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Mathematics Grade 11 NC March Test 2026 Paper & Memo

Question paper and memoMathematicsGrade 11202613 pages

Grade 11 Mathematics question paper and memo from the NC March Test 2026, 13 pages. Read online or get the free PDF download.

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DEPARTMENT OF EDUCATION DEPARTEMENT VAN ONDERWYS LEFAPHA LA THUTO ISEBE LEZEMFUNDO PUNTE/MARKS: 75 TYD/TIME: 1% uur/hours Hierdie vraestel bestaan uit 5 bladsye./ This question paper consists of 5 pages. Kopiereg voorbehou/ ~ Blaai om asseblief/ Copyright reserved Please turn over
Downloaded from Stanmorephysics.com 2 Mathematics/Grade 11 NCDOE/March 2026 INSTRUCTIONS: 1. — This test consists of 3 QUESTIONS. Answer ALL the questions. 2. . Number the answers correctly according to the numbering system used in this test. 3. \ Clearly show ALL calculations, diagrams, graphs, etcetera that you used in determining the answers. 4. — Answers only will NOT necessarily be awarded full marks. . 5. You may use an approved calculator. — 6. Write neatly and legibly. Copyright Turn the page
Downloaded from Stanmorephysics.com Mathematics/Grade 11 QUESTION 1 3x? -5x=4 x+V¥x-2=2 x(x-4) >3(x-4) (correct to TWO decimal places) 10 get ge ot 1.1.4 9 matey 115 (&-3)? =9 @ i 242.7 , calculate the value(s) P 1.3 Solve for x and y: 2x-y=1 and = y?—xy=x+7 QUESTION 2 21 x+3 Ii-P= , determine the value(s) of x for which: x5 2.1.1 P is undefined. 2.1.2 P not real. 2.2 ‘the use of a calculator: 23 r—4 _ 63 -V28 that x=2 and y=7. Show ALL your calculations. Copyright NCDOE/March 2026 (3) (4) (4) (3) (4) (4) (6) [28] (a) (2) (3) (4) = aly , where x,y¢R proof WITHOUT the use of a calculator (3) Turn the page
Downloaded from Stanmorephysics.com 4 Mathematics/Grade 11 NCDOE/March 2026 24 Given ax’+bx+e=0 with a>0;b<0 and c<0. [ 241) Determine the nature of the roots. (2) (24,2 Make a rough draft of your answer in 2.4.1 (2) 2.5 Determine the value of p, if x* +2px+5p+6=0 have no real roots. (3) [20] QUESTION 3 Si Determine in which quadrant will the cos@>0 and tan@<0. qd) a2 x 3.2.1 Determine the y—coordinate of P. (3) 32:2 Hence, determine the value of the following, WITHOUT the use of a calculator: (a) sin@ (2) (b) tan’ 9-3 (2) 33) Solve the nest equestion, correct to ONE decimal place. 33.1 sin a = tan32° (2) 3.3.2 cos(2+10°) = 0,866 (3) Copyright Turn the page
Downloaded from Stanmorephysics.com Mathematics/Grade 11 NCDOE/March 2026 3.4 Determine the value of the following expression, WITHOUT the use of a calculator, show ALL your calculations. \/1—cos’ 30° (3) 3.5 Simplify the following: 3.5.1 J2.1an150°.cos225°.sin 300° 6) 3.5.2 tan(@ -180°).cos?(180+ 4) cos(90° +6) (6) [27] TOTAL: 75 Copyright Turn the page
Downloaded from PRNEOEE F Na com Mathematics/Grade 11 NCDOE/March 2026 INFORMATION SHEET — bi Nb? ~4ac 2a A=P(l+ni) A= P(i-ni) A=P(l-i)" A=P(I+i)" T,=a4+(n-Nd S, =FRa+m-nd] a fT, = ar"? l<r<l F= x|+i)" -1 i +f") = lim F+h)-fCO h>0 A d=y(x,-%) +0,-nY y=mxtec y-Y= m=tand (x-ay +(y—by =r? joaspG: 4 =? 2 sinA sinB sinC a =b? +c? —2be.cosA area AABC = ab, sinC sin(a + B) = sina.cos B + cosa.sin cos(a + 8)=cosa.cos B -sina.sin B cos? a@—sin’ a cos2a =41—2sin’a 2cos?a-1 sin(a — £)=sina.cos f - cosa.sin B cos(ar ~f)= cosa.cos +sina.sin B sin 2a =2sina.cosa n XG -xY o? = __ n P(A of B) = P(A) + P(B) — P(A en B) p= LF -7) Ye-*
Downloaded from Stanmorephysics.com DEPARTMENT OF EDUCATION DEPARTEMENT VAN ONDERWYS LEFAPHA LA THUTO ISEBE LEZEMFUNDO PROVINSIALE TOETS PROVINCIAL TEST [ GRAAD 11 / GRADE 11 | WISKUNDE/MATHEMATICS MAART / MARCH 2026 NASIENRIGLYNE/MARKING GUIDELINES PUNTE/MARKS: 75 TYD/TIME: 1% uur/hours Hierdie nasienriglyne bestaan uit 7 bladsye./ These marking guidelines consist of 7 pages. Kopiereg voorbehou/ Blaai om asseblief/ Copyright reserved Please turn over
