Math P1 2014 November Memo hlayiso.com

Downloaded from hlayiso.com 1 Overberg Education District GR 8 MODEL EKSAMEN/EXAM P 1 WISKUNDE/MATHS NOVEMBER 2014 MEMORANDUM

Downloaded from hlayiso.com 2 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig VRAAG/QUESTION 1 1.1 (a) 81  A (b) 363 A (c) 81; 189; 450  A (all 3 correct) (d) 5A (4) 1.2 2 678 879  A (1)     1 A for each number in 1.3 30 + 8 ÷ 2 - 10 = 24 (4) correct position 1.4 - 20 (150 x - 90 + 10 ) 45 1 M A -300 = - 20 (-300 + 10)  MA 1 CA -290 = -20 x -290  CA 1CA answer = 5 800  CA (3) 1.5 4 = 100 80 5 9 36 = 25 100 6 60 = 10 100 3 15 = A 1 mark for each 2 correct 20 100  A conversions 4 6 44 9 3 1 ; ; ; ; ; CA 5 10 100 25 20 100 1 CA descending/dalende (3) 1.6 1,123 x 105 = 112 300  A 9,2 x 103 = 9 200  A Therefore 9,2 x 103 smallest/kleinste CA (3)

Downloaded from hlayiso.com 3 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig 1.7 2 916 2 2916 2 1458 3 729 3 243  M 1 M any method you have 3 81 taught! 3 27 3 9 3 3 1 2 916 = 22 x 36  CA 1 CA powers of prime no’s Magte van priemfaktore √2 916 = 2 x 33 = 54 CA 1 CA antwoord (3) 1.8. 0,5kg:250g = 500g:250g  C OR 0,5kg:0,25kg 1 C conversion/omskakeling = 2:1  CA 1 CA simplification (2) 1.9. 4 750 x 3  A 2A x correct numerator & denominator/teller & noemer = R1 000 CA 1CA answer (3) 1.10.1 Profit = R75 A (1) 1.10.2 75 CA x 100  M 1 CA fraction with 250 D/N 250 1M x100 = 30%  CA 1CA answer (3) 1.11 2 800 x 0,2 x2 = R1 120  A = Total amount payable/bedrag betaalbaar 1A interest amount/rente = 1 120 + 2 800 bedrag = R3 920  CA 1CA total amount/bedrag Monyhly installments/paaiement = 3 920  CA 1CA ÷ 24 24 1CA answer = R163,33  CA (4)

Downloaded from hlayiso.com 4 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig [34] VRAAG/QUESTION 2 2.1 -2𝑥𝑥 – 𝑥𝑥3 + 9 𝑥𝑥2 + 14(𝑥𝑥2 + 2) 2.1.1 4 A (1) 2.1.2 -2(-2) – (-2)3 + 9(-2)2 +14((-2)2 +2) SF 1SF substitution/stel in =4 + 4 +36 + 84 CA 1CA simplification/ = 132 CA Vereenvoudiging (3) 1CA answer 2.2.1 𝑝𝑝4 . 𝑞𝑞 4 . 𝑞𝑞 2 . 𝑝𝑝3 q6 . 𝑝𝑝6 A A = 𝑝𝑝 7−6 . 𝑞𝑞 6−6 1A p correct 1A q correct = 𝑝𝑝 CA 1CA answer (3) 2.2.2 4 2 3 4 (-8𝑥𝑥 𝑦𝑦 )(5𝑥𝑥 𝑦𝑦 )( -2𝑥𝑥) A A A 1A for each item = 80 𝑥𝑥 8 𝑦𝑦 6 completely correct Vir elke item heeltemal korrek (3) 2.2.3 -5 (2𝑥𝑥 2 + 𝑥𝑥 – 20) + 12𝑥𝑥 2+3 𝑥𝑥 A 1A brackets correctly = -10𝑥𝑥 - 5 𝑥𝑥 + 100 + 12𝑥𝑥 2+3 𝑥𝑥 2 removed/ Hakies korrek verwyder = 2𝑥𝑥 2 - 2 𝑥𝑥 + 100   CA 1CA 3 terms 1CA correctly (3) simplified

Downloaded from hlayiso.com 5 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig 2.3.1 4𝑥𝑥 + 5 = 5𝑥𝑥 − 9 -𝑥𝑥 = - 14 A 1A both sides correct 𝑥𝑥 = 14 CA 1CA answer (2) 2.3.1 5(𝑥𝑥 − 1) − (1 − 2𝑥𝑥 ) = 8 A A 5𝑥𝑥 - 5 -1 + 2𝑥𝑥 = 8 2A for both brackets 7𝑥𝑥 = 14 CA correctly removed 𝑥𝑥 = 2 CA 1CA for simplification 1CA for answer (4) 2.4 Let son be 𝑥𝑥 ANY METHOD!! Then father = 𝑥𝑥 + 25  In 5 years’time/oor 5 jaar ENIGE METODE!! Son = 𝑥𝑥 + 5 Father = 𝑥𝑥 + 30  Then/dan: 2( 𝑥𝑥 + 5) = 𝑥𝑥 + 30  2𝑥𝑥 + 10 = 𝑥𝑥 + 30 𝑥𝑥 = son = 20  (4) 2.5.1 13A (2) 2.5.2 N = 3p-2 A (3) 2.5.3 N = 3 (100) – 2 SF 1 SF substitute/instel = 298 CA (2) 1CA answer 2.6.1 6:00 (1) 2.6.2 7:30 (1) 2.6.3 1h (2) 2.6.4 9:00 (1) 2.7.1 1 mark for each two x ―1 0 1 2 3 correct, plus 1 mark for last one correct y -5 -3 -1 1 3 1 punt vir elke twee  CA korrek, plus 1 punt vir die laaste 1 korrek

Downloaded from hlayiso.com 6 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig (3) 2.7.2 ANNEXURE A/BYLAE A (3;3) (2;1) (1;-1) (0;-3) (-1;-5) Scales on both x-and y- axes correct/ Skale vir beide x-en y-asse korrek A All 5 points plotted correctly/ Al 5 punte korrek geplot CA Join points for a straight line/Verbind punte vir reguitlyn CA (3) [41]

Downloaded from hlayiso.com 7 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig TOTAL 75