Mathematical Literacy Grade 12 P2 2026 Memo (Eng)

hlayiso mock exams Practice Series: Grade 12 NSC Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P2 PREDICTION EXAMINATION 2026 MARKING GUIDELINES MARKS: 150 These marking guidelines consist of 10 pages. Copyright reserved Please turn over

Mathematical Literacy/P2 2 Hlayiso/Prediction 2026 NSC – Marking Guidelines SYMBOL AND EXPLANATION Symbol Explanation Symbol Explanation M Method A Accuracy MA Method with accuracy CA Consistent accuracy MCA Method with consistent accuracy C Conversion D Definition SF Substitution in a formula J Justification O Opinion/Reason/Conclusion P Penalty (units, rounding) R Rounding RT/RG/RM Reading from a table/graph/map S Simplification M/MP/P Topic (Measurement/Maps/Prob.) L1–L4 Taxonomy level NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines. Stop marking at the second calculation error. • Answers only, without working, are awarded full marks unless the question requires calculations to be shown (e.g. “Verify, showing ALL calculations”). • For verification questions, the final conclusion (J/O) is only awarded if it is supported by calculations. • Measurements from the map and plan: accept a tolerance of ±2 mm (answer book printed at 100% on A4). If the candidate’s measurements differ because of printing, mark CA from the candidate’s measured values. • The topic and taxonomy level of each item is shown at the bottom of the explanation column. QUESTION 1 [28 MARKS] 1.1.1 B ✓✓A correct letter M/L1 (2) 1.1.2 J ✓✓A correct letter MP/L1 (2) 1.1.3 H ✓✓A correct letter M/L1 (2) 1.1.4 D ✓✓A correct letter P/L1 (2) Copyright reserved Please turn over

Mathematical Literacy/P2 3 Hlayiso/Prediction 2026 NSC – Marking Guidelines 1.1.5 F ✓✓A correct letter M/L1 (2) 1.2.1 100 mℓ ÷ 1 000 ✓C dividing by 1 000 = 0,1 ℓ ✓A answer in litres M/L1 (2) 1.2.2 4 years old: dose = 7,5 mℓ ✓RT correct dose Maximum = 4 × 7,5 mℓ ✓A maximum volume = 30 mℓ M/L1 (2) 1.2.3 06:45 + 4 hours = 10:45 ✓M adding 4 hours = 10:45 a.m. ✓A 12-hour format with a.m. (Accept 10:45 in the morning; 1 mark if not in 12-hour M/L1 (2) format) 1.2.4 March 2027 ✓RT month ✓RT year M/L1 (2) 1.2.5 ◦ F = (1,8 × 25) + 32 ✓SF substitution of 25 = 77 ◦ F ✓A answer M/L1 (2) 1.3.1 3 + 1 + 1 + 1 + 6 + 12 + 6 ✓MA adding ALL quantities = 30 pieces ✓A answer MP/L1 (2) 1.3.2 2 washers ✓✓A answer (one on each side of the leg) MP/L1 (2) 1.3.3 D ✓RD letter Ash tray ✓RD name MP/L1 (2) 1.3.4 A ✓✓A correct letter M/L1 (2) [28] Copyright reserved Please turn over

