Mathematics Grade 9 Gauteng November 2017 Memo

Downloaded from hlayiso.com testpapers.co.za GAUTENG DEPARTMENT OF EDUCATION GAUTENGSE DEPARTEMENT VAN ONDERWYS PROVINCIAL EXAMINATION PROVINSIALE EKSAMEN NOVEMBER / NOVEMBER 2017 GRADE / GRAAD 9 MATHEMATICS WISKUNDE MEMORANDUM 7 pages / bladsye 1

Downloaded from hlayiso.com Mathematics / Wiskunde MEMORANDUM GRADE / GRAAD 9 QUESTION / VRAAG 1 1.1 C 1.2 D 1.3 B 1.4 A 1.5 C 1.6 C 1.7 B 1.8 B 1.9 C 1.10 C QUESTION / VRAAG 2 2.1.1 1 for / vir a-2a ( ) ( ) 1 for / vir b-2b 1 for answer / vir antwoord 2.1.2 1 for / vir ( ) 1 for/ vir ( ) 1 for LCD /vir KGV ( ) ( ) 1 for answer / vir = ( )( ) antwoord = ( – )( – ) 2.1.3 1 for / vir ( )( ) 1 for multiply / vir maal ( )( ) 1 for / vir ( ) ( ) 1 for answer / vir antwoord 2

Downloaded from hlayiso.com Mathematics / Wiskunde MEMORANDUM GRADE / GRAAD 9 2.2.1 1 for / vir ( ) 1 for / vir ( ) 2.2.2 ( ) ( ) 1 for / vir ( )( ) 1 for / vir (x2 – 4) ( )( )( ) 1 for / vir ( )( )( ) 2.3.1 ( ) ( ) 1 for / vir 1 for / vir 1 for / vir 2.3.2 1 for / vir 1 for / vir QUESTION / VRAAG 3 3.1.1 1 for / vir 3.1.2 1 for / vir 1 for / vir OR 1 for / vir 3.1.3 1 for adding / vir optel 1 for / vir 3.1.4 1 for / vir 36 1 for / vir 3.1.5 1 for adding / vir optel 1 for / vir 3.2 A: R40 – R18,50 = R21,50 …. 1kg 1 for / vir 1 kg B: (0,5 x R21,50)+R4,25 = R15,00 1 for / vir R15,00 C: 3,5 x R21,50 = R75,25 R200 – R75,25 = R124,75 1 for / vir R124,75 3

Downloaded from hlayiso.com Mathematics / Wiskunde MEMORANDUM GRADE / GRAAD 9 QUESTION / VRAAG 4 4.1.1 1 for substitution / vir substitusie 1 for / vir 4 4.1.2 y = mx+c 1 for / vir m=4 y = 4x+1 1 for / vir 1 QUESTION / VRAAG 5 5.1 22; 28 1 for / vir 22 and 1 for / vir 28 5.2 Add 6 to the previous term to get the next term. / Die verskil 1 for answer / vir antwoord van 6 is by die vorige termyn bygevoeg om die volgende termyn te verkry. 5.3 Tn = 6n – 2 1 for substitution and 1 for the answer / 1 vir substitusie en 1 vir die antwoord 5.4 T10 = 6(10) –2 1 for substitution and 1 for = 58 the answer / 1 vir substitusie en 1 vir die antwoord 5.5 T = 6n – 2 1 for substitution / vir substitusie 76 = 6n – 2 1 for / vir 78 1 for the answer / vir die antwoord. 13 = n 4

Downloaded from hlayiso.com Mathematics / Wiskunde MEMORANDUM GRADE / GRAAD 9 QUESTION / VRAAG 6 6.1 1 1 for substitution / V = 2bxhxH vir substitusie 1 for answer / vir 1 antwoord = 2 x 48 cm x 20 cm x 72 cm = 34 560 cm3 6.2 1 1 for substitution / SA = 2( 2 b x h)  (b  s  s) x H vir substitusie (48 cm x 20 cm) 1 1 for substitution / = 2( 2 x 48 cm x 20 cm)  (48 cm  25 cm  25 cm) x 72 cm vir substitusie (48 cm + 50 cm) x = 960 + 7 056 72 cm = 8 016 cm2 1 for answer / vir antwoord 6.3 In Δ ABD 1 for Pythagoras theorem / vir (AD)2 = (AB)2 – (BD)2 Pythagoras theorem / teorie Pythagoras teorie = (25 cm)2 – (24 cm)2 1 for substitution / vir substitusie = 625 cm2 – 576 cm2 1 for / vir 49 cm2 = 49 cm2 1 for answer / vir antwoord  AD  7 cm OR / OF (AC)2 = (AD)2 + (DC)2 (Pythagoras) 1 for Pythagoros 2 2 theorem / vir (AD) = (AC) – (DC) Pythagoras teorie = (25 cm)2 – (24 cm)2 1 for substitution / vir substitusie = 625 cm2 – 576 cm2 1 for / vir 49 cm2 = 49 cm2 1 for answer / vir antwoord  AD  7 cm 5

Downloaded from hlayiso.com Mathematics / Wiskunde MEMORANDUM GRADE / GRAAD 9 QUESTION / VRAAG 7 7.1.1 Vertically Opposite angles / Vertikale teenoorgestelde hoeke 1 for reason / rede 7.1.2 1 for answer / antwoord 7.1.3 1 for answer / antwoord 7.1.4 CF or FC ; opposite the equal sides / teenoorgestelde van die 1 for CF / vir CF ewewydige sy 1 for reason / vir rede 7.2 2 Construct / konstrueer ∆ correctly / korrek E 1 Correct length, sizes / korrekte lengte, 6 cm groottes 3 cm 1 Labelling / etikettering FG, EF & F EG.  6,5 cm G 7.3.1 1 for answer / antwoord 1 for reason / rede 7.3.2 ( ) Corr. angles / Ooreenk hoeke 1 for answer / antwoord 1 for reason / rede Alt. angles / Verwiss hoeke 1 for answer / antwoord 1 for reason / rede Angles on straight line / Hoeke op reguit lyn 1 for answer / antwoord 1 for reason / rede 7.3.3 ( ) Corr. angles / Ooreenkomstige hoeke 1 for answer / antwoord 1 for reason / rede 1 for answer / antwoord Angles on straight lines / Hoeke op reguit 1 for reason / rede lyne Or / of Sum of angles of triangle. / Som van hoeke op driehoek. 6

Downloaded from hlayiso.com Mathematics / Wiskunde MEMORANDUM GRADE / GRAAD 9 7.4 1 for substitution / substitusie y = 45 x=4 1 for / vir 45 1 for / vir 4 QUESTION / VRAAG 8 8.1 132 132 141 142 155 156 161 162 163 169 170 172 1 all correct / almal reg 8.2.1 1 for / vir 1855 1 for answer / vir antwoord 8.2.2 1 for / vir 1 for answer / vir antwoord 8.2.3 132 1 for answer / vir antwoord 8.3 LENGTH OF LEARNERS AT SCHOOL / LENGTE VAN LEERDERS OP SKOOL 1 for / vir 2 1 for / vir 4 10 1 for / vir 1 9 8 7 6 5 4 3 2 1 0 130-140 140-150 150-160 160-170 170-180 8.4 BGB 1 for / vir BGB 1 for / vir BGG BGG 7