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PROVINCIAL EXAMINATION/
PROVINSIALE EKSAMEN
NOVEMBER 2023
GRADE/GRAAD 11
MARKING
GUIDELINES/NASIENRIGLYNE
PHYSICAL SCIENCES: CHEMISTRY/
FISIESE WETENSKAPPE: CHEMIE
PAPER/VRAESTEL 2
9 pages/bladsye
P.T.O./ B.O.
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Gr 11 Physical Sciences P2 (ENG & AFR) 2023 Possible Answers_hlayiso.com_.pdf
Physical Sciences · Grade 11 · Gauteng November Exam · 2023. Memorandum, 9 pages. Read online or download the PDF.
- Subject
- Physical Sciences
- Grade
- Grade 11
- Document type
- Memorandum
- Year
- 2023
- Exam period
- Gauteng November Exam
- Paper
- 2
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- 9
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PHYSICAL SCIENCES: CHEMISTRY
MARKING GUIDELINES/ FISIESE WETENSKAPPE: CHEMIE
NASIENRIGLYNE PAPER/VRAESTEL 2 GRADE/GRAAD 11
QUESTION/VRAAG1
1.1 C ✓✓ (2)
1.2 B ✓✓ (2)
1.3 D ✓✓ (2)
1.4 A ✓✓ (2)
1.5 C ✓✓ (2)
1.6 A ✓✓ (2)
1.7 C ✓✓ (2)
1.8 D ✓✓ (2)
1.9 B ✓✓ (2)
1.10 B ✓✓ (2)
[20]
QUESTION/VRAAG 2
2.1 2.1.1.
✓✓ (2)
2.1.2.
✓✓ Without brackets only 1 mark/
(2)
✓✓ Sonder hakies slegs 1 punt
2.2. A covalent bond is a bond in which electron pairs are shared between the two
atoms to form a molecule. ✓✓
ʼn Kovalente binding is ʼn binding waar elektronpare gedeel word tussen twee
atome om ʼn molekule te vorm. ✓✓ (2)
2.3 Calcium/Ca ✓
Kalsium/Ca ✓ (1)
2.4 The bond between positive ions and delocalised valence electrons in a
metal. ✓✓
ʼn Binding tussen positiewe ione en gedelokaliseerde elektrone in ʼn metaal.✓✓ (2)
2
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PHYSICAL SCIENCES: CHEMISTRY
MARKING GUIDELINES/ FISIESE WETENSKAPPE: CHEMIE
NASIENRIGLYNE PAPER/VRAESTEL 2 GRADE/GRAAD 11
2.5 2.5.1 CO2/carbon dioxide ✓
CO2/koolstofdioksied ✓ (1)
2.5.2 CaO ✓ (1)
2.6 Electronegativity is a measure of the tendency of an atom in a molecule to
attract bonding electrons. ✓✓
Elektronegatiwiteit is die maatstaf van die neiging van ʼn atoom in ʼn molekuul
om bindingselektrone aan te trek. ✓✓ (2)
2.7 ΔEN = 3,5 – 1 = 2,5 ✓
∴ Ionic bond ✓/Ioniese binding✓ (2)
2.8 Non-polar molecule ✓/Nie-polêre molekule ✓ (1)
2.9 ΔEN = 3.5 – 2,5 = 1,0
∴ polar bond ✓/
∴ polêre binding ✓
But shape is symmetrical thus the molecule is polar ✓/Maar die vorm is
simmetries en dus is die molekule polêr. ✓ (2)
[18]
QUESTION/VRAAG 3
3.1 The temperature at which the vapour pressure of a substance equals
atmospheric pressure. ✓✓
Die temperatuur waarby die dampdruk van ʼn stof gelyk is aan die atmosferiese
druk. ✓✓ (2)
3.2 3.2.1 London/dispersion forces ✓
London/dispersiekragte ✓ (1)
3.2.2 I2 ✓ (1)
3.2.3 As the molecular mass increases, ✓
the strength of the intermolecular forces increases ✓
Therefore more energy is needed to overcome/weaken the
intermolecular forces. ✓ (no mark if BROKEN is used instead of
overcome or weaken)
Thus the boiling boiling point increases. ✓✓
Indien die molekulêre massa toeneem, ✓
word die sterkte van die intermolekulêre kragte groter. ✓✓
Meer energie word benodig om die intermolekulêre kragte te
oorkom/te verswak. ✓ (geen punte indien GEBREEK in plaas van
oorkom gebruik word nie.) (3)
3
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PHYSICAL SCIENCES: CHEMISTRY
