Technical Sciences Grade 11 P1 2026 Memo (Eng)

Mock hlayiso mock exams Practice Series: Grade 11 Exam Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 11 TECHNICAL SCIENCES P1 NOVEMBER EXAMINATION 2026 (MOCK) MARKING GUIDELINES MARKS: 150 These marking guidelines consist of 11 pages. Copyright reserved Please turn over

Technical Sciences/P1 2 Hlayiso/Mock 2026 NSC – Marking Guidelines GENERAL MARKING GUIDELINES 1. Calculations: Marks are awarded for the correct formula, correct substitution and the correct final answer WITH the correct unit, as indicated by the ticks (✓). No mark is awarded for a formula that is not followed by a substitution. If an incorrect formula is used, no further marks are awarded for that calculation. 2. Units: The final-answer mark is only awarded if the correct unit is given. Penalise an omitted or incorrect unit only ONCE per question. 3. Rounding: Accept final answers rounded to a minimum of TWO decimal places. Small differences caused by rounding of intermediate values are accepted. 4. Positive marking: Where an incorrect answer from a previous question is used correctly in a later calculation, full marks are awarded for the later calculation. 5. Negative marking: If a candidate must explain or motivate a choice (e.g. INCREASES or DECREASES) and the choice is incorrect, no marks are awarded for the explanation. 6. Definitions/laws: Where key words are underlined, deduct 1 mark for EACH key word or phrase that is omitted. Accept equivalent wording that conveys the same meaning. 7. Free-body diagrams: ONE mark for each force represented by an arrow with a correct label. Penalise ONCE for: no arrows, gaps between the arrows and the dot, dotted lines, or additional (non-applicable) forces. 8. Scale drawings: Accept answers within the stated range. No marks for the answer if no scale drawing is shown. 9. Sign convention: Candidates may choose either direction as positive, provided it is applied consistently. Copyright reserved Please turn over

Technical Sciences/P1 3 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 1 1.1 B ✓✓ (2) 1.2 C ✓✓ (2) 1.3 D ✓✓ (2) 1.4 A ✓✓ (2) 1.5 C ✓✓ (2) 1.6 B ✓✓ (2) 1.7 D ✓✓ (2) 1.8 A ✓✓ (2) 1.9 A ✓✓ (2) 1.10 C ✓✓ (2) [20] Copyright reserved Please turn over

Technical Sciences/P1 4 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 2 2.1 A single force that, acting together with the other forces, produces equilibrium / is equal in magnitude but opposite in direction to the resultant. ✓✓ (2) 2.2.1 The angle between the (two) forces ✓ (1) 2.2.2 The magnitude of the resultant (force) ✓ Accept: reading on the third spring balance / equilibrant. (1) 2.3 R2 = F21 + F22 ✓ R2 = (40)2 + (25)2 ✓ X = R = 47,17 N ✓ (3) 2.4 R 25 N (50 mm) 120◦ 40 N (80 mm) Criteria: Both forces drawn to the correct scale (80 mm and 50 mm) ✓ Correct angle between the directions of the forces (120◦ , i.e. 60◦ inside the triangle) ✓ Resultant drawn from the tail of the first to the head of the last vector, with arrow ✓ Y = 35 N (range 34 N – 36 N) ✓ (4) 2.5 As the angle between the forces INCREASES, the magnitude of the resultant DECREASES. ✓✓ Accept the inverse statement. Accept: The resultant is a maximum at 0◦ and a minimum at 180◦ (1 mark only). (2) 2.6 65 N ✓ (1) [14] Copyright reserved Please turn over

Technical Sciences/P1 5 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 3 3.1 VECTOR ✓ (1) 3.2 (–5 ; 7) ✓✓ (1 mark for each correct coordinate) Accept (–100 ; 140) (in metres). (2) 3.3 East–west component: 100 m (west) ✓ North–south component: 140 m (north) ✓ If grid units (5 and 7) are given without converting to metres: 1/2. (2) 3.4 POSITIVE MARKING FROM QUESTION 3.3 ∆x2 = (100)2 + (140)2 ✓ ∆x = 172,05 m ✓ (2) 100 3.5 tan θ = ✓ 140 θ = 35,54◦ (west of north) ✓ Bearing = 360◦ – 35,54◦ = 324,46◦ ✓ OR: tan α = 140 ◦ ◦ ◦ ◦ 100 ✓; α = 54,46 (north of west) ✓; bearing = 270 + 54,46 = 324,46 ✓. 100 or cos θ = 140 . Accept sin θ = 172,05 172,05 (3) [10] Copyright reserved Please turn over

