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SENIOR CERTIFICATE EXAMINATIONS/
SENIORSERTIFIKAAT-EKSAMEN
NATIONAL SENIOR CERTIFICATE EXAMINATIONS/
NASIONALE SENIORSERTIFIKAAT-EKSAMEN
MATHEMATICAL LITERACY P2/
WISKUNDIGE GELETTERDHEID V2
MARKING GUIDELINES/NASIENRIGLYNE
2019
MARKS/PUNTE: 150
Symbol/Kode Explanation/Verduideliking
M Method/Metode
MA Method with accuracy/Metode met akkuraatheid
CA Consistent accuracy/Volgehoue akkuraatheid
A Accuracy/Akkuraatheid
C Conversion/Herleiding
S Simplification/Vereenvoudiging
RT Reading from a table/a graph/document/diagram/Lees vanaf tabel/grafiek/diagram
SF Correct substitution in a formula/Korrekte vervanging in formule
O Opinion/Explanation/Opinie/Verduideliking
P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen
eenhede/verkeerde afronding, ens.
R Rounding off/Afronding
NPR No penalty for rounding/Geen penalisasie vir afronding nie
AO Answer only/Slegs antwoord
MCA Method with constant accuracy/Metode met volgehoue akkuraatheid
These marking guidelines consist of 20 pages.
Hierdie nasienriglyne bestaan uit 20 bladsye.
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Mathematical Literacy P2 May June 2019 Memo Afr Eng hlayiso.com
Mathematical Literacy · Grade 12 · NSC June Exam · 2019. Memorandum, 20 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2019
- Exam period
- NSC June Exam
- Paper
- 2
- Pages
- 20
- File size
- 670.4 KB
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 2 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
NOTE:
• If a candidate answers a question TWICE, mark only the FIRST attempt.
• If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the
solution mark the crossed out (cancelled) version.
• Consistent accuracy (CA) applies in ALL aspects of the marking guidelines, however it
stops at the second calculation error.
• No CA mark follows after a breakdown.
• If the candidate presents any extra solution when reading from a graph, table, layout plan
and map, then penalise for every extra item presented.
LET WEL:
• As 'n kandidaat 'n vraag TWEE KEER beantwoord, merk slegs die EERSTE poging.
• As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, merk
die doodgetrekte (gekanselleerde) poging.
• Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit
hou op by die tweede berekeningsfout.
• Geen CA-punt volg na 'n afbreking nie.
• Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en
ekstra antwoorde gee, penaliseer vir elke ekstra item.
QUESTION/VRAAG 1 [28 MARKS/PUNTE]
Q/V Solution/Oplossing Explanation/Verduideliking T&L
D
1.1.1 750 MA 1MA dividing by 50 L2
A=
50 A
= 15 occupants/bewoners 1A occupants
B = 2 500 × 30 MA 1MA multiplying
= 75 000 A 1A litres
OR/OF OR
Using ratios
A : 22 500
8 : 12 000
1M dividing and multiplying
M
A 22 500
8 × 22500
A= = 15 or/of A= = 15 1A occupants
12 000 1 500
50 : B
1 : 1 500 1M multiplying
B = 1 500 × 50 M 1A litres
= 75 000 A
AO
(4)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 3 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
M
1.1.2 Number of days/Aantal dae L4
1500 1MA dividing correct pair
= MA
50
= 30 A 1A number of days
But July has 31 days/Maar Julie het 31 dae O
His statement is NOT valid./Sy bewering is NIE geldig nie. 1O verification
OR/OF OR/OF
A 1A number of days
Number of days in July 31
1M multiply
M
1 500 × 31 = 46 500 or 50 ×31 = 1 550
1O verification
O
