Physical Sciences Grade 11 P1 Gauteng November 2019 Memo

Downloaded from hlayiso.com testpapers.co.za NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 11 PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) NOVEMBER 2019 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 These marking guidelines consist of 13 pages./ Hierdie nasienriglyne bestaan uit 13 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 2 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.1 B  (2) 1.2 C  (2) 1.3 A  (2) 1.4 B  (2) 1.5 B  (2) 1.6 C  (2) 1.7 D  (2) 1.8 B  (2) 1.9 A  (2) 1.10 D  (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 3 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 2/VRAAG 2 2.1 F net = 0/Object in equilibrium/Resultant is zero  F net = 0/Voorwerp in ewewig/Resultant is nul. (2) 2.2 w = mg = (15)(9,8)  = 147 N  (2) 2.3 T w 40º F Accepted Labels/Aanvaarbare byskrifte Mark/Punt w weight/F g /F  gewig/gravitasiekrag/swaartekrag F Applied force/F/F A/ Toegepaste krag  T Tension/T/Spanning  Any angle correctly shown (40° or 50° or 90°)  Enige hoek korrek aangedui (40° of 50° of 90°) Triangle not closed/Driehoek nie geslote nie: Max./maks. 3 4 (4) 2.4 POSITIVE MARKING FROM QUESTION 2.2. POSITIEWE NASIEN VANAF VRAAG 2.2. OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 w w T= T= sin 40° cos 50° 147 147 =  =  sin 40° cos 50° = 228,69 N  = 228,69 N  (2) 2.5 The two forces act on the same object (the billboard).  (For the Newton's third law, the forces act on different objects.) Die twee kragte werk op dieselfde voorwerp (die bord) in. (Vir Newton se derde wet moet die kragte op verskillende voorwerpe inwerk.) (1) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 4 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 3/VRAAG 3 3.1 Marking guidelines/Nasienriglyne If any of the underlined key words/phrases are omitted: minus 1 mark Indien enige van die onderstreepte sleutelwoorde/frases uitgelaat is: minus 1 punt A body will remain in its state of rest or motion at constant velocity unless a non-zero resultant/net force acts on it.  'n Liggaam sal in sy toestand van rus of beweging teen konstante snelheid volhard tensy 'n nie-nul resulterende/netto krag daarop inwerk. (2) 3.2 N F w Accepted Labels/Aanvaarbare byskrifte w weight/F G /F g  gewig/gravitasiekrag/swaartekrag N Normal force/F N /Normaalkrag/F N  F Force applied/ F /F A /Toegepaste krag  Any additional forces/Enige addisionele kragte: Max./maks. 2 3 If arrows do NOT touch object/Indien pyle NIE voorwerp raak NIE: Max./maks. 2 3 (3) 3.3. 3.3 F g┴ = mgcos θ  = (4)(9,8)cos 30° = 33,95 N  (3) 3.3.2 F net = ma  Any one/Enige een F - Fg // = 0 F - (4)(9,8)sin 30° = 0  = 19,6 N  (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 5 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne 3.4 3.4.1 F net = ma  Any one/Enige een F - f k - Fg // = ma 25 - f k - 4(9,8)sin 30º  = 4(0,2)  f k = 4,6 N  (4) 3.4.2 POSITIVE MARKING FROM QUESTION 3.3.1 and 3.4.1. POSITIEWE NASIEN VANAF VRAAG 3.3.1 en 3.4.1. fk = µkN  4,6 = µ k (33,95)  µ k = 0,135  (3) 3.5 3.5.1 Same in magnitude  and same in direction  Dieselfde grootte en dieselfde rigting (2) 3.5.2 Increasse in magnitude  and opposite direction  Toeneem in grootte en teenoorgestelde rigting (2) 3.5.3 Same in magnitude  and opposite direction  Dieselfde grootte en teenoorgestelde rigting (2) [24] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 6 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 4/VRAAG 4 4.1 Marking guidelines/Nasienriglyne If any of the underlined key words/phrases are omitted: minus 1 mark Indien enige van die onderstreepte sleutelwoorde/frases uitgelaat is: minus 1 punt When a resultant/net force act on an object, the object will accelerate in the direction of the force at an acceleration directly proportional to the force and inversely proportional to the mass of the object.  