Mathematical Literacy Grade 12 P2 2026 Memo (Eng)

hlayiso mock exams Practice Series: Grade 12 NSC Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P2 MOCK EXAMINATION 2026 MARKING GUIDELINES MARKS: 150 These marking guidelines consist of 7 pages. Copyright reserved Please turn over

Mathematical Literacy/P2 2 Hlayiso/Mock 2026 NSC – Marking Guidelines SYMBOL AND EXPLANATION Symbol Explanation Symbol Explanation M Method A Accuracy MA Method with accuracy CA Consistent accuracy C Conversion D Definition F Choosing the correct formula SF Substitution in a formula J Justification O Opinion/Reason/Example P Penalty (e.g. no units, incorrect rounding) R Rounding RT/RG/RM Reading from a table/graph/map S Simplification NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines. • For verification questions, the final conclusion (J) is only awarded if supported by calculations. • Measurements from maps/plans: accept a tolerance of ±2 mm. QUESTION 1 1.1.1 P = R2 400 + R18,50 ×100 = R4 250 ✓M method Q = R2 400 + R18,50 ×200 = R6 100 ✓A P ✓A Q (3) 1.1.2 Income ✓A starts at (0 ; 0) 8000 ✓A point e.g. (100 ; 3 500) Cost ✓A straight line to (250 ; 8 750) ✓ label (4) 4000 0 0 100 200 1.1.3 Break-even point ≈ 145 kotas and R5 100 ✓RG number of kotas (Accept 140 – 150 kotas; R5 000 – R5 200) ✓RG amount At the break-even point income equals total cost: ✓✓O explanation (4) Sipho makes neither a profit nor a loss. Copyright reserved Please turn over

Mathematical Literacy/P2 3 Hlayiso/Mock 2026 NSC – Marking Guidelines 1.1.4 Kotas sold = 6 × 22 = 132 ✓M 132 kotas Income = 132× R35 = R4 620 ✓A income Cost = R2 400 + R18,50 ×132 = R4 842 ✓A cost Profit = R4 620 − R4 842 = −R222 (a loss of R222) ✓CA loss The statement is NOT VALID. ✓J conclusion (5) 1.1.5 New cost per kota = R18,50 ×1,12 = R20,72 ✓M 12% increase Contribution per kota = R35 − R20,72 = R14,28 ✓M difference Break-even = R2 400 ÷ R14,28 = 168,07 ✓M dividing ≈ 169 kotas ✓R rounding up (4) 1.2.1 Block 1: 350× R2,45 = R857,50 ✓A block 1 Block 2: 150× R3,10 = R465,00 ✓A block 2 Block 3: (620 − 500)× R3,65 = 120× R3,65 = ✓M 120 kWh R438,00 ✓A block 3 Total = R1 760,50 ✓CA total (5) 1.2.2 New use = 620 × 0,8 = 496 kWh ✓M 496 kWh Cost = R857,50 +(496 − 350)× R3,10 ✓M block 2 units = R857,50 + R452,60 = R1 310,10 ✓A new cost Saving = R1 760,50 − R1 310,10 = R450,40 ✓M difference % decrease = 450,40 × 100% = 25,58% ✓A percentage 1 760,50 ✓J conclusion (6) 25,58% > 25%, so the claim is VALID. 1.2.3 R2,45 ×1,127 = R2,76 per kWh ✓M increase ✓A answer (2) [33] QUESTION 2 2.1.1 Radius = 1,55 m ÷ 2 = 0,775 m ✓M dividing by 2 ✓A answer (2) 2.1.2 Volume = 3,142 × (0,775)2 × 2,18 ✓SF radius = 4,114 m3 ✓SF height Capacity = 4,114 × 1 000 = 4 114 ℓ ✓A volume ✓C ×1 000 ✓CA litres (5) Copyright reserved Please turn over

Mathematical Literacy/P2 4 Hlayiso/Mock 2026 NSC – Marking Guidelines 2.1.3 Roof area = 9 × 7 = 63 m2 ✓M roof area Rainfall = 25 ÷ 1 000 = 0,025 m ✓C 0,025 m Volume = 63 × 0,025 = 1,575 m3 ✓A 1,575 m3 Water reaching tank = 85% × 1,575 = 1,33875 m3 ✓M 85% = 1 338,75 ℓ ✓CA litres (5) 2.1.4 Days = 4 114 ÷ 180 = 22,86 ✓M dividing = 22 full days ✓A 22,86 ✓R rounding down (3) 2.1.5 Three events = 3 × 1 338,75 = 4 016,25 ℓ ✓M ×3 4 016,25 ℓ < 4 114 ℓ ✓A 4 016,25 ℓ The tank will NOT be full. The statement is NOT ✓M comparing VALID. ✓J conclusion (4) 2.2.1 Wall area = 2(8 × 3) + 2(7 × 3) = 48 + 42 = 90 m2 ✓M wall method Doors = 2 × 0,9 × 2,1 = 3,78 m2 ✓A 90 m2 Windows = 4 × 1,5 × 1,2 = 7,2 m2 ✓A doors Area to paint = 90 − 3,78 − 7,2 ✓A windows = 79,02 m2 ✓M subtracting ✓ answer shown (6) 2.2.2 Two coats = 2 × 79,02 = 158,04 m2 ✓M ×2 Paint = 158,04 ÷ 8 = 19,76 ℓ ✓M dividing by 8 Tins = 19,76 ÷ 5 = 3,95 ✓A 19,76 ℓ ≈ 4 tins ✓M dividing by 5 ✓R 4 tins (5) 2.2.3 Paint = 4× R649,99 = R2 599,96 ✓CA paint cost Hours = 158,04 ÷ 12 = 13,17 ≈ 14 hours ✓M hours Labour = 14× R180 = R2 520 ✓R 14 hours Total = R2 599,96 + R2 520 = R5 119,96 ✓A labour R5 119,96 > R5 000, so the budget is NOT sufficient. ✓J conclusion with total (5) [35] Copyright reserved Please turn over

