GRADE 11
MATHEMATICS P1 MEMORANDUM
JUNE 2017
MARKS: 100
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Mathematics Grade 11 Paper 1 North West June 2017 Memo
Grade 11 Mathematics Paper 1 memorandum from the North West June 2017, 9 pages. Read online or get the free PDF download, question paper linked when available.
Mathematics · Grade 11 · North West June · 2017. Memorandum, 9 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 11
- Document type
- Memorandum
- Year
- 2017
- Exam period
- North West June
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 9
- File size
- 693.5 KB
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1 of 9
This exam
North West June 2017
- Paper 1Question paperMemo
- Paper 2Question paperMemo
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Mathetics/P1 2 June/2017
NSC
QUESTION 1
1.1.1
2x2 – 7x = 0 factors
x(2x – 7) = 0 x = 0
x = 0 or x =
x = (3)
1.1.2. 2x (x – 3) = 1
2x2 – 6x – 1 = 0 2x2 – 6x – 1 = 0
formula
sub. into correct formula
answer (4)
x = 3,16 or x = – 0,16
1.1.3
squaring
Square both sides, 1+ x = x2 – 10x + 25 standard form
x2 – 11 x + 24 = 0
factors
(x – 8 )( x – 3 ) = 0
answer
x = 8 or x = 3 N/A
(5)
1.1.4
x2 + 3x = k
Let x2 + 3x = k
std form in k
factors
k2 – 26k – 56 = 0
vales of k
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Mathetics/P1 3 June/2017
NSC
( k – 28 )(k + 2 ) = 0
2 eqs. in x
k = 28 or k = – 2
4 values of x (7)
x2 + 3x = 28 or x2 + 3x = – 2
x2 + 3x– 28 = 0 or x2 + 3x + 2 = 0
(x +7) (x – 3) = 0 or (x + 2)(x + 1) = 0
x = –7 or x =3 or x = – 2 or x = – 1
( x – 3)( 2 – x) > 0
1.1.5 ( x + 3)( 2 – x) > 0 end values
( x + 3)( x – 2) < 0 - notation (3)
-3 2
– 3 < x < 2
1.1.6
factors
x = 16 (4)
N/A
x = 16
1.2 x2 – 2xy – 3y2 and 3x + y – 2 = 0
y = 2 – 3x
y = 2 – 3x
x2 – 2x(2 – 3x) – 3(2 – 3x )2 = 0 sub. of y
x2 – 4x + 6x2 – 3(4 – 12x + 9x2 ) = 0
x2 – 4x + 6x2 – 12+ 36x – 27x2 ) = 0
–20 x2 + 32x –12 = 0 std form
5 x2 – 8x + 3 = 0
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Mathetics/P1 4 June/2017
NSC
(5x – 3) (x – 1) = 0 factors
or x = 1
x = 1
or y = 2 – 3 (1)
y values (7)
y = y = –1
1.3.1
sub of k in
When k = 5,
= 0
Roots are real and equal
equal and real (2)
1.3.2 For non-real roots,
25 – 5k < 0
k>5 k>5 (2)
QUESTION 2
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Mathetics/P1 5 June/2017
NSC
2.1.1
= taking common factor
outside
=
ans (2)
= 3
2.1.2
=
= 6x – 2x
= 4x ans (2)
2.1.3
Convert base into prime
= numbers
removing the bracket
=
apply the law
=
=
answer (4)
=
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Mathetics/P1 6 June/2017
NSC
2.2.1
taking common factor
outside
answer (3)
2.2.2
x = –1 answer (3)
QUESTION 3
3.1
2 6 12 20
4 6 8
2 2
T5 = 30 T5 = 30
T6 = 42 T6 = 42 (2)
3.2 2a = 2 ; 3a + b = 4; a+b+c = 2 3a + b = 4;
a= 1 3(1) + b = 4 1 +1 + c = 2 a+b+c = 2
b =1 c =0 value of a
Value of b
Tn = n2 + n value of c (5)
QUESTION 4
4.1.1 i m
(
i eff = 1 +
m )
-1 formula
correct sub. into formula
=
= 0.087747961...
answer (3)
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Mathetics/P1 7 June/2017
NSC
Rate = 8,77%
4.1.2
formula
sub. into the formula
= R 18273,54 answer (3)
4.2
formula
= 150000(1- 0,124)5
sub. into the formula
= R77376,98
answer (3)
4.3
i
equation
x(3,52612449) = 20000
x(3,52612449) = 20000
answer (4)
x = R5671,95
QUESTION 5
5.1
x = -2 or x = 6
OA = 2
OA = 2 and OB = 6 OB = 6 (2)
5.2
= -24 x =0
y = -24 (2)
C(0; -24)
5.3
Axis of symmetry is x = 1
x=1
= -30
TP(1 ; -30)
TP(1 ; -30)
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Mathetics/P1 8 June/2017
NSC
Range is y ans (3)
5.4 Notation
end values (2)
5.5 c = - 24
c = -24
Passing through (6 ;0) sub. of (6;0)
m= 4
m= 4 (3)
5.6 T.P of h(x) is ( 1 ; 30) x value
y value (2)
QUESTION 6
6.1.1 Asymptotes are x = 3 and y = - 2 x = 3
y = -2
6.1.2
making y = 0
x –intercepts:
2(x -3) = 2 x =4
2x = 8
x = 4 making x = 0
y-intercepts y =
(4)
=
6.1.3 x-int
y-int
shape
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Mathetics/P1 9 June/2017
NSC
6.1.4
Domain is answer (1)
6.1.5 y = (x – 3) – 2
m= 1
= x – 5 c = -5 (2)
6.2
q = –1 value of q
Passing through (0; -2)
Sub. of (0;-2)
a = -1
value of a
sub. of
-3 = b-1
b = value of b
(5)
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