Technical Sciences Grade 11 P2 2026 Memo (Eng)

Mock hlayiso mock exams Practice Series: Grade 11 Exam Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 11 TECHNICAL SCIENCES P2 NOVEMBER EXAMINATION 2026 (MOCK) MARKING GUIDELINES MARKS: 75 These marking guidelines consist of 6 pages. Copyright reserved Please turn over

Technical Sciences/P2 2 Hlayiso/Mock 2026 NSC – Marking Guidelines GENERAL MARKING GUIDELINES 1. Calculations: Marks are awarded for the correct formula, correct substitution and the correct final answer WITH the correct unit, as indicated by the ticks (✓). No mark is awarded for a formula that is not followed by a substitution. 2. Units: Penalise an omitted or incorrect unit only ONCE per question. Temperatures may be given in ◦ C or K where a temperature CHANGE is used (∆T in ◦ C = ∆T in K). Masses must be converted to kg for the specific heat capacity values on the data sheet. 3. Positive marking: Where an incorrect answer from a previous question is used correctly in a later calculation, full marks are awarded for the later calculation. 4. Half-reactions: Award full marks for the correct half-reaction with the correct arrow (→). If ⇌ is used, award a maximum of 1 mark. If the half-reaction is reversed, award 0 marks. Ignore phases. 5. Oxidation numbers: 1 mark for the correct working (equation of oxidation numbers), 1 mark for the final oxidation number WITH its sign. 6. Definitions: Accept equivalent wording that conveys the same meaning. Where key words are underlined, deduct 1 mark for EACH key word or phrase that is omitted. 7. Negative marking: If a candidate must explain a choice and the choice is incorrect, no marks are awarded for the explanation. Copyright reserved Please turn over

Technical Sciences/P2 3 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 1 1.1 C ✓✓ (2) 1.2 B ✓✓ (2) 1.3 B ✓✓ (Q = mc∆T = (2)(900)(5) = 9 000 J) (2) 1.4 C ✓✓ (2) 1.5 D ✓✓ (2) [10] QUESTION 2 2.1 The sum of the kinetic and potential energies of all the particles (molecules) in the system. ✓✓ (2) 2.2 Temperature ✓ Pressure ✓ Volume ✓ Accept: mass / amount (number of moles) of steam as ONE of the three. (3) 2.3 The substance (fluid, e.g. a gas or steam) in a heat engine that absorbs (or releases) heat and does work (or has work done on it). ✓✓ (2) 2.4 ∆Q = ∆U + ∆W ✓ ∆Q = (–600) + 1 500 ✓ ∆Q = 900 J = 0,9 kJ ✓ If ∆U = +600 J is used (∆Q = 2 100 J / 2,1 kJ): maximum 2/3. If 1,5 (kJ) and 600 (J) are mixed without converting: maximum 2/3. Answer in J only (900 J): accept. (3) [10] Copyright reserved Please turn over

Technical Sciences/P2 4 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 3 3.1 The quantity of heat (energy) needed to raise the temperature of the whole object (substance) by 1 K (1 ◦ C). ✓✓ (2) 3.2.1 C = mc ✓ C = (1,2)(460) ✓ C = 552 J·K–1 ✓ (3) 3.2.2 Q = mc∆T ✓ Q = (1,2)(460)(180 – 22) ✓ Q = 87 216 J (87,22 kJ) ✓ OR (positive marking from 3.2.1): Q = C∆T = (552)(158) = 87 216 J (3) 3.3 Qlost by hot water = Qgained by cold water OR (mc∆T)hot = (mc∆T)cold ✓ (0,15)(4 200)(85 – 40) ✓ = m(4 200)(40 – 15) ✓ 28 350 = 105 000 m m = 0,27 kg (270 g) ✓ (4) 3.4.1 When two bodies at different temperatures are in contact in an isolated system, the heat lost by the hotter body is equal to the heat gained by the colder body. ✓✓ (2) 3.4.2 Qlost by metal = Qgained by water OR (mc∆T)metal = (mc∆T)water ✓ (0,15) c (98 – 24,8) ✓✓ = (0,25)(4 200)(24,8 – 20) ✓ 10,98 c = 5 040 ✓ c = 459,02 J·kg–1 ·K–1 ✓ Marking: 1 mark for the principle; 2 marks for the correct substitution of the metal side (mass + ∆T); 1 mark for the water side; 1 mark for simplifying; 1 mark for the final answer with unit. Accept 459 to 459,02. (6) 3.4.3 Iron ✓ (Positive marking from 3.4.2: the metal in TABLE 1 with the value closest to the calculated value. If the value from 3.4.2 is closest to 380, accept brass OR zinc.) (1) 3.4.4 HIGHER THAN ✓ Some of the heat lost by the metal goes to the surroundings, so Q gained by the water (used in the calculation) is less than the heat lost by the metal; the calculated c is therefore too low. ✓ Accept: the measured final temperature is too low, so ∆T of the water is too small / ∆T of the metal is too large. (2) [23] Copyright reserved Please turn over

