Maths Lit P1 Memo June 2017 English hlayiso.com

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 JUNE 2017 MATHEMATICAL LITERACY P1 MEMORANDUM MARKS: 100 Symbol Explanation M Method A Accuracy CA Consistent accuracy RT/RG/RM Reading from a table/Reading from a graph/Read from map SF Substitution in a formula P Penalty, e.g. for no units, incorrect rounding off etc. S Simplification R Rounding/Reason This memorandum consists of 6 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/JUNE 2017) QUESTION 1 [28 Marks] Quest Solution Explanation Marks 1.1.1 p.a. means per annum  OR annual earning R (2) 1.1.2 One million, two hundred eighty five thousand, R four hundred and fifty six  (2) 1.1.3 1 285 500  Rounding (2) 1.2.1 17,99 1A for 12 Price of an egg = = 1,499  12 = R1,50  1CA (2 dp. money) (2) 1.2.2 14 1M Multiplication VAT = 100 × 59,88  = R8,38  1A (2 dp. for money) (2) 1.2.3 2,5 × 1 000 = 2 500 g  1MA Multiplication 1A (2) 1.2.4 10 𝑚ℓ → 8𝑔 2M 150 𝑚ℓ →? 150 × 8 ?=  = 120 𝑔  10  1A (2) 1.3 Juice: Water = 1 : 5 1M 10: ?? 1A 10 × 5  ?? = = 50 glasses of water  (2) 1 1.4 0,294 1M division Length = 0,01 = 29,4 cm  1A (2) 1.5.1 Number of boys = 9 – 3 1MA =6 1A (2) 1.5.2 Range = 13 – 3  = 10  1MA 1A (2) 1.6.1 Learners that took part in research = 32  2 RG (2) 1.6.2 Formal dress code  2 RG (2) 1.6.3 Boys that preferred traditional dress code = 1M subtraction of 24 – 16 = 8  the values OR counting from graph – 8 boys  1CA AO (2) [28] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2017) MATHEMATICAL LITERACY P1 3 QUESTION 2 [26 Marks] Quest. Solution Explanation Marks 2.1.1 Profit for 2015 = Income – expenditure = 262 600 – 188 560  1MA subtraction = 74 040  1A (2) 2.1.2 Total expenditure in 2016 = 1M addition of 160 400 + 7 400 + 2 600 +10 400 + 360 + 7 expenses 200 +1 600 + 2 440 = 192 400  1A OR Total expenditure = Income – profit 1M addition of = 318 860 − 126 460  expenses = 192 400  1A (2) 2.1.3 Depreciation increased by 50%  2RT (2) 2.1.4 𝑖𝑛𝑐𝑟𝑒𝑎𝑠𝑒 𝑖𝑛 𝑠𝑎𝑙𝑎𝑟𝑖𝑒𝑠 % 𝑖𝑛𝑐𝑟𝑒𝑎𝑠𝑒 𝑖𝑛 𝑠𝑎𝑙𝑎𝑟𝑖𝑒𝑠 = × 100 𝑠𝑎𝑙𝑎𝑟𝑖𝑒𝑠 𝑖𝑛 2015 1SF 160 400 − 160 000 = × 100  160 000 400 = × 100 = 0,25%  1A (2) 160 000 2.2.1 Minutes (time)  2RT (2) 2.2.2 GRAPH SHOWING CELLEPHONE DEALS OPTIONS: A; B; C Point (0; 500), another point on line cost = 500  line cost = 500  (3)