MARKING GUIDELINES/ FISIESE WETENSKAPPE: CHEMIE
NASIENRIGLYNE PAPER/VRAESTEL 2 GRADE/GRAAD 11
3.3 3.3.1 NH3/ammonium ✓
NH3/ammoniak ✓ (1)
3.3.2 HCℓ/hydrogen chloride ✓
HCℓ/waterstofchloried ✓ (1)
[9]
QUESTION/VRAAG 4
4.1 What is the relationship between the pressure and volume of an enclosed
mass of gas, when the temperature is kept constant? ✓✓
Wat is die verband tussen die druk en volume van ʼn ingeslote massa gas,
indien die temperatuur konstant gehou word. ✓✓ (2)
4.2.1 Pressure ✓
Druk ✓ (1)
4.2.2 Temperature/mass of gas ✓
Temperatuur/massa van gas ✓ (1)
4.3 Boyle’s Law.✓ The pressure of an enclosed gas is inversely proportional to the
volume it occupies at a constant temperature ✓✓
Boyle se wet. ✓ Die druk van ʼn ingeslote gas is omgekeerd eweredig aan die
volume van die gas by ʼn konstante temperatuur. ✓✓ (3)
4.4 OPTION/OPSIE 1 OPTION/OPSIE 2
p1V1 = p2V2 ✓ p1V1 = p2V2 ✓
(200)(16,5) = (110)X ✓ (150)(1,65x 10-2) = (110)X ✓
X = 30 cm3 ✓ X = 3 x 10-2 dm3 ✓ (3)
4.5 At low temperatures, a real gas’s particles will occupy space and have
volume. ✓✓
By lae temperature sal ʼn werklike gas se deeltjies spasie inneem en volume
besit. ✓✓
OR/OF
The attraction and repulsive forces between the particles become
significant. ✓✓ Thus, a real gas will liquify at low temperatures.
Die aantrekkings- en afstotingskragte tussen deeltjies raak
noemenswaardig. ✓✓ Dus sal ʼn werklike gas vervloei by lae temperature. (2)
4.6 pV = nRT ✓
200 x 103 (50 x 10-6) ✓= n 8,31 (298) ✓
n = 0,00403 mol/4,30 x 10-3 mol ✓ (4)
4.7 The average kinetic energy of the molecules of the gas. ✓✓
Die gemiddelde kinetiese energie van die molekules van die gas. ✓✓ (2)
4
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PHYSICAL SCIENCES: CHEMISTRY
MARKING GUIDELINES/ FISIESE WETENSKAPPE: CHEMIE
NASIENRIGLYNE PAPER/VRAESTEL 2 GRADE/GRAAD 11
4.8 The volume of the container is constant thus: ✓
As the kinetic energy of the molecules of the gas increases, the number of
collisions on the sides of the container increases. ✓
Pressure will increase. ✓
Die volume van die houer is konstant dus: ✓
Soos wat die kinetiese energie van die molekules van die gas toeneem, sal
die aantal botsings teen die kante van die houer toeneem. ✓
Die druk sal toeneem. ✓ (3)
[21]
QUESTION/VRAAG 5
5.1 5.1.1 The simplest ratio in which the elements of the compound are bonded
to each other.✓✓
Die eenvoudigste verhouding waarin die elemente van ʼn verbinding
aanmekaar gebind is. ✓✓ (2)
5.1.2 O% = 100 – (60,0+ 4,44)
= 35,56%
𝑚 60,0
C: n= 𝑀 = 12 = 5 mol
𝑚 4,44
H: n= 𝑀 = = 4,44 mol
1
𝑚 35,56
O: n= 𝑀 = 16 = 2,22 mol
C : H : O
5 4,44 2,22
: :
2,22 2,22 2,22
2,25 : 2 :1
9 : 8 :4
Empirical formula/Empiriese formule: C9H8O4 (6)
5.1.3 M(C9H8O4) = 9(12) + 8(1) + 4(16)
= 180 g.mol-1
molar mass/molêre mass 180
= =1
emprical mass/empiriese massa 180
molecular formula/molekulêre formule: C9H8O4 (2)
5.2 M (Na2CO3) = 106g·mol-1
M (x H2O) = 268 – 106 = 162g·mol-1
n(H2O) =m/M =162/18
n(H2O) = 9 mol (4)
[14]
5
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PHYSICAL SCIENCES: CHEMISTRY
MARKING GUIDELINES/ FISIESE WETENSKAPPE: CHEMIE
NASIENRIGLYNE PAPER/VRAESTEL 2 GRADE/GRAAD 11
QUESTION/VRAAG 6
6.1 6.1.1 The limiting reagent is the reactant that is used up first.
Die beperkende reagens is die een wat eerste opgebruik word. ✓✓ (2)
6.1.2 n(KCl) = cV
= 0,25 (0,055)
= 0,0138
n(AgNO3) = cV
= 0,15(0,07)
= 0,0105
KCℓ : AgNO3
1 : 1
0,0105 : 0,0105
AgNO3 is the limiting reagent/die beperkende reagens (5)
6.1.3 n(AgCl) = n(AgNO3) = 0,0105 mol
m = nM
= 0,0105(143,5)
= 1,51 g (4)
𝑚
6.2 6.2.1 n(CaCO3) =
𝑀
50
= 100
= 0,5 mol (3)
6.2.2 𝑚 18,2
n(CO2) = 𝑀 = 44
= 0,414 mol
n(CaCO3) = n(CO2) = 0,414 mol
m(CaCO3) = nM
= 0,414(100)
= 41,4 g
41,4
% purity/suiwerheid = 50 x 100
= 82,8% (5)
m
6.2.3 % purity/suiwerheid = 70% = 50
m = 35 g CaCO3
𝑚 35
n(CaCO3) = 𝑀 = 100
= 0,35 mol
n(CO2) = n(CaCO3)
= 0,35 mol
m(CO2) = nM
= 0,35(44)
= 15,4 g (5)
[24]
6
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PHYSICAL SCIENCES: CHEMISTRY
MARKING GUIDELINES/ FISIESE WETENSKAPPE: CHEMIE
NASIENRIGLYNE PAPER/VRAESTEL 2 GRADE/GRAAD 11
QUESTION/VRAAG 7
7.1 7.1.1 An acid is a proton (H+ ion) donor.
ʼn Suur is ʼn proton (H+- ioon) skenker. ✓✓ (2)
7.1.2 It ionises to form 2 protons/2 moles of H+ ions. /
Dit ioniseer om 2 protone/2 mol H+ ione te vorm. ✓✓
OR/OF
It donates 2 H+ ions per H2SO4 molecule.
Dit skenk 2 H+ ione per H2SO4 molekule. (2)
7.1.3 Ampholyte
Amfoliet (1)
7.2 7.2.1 A solution of precisely known concentration.
ʼn Oplossing waarvan die konsentraise presies bekend is. (2)
7.2.2 H2SO4(ℓ) + 2H2O(ℓ) → 2H3O+(aq) + SO2-4 (aq)
(balancing/balansering) (3)
7.3 7.3.1 na c V
= c a Va
nb b b
1 c (0,012)
a
= 0,2
2 (0,02)
ca = 0,17 mol.dm-3 (5)
7.3.2 Methyl orange , reaction of strong acid and strong base .
Metieloranje , reaksie van ʼn sterk suur en ʼn sterk basis. (3)
[18]
QUESTION/VRAAG 8
8.1 Endothermic✓
Endotermies (1)
8.2 The Products have more Potential energy than the reactants. ✓✓
Die produk het meer Potensiële energie as die reaktante.