Not valid since it is not the same values /Nie geldig nie want die
waardes verskil
OR/OF OR/OF
July has 31 days A 1 A days in July
1500 ÷ 31 M 1M dividing
= 48,39 ℓ /pp
48,39 < 50
Not valid / Nie geldig nie
O 1O verification
[using any of maximum litres/month or maximum litres/day]
(3)
M
1.1.3 Total occupants/Totale bewoners L3
(a) 1MA no. of occupants
MA
= 2 + 4 + 2 + 2 = 10
Volume of water allowed/Volume water toegelaat
MCA M 1MCA 500
= (10 × 50) × 31 1M multiplying by 31
= 15 500 ℓ CA 1CA no. of litres
Extra/Ekstra = 20% × 15 500 1CA calculating 20%
= 3 100 ℓ CA
1CA Adding litres
Total volume/Totale volume = 15 500 + 3 100 CA
= 18 600 ℓ
= 18,6 kℓ C 1C Converting to kilolitres
(7)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 4 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
OR/OF
Total occupants/Totale bewoners
= 2 + 4 + 2 + 2 = 10 MA
1MA no. of occupants
Volume of water allowed per day
Volume water toegelaat per dag
= 50 × 10 = 500 ℓ MCA 1MCA 500
Extra/Ekstra = 20% × 500
= 100 ℓ CA 1CA calculating 20%
Total volume per day/Totale volume per dag = 500 + 100 1CA Adding litres
= 600 ℓ CA
1M multiplying by 31
Total volume for May/Totale volume vir Mei = 600 × 31 M
= 18 600 ℓ CA 1CA no. of litres
= 18,6 kℓ C 1C Converting to kilolitres
OR/OF OR/OF
Total occupants/ Totale bewoners = 2 + 4 + 2 + 2 = 10 MA 1MA no. of occupants
Increased quota per day / Verhoogde kwota per dag
1CA calculating 20%
CA
1CA Adding litres
= 50 + 20% × 50 = 60 CA
Maximum consumption / maksimum verbruik
1CA 600
CA M CA
= 60 × 10 × 31 = 18 600 ℓ 1M multiplying by 31
1CA no. of litres
=18,6 k ℓ C 1C Converting to kilolitres
(7)
F
1.1.3 Amount payable/Bedrag betaalbaar L3
1MA multiplying by rate
(b) MA 1CA correct answer
First 6 kℓ = 6 × R29,93 = R179,58 CA
1M same correct column
M calculation
Next 4,5 kℓ= 4,5 × R52,44 = R235,98
1M same correct column
M calculation
Next 4,8 kℓ = 4,8 × R114,00 = R547,20
M 1M adding
Total amount/Totale bedrag = R179,58 + R235,98 + R547,20
= R962,76 CA 1CA total
(6)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 5 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
1.1.3 Accept one of the following applicable reasons M
(c) • Close taps while brushing your teeth/washing your hands L2
• Rather take a shower than bath
• Fix leaking taps, pipes etc.
• Use grey water (bath or washing machine water) in the
garden or to flush the toilet
• Do not fill your swimming pool O
• Reduce the Capacity of the flush tank of toilet cistern
• Water garden once a week
• Use buckets to wash car
• Install a tank or borehole 2O relevant answer
Aanvaar een van die volgende toepaslike redes
• Maak krane toe terwyl jy tande borsel/hande was
• Stort eerder as bad
• Maak lekkende krane, pype ens. reg
• Gebruik grys water(bad- of wasmasjienwater) in die tuin
of om die toilet te spoel
• Moenie swembad volmaak nie
• Verminder die kapasiteit van die spoelbak van die toilet
• Maak tuin slegs een keer ‘n week nat
• Was die motor met ‘n emmer
• Installeer ‘n tenk of boorgat
OR/OF
Accept any other relevant answer
Aanvaar ander toepaslike rede (2)
R F
1.2 Labour day 1 = 6 hours × R129,99/h 1R rounding L4
Arbeid dag 1 = R779,94 M 1M 1st day labour
calculation
Day 2/Dag 2 = 2 hours × R129,99/h
= R259,98 CA 1CA 2nd day labour
calculation
Total/Totaal = R779,94+ R259,98
= R1 039,92 CA 1CA Adding 2 day values
Cost of installing the tank/Koste om tenk te installeer
