remain constant. (1) [12] Copyright reserved

Downloaded from hlayiso.com Physiew stasnde (6riao m0) Sfanmorepbgsics.com 7 QUESTION 4 (Start on a new page.) November 2023 Some information for the substances IRON and the SULPHIDE ION are given in the table below. Number of | Number of | Number of Name 10 protons electrons neutrons IRON | Fe 4.1.1 26 4.1.2 SULPHIDE ION 4.1.3 16 4.1.4 16 4.1 Complete the table by providing the answers to questions 4.1.1 to 4.1.4. Do not redraw the table. Write the numbers (4.1.1— 4.1.4) down and the correct answer next to it. (4) 4.2 Draw the aufbau diagram and write down the electronic configuration (sp-notation) for the sulphide ion. (3) 4.3 How many valence electrons does the sulphide ion have? (1) 4.4 Iron (Fe) has three common isotopes as indicated below Isotope Percentage Abundance Fe - 54 5,8 % Fe - 56 91,7% Fe - 57 REMAINDER 4.4.1 Define the term isotope in words. (2) 4.4.2 Determine the relative atomic mass of Iron (Fe). (3) [13] Copyright reserved

Downloaded from hlayiso.com Physiew stasnde (6riao m0) Sfanmorepbgsics.com November 2023 8 QUESTION 5 (Start on a new page.) 5.1 The table below shows the first and second ionisation energies of elements in PERIOD 2 of the periodic table. <4cFIRST IONISATION ENERGY | SECOND IONISATION ENERGY ‘2lti.3.mol) (kJ.mo!*) Li }~520 7 297 Be 899 1757 B 801 2 427 Cc 1086 2 352 N 1 402 2 854 fe) 1214 3391 F 1681 3381 Ne 2 080 3 964 5.1.1 Explain why there is a general increase in the first ionisation energy on going from left to right across the period. (2) 5.1.2 It is observed that the second ionisation energy of Li (Lithium) is considerably higher than Be (Beryllium). Explain this observation. (2) 5.1.3 Write down the NAME of the group whose elements have the highest first ionisation energy in the period. (1) 5.2 Write down the CHEMICAL FORMULA for: 5.2.1 Sodium oxide (1) 5.2.2 Calcium phosphate (1) 5.2.3 Copper (Il) carbonate (1) 5.3 Write down the CHEMICAL NAME for: 5.3.1 MgBrz2 (1) 5.3.2 (NHa4)2SO4 (1) [10] Copyright reserved

Downloaded from hlayiso.com Physiew stasnde (6riao m0) Sfanmorepbgsics.com November 2023 9 QUESTION 6 (Start on a new page) Sulphur dioxide (SOz) reacts with oxygen (Oz) to form sulphur trioxide (SO3), as shown in the balance: uation below. 2SO02(g) + O2(g) > 2SO0s(g) In one such reaction 2450 cm? sulphur trioxide (SOs), is formed at STP. 6.1 State Avogadro’s law in words. (2) 6.2 Calculate the: 6.2.1 Number of moles of SO3 that formed. (4) 6.2.2 Mass of SOz that reacted. (4) 6.2.3 Number of oxygen (Oz) molecules that reacted (4) [14] QUESTION 7 (Start on a new page) rok The analysis of a compound made up of the elements sodium (Na), sulphur (S) and oxygen (O) provides the following percentage composition, by mass. = Element ercente osition Sodium (Na) lang Sulphur (S) 4 Oxygen (O) 30. 7.1.1 Define the term empirical formula in words. (2) 7.1.2 Determine the empirical formula of this compound (5) 7.2 Determine the percentage composition of water (H2O) in hydrated copper sulphate (CuSO4*5H20). (4) [11] Copyright reserved

Downloaded from hlayiso.com Phyiewstisnde (6rfao m0) SLanmorepsbeEsics.com November 2023 10 QUESTION 8 (Start on a new page) Calcium carbonate (CaCOs) reacts completely with excess phosphoric acid (HsPOs) of concentration mol-dm*. The reaction is! presented by the following balanced equation: 3CaCOx(s) + 2HsPO«(aq) — Cas(POa)2(aq) + 3CO2(g) + 3H20(2) The graph below (not drawn to scale), shows the mass of the calcium carbonate (CaCOs) as the reaction progresses 0123 4 Time (min) 8.1 Determine the number of moles of Cas(PO4)z2 FORMED AFTER 1 MINUTE. (5) The reaction is thereafter allowed to reach completion. 8.2 Determine the number of moles of calcium carbonate (CaCOs) used. (2) 8.3 Calculate the volume of phosphoric acid that reacts with the calcium carbonate after 4 MINUTES. (4) 8.4 Calculate the percentage yield of carbon dioxide (COz), if 4 dm? of COz2 was formed at STP. (4) [15] TOTAL: 100 Copyright reserved

