LP-Physical-Sciences-Grade-10-September-2025-QP-and-Memo.pdf

Downloaded from Stanmorephysics.com pre arig LIRA PCPS PROVINCIAL GOVERNMENT REPUBLIC OF SOUTH AFRICA DEPARTMENT OF EDUCATION NATIONAL SENIOR CERTIFICATE GRADE 10 MARKS: 100 TIME: 2 HOURS This question paper consists of 12 pages including DATA SHEETS.

Dowinleadedsfieom Stanmorephysics.com LDoE/September 2025 INFORMATION AND INSTRUCTIONS 1... Write your name and surname, as well as your class on the provided ANSWER BOOK. 2. The Question paper consists of SIX questions. Answer ALL questions on the provided ANSWER BOOK. 3. Start EACH question on a new page. 4. Number the answers correctly according to the numbering system used in this question paper. 5. Leave ONE line between two sub-questions, e.g. between QUESTION 2.1 and QUESTION 2.2. 6. It is recommended that you use the provided DATA SHEET. 7. Show ALL formulae and substitutions in ALL calculations. minimum of TWO decimal places. 9. Give brief motivat ussions, et cetera where required. 10. You may use I calculator and appropriate mathematical instruments. 11. Write neatly and legibly. Copyright Reserved Please Turn Over

LDoE/September 2025 Dowinleadedsfieom Stanmorephysics.com QUESTION 1 (MULTIPLE CHOICE QUESTIONS) Various options are provided as answers to the following questions. Choose the answer and write only letter (A — D) next to the question number (1.1 — 1.8) in the ANSWER SCRIPTS, for example 1.9 A. 4.1. Which ONE of the following combinations is correct? Distance Displacement Velocity A. | Scalar Scalar Scalar B. | Scalar Vector Vector C. | Vector Scalar Vector D. | vector vector scalar (2) 1.2 A trolley runs down a slope, pulling a ticker tape behind it through a ticker timer. A portion of the tape is shown below and represents the distances moved during equal intervals. 31 mm ox my The ticker tape re ts an acceleration that is ... A. zero uniform increasing 90 ® decreasing (2) Copyright Reserved Please Turn Over

Dowiwloadeds fiom Stanmorephysics.com LDoE/September 2025 1.3__The motion of two objects, P and Q, are represented in the following 1.4 1.5 position versus time graph. The graph ind A. Qis moving faster than P. B. P and Qare accelerating uniformly. C. P and Q are on a collision course. D. P and Q ar e directions. (2) An object, sta } increasing its vel The acceleratior time, will be ... eriences a constant acceleration a, when g the velocity from v to 2v in the same A. a , B. 2a omer (2) Consider the vector diagram below: Pp >< Q R Which ONE of the following is the correct relationship between vectors P, Qand R? A. P=Q+R B. R=P+Q C. Q=P+R Copyright Reserved Please Turn Over

Dowiwloadeds fiom Stanmorephysics.com LDoE/September 2025 1.6 Consider the balanced equation for the reaction below: (2) 1.7 Which ONE of the following contains 6,02 x 10 23 ATOMS? A. 1 mole of COz B. 16 g of O2 gas (2) 1.8 Which ONE of | g expressions is correct for the percentage D. —x 100 (2) [16] Copyright Reserved Please Turn Over

Dowiwloadeds fiom Stanmorephysics.com LDoE/September 2025 QUESTION 2 (Start on a new page) A basketball player runs around the basketba OD A D In one such training from D, goes back from A to D, then back to the centre line toA. 2.1. Calculate the tc red by the player. (1) 2.2 Calculate the time'it too the player to complete the session if his average speed was 2,5, (3) 2.3 Define the term average velocity in words. (2) 2.4 Determine the average velocity of the athlete. (2) [8] Copyright Reserved Please Turn Over