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/JUNE 2017) 2.2.3 Same cost for all the options.  OR 2RG None is cheaper.  (2) 2.2.4 1 1 numerator P(C) = 3  1 denominator (Answer only full marks) (2) 2.3.1 Cost of paraffin = 5,60 × 3 = R16,80  1MA Multiplication (2) 1A 2.3.2 P = 5,60 × 1,1  = R6,16  2 MA Multiplication OR 1A 110 P = 5,60 ×  = R6,16  100 1MA for the OR increase Increase = 5,60 × 10% = R0,56  1M addition P = 5,60 + 0,56  = R6,16  1A (3) 2.3.3 30 1A for 15 No. of tanks = 2 = 15  1M Multiplication Cost = 15 × 3 × 6,16 = R277,20  1CA (3) [26] QUESTION 3 [13 Marks] Quest. Solution Explanation Marks 3.1.1 Perimeter = 8 × 500  1M multiplication = 4 000 ÷ 100 = 40 m  1M dividing by 100 1CA (3) 3.1.2 𝐴 = 3,142 × 252  1S radius and 3,142 =1 963,75 𝑐𝑚2  1A (-1 for using calculator pi) (2) 3.1.3 1 Area of the rectangle = 5 𝑡ℎ of the area of the 1S (Area from 3.1.2) sign post Type 2 1 = 5 ×196 3,75  1CA = 392,75 𝑐𝑚2  (2) 3.2.1 V = 𝜋𝑟 2 ℎ h = 20 cm r = 10 cm  1A (r = 10 cm) V = 3,142 × 102 × 20  1SF V = 6 284 𝑐𝑚3  1S 1CA (3) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2017) MATHEMATICAL LITERACY P1 5 3.2.2 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑠𝑖𝑔𝑛 𝑝𝑜𝑠𝑡𝑠 2 × 𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑡ℎ𝑒 𝑝𝑎𝑖𝑛𝑡 = 1SF (𝐴𝑟𝑒𝑎 𝑜𝑓 𝑠𝑖𝑔𝑛 𝑝𝑜𝑠𝑡 𝑇𝑦𝑝𝑒 2 − 𝑎𝑟𝑒𝑎 𝑜𝑓 𝑒𝑛𝑐𝑙𝑜𝑠𝑒𝑑 𝑟𝑒𝑐𝑡𝑎𝑛𝑔𝑙𝑒) 2 × 6284 1S simplification = (1 963,75−392,75)  = 8 1CA (3) [13] QUESTION 4 [16 Marks] Quest Solution Explanation Marks 4.1.1 A  2R (2) 4.1.2 Allow any value between 85 ‒ 90 km  2 RM (2) 4.1.3 Highest point: UMLAAS RD  2 RM (2) 4.1.4 𝐷𝑖𝑠𝑡𝑎𝑛𝑐𝑒 85 1S Speed = = 12 = 7,08 km/h 𝑡𝑖𝑚𝑒 1CA 90 = 12 = 7,5 km/h Allow answer between (7,08 – 7,5) km/h  1A unit (km/h) (3) 4.2.1 Distance Cape Town to Durban 1M multiplication 1 : 16 000 000 1M division 70 mm : 16 000 000 x 70 mm  Distance = 16 000 000 x 70 ÷1000 000  =1 120 km  1A (with units) (3) 4.2.2 NW/𝑁𝑜𝑟𝑡ℎ 𝑊𝑒𝑠𝑡  2 Reading Map (2) 4.2.3 8  2 Reading Map (2) [16]

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/JUNE 2017) QUESTION 5 [17 Marks] Quest. Solution Explanation Marks 5.1 5.1.1 Bar graph  2 RG (2) 5.1.2 Ascending order 1M order 2,4; 2,4; 5,6; 9,7; 14,8; 17,4; 19, 7; 28, 0; 28,4; 31,6; 36,0  1M middle value Median = 17,4  2M middle values (2) 5.1.3 Mean = 2.3+0.7+5.1+17.3+25.6+28.8+15.8+13.4+15.5+5.5+4.6 M1 Addition 11 1M division by 11 134.6 = 11  = 12,24  1A (3) 5.1.4 The male age groups that have more than the upper quartile are 30‒34:  and 2 RG 35‒39  (Allocate 1 mark if % is given instead (36% and 28,8%) of age groups) (3) 5.2 5.2.1 10 260 829 + 461 934 + 713 856+ 2 063 128 + 2 315 279+49 277 + 377 231+271 895 + 409 881= 1M addition 16 923 309  1A (2) 5.2.2 1 266 102 1MA Value of B = 14 450 161 x 100 = 8,76 = 1A 8,8%  1M (100 ‒ the OR total of the other Value of B = 100% ‒ (57,0 + 3,1 +2,5 + %) 19,3 + 2,1 + 2,1 + 5,2) = 8,8%  CA (2) 5.2.3 P(flush toilet) = (60,6% + 2,7%)  1M = 63,3%  1S 1A OR 𝑡𝑜𝑡𝑎𝑙 𝑤𝑖𝑡ℎ 𝑓𝑙𝑢𝑠ℎ 𝑡𝑜𝑖𝑙𝑒𝑡 1SF (numerator P(flush toilet) = 𝑡𝑜𝑡𝑎𝑙 𝑜𝑓 𝑠𝑢𝑟𝑣𝑒𝑦 and denominator) 10 722 763  = × 100  = 63,4%  1M multiplication 16 923 309 with100 1CA (3) [17] TOTAL: 100 Copyright reserved Please turn over