= R12 958,00 + R1 943,70 + R1 039,92
1CA total cost
= R15 941,62 CA
Mr Vellem's budget is NOT enough O
Mnr. Vellem se begroting is NIE genoeg nie. 1O verification
OR/OF OR/OF
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 6 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
R CA 1R rounding
Total labour = 6 hours + 2 hours = 8 hours 1CA total hours labour
M
Labour cost = 8 × R129,99 1M labour calculation
= R1 039,92 CA 1CA labour cost
Cost of installing the tank/Koste om tenk te installeer
= R12 958,00 + R1 943,70 + R1 039,92
= R15 941,62 CA 1CA total cost
Mr Vellem's budget is NOT enough O 1O verification
Mnr. Vellem se begroting is NIE genoeg nie
OR/OF OR/OF
R 1R rounding
CA
Total labour = 6 hours + 2 hours = 8 hours 1CA total hours labour
M CA 1M subtracting from budget
Budget = R15 900 – R12 958,00 – R1 943,70 – R129,99 × 8 1CA labour cost
= – R41,62 CA 1CA simplification
Mr Vellem's budget is NOT enough
O
Mnr. Vellem se begroting is NIE genoeg nie 1O verification
(6)
[28]
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 7 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 2 [32 MARKS/PUNTE]
Q/V Solution/Oplossing Explanation/Verduideliking T&L
NOTE: 2.1.1 IS NOT TO BE MARKED, MARKS WILL BE M
2.1.1 SCALED L2
(a) LET WEL: 2.1.1 WORD NIE GEMERK, PUNTE SAL
AANGEPAS WORD
Total surface area/Totale buite oppervlakte
= 2(L × W) + 2(L × H) + 2(W × H) 1C conversion
C
= 2(6,5 × 6,5) + 2(6,5 × 12,5) + 2(6,5 × 12,5) cm2SF 1SF substitution
= 2(42,5) cm2 + 2(81,25) cm2 + 2(81,25) cm2
= 84,5 cm2 + 162,5 cm2 + 162,5 cm2
S 1S simplification
= 409,5 cm2 CA 1CA total area
(4)
M
O
2.1.1 To appeal to young children. L4
(b) Om die medisyne vir die kinders aantreklik te maak.
OR/OF
To advertise the medicine/Om die medisyne te adverteer O 2O reason
OR/OF
O
To show it is for children/Om aan te toon dat dit vir kinders
is
OR/OF (2)
Accept any valid reason/Aanvaar enige geldige rede
M
2.1.2 radius = 2,52 cm = 1,26 cm A 1A radius L3
SF
2
10 mℓ = 3,142 × (1,26 cm)2 × ℎ P 1SF substituting volume
10cm3 M 1M changing the subject of
=h
4,9882392cm2 the formula
2,0047…m =h CA 1CA height
NPR
(4)
MP
2.2 Number of boxes in one carton L2
Aantal bokse in een karton
= 6 × 8 × 4 M In each carton 1 layer has 1M multiplying
= 192 A 6 × 8 = 48 boxes 1A number per box
Each carton has 4 layers
Total number of boxes 48 × 4 = 192 boxes
Totale aantal bokse They ordered 5 cartons
= 192 × 5 M 1M multiply
= 960 A 192 × 5 = 960 boxes 1A total
OR/OF
OR/OF
1M multiplying 2 values
Total number of boxes/Totale aantal bokse
1M multiplying with 3rd value
M M M 1M multiplying with 4th value
=6×8×4×5
1A total
= 960 A
(4)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 8 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
D
2.3.1 Range = N – Lowest value 1M writing formula L2
Omvang = N – laagste waarde M 1SF substitution
4 527 = N – 612 SF
4 527 + 612 =N M 1M change the subject of the
5 139 =N CA formula
1CA when 76 for unknown
age is used
(4)
CA from 2.3.1 D
2.3.2 612 , 1 280 , 2 221 , 3 051 , 3 429 , 5 139 M 1M arranging L3
Interquartile Range /Interkwartiel omvang
1A Q1
A A
= 3 429 – 1 280 1A Q3
M
1M subtraction
= 2 149 CA 1CA Simplify
(5)
CA from 2.3.1
2.3.3 Total/Totaal D
= 1 280 + 612 + 3 051 + 2 221 + 5 139 + 3 429 + 76 L4
1MCA adding all values
= 15 808 MCA
1RT unknown age value
76 RT
Percentage = × 100% M 1M % calculation