Doweloadedsfieom Stanmorephysics.com LDoE/September 2025 QUESTION 3 (Start on a new page) The velocity versus time graph below represents the motion of a car over a time period of 12 seconds. The car initially moves NORTH. Graph of velocity versus time 2] _ 10 —---- 8 SEEIE > 6 Bases SSRRSSe = Bo = a) = 4 rs Sfaictekwal 6 6 8 3.1 Define the term acceleration in words. (2) 3.2 Describe the motion of the car from C to E. (3) 3.3 WITHOUT USING EQUATIONS OF MOTION, calculate: 3.3.1 Distance that the car travels from A to C. (4) 3.3.2 Acceleration of the car between B and C. (4) 3.4 How does the magnitude of acceleration of the car between B and C compare to the magnitude of its acceleration between C and D? Choose from GREATER THAN, SMALLER THAN or EQUAL TO. (1) 3.5 Refer to the graph and give a reason for the answer to QUESTION 3.4. (1) 3.6 Write down the direction of the resultant displacement of the car. (1) 3.7 Use an equation of motion to calculate the instantaneous velocity of the caratt=5s. (4) [20] Copyright Reserved Please Turn Over

Dowiwloadeds fiom Stanmorephysics.com LDoE/September 2025 QUESTION 4 (Start on a NEW page) A motor car is 100 m behind the truck. Both the vehicles are travelling in the same direction at 72 km.h'. The truck drives over the landmine, which explodes, causing it to stop at that point. 72 kmh" oes Motor car The driver of the mo akes 0,4 s before he applies the car's brakes. Once the brakes are a the car slows down uniformly at 2,5 m.s®. 4.1 Explain the term ‘slows down uniformly at 2,5 m.s®’. 4.2 Show that 72 km.h"' = 20 m.s*. 4.3 Determine the distance travelled by the motor car during the 0,4 s reaction time. 4.4 Calculate the total time taken for the motor car to come to rest, from the instant that the driver saw the landmine exploding. 4.5 Will the motor car stop before reaching the wreck of the truck? Show all working in your answer. (2) (2) (3) (4) (5) [16] Copyright Reserved Please Turn Over

Dowiwloadeds fiom Stanmorephysics.com LDoE/September 2025 QUESTION 5 (Start on NEW page) 5.1. You are given 25 g of sodium sulphate (Na2SOs). 5.1.1 Calculate the number of moles of sodium sulphate crystals. (3) 5.1.2 Calculate the number of sodium atoms present in 25 g of sodium sulphate crystals. (4) 5.2 A substance contains 40% Carbon, 6,67% Hydrogen, and 53,53% Oxygen by mass. 5.2.1 Define the term empirical formula. (2) 5.2.2 Determine the empirical formula of the substance. (5) 5.2.3 If the molecular mass of the substance is 60 g.mol', determine its molecular formula. (2) [16] Copyright Reserved Please Turn Over

Dowimloadedeficom Stanmorephysizs.com QUESTION 6 (Start on a NEW page) 6.1 6.2 6.3 Copyright Reserved Solid Potassium chlorate (KCIOs) is heated to produce potassium chloride and oxygen gas according to the chemical equation given below. KCf03 + KCL + Q2 6.1.1 Balance the given chemical equation. 6.1.2 Calculate the mass of the potassium chlorate that must be used to produce 160 g of potassium chloride. 6.1.3. Calculate the volume of oxygen gas produced at STP if 200 g of potassium chloride is produced. Potassium oxide crystals, K2O are dissolved in 250 cm® of water to produce Potassium hydroxide solution of concentration 0,25 mol.dm. The potassium hydroxide (KOH) solution is reacted completely with sulphuric acid according:to the balanced chemical equation. 6.2.3. When this experiment was done in the school laboratory, 0,87 g of K2SOs« was produced. Calculate the percentage yield of K2SOs. The molar mass of hydrated copper sulphate is found to be 249,5 g.mol". The formula of hydrated copper sulphate is CuSO4.XH20. Calculate the number of moles of water of crystallisation (X) in the compound. TOTAL = 100 LDoE/September 2025 (2) (4) (4) (2) (4) (4) (4) [24] Please Turn Over

Dowloadedsfieom Stanmorephysizs.com LDoE/September 2025 TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/SIMBOOL | VALUE/WAARDE idétbtragverseling : 9ams* TEI vai in vata c 3.010" ms" Planck se konstant h 6.63% 10% J Lading op eer e 48x 10°C Elsktonmess me 0,11 x 10° kg TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING V; =v, tadt Ax =v,At+taat? VA +Vj Vy) =v)? +2adx AX = =. a TABLE 2: FORMULAE/TABEL 2: FORMULES n= C= </> /=/3 Bh A m V ORIOF c=” ven =v Vp Copyright Reserved Please Turn Over