Wanneer 'n resulterende/netto krag op 'n voorwerp inwerk, sal die voorwerp in die rigting van die krag versnel teen 'n versnelling direk eweredig aan die krag en omgekeerd eweredig aan die massa van die voorwerp. (2) 4.2 N f T w (4) Accepted Labels/Aanvaarbare byskrifte w weight/F g /gewig/gravitasiekrag/swaartekrag  N Normal force/F N/ Normaalkrag/F N  T Tension/Spanning  f Friction/F f/ Wrywing  Any additional force/Enige addisionele krag: Max./maks. 3 4 If arrows do NOT touch object/Indien pyle NIE voorwerp raak NIE: Max./maks. 3 4 (4) 4.3 6 kg block/blok: Marking guidelines/Nasienriglyne F net = ma  • Formule/Formule: F net = ma  T - f k = ma • T – F k = T – 24  T - 24  = 6a  • F g - T = 3(9,8) – T  T = 6a + 24 …….(1) • 3a OR/OF 6a  • Equating two equations or 3 kg block/blok: substitute one into the other/Stel F net = ma twee vergelykings gelyk aan F g - T = ma mekaar of vervang die een in die (3)(9,8) - T  = 3a ……….(2) ander.  • Final answer/Finale antwoord: 0,6 m·s-2  (6) Substitute (1) into (2)/Vervang (1) in (2): 29,4 - (6a + 24) = 3a  a = 0,6 m·s-2  4.4 The velocity changes with 0,6 m·s-1 during every second.  Die snelheid verander met 0,6 m·s-1 gedurende elke sekonde (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 7 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne [14] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 8 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5 5.1 M g is directly proportional to . R2 M g is direk eweredig aan . R2 (1) 5.2 Any two points from the graph can be used for example: Enige twee punte vanaf die grafiek kan gebruik word byvoorbeeld: 9−0  Gradient = 1,35 × 1011 − 0  = 6,67 x 10-11  OR/OF 10 − 0 Gradient = 1,5 × 1011 − 0 = 6,67 x 10-11 OR/OF 20 − 0 Gradient = 3 × 1011 = 6,67 x 10-11 (3) 5.3 G / Gravitational constant  G / Gravitasie konstante (1) 5.4 1,35 x 1011 (kg∙m-2)  Range/Gebied: 1,34 – 1,36 x 1011 (kg∙m-2) (2) 5.5 POSITIVE MARKING FROM QUESTION 5.4. POSITIEWE NASIEN VANAF VRAAG 5.4. OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 M GM 2 = 1,35 x 1011 g= 2 R R M 11 6,67 × 10 11M = 1,35 x 10  9 =  (2,54 × 10 7 ) 2 (2,54 × 10 7 ) 2 M = 8,71 × 1025 kg  M = 8,71 × 1025 kg  25 (8,7097 × 10 kg) (8,705 × 1025 kg) (2) [9] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 9 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 6/VRAAG 6 6.1 Marking guidelines/Nasienriglyne If any of the underlined key words/phrases are omitted: minus 1 mark Indien enige van die onderstreepte sleutelwoorde/frases uitgelaat is: minus 1 punt The angle between the normal to a surface and the refracted light ray.  Die hoek tussen die normaal op die oppervlak en die gebreekte ligstraal. (2) 6.2 n i sin θ i = n r sin θ r  1sin 38º = 1,5sin θ r  θ r = 24,23º  (3) 6.3 Marking criteria/Nasienriglyne: • Light ray bends towards normal.  Ligstraal breek na normal toe. 38º • Angle of refraction correctly shown.  