15 808
= 0,48 CA 1CA simplification
≈ 0,5%
It is correct, due to rounding. O 1O explanation
Dit is korrek as gevolg van afronding. (5)
D
2.3.4 Number hospitalised < 6 months L3
Aantal gehospitaliseer< 6 maande
= 1 280 × 44,2% MA 1MA % calculation
= 565,76 A 1A simplification
Number hospitalised 20+/Aantal gehospitaliseer 20+
= 3 429 × 7,6%
= 260,6 A 1A simplification
Difference/Verskil = 565,76 – 260,60
= 305,1 1CA difference
CA NPR
≈ 305
(4)
[32]
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 9 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 3 [26 MARKS/PUNTE]
Q/V Solution/Oplossing Explanation/Verduideliking T&L
F
3.1.1 3 200 RT 2RT number of copies L2
[Accept values from 3 100 to 3 250
Aanvaar waardes van 3 100 tot 3 250] (2)
F
3.1.2 Contract 2/Kontrak 2 RT 2RT correct contract L2
(2)
F
3.1.3 Total cost = fixed cost + cost per page A 1A setting up the equation L4
RT 1RT constant cost
= R625 per month for the first 600 pages +
RT M 1RT values from graph
1M calculating the increment
(R1 475 – R625) ÷ (4 000 – 600) per page more than 600
per page
CA
= R625 for the first 600 pages + R0,25 per page extra 1CA cost per page extra
Totale koste = vaste koste + koste per bladsy A
RT
= R625 per maand vir die eerste 600 bladsye +
RT M
(R1 475 – R625) ÷ (4 000 – 600) per bladsy meer as 600
CA
= R625 vir die eerste 600 bladsye + R0,25 per ekstra
bladsy
OR/OF OR/OF
M
RT CA A 1RT constant cost
Total cost = R625 + R0,25 (n – 600) where n is the 1M calculating the increment
per page
number of pages more than 600. A 1CA cost per page extra
1A setting up the equation
1A explaining the unknown
in the equation
(5)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 10 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
F
3.1.4 Monthly photocopying costs for different L2
3 000
contracts
Contract 1
Contract 2 A
Contract 3
2 500
COMPANY B
2 000
Monthly cost in rand
1 500 1 475
A
1 000
625
500
0 A
0 500 1 000 1 500 2 000 2 500 3 000 3 500 4 000
Number of pages of photo copies
1A Starting point (0 copies ; R0,00 charge)/Beginpunt (0 kopieë ; R0,00 koste)
1A end point (4 000 ; 2 800)/Eindpunt (4 000 ; R2 800)
1A connecting points with a straight line./Verbind punte met reguit lyn.
(3)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 11 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
MP
3.2 The electrical lead is crossing the floor. A L4
This can be dangerous since persons can step on it and
perhaps unplug the copier which might damage the
machine or O
A person can trip over the lead and fall causing injury. 1A justification
Die elektriese koord lê oor die vloer
Dit kan gevaarlik wees aangesien persone daarop kan
trap en veroorsaak dat dit uittrek wat die kopieerder kan 2O reason
beskadig of
'n Persoon kan daaroor val en 'n besering veroorsaak.
OR/OF A
Copier in the middle of the room takes up space, if it is
against the wall the room is not so crowded O
Fotostaatmasjien is in die middel van die kamer en dit
neem ruimte op, indien dit teen die muur van die kamer
is, sal daar meer spasie wees (3)
A OR/OF
Not suitably placed. Directly facing the window, it can
attract criminals O
Dit is nie op ‘n geskikte plek nie. Direk voor die venster,
dit kan skelms aanlok.
A OR/OF
The copier is suitably placed since it can now be accessed
from all sides. O
Die fotostaatmasjien staan op die regte plek vir toegang
daartoe van alle kante.