Mathematical Literacy/P2 4 Hlayiso/Prediction 2026 NSC – Marking Guidelines QUESTION 2 [32 MARKS] 2.1.1 R528 ✓✓RM correct road MP/L1 (2) 2.1.2 East ✓✓A direction (Accept east-north-east) MP/L1 (2) 2.1.3 Ebenezer Dam ✓✓RM correct dam MP/L1 (2) 2.1.4 Towns on the map: Polokwane, Mankweng, ✓RM 4 towns Haenertsburg, Tzaneen, Modjadjiskloof = 5 ✓RM 5 towns Towns on the R71: Polokwane, Mankweng, ✓A percentage Haenertsburg, Tzaneen = 4 P/L2 (3) 4 P(town on R71) = × 100% 5 = 80% (If Polokwane and Tzaneen are excluded as end points: 2 5 = 40%, max. 1 mark for the 5-town denominator) 2.1.5 From the airport, travel south on the N1 to Polokwane. ✓RM N1 south Turn left onto the R71 and travel east through ✓RM R71 east Mankweng and Haenertsburg. ✓RM through the pass/past Continue on the R71 (north-east) through the Haenertsburg Magoebaskloof Pass. ✓RM left onto the gravel Turn left (north) onto the gravel road to the Debengeni road Falls. MP/L2 (4) 2.1.6 Measured distance on map ≈ 12,8 cm ✓A measuring map distance (Accept 12,6 cm – 13,0 cm) ✓A measuring bar scale Bar scale: 1,8 cm represents 10 km ✓M dividing Distance = 12,8 × 10 km ✓M multiplying by 10 1,8 ✓CA answer in km = 71,11 km MP/L3 (5) (Accept 70 km – 72,2 km) Copyright reserved Please turn over

Mathematical Literacy/P2 5 Hlayiso/Prediction 2026 NSC – Marking Guidelines 2.1.7 Difference = 98 − 71,11 = 26,89 km ✓M difference % longer = 26,89 × 100% ✓M percentage concept 71,11 ✓CA percentage = 37,8% ✓O conclusion 37,8% > 30%, so his statement is VALID. MP/L4 (4) OR 130% × 71,11 km = 92,44 km; 98 km > 92,44 km ∴ VALID (CA from 2.1.6) 2.2.1 1 450 m ✓✓RG reading (Accept 1 440 m – 1 460 m) MP/L1 (2) 2.2.2 1 380 − 700 ✓RG both values = 680 m ✓A difference (Accept start 1 370 m – 1 390 m; answer 670 m – 690 MP/L2 (2) m; CA from readings) 2.2.3 Time = 09:10 − 07:40 = 1 h 30 min = 1,5 h ✓A 1 h 30 min Speed = distance 34 km = ✓C 1,5 h time 1,5 h ✓M dividing distance by = 22,67 km/h time ✓CA speed MP/L3 (4) 2.2.4 Any ONE, e.g. ✓✓O valid reason • The cyclists have just finished the long uphill climb MP/L4 (2) and will be tired and thirsty. • It is before the long, fast descent where cyclists cannot easily stop to drink. • It is the highest and most strenuous point of the race. [32] Copyright reserved Please turn over

Mathematical Literacy/P2 6 Hlayiso/Prediction 2026 NSC – Marking Guidelines QUESTION 3 [32 MARKS] 3.1.1 2 (the front door and the back door) ✓✓A answer MP/L1 (2) 3.1.2 North ✓✓A direction (the front door opens onto the stoep) MP/L1 (2) 3.1.3 Measured length = 14 cm (Accept 13,8 cm – 14,2 cm) ✓A measurement 10,5 m = 1 050 cm ✓C converting to cm Scale = 14 : 1 050 ✓M ratio in the same units = 1 : 75 ✓CA scale in the form 1 : … (Accept 1 : 74 – 1 : 76; CA from measurement) MP/L3 (4) 3.1.4 In South Africa (southern hemisphere) the sun is in the ✓✓O valid reason northern sky, so the north-facing living room receives MP/L4 (2) the most sunlight: it is warmer in winter and has more natural light during the day. (Accept: saves electricity for heating/lighting) 3.2.1 Living room = 6 × 4,8 = 28,8 m2 ✓SF living room dimensions Kitchen = 3,6 × 2,4 = 8,64 m2 ✓A 28,8 m2 Total = 28,8 + 8,64 ✓A 8,64 m2 = 37,44 m2 ✓M adding (Answer given: no mark for 37,44 only) MP/L2 (4) 3.2.2 Area of one tile = 0,6 × 0,6 = 0,36 m2 ✓C 0,6 m Tiles = 37,44 ÷ 0,36 = 104 ✓A 104 tiles With 10% extra: 104 × 1,1 = 114,4 ≈ 115 tiles ✓M 10% extra Boxes = 115 ÷ 4 = 28,75 ✓M dividing by 4 ≈ 29 boxes ✓R rounding up to 29 OR M/L3 (5) Living room: 10 × 8 = 80 tiles; kitchen: 6 × 4 = 24 tiles; total 104 tiles … Copyright reserved Please turn over

