Mathematical Literacy Grade 12 Paper 1 NSC June 2021 Memo

Downloaded from hlayiso.com SENIOR CERTIFICATE EXAMINATION/ NATIONAL SENIOR CERTIFICATE EXAMINATION SENIORSERTIFIKAAT-EKSAMEN/NASIONALE SENIORSERTIFIKAAT-EKSAMEN MATHEMATICAL LITERACY P1/WISKUNDIGE GELETTERDHEID V1 MAY-JUNE 2021 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 Symbol/Kode Explanation/Verduideliking M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule O Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding, ens. R Rounding off/Afronding NPR No penalty for rounding/Geen penalisasie vir afronding nie AO Answer only/Slegs antwoord MCA Method with consistent accuracy/Metode met volgehoue akkuraatheid This marking guideline consists of 15 pages Hierdie nasienriglyne bestaan uit 15 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 2 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented. • General principle of marking, if the candidate makes one mistake he loses one mark. LET WEL: • As 'n kandidaat 'n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na. • As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, sien die doodgetrekte (gekanselleerde) poging na. • Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou op by die tweede berekeningsfout. • Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra item. • Die algemene beginsel van merk as 'n leerder een fout maak verloor hy een punt. QUESTION/VRAAG 1 [32 MARKS/PUNTE] ANSWER ONLY FULL MARKS Q/V Solution/Oplossing Explanation/Verduideliking T&L M 1.1.1 Radius/Radius = 300 mm ÷ 2 MA 1MA dividing by 2 L1 = 150 mm OR/OF 15 cm A 1A simplify (2) RT 1RT reading all the values F 1.1.2 R330,00; R275,00; R220,00; R110,00 CA 1CA correct order L1 (2) F 1.1.3 VAT/BTW = R275,00 × 15% MA 1MA multiplying by 15% L1 = R41,25 A 1A simplify OR/OF OR/OF Price including VAT/Prys BTW ingesluit = R275 1,15 = R316,25 MA 1MA calculating VAT VAT = R316,25 – R275 = R41,25 A 1A simplify (2) M 1.1.4 150 ÷ 60 A 1A divide by 60 L1 = 2,5 OR/OF 2 hours/uur A 1A 2,5 hours (2) Copyright reserved/Kopiereg voorbehou

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 3 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 1.1.5 Total cost/Totale Koste L1 MA 1MA adding all correct values = R330,00 + R275,00 + R220,00 + R220,00 + R165,00 + R110,00 = R1 320 MCA 1MCA simplify (at least 5 correct values) (2) F 1.1.6 Discount/ Afslag = R330,00 × 7,5% MA 1MA multiplying by 7,5% L1 = R24,75 A 1A simplification (2) M 1.2.1 1 250 g 1MA dividing by 1 000 L1 MA 1 000 1A simplification = 1,25 kg A (2) F 1.2.2 Cost Price/Kosprys L1 1MA subtracting correct = R55,00 – R30,30 MA values in the correct order = R24,70 A 1A simplification (2) M 1.2.3 1 250 : 500 MA 1MA values in correct order L1 5 : 2 OR/OF 2,5 : 1 OR/OF 1: 0,4 CA 1CA simplified form (2) M 1.2.4 Number of packets/Aantal pakkies L1 4 000 g 1A number of 500g packs  8 A 500 g Mass/Massa 100 g 1MA dividing 100 g by 8 MA 8 1CA simplification = 12,5 g CA OR/OF OR/OF Mass/Massa MA 1MA number of 500g packs 500 g  100 g 1A dividing 4 000 g  12,5 g CA 4 000 g A 1CA simplification Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 4 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L OR/OF OR/OF 4000 g : 100 g MA 1MA correct ratio concept 500 g : mass of raisins/massa van rosyntjies 50 000 g Mass of raisins  4 000 A 1A dividing 4 000 g Mass of raisins/Massa van