Technical Sciences/P1 6 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 4 4.1 Static frictional force: The frictional force that acts on an object when it is stationary (not moving) relative to the surface / opposes the tendency of motion. ✓✓ Kinetic frictional force: The frictional force that acts on an object while it is moving (sliding) over the surface. ✓✓ (4) 4.2.1 100 N ✓ to the left (opposite to the push) ✓ (2) 4.2.2 N = Fg = mg = (45)(9,8) = 441 N ✓ fmax s = µs N ✓ max fs = (0,40)(441) ✓ fmax s = 176,40 N ✓ Minimum force needed = 176,40 N (horizontally, to the right) Accept: (slightly) more than / greater than 176,40 N. (4) 4.3.1 N / FN / normal force ✓ F / FA / 180 N / tension ✓ fk / friction ✓ Fg / w / weight ✓ Do not penalise for relative lengths of arrows. Accept the components of F instead of F only if F itself is not also drawn as an extra force. (4) 4.3.2 Fy = F sin θ = 180 sin 25◦ ✓ Fy = 76,07 N ✓ N + Fy = Fg OR N = Fg – Fy ✓ N = 441 – 76,07 ✓ N = 364,93 N (4) 4.3.3 fk = µk N ✓ fk = (0,28)(364,93) ✓ fk = 102,18 N ✓ (3) 4.4 DECREASES ✓ (A larger vertical component of F reduces the normal force.) (1) [22] Copyright reserved Please turn over

Technical Sciences/P1 7 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 5 5.1 The distance between two successive (consecutive) points in phase (e.g. two successive crests or troughs). ✓✓ (2) 5.2.1 Crest ✓ (1) 5.2.2 Trough ✓ (1) 5.3 Any ONE pair: P and S / P and U / S and U / Q and T ✓ (1) 1,6 5.4 A= ✓ 2 A = 0,8 m ✓ If 1,6 m is given: 0/2. (2) 27 5.5 λ= ✓ 3 λ =9m✓ (2) 50 5.6 T= =5s✓ 10 1 1 f= = ✓ T 5 f = 0,2 Hz ✓ OR: f = numbertime of waves = 10 ✓✓ = 0,2 Hz ✓ 50 (3) 5.7 POSITIVE MARKING FROM QUESTIONS 5.5 AND 5.6 v = fλ ✓ v = (0,2)(9) ✓ v = 1,8 m·s–1 ✓ (3) 5.8 POSITIVE MARKING FROM QUESTION 5.7 ∆x v= ✓ ∆t 150 1,8 = ✓ ∆t ∆t = 83,33 s ✓ (3) [18] Copyright reserved Please turn over

Technical Sciences/P1 8 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 6 6.1 The highness or lowness of a sound, which is determined by its frequency. ✓✓ Accept: The effect produced in the ear by a sound of a particular frequency. (2) 6.2.1 Q✓ Q shows MORE complete waves in the same time interval ✓ / shorter period, so it has a HIGHER frequency (and pitch increases with frequency). ✓ (3) 6.2.2 P✓ P has the LARGER amplitude (loudness increases with amplitude). ✓ (2) 6.3.1 NO ✓ 40 kHz is ABOVE the upper limit of the human hearing range (20 kHz) / it is ultrasound. ✓ (2) 4,0 × 10–3 6.3.2 Time for the pulse to reach the wall: ∆t = = 2,0 × 10–3 s ✓ 2 ∆x v= ✓ ∆t ∆x 340 = ✓ 2,0 × 10–3 ∆x = 0,68 m ✓ OR: 2∆x = v∆t = (340)(4,0 × 10–3 ) = 1,36 m ✓✓✓; distance = 0,68 m ✓. If 1,36 m is given as the distance: max 2/4. (4) 6.3.3 v = fλ ✓ 340 = (40 × 103 )λ ✓ λ = 8,5 × 10–3 m (0,0085 m) ✓ If 40 is used instead of 40 000 Hz: max 2/3. (3) 6.4 Any ONE: Scanning a foetus (pre-natal scans) / imaging internal organs / breaking up kidney stones / physiotherapy (treating injured muscles) / measuring blood flow ✓ (1) [17] Copyright reserved Please turn over

