Physical Sciences Grade 11 2023 QP & Memo

Downloaded-from-hlayiso.com education Department: Education PROVINCE OF KWAZULU-NATAL AMAJUBA DISTRICT MARKS: 50 TIME: 1 hour This question paper consists of 7 pages and 1 data sheet.

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com INSTRUCTIONS AND INFORMATION Write your NAME and SURNAME in the appropriate spaces on the ANSWER BOOK provided. Answer Att the questions. You may use a non-programmable calculator. You may use appropriate mathematical instruments. Number the answers correctly according to the numbering system used in this question paper. Data sheets and a periodic table are attached for your use. Give brief motivations, discussions, et cetera where required. PAPER 1: PHYSICS QUESTION 1: Multiple choice questions Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the correct answer and write the letter (A — D) next to the question number (1.1 — 1.4) 1.1 1.2 The frictional force acting on a sliding object is ... A dependent of the apparent area of contact. B__ proportional to the normal force. C dependent of the velocity of object. D__ independent of the type of surface. (2) When a spaceship moves at constant velocity, it means that the resultant force acting on the body is zero. This phenomenon is best ined by Newton’s First Law. Newton’s Second Law. Newton's Third Law. 0 QO DBD > Newton's Universal Gravitational Law. (2) Page 2 of 10

1.3 00ND > Downloaded from hlayiso.com Downloaded from Stanmorephysics.com A learner pulls a block ata CONSTANT SPEED over a rough horizontal surface with a force F. The force diagram below shows all the forces acting on the block. Soh Y Z > Which ONE of the following relationships between the magnitudes of the forces F, X, Y and Z is true? > > nma.mnn 7 Y andX = Y andX < Y andX = Z Z Z Y andX < Z Page 3 of 10 (2) [6]

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 2 The diagram below shows three forces P, Q and R of 5 N, 3 N and 4 N respectively acting on an object in the same Cartesian plane. (2) 2.1. Give areason why the three forces are classified as vectors. 2.2 Determine the magnitude and direction of the resultant force, either by CALCULATION or by ACCURATE CONSTRUCTION AND MEASUREMENT. Use scale 10 mm: 1N (7) A box of weight (w) 60 N hangs on a ceiling as shown in the sketch below. A horizontal force F acts horizontally to the right through knot S. The knot S is in equilibrium. 2.3 Explain what is meant by the knot S is in equilibrium. (2) 2.4 Draw the triangle of the three forces T, F and w. Clearly label th s and all (3) the angles. 2.5 Calculate the magnitudes of the force F and the tension T. (4) [18] Page 4 of 10

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 3 A crate of mass 95 kg crate lies on a plank inclined at 23,2°. At this angle the crate is just about to move down the incline. Refer to the diagram below. 3.1 Define the term frictional force. (2) 3.2. Sketch a free body diagram showing the force(s) acting on the crate at its current (3) position. 3.3. CALCULATE: 3.3.1 The magnitude of the static frictional force (3) 3..3.2 The coefficient of static friction between the plank and the block. (5) 3.4 The plank is now tilted at an angle of 20.0°. State whether the static friction force will be LESS THAN; EQUAL TO; OR GREATER THAN Question 3.3.1 above. (1) [14] Page 5 of 10

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 4 A 6 kg block on a horizontal rough surface is joined to a 2 kg block by a light, inelastic string running over a frictionless pulley. The frictional force between the 6 kg block and the table is 11,76 N. Ado ards force F of 2 N is applied to the 2 kg block as indicated in the diagram below. 6kg l 2kg F=2N 4.1 State Newton’s Second Law of motion in words. (2) 4.2 Identify ONE action-reaction force pair acting on the 6 kg block. (2) 4.3, CALCULATE: 4.3.1 The magnitude of the acceleration of the 6 kg block. (5) 4.3.2 The magnitude of the tension (T) in the string connecting the two blocks (2) 4.4 The rough surface is replaced by a smooth frictionless surface. How will this change affect the answer in QUESTION 4.4.1? Write only INCREASES, DECREASES or REMAINS THE SAME. (1) [12]