M
3.3.1 100% – 58,5 % = 41,5 % M 1M subtraction from 100% L3
Length of truck on original picture
Lengte van vragmotor op die oorspronklike prent
76 mm 1M dividing the 76 mm with
= M
41,5 % the percentage
≈ 183 mm
Length of the real truck
Lengte van die werklike vragmotor
1M Multiplying by 50
= 183 mm × 50 M 1S simplifying
S C 1C conversion
= 9156 mm = 9,156 m
NPR (5)
OR/OF
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 12 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
Length /Lengte = 76 mm × 50 1M Multiplying by 50
M 1S simplifying
S
= 3 800 mm = 3,8 m C 1C conversion
100% – 58,5 % = 41,5 %
Length of real truck/ Lengte van werklike vragmotor
3,8 m M 1M dividing 3,8 m by the
= percentage
41,5 %
= 9,157 m CA 1CA real length
(5)
F
M
3.3.2 A$ 45 × 300 × R9,41564/A$ 1M multiplying by 300 L4
= R127 111,14 C 1C conversion
VAT/BTW = R127 111,14 × 15 %
= R19 066,67 CA 1CA when 15% is used
Import duties/Invoerbelasting
= R127 111,14 × 4,7%
= R5 974,22 CA 1CA simplification
Cost/Koste = R127 111,14 + R19 066,67 + R5 974,22
CA 1CA adding all costs
= R152 152,03
NOT correct/NIE korrek NIE O 1O verification
OR/OF OR/OF
Cost of 300 trucks /Koste van 300 vragmotors
M
= A$ 45 × 300 = A$ 13 500 1M multiplying by 300
Rand value /Rand waarde
= A$ 13 500 × R9,41564/A$ = R127 111,14 C 1C conversion
Total tax rate /Totale belasting koers
= 15% + 4,7% = 19,7% A 1A total tax rate
Total taxes = R127 111,14 × 19,7% = R25 040,89 CA 1CA simplification
CA
Cost/Koste = R127 111,14 + R25 040,89 = R152 152,03 1CA adding all costs
NOT correct/NIE korrek NIE O 1O verification
OR/OF OR/OF
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 13 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
M 1M multiplying by 300
A$ 45 × 300 × R9,41564/A$
= R127 111,14 C 1C conversion
A M 1A using total tax rate
Cost /Koste = R127 111,14 × 119,7% 1M multiplying with total
= R152 152,03 CA rate
1CA simplification
NOT correct/NIE korrek NIE O 1O verification
OR/OF OR/OF
159778,70
M 1M dividing by 300
300
= R532,5956667
100 532,5956667 1A total tax rate
× A M
119,7 1 1M dividing by 119,7%
= R 444,9420774 S
1S simplification
444,9420774
9,41564
C
= A$47,26 1C conversion
A$45<A$47,26
NOT correct /Nie korrek nie O 1O verification
NPR
(6)
[26 ]
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 14 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 4 [34 MARKS/PUNTE]
Q/V Solution/Oplossing Explanation/Verduideliking T&L
MP
4.1.1 SW (South west/Suidwes) A 2A reading direction L2
(2)
A MP
4.1.2 Part or sections of the railway line are not seen from 2A description L2
above. (2)
'n Gedeelte van die treinspoor is nie sigbaar op die kaart
OR/OF
The road stays continuous (whole) while the railway line
is in sections.
Die pad is aaneenlopend (heel) terwyl die treinspoor in
“stukkies” is.
MP
4.1.3 Toyota or 11 A 2A correct circle L2
(2)
A A MP
4.1.4 Proceed straight on Stateway Street until you turn right at 1A straight on Stateway L3
A 1A turn right
the City Council into Arrarat Street. Then proceed straight 1A Arrarat
A A 1A straight until Alma
until Alma. Destination is on the left-hand side. 1A destination on left-hand
Ry reguit met Staatsweg totdat jy regs by die Stadsraad
uitdraai in Arrarat . Gaan reguit voort tot in Alma. Die
bestemming is aan die linkerkant.
OR/OF OR/OF
Continue (NW) along Stateway.