θr Brekingshoek korrek aangetoon. (2) 6.4 n i sin θ i = n r sin θr 1,5sin 36° = n r sin 41º  n r = 1,34  (2) 6.5 Smaller than  Kleiner as (1) 6.6 For a constant speed of light, c,  the refractive index is inversely proportional to the speed of light in the medium (v).  Therefore, the higher the refractive index, the lower the speed (v). Vir 'n konstante spoed van lig, c, is die brekingsindeks omgekeerd eweredig aan die spoed van lig in die medium (v). Dus, hoe groeter die brekingsindeks, hoe kleiner die spoed (v). (2) 6.7 The angle of incidence when the angle of refraction is 90º.  Die invalshoek wanneer die brekingshoek gelyk is aan 90º. (2) 6.8 Total internal reflection occurs  because the light ray passes from an optical denser to less dense medium  and the angle of incidence is greater than the critical angle.  Totale interne weerkaatsing vind plaas omdat die ligstraal van 'n opties meer dig na minder digte medium beweeg en die invalshoek is groter as die grenshoek. (3) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 10 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 7/VRAAG 7 7.1 Marking guidelines/Nasienriglyne If any of the underlined key words/phrases are omitted: minus 1 mark Indien enige van die onderstreepte sleutelwoorde/frases uitgelaat is: minus 1 punt A wave front is an imaginary line joining the points on a wave that are in phase.  'n Golffront is 'n denkbeeldige lyn wat punte op 'n golf, wat in fase is, verbind. (2) 7.2 Wave nature  Golfgeaardheid (1) 7.3.1 Slit width  Spleetwydte (1) 7.3.2 Colour of light/Wavelength of light  Kleur van lig/Golflengte van lig (1) 7.4 Wavelength increases from blue to red light.  λ (Degree of) diffraction α  w For the same slit width,  degree of diffraction increases with wavelength.  Golflengte neem toe van blou na rooi lig. λ (Mate van) diffraksie α w Vir dieselfde spleetwydte, sal mate van diffraksie toeneem met langer golflengte. (4) 7.5 Increases  (Degree of) diffraction is inversely proportional to slit width  Afneem (Mate van) diffraksie is omgekeerd eweredig aan spleetwydte (2) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 11 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 8/VRAAG 8 8.1 Marking guidelines/Nasienriglyne If any of the underlined key words/phrases are omitted: minus 1 mark Indien enige van die onderstreepte sleutelwoorde/frases uitgelaat is: minus 1 punt The magnitude of the electrostatic force exerted by two point charges on each other is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.  Die grootte van die elektrostatiese krag wat deur twee puntladings op mekaar uitgeoefen word, is direk eweredig aan die produk van die grootte van die ladings en omgekeerd eweredig aan die kwadraat van die afstand tussen hulle. (2) 8.2 kQ 1Q 2 F=  r2 (9 × 10 9 )( 4,2 × 10 −6 )(6,8 × 10 −6 ) =  (0,3)2 = 2,86 N  (3) 8.3 Q1 + Q 2 Q= 2 4,2 × 10 −6 + ( −6,8 × 10 −6 ) =  2 = -1,3 × 10-6 C  (2) 8.4 Criteria for marking/Nasienkriteria Charges correctly indicated  Ladings korrek aangedui - - Shape of the field  Vorm van veld Direction of the field  Rigting van veld NOTE/LET WEL: IF lines don't touch charges or lines cross etc. INDIEN lyne nir doe ladings raak nie of lyne kruis ens. Max./maks. 2 3 (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 12 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne 8.5 POSITIVE MARKING FROM QUESTION 8.4. POSITIEWE NASIEN VANAF VRAAG 