rosyntjies 1CA simplification = 12,5 g CA (3) M 1.2.5 Number of cups/aantal koppies L1 MA =2×5 1MA multiply by 2 and 5 = 10 A 1A simplification OR/OF OR/OF 4 000 : 5 MA 1MA correct ratio 8 000 : 10 The number of cups = 10 A 1A simplification (2) F 1.3.1 Money earned on an investment/ L1 Geld verdien op 'n belegging. A 2A definition (2) M 1.3.2 25 months/maande A 2A correct number of months L1 (2) F 1.3.3 Bank A A 2A correct bank L1 (2) F 1.3.4 Difference/Verskil L1 RT RT 1RT correct value from tables 7,50% 6,7% 1RT correct value from tables = 0,8% CA 1CA simplification (one value must be correct) (3) [32] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 5 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 2 [37 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.1.1 Dr. JJ Ndlovu A 2A correct name L1 (2) F 2.1.2 Year of birth/Geboortejaar L1 2RT reading from table 1982 / '82 RT (2) F 2.1.3 R0,00/nothing/niks A 2A correct amount L1 (2) F 2.1.4 Amount excluding VAT/Bedrag BTW uitgesluit L2 115 1A OR 100 115 100 100 115 R1 744,75 ÷ OR/OF × 100 115 A 1M ÷ 115 OR × 100 R1 744,75 ÷ 1,15 M 100 115 = R1 517,17 CA 1CA simplification OR/OF OR/OF VAT amount/BTW bedrag 15 R1 744,75  115 = R227,58 A 1A amount VAT Amount excluding VAT/Bedrag BTW uitgesluit = R1 744,75 – R227,58 M 1M subtracting VAT 1CA simplification = R 1 517,17 CA (3) F 2.1.5 One infection control /Een infeksiebeheer L1 =R40,55 ÷ 2 MA 1MA divide by 2 = R20,28 A 1A simplification NPR AO (2) F 2.2.1 Total fixed cost/Totale vaste koste L1 = R140,00 + R60,00 RT 1RT correct values = R200,00 CA 1CA simplification (one value must be correct) (2) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 6 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.2.2 Expenses/Uitgawes L2 Expenses (A) = R200,00 + R12,50 × number of packets A = R200,00 + R12,50 × 10 SF 1SF correct substitution A = R200,00 + R125,00 = R325,00 A 1A simplification SF SF B = 400 ÷ 25 OR/OF B = (400 – 200 ) ÷ 12,5 1SF correct substitution = 16 A = 16 A 1A simplification AO (4) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 7 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.2.3 INCOME AND EXPENDITURE OF 1 kg OF MIXED VEGETABLE PACKS L2 (a) INKOMSTE EN UITGAWES VAN I kg GEMENGDEGROENTE-PAKKE 1300 Income A 1200 Inkomste 1100 1000 900 Expenses 800 Uitgawes Amount in rand 700 A 600 Bedrag in rand 500 400 300 200 100 0 A 0 5 10 15 20 25 30 35 40 45 50 Number of 1 kg vegetable packs Aantal 1 kg groentepakke 1A starting point (0; 0) 1A endpoint (50; 1 250) 1A straight line (must be joining at least 3 points stated in the table; CA for using B) (3) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 8 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.2.3 Where the cost price of mixed vegetable packs equals the L1 (b) selling price of the packs/Waar die kosprys van 'n pak groente gelyk is aan die verkoopprys van die pak groente. 