A 1A exit point
st nd
• At 1 circle (13) take 2 exit along Stateway. A 1A correct street
• At 2 circle (Smith)(14) take 3 exit to Arrarat St. 1A exit point
nd rd A
• Continue in Arrarat passing further three circles A
1A description
A
Bingo (10), Alfa(8) and Engen(4) (from each
1A naming the circles
circle taking 2nd exit to NE).
Ry (NW) met Stateway
• By die 1ste sirkel neem die 2de uitgang gaan voort
in Stateway
• By die 2de sirkel neem die 3de uitgang na
Arraratstr.
• Gaan voort in Arrarat verby drie sirkels Bingo,
Alfa en Engen (by elke sirkel neem die 2de uitgang
Noordoos)
(5)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 15 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
MP
4.1.5 Distance between Alfa and Engen circles = 5mm A L3
Afstand tussen Alfa- en Engensirkels = 5mm 1A measuring given distance
∴ 5mm = 500m
1CA simplification or scale
CA
1mm = 100m or 1: 100 000
A 1A measure distance
Distance between circles 13 and 14 is 28 mm = 1,4 km
Afstand tussen sirkels 13 en 14 is 28 mm = 1,4 km
∴ 28 mm = 1 400 m
1mm = 50m or 1 : 50 000 CA 1CA simplification or scale
This map is NOT drawn to scale. O 1O explanation
Die kaart is nie volgens skaal geteken nie.
4 – 7 for distance between Afla and Engen
24 – 29 for distance between 13 and 14
(5)
5 M
4.1.6 5 minutes = ≈ 0,083 hour C 1C minutes to hours L4
60
Distance = Speed × time 1MA substituting
4 = speed × 5 min MA
Distance/ Afstand 4
Speed/Spoed = =
Time/ Tyd 0,083
1CA Speed value
= 48 km/h CA
O 1O conclusion
The car's speed was within the speed limit. NPR
Die motor se spoed is minder as die spoedbeperking
OR/OF
OR/OF
1MA substituting
Speed/Spoed = 4 km ÷ 5 min MA
1C converting
= 0,8 km/min × 60 min/hour C
= 48 km/h CA 1CA Speed value
The car's speed was less than the limit. 1O conclusion
O
Die motor se spoed is minder as die spoedbeperking (4)
P
4.1.7 3 RT 1RT numerator L4
P=
20 RT 1RT denominator
= 0,15 S 1S simplification
Valid/Geldig O 1O conclusion
(4)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 16 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
RT D
4.2.1 104 : 88 A 1RT correct values L2
1A correct order
= 13 : 11 S 1S simplification
(3)
P
203 RT 1RT numerator L2
4.2.2 1RT denominator
1 724 RT
= 0,11774942
1CA simplification
≈ 0,12 CA
NPR
(3)
P
4.2.3 Total NOT electrical repairs/Totaal nie elektriese L3
herstelwerk nie
1A numerator
= 1 + 206 + 103 = 310 A
310 M 1RT denominator
P (NOT) = × 100%
368 RT 1M multiplying with 100%
≈ 84% CA 1CA rounded simplification
OR/OF OR/OF
58
P (electr) =
368 RT 1RT denominator
58
P (NOT) = 1 –
368
A 1A numerator
310 1M multiplying with 100%
= × 100% M
368
1CA rounded simplification
≈ 84% CA
OR/OF
OR/OF
58 1RT denominator
P (electr) = × 100%
368 RT 1M multiplying with 100%
≈ 16% M
1A subtracting from 100%
P (NOT) = 100% – 16% A
= 84 % CA 1CA simplification
(4)
[34]
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 17 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 5 [30 MARKS/PUNTE]
Q/V Solution/Oplossing Explanation/Verduideliking T&L
F
5.1.1 Motor claims/Motor eise RT L2
= R100 712 182 – (R18 513 071 + R15 498 565 1RT correct values
+ R7 339 724 + R6 463 292)
M 1M subtracting from the total
=R100 712 182 – R47 814 652
= R52 897 530
≈ R53 million/miljoen CA 1CA rounded value
OR/OF OR/OF
Motor claims/Motoreise
1RT correct values
RT
= 53% × R100 712 182 M 1M percentage calculation
= R53 377 456
≈ R53 million/miljoen CA 1CA rounded value
(3)
F