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com DATA FOR PHYSICAL SCIENCES TABLE 1: PHYSICAL CONSTANTS = av SYMBOL VALUE Acceleratioiralg to gravity 8 9,8 m-s™ Universal gravitational constant G 6,67 x 10" N-m™-kg~ Electron mass Me 9,11 x 10°" kg Mass of Earth Me 5,98 x 10” kg Radius of Earth Re 6,38 x 10° m TABLE 2: FORMULAE MOTION Vp =v tat Ax =v At + dat? or/of Ay = v,At+ dadt? v, +Vv v, +Vv V, =v, + 2aAxor/ofv, =v, +2ady | Ax= (Sea or/of Ay = fem FORCE Fret = Ma w=mg fs¢maxy = HsN fx = KN F-S oR FS <S OR gS (aTaYay Page 9 of 10

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Downloaded from hlayiso.com PROVINCE OF KWAZULU-NATAL AMAJUBA DISTRICT MEMORANDUM This question paper consists of 7 pages and 1 data

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 1 11 BV ) 1.2 Cv him (2) 1.3 c rng (2) jaca — [6] QUESTION 2 21 They have both magnitude and direction. ¥W (2) 2.2 F, = Q+Rcos 45° =3+4cos45°V = 5,828 N, right F, = P —Rsin 45° =5-—4sin45°V = 2,172 N, up F, Fy net Fy F,, =F? +F; = 5,828" +2172 v =6,22N tang = ang = & 2,172 tan == vv 6 = 20,44° Resultant force = 6,22 NV in direction: 20,44° YOR Bearing 69,56°, N69,56°E or 20,44° North of East Page 2 of 6

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com 2.2 SCALE DRAWING: 3N Resultant = 6 N CRITERIA MARK Each angle correctly measured 1x2 Correct tail to head drawing of PQR 1x3 Resultant both magnitude and direction correct starting from origin to head of 1x2 vector R TOTAL | 7 MARKS 2.3 The resultant of all forces Y acting at point S is zero ¥ (2) 24 55° w 90° 35° (3) F e Correct shape of triangle VW e Forces labelled and point correct directions ¥ e Labelled angles are all correct V 25 sin35° == ACCEPT: oy Sine rule, sin35° = | cosine rule, T = 104,61 NY component method and tan 35° =t any other 60 trigonometric tan35 =>¥ method F = 85,69 NY [18] Page 3 of 6

Downloaded from hlayiso.com Downloaded from Stanmorephysics.com QUESTION 3 3.1 | The force that opposes the motion of an object Wand which acts par, ‘o the surface. ¥ (2) Fu 3.2 Other labels to be accepted: Normal/ N (3) | Friction/ f Weight/ gravity/ Fy wv 3.3 3.3.1 f; = mg sin 0Y (3) = 95,0 x 9.8 x sin 23.2°% = 366.76NY 3.3.2 N = mgcos OY N = 95.0 x 9.8 x cos 23.2°V N = 855.72N fo = Us NV¥ 366,76 = ux 855,72¥ Ms = 0,43 (5) 3.4 | Less than ¥ (1) [14] QUESTION 4 4.1 | When a resultant (net) force acts on an object, the object will (2) accelerate in the direction of the force. This acceleration is directly proportional to the forceY and inversely proportional to the mass of the object. ¥ is 4.2 Force of the block on the table “and the force of the table on the block. ¥ OR Force of the block on the string Y and the force of the string on the block. ¥ Page 4 of 6

Downloaded from Stanmorephysics.com Downloaded from hlayiso.com 4.3 = mav +(-f) =ma T = 11.76 = 60M over os oe (1) 2 kg: T F Ww Fret = ma w+F+(-T)=ma (2x 9.8) +2-—T = 2av 21,6 — TH 20 ore vee vve os (2) (5) (1) + (2): 9,84 = 8av¥ a=1,23m:s?v¥ 43.2 T—11,76=6(1,23)V Q) T=19,14 NY 4.4 | Increases V (1) [12] Page 5 of 6