2A explanation (2) CA from Q2.2.2 / 2.2.3 (a) F 2.2.3 16 packs/pakke A 2A correct number of L1 (c) packs (2) F 2.3.1 Deposit/Deposito L1 (a) R1 799,00 × 20 100 MA 1MA calculating 20% = R359,80 A 1A simplification (2) CA from Question 2.3.1(a) F 2.3.1 Total amount/Totale bedrag L2 (b) MA 1MA multiplying by 24 = R359,80 + (24 × R95,00) = R359,80 + R2 280,00 MCA 1MCA adding the deposit = R2 639,80 CA 1CA simplification = R2 640,00 R 1R to the nearest rand (4) A A F 2.3.2 The value of one currency relative to the value of another 1A value of one currency L1 (a) currency/Die waarde van een geldeenheid relatief tot die 1A relative to the value of waarde van 'n ander geldeenheid. another currency (2) A A F 2.3.2 yen / jen / Ұ OR/OF Japanese yen / Japanese jen 2A correct currency L1 (b) (2) F 2.3.2 1 ZAR = 0,067251 dollar ($) RT 1RT exchange rate L2 (c) $130  R1 C 1C conversion $0,067251 = R1 933,056758 1R correct rounding = R1 933,00 R OR/OF OR/OF 1RT exchange rate Dollar ($) = ZAR14,86966737 RT $130 1C conversion  R14,86966737 C $1 = R1 933,056758 = R1 933,00 R 1R correct rounding (3) [37] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 9 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3 [22 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L M 3.1.1 Width/breedte = 3 × 10,4 cm MA 1MA for multiplying diameter by 3 L1 = 31,2 cm A 1A simplification Length/Lengte = 4 × 10,4 cm MA 1MA for multiplying diameter by 4 = 41,6 cm A 1A simplification (4) M 3.1.2 Ribbon needed for one candle (cm) L3 Lint benodig vir een kers (cm) = 2 × 3,142 × radius + 3 cm = 2 × 3,142 × 5,2 cm + 3 cm SF 1SF correct substitution (radius) = 35,6768 cm A 1A length for 1 candle 20 × 100 = 2 000 cm C 1C conversion Number of candles/Aantal kerse 2 000 cm ÷ 35,6768 cm MCA = 56, 05883936 1MCA dividing by length of = 56 candles/kerse R ribbon 1R correct number of candles Accept 55 candles if rounded earlier (5) CA from Question 3.1.2 M 3.1.3 Volume = 3,142 × (5,2cm)2 × 11,4cm SF 1SF substituting correct L2 values = 968,54 cm3 CA 1CA answer in cm3 Volume of horsehead/Volume van kers met perd 2 968,54 cm3 1MCA multiply by 2 and dividing =  MCA 3 1 by 3 = 645,69 cm3 CA 1CA simplification OR/OF OR/OF CA 968,54 2CA answer in cm3 = 322,84666 × 2 MCA 1MCA multiply by 2 and dividing 3 by 3 = 645,69 cm3 CA 1CA simplification Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 10 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L OR/OF OR/OF 3.1.3 Volume = 3,142 × (5,2)2 × 11,4 cm SF 1SF substituting correct values = 968,54 cm3 CA 1CA answer in cm3 Volume of horsehead = 968,54 cm3 - (968,54 cm3) = 968,54 – 322,85 MCA 1MCA subtracting = 645,69cm3 CA 1CA simplification (4) P 3.2.1 Ribbon/Lint OR/OF R/L A 2A ribbon L1 (a) A (2) P 3.2.1 HBN /PSG A 2A HBN/PSG L1 (b) (2) P 3.2.2 A A M L2 M (a) P[candle with ribbon/ kers met lint ] = 1  100 % OR/OF 4 100 1A fraction  % 2 1 8 1 1M concept of percentage = 50% CA = 50%CA 1CA for percentage A A AO (3) P 3.2.2 L2 (b) P/W P[Gold horsehead candle / Goue perdekop kers ] = 0 A A OR/OF 2A correct probability 0 Impossible / Onmoontlik / / 0% / 0,0 A 8 A (2) [22] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 11 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 [21 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L MP 4.1.1 North West / NW L1 Noord-wes/ NW RT 2RT reading from map (2) MP 4.1.2 N8 RT 2RT N8 L1 (2) MP 4.1.3 Campbell RT 2RT town L1 (2) MP 4.1.4 04:00 – 09:30 L2 = 5 hours 30 min / 5,5 hours/ure A 1A calculating 5,5 hours Average Speed /Gemiddelde spoed 496,9 MCA 1MCA dividing correct values in correct = order 5,5 = 90,3454545 km/h CA 1CA simplification = 90 km/h R 1R rounding (4) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 12 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L MP 4.2.1 1 unit on the plan represents 380 units in real life./ L1 1 eenheid op