peniesay yyBuAdog TABLE 3: THE PERIODIC TABLE OF ELEMENTS/TABEL 3: DIE PERIODIEKE TABEL VAN ELEMENTE 1 2 3 4 5 6 7 8 9 10 #114 #212 #139 «8694 © «©6196 0 Une —ltr-/Pag 10) (I!) (i) (IV) YY) (Vt) 1 Atomic number 2 =H KEY/SLEUTEL Atoomgetal He 1 4 3 4 - 5 6 7 8 9 | 10 Electronegativity = LT |S Be Elektronegatiwiteit_y| <= x Blac ieN|40\¢ F| Ne 7 9 11| 12| 14] 16| 19| 20 11 12 7 13 | 14|[ | 16| 17! 18 2 Na|& Mg Approximate rela ive atomic mass S£ACI2 Sils Pj8 S$ /8ce| Ar 23 | 24 Benaderde relatiewe ato 27 | 28| 31| 32| 35,5] 40 19/ 20| 2)] 22) 23 30/ 31/ 32] 33] 34] 35/ 36 $ K |2 Cal? Sc (2 Ti/2 v |e 2 Zn |2 Ga/2 Gel As|% Se/& Br} Kr 39 | 40/ 45| 48| 51/ 52| 55/ 56| 59/ 59| 635| 65| 70/ 73| 75| 79| 80| 984 37| 38] 39| 40{ 41/ 42| 43] 44[ 45/ 46| 47| 48/ 49] Sol 51] 52] 53] 54 ¢Rb/2 Srj& Y |f Zr} Nb/2Mol|2 Te |} Ru|§ Rhiy Pd|2 Ag |= Cd|= In |Z Sn|2Sb/5 Te/G 1 | Xe s¢| 98 | 89| 91] 92] 96 101| 103} 106| 108| 112] 115| 119] 122] 128| 127| 131 55 | 56| 67 | 72| 73| #%@4| #+%7| +%76| +77/| +78) 79| 80| 81| 82] 83] 84] 85] 86 S$ Cs\/2 Ba| Lal Hf] Ta} W| Re| Os| Ir| Pt] Au| Hg/2Te\2Pb/2 Bi\SPo/g At} Rn 133| 137| 139| 179| 181| 184| 186] 190| 192| 195| 197] 201| 204| 207/ 209 87 | 98 | 89 th a, 3 Fr |g heed Ac 5] 59 | 60 | 61 | 62 | 6 | 64] 65 | 66 | 67 | 68 | 69 | 70 | 71 Ce | Pr | Nd | Pm} Sm| Eu | Gd | Tb | Dy | Ho| Er | Tm) Yb | Lu 140 | 141 | 144 150 | 152 | 157 | 159 | 163 | 165 | 167 | 169 | 173 | 175 90 | 91 | 92 | 93 | 94 | 95 | 96 | 97 | 98 | 99 | 100 | 101 | 102 | 103 Th | Pa} U | Np} Pu Am|Cm| Bk | Cf | Es | Fm} Md} No| Lr 232 238 Wor" S2isdydeLOUUDIS Wodpapepejenwiag $z0z Jequiaydeg/30q7

Downloaded from Stanmorephysics.com REPUBLIC OF SOUTH AFRICA (FR LIM POP©O PROVINCIAL GOVERNMENT DEPARTMENT OF EDUCATION NATIONAL SENIOR CERTIFICATE f GRADE/GRAAD 10 ] MARKS/PUNTE: 100 These marking guidelines consists of 8 pages./Hierdie nasienriglyne bestaan uit 8 bladsye