Technical Sciences/P2 5 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 4 4.1 The gain of electrons (by an atom, ion or molecule). ✓✓ (2) 4.2.1 (+1) + Cℓ + 3(–2) = 0 ✓ Cℓ = +5 ✓ (2) 4.2.2 N + 4(+1) = +1 ✓ N = –3 ✓ (2) 4.2.3 (+1) + N + 2(–2) = 0 ✓ N = +3 ✓ (2) 4.3.1 The oxidation number of Cu DECREASES from +2 to 0 (Cu is reduced) ✓ and the oxidation number of H INCREASES from 0 to +1 (H is oxidised). ✓ Oxidation and reduction take place at the same time (electrons are transferred), therefore it is a redox reaction. (2) 4.3.2 CuO ✓ (accept Cu2+ ) (1) 4.3.3 H2 (hydrogen) ✓ The oxidation number of hydrogen INCREASES ✓ from 0 (in H2 ) to +1 (in H2 O). ✓ Accept: H2 is oxidised / loses electrons, with the change in oxidation number from 0 to +1. (3) 4.4 2Aℓ + 3Cu2+ → 2Aℓ3+ + 3Cu Reactants and products ✓ Balancing ✓ Ignore phases. If electrons are shown in the final equation: maximum 1/2. If the full (molecular) equation 2Aℓ + 3CuSO4 → Aℓ2 (SO4 )3 + 3Cu is given: maximum 1/2. (2) [16] Copyright reserved Please turn over

Technical Sciences/P2 6 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 5 5.1 A substance (solution or molten compound) that conducts electricity because it contains free-moving ions. ✓✓ (2) 5.2 Any TWO: Carbon (graphite) is a good conductor of electricity / it is inert (does not react with the electrolyte or the products) / it is cheap and readily available / it has a high melting point. ✓✓ (2) 5.3 P✓ It is connected to the NEGATIVE terminal of the battery / reduction takes place at P / Cu2+ ions gain electrons at P. ✓ (2) 5.4 Cu2+ + 2e– → Cu ✓✓ (2) 5.5 2Cℓ– → Cℓ2 + 2e– ✓✓ (2) 5.6 Electrode P: a reddish-brown (pink) layer of copper is deposited / P becomes coated with copper ✓ Electrode Q: bubbles of a (pale) greenish-yellow gas with a pungent (sharp) smell form / gas bubbles are released ✓ (2) 5.7 The blue colour becomes LIGHTER (paler / fades) ✓ (Cu2+ ions are removed from the solution.) (1) 5.8 Cℓ– ✓ (Accept: chloride ions. Q is the anode / positive electrode.) (1) 5.9 Replace electrode P (cathode) with the iron key / connect the iron key to the NEGATIVE terminal. ✓ Replace electrode Q (anode) with a copper electrode (plate). ✓ Accept: use an electrolyte containing Cu2+ ions (e.g. CuSO4 ) as ONE change only if one of the electrode changes above is also given. (2) [16] TOTAL: 75 Copyright reserved