Downloaded from hlayiso.com Physiew stasnde (6riao m0) Sfanmorepbgsics.com November 2023 11 DATA FOR PHYSICAL SCIENCES GRADE 10 CHEMISTRY TABLE 1: PHYSICAL CONSTANTS NAME SYMBOL VALUE Standard pressure p° 1,013 x 10° Pa Molar gas volume at STP Vin 22,4 dm*-mol? Standard temperature T° 273K Avogadro's constant Na 6,02 x 107 mol TABLE 2: FORMULAE n=™ n= M Na n m Vv c=— or c=— n=—— Vv MV Vin Copyright reserved

Downloaded from hlayiso.com Physicebeuenaadedefiopm Stanmorephysics.com NSC June 2023 12 TABLE 3: THE PERIODIC TABLE OF ELEMENTS 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 ()) (I) . ay (iv) (VY) (VI) s(t) Ss () Atomic number 4 1 KEY/SLEUTEL Atoomgetal 2 ; H He N 1 29 4 3 4 Electronegativity || o, Cu ¢_Symbol 5 6 7 8 9 10 3 Li |/% Be Elektronegatiwiteit “| 4 63,5 | Simbool = Bt Nie ¢ Ne 7 9 , 11 12 14 16 19 20 11 12 f 13/ 14/ 15| 16/ 17| 18 o Na|S Mg Approximate relative atomic mass 2 Al\2 Si ls P IS &Ce! Ar 23 24 Benaderde relatiewe atoommassa 27 28 31 32 35,5 40 19 20 21 22 23 24] 25| 26 27] 28 29 30 31 32 33 34 35 36 e K |3 Cal Se |S Ti |S & Cr |3Mn|& Fe |3 Co/S Ni |G Cu/S Zn |S Ga|S Ge |S As |S Se |S Br| Kr 39 40 45 48 51 52| 55| 56 59 59 | 63,5| 65 70 73 75 79 80 84 37 38 39 40 41 42| 43] 44/ 45| 46| 47 48 49 50 51 52 53 54 6 Rb|S Sr |S Y |S Zr| Nb|SMo|3 Tc|s Ru|s Rh|a Pd /3 Ag |S Cd/5 In (8 Sn/3Sb\5 Te\G | | Xe 86 88 89 91 92 96 101| 103| 106/ 108| 112| 115/ 119| 122) 128| 127| 131 55 56 57 72 73 74 | 75| 76 77 78 79 80 81 82 83 84 85 86 5 Cs|2 Ba} La|S$ Hf) Ta| W]| Re| Os| Ir| Pt| Au| Hg/% Te |2Pb/% Bi /3Po/s At| Rn 133| 137| 139| 179| 181| 184| 186/] 190| 192| 195; 197| 201| 204| 207| 209 87 88 89 cS Fr |G Ra| Ac S © 396 58 59 | 60 | 61 62 63 64 65 66 67 68 69 70 71 Ce | Pr | Nd | Pm| Sm/| Eu | Gd | Tb | Dy | Ho | Er | Tm! Yb | Lu 140 | 141 | 144 150 | 152 | 157 | 159 | 163 | 165 | 167 | 169 | 173 | 175 90 91 | 92 | 93 94 | 95 96 97 98 99 | 100 | 101 | 102 | 103 Th | Pa} U | Np/| Pu | Am/|Cm| Bk | Cf | Es | Fm | Md | No | Lr 232 238 Copyright reserved

Downloaded from hlayiso.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE MARKS: 100 DURATION: 2 hours Copyright reserved

Downloaded from hlayiso.com queemoteaded from Stanmorephysics.com det Dvv 12 Cvv 1.3 Cvv 1.4 Byv 1.5 Dvv QUESTION 2.1 Element. ¥ It consists of one type of atom only. ~ 2.2 (Substance) Z ¥ 2.3 Ammonia ¥ 2.4 vv 2.5 lonic bond ¥ 2.6 2.6.1 N2 + 3H2 > 2NH3 LHS v 2.6.2 2.6.3 Copyright reserved RHS v¥ Balancing ¥ Synthesis. ¥ Smaller elements are combining to form a larger compound ¥ POSITIVE MARKING FROM 2.6.1 Mass of reactants = 14x2+ 3 (1x2) v = 34 g.mol? Mass of products = 2(14 + 1x3) v = 34 g.mol? Mass of reactants is equal to the mass of products. Therefore mass is conserved. ¥ (2) (2) (2) (2) (2) [10] (2) (1) (1) (2) (1) (3) (2) (3) [15]