Ovwntoedet: from Stanmorephysics .com LDoE/September 2025 NSC/NSS Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 (2) (2) (2) (2) (2) (2) (2) (2) [16] (1) (3) 2.3. Rate of change of position. ~™“/ Tempo van verandering van posisie (2) 24 Omstvv (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Ones foiedeér from Stanmorephysics.com LDoE/September 2025 NSC/NSS Marking Guidelines/Nasienriglyne QUESTION 3/VRAAG 3 3.1 Rate of change of velocity ¥ “/ Tempo van verandering van snelheid (2) 3.2 C-D e The car moves in opposite direction. ~/ Die motor beweeg in die teenoorgestelde rigting e Increasing velocity/constant acceleration ¥/ Toenemende snelheid/konstante versnelling D-E e The car moves with a constant velocity south/in opposite direction. “/ Die motor beweeg teen 'n konstante snelheid suid/in teenoorgestelde rigting. (3) 3.3. 3.3.1 AreaA—-B=Ixb =10x2v =20m (4) = 2,5 m.s* South W/suid (4) 3.4 GREATER THAN Y/GROTER AS (1) of graph BC isysteep an CD v/ Die helling van grafiek BC is (1) (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Ovvnntoedet from Stanmorephysics.com LDoE/September 2025 Marking Guidelines/Nasienriglyne OPTION 2/OPSIE 2 vF= vi + adt ¥ =5 ¥+ (-2,5)(1) ¥ = 2,5 m.s North Y/noord (4) [20] QUESTION 4/VRAAG 4 4.1 Velocity decreases by 2,5 m.s"! every second. v V/ Snelheid neem elke sekonde met 2,5 m.s” af. (2) 4.2 72000mv 3600s =20ms'1v¥ OR/OF T2v 3,6 =20ms'v (2) 4.3 OPTION 1/OPS LV a @\ ie Aeafinorephysics.com =20x0,4v =8mv OPTION 2/OPSIE 2 AX = viAt + ; aAt? ¥ = (20)(0,4) an (0)(0,4)2 ¥ (3) Ov =20 + (-2,5)Atv At=8s Attotal = 0,4 + 8 = v 84s (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Ones foiedeér from Stanmorephysics.com LDoE/September 2025 Marking Guidelines/Nasienriglyne 4.5 OPTION 1/OPSIE 1 ve =vi?t + 2aAx ¥ (0)? = (20) + 2(-2,5)Ax ¥ Ax = 80 mv The motor car will stop. “/ Die motor sal stop. Since it comes to a halt within (80 + 8) m ¥ (which is less than 100 m)/ Aangesien dit tot stilstand kom binne (80 + 8) m (wat minder as 100 m is) POSITIVE MARKING FROM 4.3/ POSITIEWE PUNTE VANAF 4.3 OPTION 2/OPSIE 2 Ax = viAt + - aAt? v = (20)(8) + 5 (-2,5)(8) v =80mv The motor car willistop. “/ Die motor sal stop. Since it covers +8)m h is less than 100 m./ Aangesien dit (80 + 8) md d 0 mis. = =~ (5) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Ones foiedeér from Stanmorephysics.com LDoE/September 2025 NSC/NSS Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5 5.1 5.1.1 n=m/Mv¥ = 25/142 v = 0,18 moles V/mol (3) 5.1.2 n=N/NAY 0,18 = N/6,02 x 107 v = 1,08 x 10% x2 v = 2,16 x 1073 atoms Vv (4) 5.2 5.2.1 The simplest whole number ratio of atoms in a compound. Vv ¥/ Die eenvoudigste heelgetalverhouding van atome in 'n verbinding. (2) 5.2.2 Empirical formula/empiriese §.2.3 M(CHz2) 30 g.molt n = 60/30 v =2 molecular formula/molekulére formule C2H4O2 ¥ (2) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Ovvnntoedet from Stanmorephysics.com NSC/NSS Marking Guidelines/Nasienriglyne QUESTION 6/VRAAG 6 6.1 6.1.1 2KCIOs ¥ > 2KCI + 302v 6.1.2 n(KCl) =m/M = 160/74.5 v = 2,1476 moles/Mol KCIOs : KCI 2,1476 : 2,1476 v m=nxM = 2,1476 x 122,5 v = 263,08 g ¥ per volume oplossing teenwoordig is. Copyright reserved/Kopiereg voorbehou LDoE/September 2025 (2) (4) (4) he amount of a substance present per volume ‘onsentrasie is die hoeveelheid van 'n stof wat (2) Please turn over/Blaai om asseblief

Ones foiedeér from Stanmorephysics.com LDoE/September 2025 NSC/NSS Marking Guidelines/Nasienriglyne 6.2.2 n=cxV = 0,25 x 0,25 ¥ = 0,0625 moles/mol KOH : K2SO4 Z : 4 0,0625 : 0.03125 v m=nM = 0.03125 x 174 v =5,44g v (4) 6.2.3 % yield = actual yield/theoretical yield x 100 v / % opbrengs = werklike opbrengs/teoretiese opbrengs x 100 (4) 6.3 (4) = 90/18 v =5 x = 5 orlof CuSO4.5H20 ¥ [24] TOTAL/TOTAAL = 100 Copyright reserved/Kopiereg voorbehou