Mathematical Literacy/P2 7 Hlayiso/Prediction 2026 NSC – Marking Guidelines 3.2.3 Tiles = 29× R289,90 = R8 407,10 ✓CA cost of tiles Adhesive: 37,44 ÷ 5 = 7,488 ≈ 8 bags ✓R 8 bags 8× R139,95 = R1 119,60 ✓A cost of adhesive Grout = 2× R89,99 = R179,98 ✓A grout Labour = 37,44× R110 = R4 118,40 ✓A labour Total = R8 407,10 + R1 119,60 + R179,98 + ✓CA total R4 118,40 ✓O conclusion = R13 825,08 M/L4 (7) R13 825,08 < R14 000, so the budget IS enough. (CA from 3.2.2) If adhesive is calculated on 41,18 m2 : 9 bags = R1 259,55, total R13 965,03 < R14 000; award R for 9 bags but max. 6/7 (wrong area). If labour is calculated on 41,184 m2 : R4 530,24, total R14 236,92 > R14 000, NOT enough; penalise once (labour A mark), CA for total and conclusion. 3.3.1 Radius = 4,2 ÷ 2 = 2,1 m ✓A radius Area = 21 × 3,142 × (2,1)2 ✓SF substitution = 6,93 m2 ✓CA area M/L2 (3) 3.3.2 Diameter on drawing = 420 cm ÷50 = 8,4 cm (radius ✓C 8,4 cm diameter (4,2 cm 4,2 cm) radius) ✓A semicircle shape (curved arc and straight diameter) ✓A accurate size (±2 mm) MP/L2 (3) 8,4 cm (diagram not to scale in this memo) [32] Copyright reserved Please turn over

Mathematical Literacy/P2 8 Hlayiso/Prediction 2026 NSC – Marking Guidelines QUESTION 4 [32 MARKS] 4.1.1 7,5 ÷ 2 ✓M dividing by 2 = 3,75 cm ✓A radius M/L1 (2) 4.1.2 Volume = 3,142 × (3,75)2 × 10 ✓SF radius = 441,84 cm3 ✓SF height ✓CA volume M/L2 (3) 4.1.3 Mass of one candle = 0,9 × 441,84 = 397,66 g ✓M density concept (mass = Mass for 60 candles = 60 × 397,66 = 23 859,6 g density × volume) = 23,86 kg ✓A 397,66 g Slabs = 23,86 ÷ 5 = 4,77 ✓M ×60 ≈ 5 slabs ✓C g to kg (or 5 kg = 5 000 12 OR (wax only, 13 of the mass): 22,02 kg g) ÷5 = 4,40 ≈ 5 slabs ✓M dividing by 5 (CA from 4.1.2) ✓R rounding up to 5 M/L3 (6) 4.1.4 Fragrance oil = 23 859,6 ÷ 12 = 1 988,3 g ✓M using the ratio Bottles = 1 988,3 ÷ 250 = 7,95 ✓M dividing by 250 ≈ 8 bottles ✓R 8 bottles 1 (Accept 13 of the total mass: 1 835,4 g M/L2 (3) ÷250 = 7,34 ≈ 8) 4.1.5 Circumference = 3,142 × 7,5 = 23,565 cm ✓SF circumference Length of label = 23,565 + 1 = 24,565 cm ✓M adding the overlap Area = 24,565 × 6 ✓M multiplying by 6 = 147,39 cm2 ✓CA area (Without the overlap: 141,39 cm2 , max. 3 marks) M/L2 (4) 4.1.6 185 = (1,8 × ◦ C) + 32 ✓SF substitution of 185 ◦ C = 185 − 32 ✓M changing the subject 1,8 ✓A answer = 85 ◦ C M/L2 (3) 4.2.1 (a) L ✓A (a) (b) R ✓A (b) (c) LLa ✓A (c) P/L2 (3) Copyright reserved Please turn over