die plan verteenwoordig 380 eenhede in werklikheid. A 2A explanation (2) MP 4.2.2 Lifts/Hysbakke A L1 OR/OF Ground Floor/Grondvloer A 2A lifts OR/OF Stairs/Trappe A (2) MP 4.2.3 4 A 2A correct value L1 Accept 2 (2) MP 4.2.4 Bloed street entrance/Bloedstraat-ingang RT L1 OR/OF 2RT correct entrance South entrance/Suidelike ingang RT (2) MP 4.2.5 27 mm A 2A for correct measurement L1 1A correct wall (Accept 26 – 28 mm) (3) [21] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 13 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 5 [38 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L D 5.1.1 Range is the difference between the highest/maximum value L1 and the lowest/minimum value in a data set. A 2A correct definition Omvang is die verskil tussen die hoogste/maksimum waarde en die kleinste/minumum waarde in 'n dataversameling. (2) D 5.1.2 Line graph/Lyngrafiek L1 OR/OF A 2A correct graph Broken line graph/Gebrokelyn grafiek (2) D 5.1.3 Discrete data/Diskrete data A 2A discrete L1 (2) M D 5.1.4 1 749 + 2 239 + 1 618 + 903 + 429 +150 + 16 RT 1RT correct values L1 = 7 104 CA 1M adding ALL values 1CA simplification (at least 6 values correct) Accept 7 136 = full marks AO (3) D 5.1.5 L2 RT 3RT correct level L1 (3) CA from Question 5.1.4 D 5.1.6 Median level descriptor/Mediaanvlakbeskrywer 1MCA arranging in order L3 CA = 62; 223; 551; 935 1 231; 1 357; 1 990 MCA 1CA correct median L4 CA 1CA level descriptor OR/OF OR/OF MCA L2 : L3 ; L1 ; L4 ; L5 ; L6 , L7 CA 1MCA arranging 1CA correct order Median level/Mediaanvlak = L4 CA 1CA level descriptor AO (3) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 14 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L D 5.2.1 IIII I A 2A correct tally L1 (2) CA from Question 5.2.1 D 5.2.2 6 CA 2CA correct frequency L1 (2) RT 1RT correct values D 5.2.3 43 + 17 = 60 1MA simplification L1 MA OR/OF OR/OF RT MA 1RT correct values 0 + 3 + 6 + 12 + 7 + 15 + 17 = 60 1MA simplification (2) A A 1A stacked D 5.3.1 Stacked bar graph/Stapel staafgrafiek 1A bar graph L1 (2) A A D 5.3.2 Two hundered and ninety four thousand two hundred and 1A first part of wording L1 two/ Twee honderd vier en negentig duisend twee honderd en 1A second part of wording twee. (2) RT 1RT correct values D 5.3.3 298 607 – 222 034 9 670 M 1M subtracting L2 = 66 903 CA 1CA simplification (two values must be correct) AO (3) D 5.3.4 Mean/Gemiddelde L2 RT 1RT correct values 225458 + 263903 + 265810 + 245103 + 233858 + 222034 6 M 1M concept of mean = 242 694,33 CA 1CA simplification NPR (3) D 5.3.5 Range/Omvang L2 388 845 – 294 202 MA 1MA concept of range = 94 643 CA 1CA simplification (one value must be correct) (2) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 15 DBE/2021 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne D 5.3.6 % for Mathematics/% vir Wiskunde L2 RT 1RT correct values 222034 100 1MA percentage calculation =  MA 530311 1 41,8686% CA 1CA simplification % for Mathematical Literacy/% vir Wiskundige Geletterdheid 298607 100  530311 1 56,3079% CA 1CA simplification 56,3079% 41,8686% = 14,4 % CA 1CA simplification with correct rounding OR/OF RT M OR/OF 298 607 - 222 034 × 100 MA 1RT correct values 530 311 CA 1M subtracting values = 14,4% CA 1CA correct denominator 1MA percentage calculation 1CA simplification with correct rounding (5) [38] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou