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GAUTENG DEPARTMENT OF EDUCATION
PROVINCIAL EXAMINATION
2016
GRADE 11
MATHEMATICS
Second Paper
MEMORANDUM
11 pages
1
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Mathematics Grade 11 Paper 2 Gauteng June 2016 Memo
Grade 11 Mathematics Paper 2 memorandum from the Gauteng June 2016, 11 pages. Read online or get the free PDF download, question paper linked when available.
Mathematics · Grade 11 · Gauteng June · 2016. Memorandum, 11 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 11
- Document type
- Memorandum
- Year
- 2016
- Exam period
- Gauteng June
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 11
- File size
- 1.1 MB
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Gauteng June 2016
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MEMORANDUM Mathematics P2
GAUTENG DEPARTMENT OF EDUCATION
PROVINCIAL EXAMINATION
MATHEMATICS
(Second Paper)
INFORMATION:
A – Accuracy
C.A. – Continued Accuracy
S – Statement
R – Reason
S and R – Statement and Reason
2
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MEMORANDUM Mathematics P2
QUESTION 1 MARKS : 16
1.1 KT = Distance formula
= subst. in corr. formula
answer
=
[2/3 if answer not in surd form]
(3)
1.2
answer
=
subst. (-5 ; 1) into str. line eq.
answer (C.A)
OR
OR
answer
= subst. (7 ;-2) into str. line eq.
answer (C.A)
(3)
1.3
=
answer (A)
eq. of Line KT. (A) OR y-int
A (0 ; ) of line KT.
B (0 ; - )
1 1
AB = 5
6 4 add of y co-ord. of A and B
5 65 answer (A)
=5 OR 5,42 OR (4)
12 12
3
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MEMORANDUM Mathematics P2
1.4
β = 39,81°
β = 39,81°
= α=
........ext. of ∆
=
answer
ANY other valid solution
(PENALISE once for rounding
off , either α or β)
(6)
QUESTION 2 MARKS : 14
2.1 Let M (x ; y)
...... radii
corr. Subst. in dist. formula
simplification (C.A)
answer
(4)
Answer only 0
2.2 A(
subst. in midpt. formula
y=0
co-ord. of A
A(0 ; 4)
[2/3 if not in co-ordinate form]
(3)
2.3
Eq. of line OK:
corr. subst. in str. line formula
answer (C.A)
(3)
4
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MEMORANDUM Mathematics P2
2.4 Let T (x ; y)
......⟘ lines
...................(1)
Eq. of line OK
....................(2)
equating (1) and (2)
= answer (C.A)
(4)
Any other valid method
QUESTION 3 MARKS 28
3.1
13sinα = -5
sinα = - sinα = -
y
α
x
cartesian plane with terminal
arm in 3rd quad.
= –12 x = –12
3cosα
= 3(
subst. cosα =
=
answer
(5)
5
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MEMORANDUM Mathematics P2
3.2.1
-sin θ ; -tan θ ; cos θ ;
= – tan = –
=
=
or
(6)
3.2.2
-sin 50
=
– sin 30 ;
= cos 40 ;
– cos 40 or cos 40 = sin 50
= -1 – cos 60
answer
(6)
3.3
factorization
(4 θ – 8) sin 30° = (θ – 2) (2)
sin 30° =
factorization of denominator
=
answer
=
6
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MEMORANDUM Mathematics P2
60o 2
1
30o
3
tan 240° = tan (180° + 60°)
= tan 60° tan 60
= 3 answer
Full marks if tan 60° = 3 or
Show sketch to determine sol.
Answer only max 1 mark(surd
form)
(5)
3.4.1 1
L.H.S: (sinα tan α cos α)
tan x cos
sin α +
cos tan
= sin α +
tan
cos sin
= sin α + subst. tan α =
sin cos
cos
cos 2
cos 2 sin
= sin α +
sin
sin 2 cos 2
sin 2 cos 2 sin
=
sin
(4)
1
= =R.H.S
sin
Any other valid method
3.4.2 α = {0°; 90°; 180; 270° ; 360°} 0 ; 180°; 360°
90°; 270°
(2)
7
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MEMORANDUM Mathematics P2
QUESTION 4 MARKS 12
4.1 180 answer
(1)
4.2 -1 ;1
corr. brackets
OR OR
R -1 ;1
corr. inequalities
(2)
4.3 θ = 40
a =2 2
(2)
4.4 g(180 ) = – 0,77 answer (C.A)
(1)
4.5.1
-180 ; -103,3
-180 OR corr. inequality OR
[-180 ; - 103,3°) corr. bracket
OR
(16,7 ; 130 ) or (136,7 ; 180 ]
(2)
4.5.2
[–130° ;- 90°] OR [-130° ; -90°]
–130° ≤ x ≤ –90° corr brackets OR
corr. inequalities
[0 ;50 ] or [90 ;180]
(2)
4.6
=
=
OR answer
=
(2)
8
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MEMORANDUM Mathematics P2
QUESTION 5 MARKS 8
5.1 is perpendicular to the chord answer
(1)
5.2.1 AD = ... th. of pyth. Subst.
=
= 28,84 cm answer
(2)
5.2.2 OD = x + 16 answer
(1)
5.2.3 ......... th. of pyth
OC = OD .....radii
=
x = 10 simplification
answer
(4)
QUESTION 6 MARKS 8
6.1 PT = KT ...... line from centre ⟘ to ch. S
R
(2)
6.2 ....... th. of pyth. S
but ..... th. of pyth.
but OK = OC ..... radii subst. OK = OC
= \ subst.OP = OC – PC
= PC OC OC 2OC.PC PC2
2 2 2
simplification
= 2(OC.PC)
= 2(x + y)(y)
= subst. for OC and PC
(6)
9
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MEMORANDUM Mathematics P2
QUESTION 7 MARKS 14
7.1 .......... ⎿ at centre = 2 ⎿ on circum. Reason
=
= 55 answer
(2)
7.2 S
....... ⎿s opp = sides, radii
R
=
answer
= 35
Answer with reason full marks
(3)
7.3
R2 R3 R2 R3 ⎿s opp = sides
R 2 35 20
answer
= 15
S and R
........ ⎿s in same seg
= 15 answer
= 45 (3)
7.4 ......... vert opp. ⎿s
= 90 S and R
answer
........ ⎿s of a ∆
= S and R
=
OR answer
OR
........ ⎿s of a ∆
S and R
=
= 45 answer
......... ⎿s in the same seg.
= 45 S and R
answer
(4)
10
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MEMORANDUM Mathematics P2
7.5
R
TR ⫽ PQ ....... alt. ⎿s =
OR OR
TRP 45 TRP P
R
TRP P 45
TR ⫽ PQ ....... alt. ⎿s = (2)
11
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