OR/OF
More energy is absorbed than released ✓✓
Meer energie word geabsorbeer as vrygestel. ✓✓ (2)
8.3 + 14,8 kJ.mol-1✓✓ without a + sign only 1 mark/sonder ʼn + teken slegs een
punt (2)
8.4 4+6✓ (1)
8.5 the minimum energy needed for a reaction to take place. ✓✓
die minimum energie benodig vir ʼn reaksie om plaas te vind, ✓✓ (2)
7
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PHYSICAL SCIENCES: CHEMISTRY
MARKING GUIDELINES/ FISIESE WETENSKAPPE: CHEMIE
NASIENRIGLYNE PAPER/VRAESTEL 2 GRADE/GRAAD 11
8.6 3✓ (1)
8.7 It decreases the activation energy, ✓
by providing an alternative pathway for the reaction. ✓
Dit verminder die aktiveringsenergie, ✓
deur ʼn alternatiewe roete vir die reaksie te skep. ✓ (2)
NOTE/LET WEL:
8.8
✓ Dotted line from
reactants to products
✓ Stippellyn van
reaktante na produkte
✓ Lower that 3 and
higher than 4
✓ Laer as 3 en hoër as 4
Course of the reaction/verloop van
die reaksie (2)
[13]
QUESTION/VRAAG 9
9.1 9.1.1 An increase in the oxidation number.
ʼn Toename in die oksidasiegetal. (2)
9.1.2 +6 (2)
9.2 9.2.1 Electrons are transferred. /
Elektrone word oorgedra.
OR/OF
The oxidation number of Fe2+/Cℓ2 changes.
Die oksidasiegetal van Fe2+/Cℓ2 verander.
OR/OF
Fe2+ is oxidised/Cℓ2 is reduced.
Fe2+ is geoksideer/Cℓ2 is gereduseer. (1)
9.2.2 Fe2+ The oxidation number increases from +2 to +3.
Fe2+ Die oksidasiegetal neem toe van +2 na +3.
(2)
9.2.3 Cℓ2 + 2e- → 2Cℓ- (2)
9.2.4 Cℓ2 + 2e- → 2Cℓ-
Fe2+ → Fe3+ + e-
2Fe2+ + Cℓ2 → 2Fe3+ + 2Cℓ- (balancing/balansering) (4)
[13]
TOTAL/TOTAAL: 150
8
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PHYSICAL SCIENCES: CHEMISTRY
MARKING GUIDELINES/ FISIESE WETENSKAPPE: CHEMIE
NASIENRIGLYNE PAPER/VRAESTEL 2 GRADE/GRAAD 11
TAXONOMY GRID
Recall Comprehension Analysis Evaluation
Q no: Mark Q no: Mark Q no: Mark Q no: Mark
1.1 2 1.3 2 1.2 2
1.7 2 1.4 2 1.5 2
1.6 2 1.10 2
1.8 2
1.9 2
2.2 2 2.1.1 2 2.7 2
2.1.2 2 2.9 2
2.3 1 2.4 2
2.6 2 2.5 2
2.8 1
3.1 2 3.2.1 1
3.2.2 1
3.2.3 3
3.3.1 2
4.7 2 4.1 2 4.4 3 4.8 3
4.2 2 4.6 4
4.3 3
4.5 2
5.1.1 2 5.1.2 6 5.2 4
5.1.3 2
6.1.1 2 6.1.2 5
6.1.3 4
6.2.1 3
6.2.2 5
6.2.3 5
7.1.1 2 7.1.2 2 7.3.1 5
7.1.3 1 7.2.1 3 7.2.2 2
7.3.2 3
8.1 1 8.2 2 8.8 2
8.5 2 8.3 2
8.4 1
8.6 1
8.7 2
9.1.1 2 9.1.2 2
9.2.1 1
9.2.2 2
9.2.3 2
9.2.4 4
Actual Total 15% 23 43% 64 37% 56 5% 7
Target Total 15% 15 40% 40 35% 35 10% 10
9
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