Mathematical Literacy/P2 5 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 3 3.1.1 F2 ✓✓RM (2) 3.1.2 North-east ✓✓A (2) 3.1.3 From the taxi rank, travel east along Main Road. ✓✓RM Main Road east Turn left (north) into Mandela Drive. ✓RM left into Mandela The clinic is on the right-hand side. Drive ✓RM clinic on the right (4) 3.1.4 Bar scale: 20 mm represents 500 m ✓M measuring bar scale Distance = 63 × 500 m = 1 575 m ✓M using scale 20 ✓A 1 575 m = 1,58 km ✓C km (4) 3.1.5 20 mm : 500 m ✓C converting to mm = 20 mm : 500 000 mm ✓M dividing by 20 = 1 : 25 000 ✓A answer (3) 1,8 km 3.2 Time = = 0,4 hours ✓SF substitution 4,5 km/h = 0,4 × 60 = 24 minutes ✓A 0,4 h ✓C minutes (3) 3.3.1 22 tables ✓✓A (2) 3.3.2 Seats = 22 × 8 = 176 ✓M seats People = 172 + 10 = 182 ✓A 182 people 176 < 182: there are NOT enough seats (6 short). ✓J conclusion (3) 3.3.3 Actual side = 30 mm × 200 = 6 000 mm = 6 m ✓M using scale Area = 6 × 6 = 36 m2 ✓C 6 m Dancers = 36 ÷ 0,5 = 72 people ✓A 36 m2 ✓CA 72 people (4) 3.3.4 Floor area = 24 × 15 = 360 m2 ✓A area Maximum = 360 ÷ 1,2 = 300 people ✓M dividing ✓A answer (3) [30] Copyright reserved Please turn over

Mathematical Literacy/P2 6 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 4 4.1.1 Total ✓M adding = 72,5 + 78,1 + 80,4 + 84,0 + 86,2 + 88,9 = 490,1 ✓M dividing by 6 Mean = 490,1 ÷ 6 = 81,68% ✓A answer (3) 88,9 − 72,5 4.1.2 % increase = × 100% ✓M difference 72,5 = 22,62% ✓M dividing by 72,5 ✓A answer (3) 4.1.3 Range P = 88,9 − 72,5 = 16,4 ✓A range P Range Q = 87,0 − 79,6 = 7,4 ✓A range Q School Q has the smaller range, so its results were ✓M comparing more consistent. The claim is VALID. ✓J conclusion (4) 4.1.4 School P: pass rate increased every year (steady ✓✓O trend P upward trend). ✓O trend Q School Q: pass rate fluctuated but generally increased. ✓O school P School P is likely to have the higher pass rate in 2026, ✓O reason (5) because it improved faster and was already higher in 2025. 4.2.1 Minimum = 34 ✓A Q1 = 48 ✓A Median = 60 ✓A Q3 = 71 ✓A Maximum = 90 ✓A (5) 4.2.2 ✓A box from 48 to 71 ✓A median at 60 30 40 50 60 70 80 90 ✓A whisker to 34 ✓A whisker to 90 (4) 4.2.3 Learners with 50% or more: 11 ✓RT 11 learners 11 ✓M percentage × 100% = 73,33% 15 ✓A 73,33% 73,33% > 70%, so the claim is VALID. ✓J conclusion (4) 4.3 The vertical axis starts at 70% instead of 0%, which ✓✓O explanation (2) makes the increase in the pass rate look much bigger than it is. Copyright reserved Please turn over

Mathematical Literacy/P2 7 Hlayiso/Mock 2026 NSC – Marking Guidelines [30] QUESTION 5 5.1.1 Cash price = R12 999 ×0,95 = R12 349,05 ✓M 5% discount ✓A answer (2) 5.1.2 Deposit = 10%× R12 999 = R1 299,90 ✓A deposit Instalments = 24× R620 = R14 880 ✓A instalments Total = R16 179,90 ✓CA total (3) 5.1.3 A = 12 999(1 + 0,18 × 2) ✓SF substitution = 12 999 × 1,36 ✓M simplifying = R17 678,64 ✓A answer (3) 5.1.4 Difference = R16 179,90 − R12 349,05 = R3 830,85 ✓M difference 3 830,85 ✓M percentage of cash price % more = × 100% = 31,02% 12 349,05 ✓A 31,02% 31,02% > 30%, so the statement is VALID. ✓J conclusion (4) 5.2 Investment: A = 11 000(1 + 0,085)3 = R14 050,18 ✓SF substitution Laptop price: A = 12 349,05(1 + 0,045)3 = R14 092,32 ✓A R14 050,18 R14 050,18 < R14 092,32 (short by R42,14) ✓SF substitution The statement is NOT VALID. ✓A R14 092,32 ✓M comparing ✓J conclusion (6) 5.3.1 3% × 2 400 = 72 laptops ✓M✓A (2) 1 5.3.2 = 33,33 ✓M dividing 0,03 1 in 33 ✓A answer (2) [22] TOTAL: 150 Copyright reserved