Mathematical Literacy Grade 10 P1 2012 Memo (Eng)

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 10 MATHEMATICAL LITERACY P1 EXEMPLAR 2012 MEMORANDUM MARKS: 75 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG Reading from a table/Reading from a graph SF Correct substitution in a formula O Opinion/Example P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding off/Reason This memorandum consists of 6 pages. Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 2 DBE/2012 NSC – Grade 10 Exemplar –Memorandum QUESTION 1 [15] Ques Solution Explanation Topic M A A 1.1 1 × 60 = 20 minutes 1 A multiply 60 3 1 A answer (2) 1.2 80 g A 1A reading from the table (1) M 1.3 1 tablespoon = 12,5 mℓ A 1A tablespoon to mℓ 12,5 mℓ margarine = 12,5 g A A 2A mℓ to g ∴ Lindi added 12,5 g of margarine (3) M 1.4 Amount of water used = 4 cups = 4 × 250 mℓ M 1M multiplying = 1 000 mℓ A 1A mℓ = 1 litre C 1C conversion to litre (3) 1.5.1 1M multiplying M 2,5 kg = 2,5 × 1 000g M 1C conversion to grams = 2 500 g C (2) M 1.5.2 2 500 g M Number of times she can make porridge = 1M dividing 312,5 g 1CA simplification = 8 CA (2) M 1.6 To simmer turn knob to 1. A A 2A answer [Accept values below 3 but more than 0] (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 3 DBE/2012 NSC – Grade 10 Exemplar –Memorandum QUESTION 2 [15] Ques Solution Explanation Topic A D 2.1 5 5 6 7 7 7 8 8 8 8 9 2A arranging 10 15 15 15 15 15 15 20 23 23 (2) D 2.2 Mode is R15 A 2A answer (2) F 2.3 R23 A 2A answer (2) D 2.4 Median = R9 AA 2A answer (2) D 2.5 Mean = M 5 + 5 + 6 + 7 + 7 + 7 + 8 + 8 + 8 + 8 + 9 + 10 + 15 + 15 1M adding 21 A 1A number of entries 15 + 15 + 15 + 15 + 20 + 23 + 23 + 21 R 244 CA 1CA sum = 21 = R11,62 1CA rounded off ≈ R12 CA answer (4) P 2.6 number of learners getting R 7 1A numerator Probability (R7) = 1A denominator total number of learners 3 A = 21 A 1CA simplified answer (3) 1 = CA 7 Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 4 DBE/2012 NSC – Grade 10 Exemplar –Memorandum QUESTION 3 [20] Ques Solution Explanation Topic F 3.1.1 Total number of items = 26 AA 2A answer (2) F 3.1.2 R 32,97 1M dividing Unit price = M 3 = R10,99 A 1A simplification (2) F 3.1.3 Total amount = R324,85 A A 2A answer (2) F 3.1.4 Change = R400 – R324,85 M 1M subtracting from R400 = R75,15 CA 1CA answer (2) F 3.1.5 Mangoes A A 2A answer (2) F 3.1.6 R38,92 A 2A answer (2) F 3.2.1 Bond repayment OR Rates OR School fees OR Car instalment (any one) A A 2A answer (2) M A F 3.2.2 A: 12% × R18 350 = R2 202 1M percentage 1A correct value used (2) M F 3.2.3 B: R4 100 + R475 + R325 + R580 + R2 750 1M adding + R1 650 + R1 800 + R1 300 + R940 + R2 202 = R16 122 CA 1CA answer (2) F 3.2.4 R18 350 – R16 122 M 1M subtracting = R2 228 CA 1CA answer (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 5 DBE/2012 NSC – Grade 10 Exemplar –Memorandum QUESTION 4 [11] Ques Solution Explanation Topic SM 4.1 2 A A 2A number of restaurants (2) SM 4.2 38 A A 2A correct number (2) A A SM 4.3.1 1 unit on the map is equivalent to 500 units in 2A correct number real life. (2) S 4.3.2 1 mm represents 500 mm on the ground 180 mm represents 180 mm × 500 A 1A using the scale = 90 000 mm A 1A answer in centimetres = 90 m C 1C answer in metres (3) M 4.4 Restaurant AA 2A correct shop (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 6 DBE/2012 NSC – Grade 10 Exemplar –Memorandum QUESTION 5 [14] Ques Solution Explanation Topic D 5.1.1 Sprite and Granadilla Twist A A 2A solution (any valid cooldrink) (2) M D 5.1.2 % Fanta Orange sales = 100% – (12+55+9+7)% 1M subtracting from 100 = 17% CA 1CA answer (2) D 5.1.3 Coca-Cola A A 2A solution (2) D 5.1.4 A A 2A solution 55% OR 0,55 OR 55 100 (2) F 5.2.1 Original price = R4 999 + R500 M 1M adding = R5 499 A 1A answer (2) F amount saved 5.2.2 Percentage discount = × 100% original price 500 = × 100% SF 5 499 1SF substitution = 9,09% A 1A answer (2) F 5.2.3 Total amount paid = deposit + monthly payment × number of months = R500 + (R263 × 24) SF 1SF substitution = R6 812 A 1A answer (2) TOTAL: 75 Copyright reserved