Mathematical Literacy/P2 9 Hlayiso/Prediction 2026 NSC – Marking Guidelines 1 4.2.2 P(L and R) = ✓A numerator 6 (Accept 0,17 or 16,67%) ✓A denominator P/L2 (2) 4.3 Box: 12 × 2,54 = 30,48 cm; 9 × 2,54 = 22,86 cm; ✓C converting the 4 × 2,54 = 10,16 cm dimensions Height: 10,16 cm > 10 cm, so the candles fit upright. ✓A height check Along the length: 30,48 ÷ 7,5 = 4,06 → 4 candles ✓M dividing by 7,5 Along the width: 22,86 ÷ 7,5 = 3,05 → 3 candles ✓R 4 and 3 (rounding down) Number of candles = 4 × 3 = 12 ✓CA 12 candles Her claim is VALID. ✓O conclusion (If a candidate argues, with calculations, that the wick M/L4 (6) makes the candle taller than 10,16 cm and concludes NOT VALID: award the O mark.) [32] QUESTION 5 [26 MARKS] 5.1.1 37 × 30,48 = 1 127,76 cm ✓C feet to cm 11 × 2,54 = 27,94 cm ✓C inches to cm Total = 1 127,76 + 27,94 = 1 155,70 cm ✓M adding = 11,56 m ✓C cm to m M/L2 (4) 5.1.2 Width = 7 × 30,48 + 6 × 2,54 = 228,6 cm = 2,286 m ✓C width in metres Across the width: 2,286 ÷ 1,0 = 2,29 → 2 pallets ✓M dividing Along the length: 11,56 ÷ 1,2 = 9,63 → 9 pallets ✓R 2 and 9 (rounding down) Maximum = 2 × 9 = 18 pallets ✓CA 18 pallets (CA from 5.1.1) M/L3 (4) 5.1.3 Mass of one loaded pallet = 80 × 15 + 25 = 1 225 kg ✓M cartons × 15 kg 18 pallets = 18 × 1 225 = 22 050 kg ✓M adding the pallet In pounds: 22 050 × 2,2046 = 48 611,43 lb ✓A 22 050 kg 48 611,43 lb < 64 500 lb ✓C conversion The payload will NOT be exceeded, so his statement is ✓A comparing NOT VALID. ✓O conclusion OR M/L4 (6) 64 500 ÷ 2,2046 = 29 257,01 kg; 22 050 kg < 29 257,01 kg ∴ NOT VALID Copyright reserved Please turn over

Mathematical Literacy/P2 10 Hlayiso/Prediction 2026 NSC – Marking Guidelines 5.2.1 6 900 × 1,852 ✓C multiplying = 12 778,8 km ✓A answer M/L1 (2) 6 900 5.2.2 Time = = 405,88 hours ✓M dividing distance by 17 = 16 days 21,88 hours speed 0,88 × 60 ≈ 53 min → 16 days 21 h 53 min ✓A 405,88 h Mon 2 Nov 16:00 + 16 days = Wed 18 Nov 16:00 ✓M converting to days and + 21 h 53 min → Thursday 19 November 2026 at hours 13:53 ✓CA day and date (Accept 13:52 – 13:54) ✓CA time M/L3 (5) 3 5.3 Valencia = × 1 440 ✓M total parts (8) 8 = 540 cartons ✓M 83 of 1 440 ✓A answer M/L2 (3) 5.4 Any ONE, e.g. ✓✓O valid reason • The voyage takes more than two weeks; cooling M/L4 (2) keeps the oranges fresh and stops them from ripening too fast or rotting. • Export/quality regulations require the fruit to be kept cold (cold sterilisation against pests). [26] TOTAL: 150 Topic and level summary: Measurement 86 marks; Maps, plans and other representations 54 marks; Probability 10 marks. L1 44 (29%), L2 44 (29%), L3 33 (22%), L4 29 (19%). Copyright reserved