vakBDowsloaded from Stanmorephysics.com NK/Mrt 2026 Nasienriglyne QUESTION 1 1.1 Pll | 3x? -5x =4 3x7 -5x-4=0 Y Mstandard form - 5+ C5) -48)-4) Y CA substitusion xen tul a (3)(-4) x=2,26 or -0,59 Y CA both answers GB) 1.1.2 | x+V¥x—2=2 YM square both sides vx—2=2-x correctly x-2=(2-x) YM standard form x-2=4-4x4x? vA factorise O=x°-5x+6 ¥CA answer 0=(x-3)(x-2) learner must indicate Lmad: OF =} which answers apply na. ee and which one is n.a. to get the last mark (4) vS simplify YM standard form vA factorise / CV ¥ CA answer learner must answer in {<3. (OR. xd correct inequality form, otherwise B/D (4) 1.1.4 | 3x41 4 3x-1 = 2 a= » ~ " YM common factor YS simplify yas 3 3 =37 ¥ CA answer wx=-l (3) Kopiereg voorbehou Blaai om asseblief
vaBownloaded from Stanmoreph rephysics.com NK/Mrt 2026 YM prime factor ¥M X to the power of > vS_ simplify ¥ CA both answers (4) 4k? +4=17k 4k? -17k+4=0 (4k -1)(k-4) =0 : Edhimorephysics.com YM LCM: 4k YS factorise ¥ CA both answer (4) OR alternative method for 1.2 YM LCM: 4k YM standard form VS factorise ¥ CA both answer (4) Kopiereg voorbehou Blaai om asseblief
vakBowsloaded from Stanmorephysics.com NK/Mrt 2026 Nasienriglyn 1.3 YM rewrite to make y the subject in equation 1 YM subst. vS_ simplify x -2x-3=0 YCA factorise (x-3)(x+1) =0 Y¥CA both x-values = =-4 Z OR eal Hafimorephysics.com ¥ CA both y-values (6) [28] QUESTION 2 2.1.1 | Undefined x-5=0 vA wx=5 (1) 2.1.2 | Not real ¥M x+3<0 ux<-3 va 2) T 221 | aos3ys 64x73 YM prime and expo law ¥ S simplify ¥ CA answer GB) Kopiereg voorbehou Blaai om asseblief
vakBowsloaded from Stanmorephysics.com Nasienriglyne NK/Mrt 2026 2.2.2 [6*? x 10"? | 715-2 nf: yee x §r2gn2 A > 2H 32 sr . a a p.3'.5° ¥ M prime Y M expo law YS. simplify ¥ CA answer (4) 23 14 ¥o3 - 28 14 ex 7 V2 x7 14 “37-27 _14 V7 a i _lv7 7 =2V7 meaning that x =2 and y=7 is proved YS simplify YM multiply with Ri v7 YS simplify Q) 2.4.1 | A=b?—4ac A=CY-4HO A=+ Nature of the root A>0, real (2) (2) Kopiereg voorbehou Blaai om asseblief
vaeBawsloaded from Stanmorephysics.com NK/Mrt 2026 Nasienriglyn 2.5 x +2px+(5p+6)=0 A=b? —4ac | A=(2p)’ -4(1)(5p+6 ior” MGCP +6) YM subst. in A A =4p° -20p-24 : ~ 20+ (207 — 44-24) 2(4) Y critical points p=6 or -l ¥ CA answer A<0 learner must answer in “ol<p<6 inequality form, otherwise B/D (3) [20] QUESTION 3: 3.1 | Quadrant 4 VA () 32 3.2.1 ¥M YR pythagoras YA chosing the correct value of y = -12 @) 3.2.2a Y Y CA from 3.2.1 (2) 3.2.2b | tan? @-3 12 = [=] ma} YM subst. value tan 5 Jaa 5, 25 25 = YCA 25 (2) Kopiereg voorbehou Blaai om asseblief
vakBowsloaded from Stanmorephysics.com Nasienriglyne NK/Mrt 2026 3.3.1 | sina =tan32° sin@ = 0,62486... YM tan 32 = 0,62486... 4 =38,7° Penalize only Vv ONCE for Steuer (2) incorrect | 3.3.2 | wounding YM shift ¥ answer mt a GB) = ay 3.4 v/1—cos* 30° 2 3B = {I- 4 | ¥ subst. special A - I s 4 -|t vs 4 al 7 3 answer GB) 3.5.1 | J2.tan150°.cos225°.sin 300° v M reduction 5 oy ene YM reduction = V2.(-tan30°)(—cos 45°)(—sin 60°) Y M reduction -1][ -1]] -v3 =v2. Fa Fa =] Y subst. special A _- vcA 2 (6) 3.5.2 | tan(@—180°).cos?(180 +4) ¥ M reduction M reduction 90°+0 sont ) ¥ M reduction _ tan@.(—cos 0)” —sin@ Y¥ (-cos0@)’ =cos*@ sind os? Directly to cos’ @ loose — cos@ one mark (-1) must show —sin@ reduction first =-—cosé YM identity ¥CA (6) [27] Kopiereg voorbehou TOTAL :75 Blaai om asseblief

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