Technical Sciences/P1 9 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 7 7.1 The region (in space) around a magnet in which another magnet or a ferromagnetic material will experience a (magnetic) force. ✓✓ (2) 7.2.1 P: NORTH ✓ Q: SOUTH ✓ (Field lines point away from a north pole and towards a south pole.) (2) 7.2.2 ATTRACT ✓ (1) 7.2.3 X✓ The field lines are CLOSER TOGETHER (denser) at X. ✓ (2) 7.3 Charged particles (solar wind) from the Sun ✓ are deflected by the Earth’s magnetic field and guided towards the (magnetic) poles. ✓ There they collide with gas atoms/molecules in the upper atmosphere, which give off (emit) light. ✓ (3) 7.4 Any TWO: Electric motors / generators (dynamos) / loudspeakers and microphones / MRI scanners / maglev trains / compasses / magnetic door catches / hard drives and bank cards / electromagnets on scrap-yard cranes / relays ✓✓ (2) [12] Copyright reserved Please turn over

Technical Sciences/P1 10 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 8 8.1 The magnitude of the electrostatic force exerted by one point charge on another is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. ✓✓ (2) 8.2 X Y + – Criteria: Correct shape (lines from X curve towards Y) ✓; Direction of arrows from X (positive) to Y (negative) ✓; Field lines start/end at the surfaces of the spheres and do not cross ✓. The outer lines may be omitted. (3) kQ1 Q2 8.3 F= ✓ r2 (9 × 109 )(4 × 10–9 )(6 × 10–9 ) 6 × 10–5 = ✓✓ r2 r = 0,06 m ✓ 1 mark for substitution of the charges and k; 1 mark for the force. Ignore the negative sign if it is used. (4) 8.4 The (electrostatic) force experienced per unit positive charge placed at that point. ✓✓ (2) V 8.5.1 E= ✓ d 3 000 E= ✓ 20 × 10–3 E = 1,5 × 105 N·C–1 (V·m–1 ) ✓ If 20 m is used (no conversion): max 2/3. (3) 8.5.2 A✓ (the positive plate) (1) [15] Copyright reserved Please turn over

Technical Sciences/P1 11 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 9 9.1 The potential difference across a conductor is directly proportional to the current in the conductor at constant temperature. ✓✓ (2) 9.2 The maximum energy (work done) provided by a battery per coulomb (unit charge) passing through it. ✓✓ Accept: The potential difference across the terminals of a battery when no current flows (open circuit). (2) V 9.3.1 R= ✓ I 24 RT = ✓ 3 RT = 8 Ω ✓ (3) V 9.3.2 R= ✓ I V 4= 1 ✓ 3 V1 = 12 V ✓ (3) 9.3.3 POSITIVE MARKING FROM QUESTION 9.3.1 Rp = RT – R1 = 8 – 4 = 4 Ω ✓ 1 1 1 = + ✓ Rp R2 Rx 1 1 1 = + ✓ 4 12 Rx Rx = 6 Ω ✓ 12 = 1 A ✓; I = 3 – 1 = 2 A ✓; R = 12 = 6 Ω ✓ OR: Vp = 24 – 12 = 12 V ✓; I2 = 12 x x 2 (4) 9.3.4 POSITIVE MARKING FROM QUESTION 9.3.2 V2 = ε – V1 = 24 – 12 ✓ V2 = 12 V ✓ OR: V2 = IRp = (3)(4) ✓ = 12 V ✓ (2) 9.4 DECREASES ✓ (1) 9.5 The total (equivalent) resistance of the circuit INCREASES (only Rx is left in the parallel section). ✓ The emf stays the same, so the current decreases (I = RV ). ✓ (2) 9.6 POSITIVE MARKING FROM QUESTION 9.3.3 RT = R1 + Rx = 4 + 6 = 10 Ω ✓ V 24 I= = ✓ R 10 I = 2,4 A ✓ (3) [22] TOTAL: 150 Copyright reserved