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 3 3.1 The temperature at which a solid, given sufficient heat, becomes a liquid. VV 3.2 16°C” 3.3 Etha It ha: gher boiling point/melting point than water. ¥ 3.4 Gas 3.5 Condensation ¥ 3.6 No new substance is formed / No chemical bonds are broken. Vv 3.7 3.7.1 Cv 3.7.2 Av 3.7.3 BY QUESTION 4 4.1 4.2.1 26 ¥ 4.2.2 30 ¥ 4.2.3 stv 4.2.4 18 v 4.2 as |ty sp-notation: 1s?2s?2p°3s73p° v 4.3 8v Copyright reserved (2) (1) (2) (1) (1) (2) (1) (1) (1) [12] (1) (1) (1) (1) (3) (1)

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com 4.4 441 4.4.2 QUESTION 5 5.1 5.1.1 5.1.2 5.1.3 5.2 5.2.1 5.2.2 5.2.3 5.3 5.3.1 5.2.2 Copyright reserved Atoms of the same element having the same number of protons but different numbers of neutrons. VW % Fe-57 = 100-5,8-91,7=2,5% Vv . : 7 5,8 91,7 2a Relative atomic mass = 54x 700 + 56x 700 + 57x 700 V = 55,91 AMU ¥ As you move from left to right across a period the effective nuclear charge increase ¥ The force of attraction between the nucleus and the electrons in the outer orbital increases. ¥ Losing a second electron will result in an unstable electron state in Li Y, whilst losing a second electron results in a stable electron state in Bev The second electron in Li fi close to the nucleus, compar attraction between the nucleus an Li. Hence more energy is needed- Li compared to Be V the energy level very herefore the force of iter electron is stronger in ve the second electron in Noble gas ¥ NazO ¥ Cas(POa)2 ¥ CuCOs ¥ Magnesium bromide ¥ Ammonium sulphate ¥ (2) (3) [13] (2) (2) (1) (1) (1) (1) (1) (1) [10]

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 6 6.1 One mole of a gas occupies the same volume at the same temperature and pressure. V¥ 6.2 6.2.1 Vv v n(SOs) = 7 m 2,45 n(S0s)= 554” n (SOs) = 0,11 mol ¥ 6.2.2 POSITIVE MARKING FROM 6.2.1 SO2 : SOs 2 :2v n(SOz) = 0,11 mol m v n(SO2) = 7 =. v 0,11 = 64 m (SO2) = 7,04 g ¥ 6.2.3 POSITIVE MARKING FROM 6.2.1 O2: SOs +2" - v ao 6,02 x 1023 N(Oz) = 3,31 x 10? O2 molecules ¥ Copyright reserved (2) (3) (4) (4) [13]

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 7 Tal TAL The simplest whole number ratio of elements in a compound. v¥ ¥ 4.2 Consider 100g mass m . . Ele! n=— Simplest Ratio ment) (g) M Na 2o11 | 29-11 _ 127. v 23 v 40,51 (Obtaining ie v 7 40,51 32. 1,27 all simplest ratios) fe) 30,38 a -19 Empirical Formula: NazS2O3 ¥ 7.2 M(CuSO«.5H20). = 63,5 + 32 + 4x16 + 5(2+16) ¥ = 249,5 g.mol? . s x18 wv % H2O 49,5 x100 = 36,07 %V¥ QUESTION 8 8.1 m(CaCOs) = 25-10 ¥ =15g n(CaCO3) = 7 v _ 15 VS. ~ 100 = 0,15 mol CaCOs : Cas(POa)2 3 oe -T v n [Caa(POx)2] = 0.05 mol ¥ 8.2 _m n(CaCQ3) = M _ 25 4 ~ 400 = 0,25 mol ¥ Copyright reserved (2) (5) (4) [11] (5) (2)

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com 8.3 POSITIVE MARKING FROM 8.2 CaCOs : H3PO4 | 1 2v n(HsPOa) = 0,17 mol (4) 8.4 POSITIVE MARKING FROM 8.2 CaCOs : CO2 3.:3v n(COz) = 0,25 mol Vv n(COz) = va m v 0,25 = 224 V (COz) = 5,6 dm? actual yield theoretical yield nad % yield= 4v % yield= = x100 ¥ % yield = 71,43% Vv (5) [16] TOTAL: 100 Copyright reserved