8.4. kQ E= 2  r (9 × 10 9 )(1,3 × 10 −6 ) = 0,4 2  -1 = 73125 N·C right (9 × 10 9 )(1,3 × 10 −6 ) E=  0,12 = 1170000 N·C-1 right E net = 73 125 + 1 170 000  = 1 243 125 N·C-1  (5) [15] QUESTION 9/VRAAG 9 9.1 Faraday's law of electromagnetic induction  Faraday se wet van elektromagnetiese induksie (1) 9.2.1 ΔΦ = ΔBAcos θ  = (2,8 x10-3)(2,5)(cos 90º - cos 0º)  = -0,007 Wb  (3) 9.2.2 POSITIVE MARKING FROM QUESTION 9.2.1. POSITIEWE NASIEN VANAF VRAAG 9.2.1. N∆φ ε= −  ∆t 200( −0,007 ) 3,5 = −  ∆t Δt = 0,4 s  (3) 9.3 Emf will be halve/two times smaller  Emf is directly proportional to number of windings  Emk sal die helfte wees/twee keer kleiner Emk is direk eweredig aan die aantal windings (2) [9] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 13 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne QUESTION 10/VRAAG 10 10.1 Marking guidelines/Nasienriglyne If any of the underlined key words/phrases are omitted: minus 1 mark Indien enige van die onderstreepte sleutelwoorde/frases uitgelaat is: minus 1 punt The potential difference across a conductor is directly proportional to the current in the conductor at constant temperature.  Die potensiaalverskil oor die ente van 'n geleier is direk eweredig aan die stroom in die geleier by konstante temperatuur. (2) 10.2 More resistors connected in parallel.  Therefor the effective resistance of the circuit decreases.  Meer resistors verbind in parallel. Daarom neem die effektiewe weerstand van die stroombaan af. (2) 10.3 10.3.1 Any set of values form the table can be used for example: Enige stel waardes vanaf die tabel kan gebruik word byvoorbeeld: V R=  I 4,8 =  2,4 =2Ω (3) 10.3.2 POSITIVE MARKING FROM QUESTION 10.3.1. POSITIEWE NASIEN VANAF VRAAG 10.3.1. OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 OPTION 3/OPSIE 3 Switched 1 closed: Switches 1 and 2 closed: Switches 1, 2 and 3 closed Skakelaar 1 gesluit: Skakelaar 1 en 2 gesluit: Skakelaar 1, 2 en 3 gesluit R tot = 3 + 2  1 1 1 1 1 1 1 =5Ω = + = + + R p R1 R 2 R p R1 R 2 R 3 V emf = IR tot  1 1 1 1 1 = + = + + = (2,4)(5)  3 6 3 6 4 = 12 V  Rp = 2 Ω R p = 1,33 Ω R tot = 2 + 2  = 4 Ω R tot = 1,33 + 2  = 3,33 Ω V emf = IR tot  V emf = IR tot  = (3)(4)  = (3,6)(3,33)  = 12 V  = 12 V  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe/V1 14 DBE/November 2019 CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne 10.4 Power is the rate at which work is done or energy is transferred.  Drywing is die tempo waarteen arbeid verrig word of energie oorgedra word. (2) 10.5 POSITIVE MARKING FROM QUESTION 10.3.1 AND 10.3.2. POSITIEWE NASIEN VANAF VRAAG 10.3.1 EN 10.3.2. V ll = V emf - V series = 12 – 6  =6V OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 OPTION 3/OPSIE 3 V2 V V P = ll  I= I= R R R 6 6 62 I= I= =  6 6 6 = 1A = 1A =6W P = VI  P = I2R  = 6(1)  = 12(6)  =6W =6W (4) 10.6 Increase/ Neem toe  (1) 10.7 (As more resistors are connected in parallel, the effective resistance decreases and the current increases.) From P = I2R, power is directly proportional to I2 if R (of the bulb) stays constant. Increase in power increases brightness.  (Soos meer resistors in parallel verbind word, neem die effektiewe weerstand af en die stroom neem toe.) Volgens P = I2R is die drywing direk eweredig aan I2 indien R (van die gloeilamp) konstant bly. Toename in drywing verhoog helderheid.  (2) [20] TOTAL: 150 Copyright reserved/Kopiereg voorbehou