5.1.2 Total/Totaal 2016 × 60% = R59 438 533 M 1M relating values L3
Total/Totaal 2016 = R59 438 533 ÷ 60% M 1M dividing
= R99 064 221,67 A 1A simplification
M
Difference/Verskil = R99 064 221,67 – R87 101 354 1M subtracting from 2017
value
= R11 962 867,67 CA 1CA difference
OR/OF OR/OF
2016 60% - R59 438 533
10% - R9 906 422,17 M 1M finding rand values
16% - R15 850 275,47
7% - R6 934 495,52 × 2 M 1M double the 7% value
Total/Total : R99 064 221,67 A 1A simplification
Difference/Verskil = R99 064 221,67 – R87 101 354 M 1M subtracting from 2017
= R11 962 867,67CA value
1CA difference
(5)
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 18 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking
T&L
D
New value − Old value A
5.1.3 Percentage difference = × 100% 1A concept of percentage L3
Old value difference
Nuwe waarde − Ou waarde
Persentasie verskil = × 100%
Ou waarde
A 1M difference
R11 829 111 − R15 498 565 RT 1RT correct values
= × 100%
R15 498 565
= – 23,676…% CA 1CA percentage
(4)
≈ – 24%
D
5.1.4 Percentage Household/Persentasie Huishoudelik L4
(a) RT
M 1RT correct values
7 339 724
= × 100% 1M multiplying with 100%
100 712182
= 7,28782… % A 1A simplification
Percentage Other/Persentasie Ander
6 463 292
= × 100% = 6,41758…% A 1A simplification
100 712182
Her statement is valid; the percentage should be 6% if
rounded down. O 1O verification
Haar stelling is geldig; die persentasie moet 6% wees
indien dit afgerond word.
OR/OF OR/OF
Motor claims 2015 = 53% × R100 712 182
= R53 377 456
Total of the claims
= R18 513 071 + R15 498 565 + R7 339 724 + 1RT correct values
R53 377 456 + R6 463 292 RT
= R101 192 108
6 463 292 1M multiplying with 100%
Other % = × 100% M
101 192 108
= 6,38% A 1A simplification
7 339 724
Household % = ×100%
101 192 108
1A simplification
= 7,25% A
Her statement is valid; the percentage should be 6% if
O 1O verification
rounded down.
Haar stelling is geldig; die persentasie moet 6% wees
indien dit afgerond word.
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 19 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
OR/OF OR/OF
Rand value of the sectors /Randwaarde van die sektore
RT 1RT correct values
= 7% × R100 712 182 MA 1MA percentage calculation
= R7 049 852,74 A 1A simplification
O
Both household and other were supposed to be R7 049 852, 1O explanation
but it is not.
⸫ Her statement is valid O 1O verification
(5)
D
5.1.4 When subtracting the percentages of Commercial, Home L4
(b) owner, Household and motor from 100% Other will be 7%
due to %values in a circle diagram. O 2O reflecting
OR Percentages were rounded.
As die persentasies van Kommersieel, Huiseienaar,
Huishoudelik en motor van 100% afgetrek word sal ander
7% wees a.g.v. %waardes in die sirkeldiagram.
OF Persentasies is afgerond. (2)
F
5.1.5 Number of successful claims/Aantal suksesvolle eise L3
= 14,0858% × 2 144 MA 1MA % calculation
≈ 302 A 1A simplification
Average paid out/Gemiddeld uitbetaal
R11 829 111
= M 1M dividing
302
1CA simplification
= R39 169,24 CA
(4)
A from D
5.1.6 The percentage of commercial claims went down 1A down 2016 L4
2015 to 2016 but then again went up from 2016 to 2017. A 1A up 2017
Die persentasie van kommersiële eise het verminder van
2015 tot 2016 maar het weer vermeerder van 2016 tot 2017
OR (2)
From 2015 to 2017 the trend is it increased
Vanaf 2015 tot 2017 is die tendens dat dit vermeerder
D
5.2 Number of days/Aantal dae L4
= 21 (July/Julie) + 31 + 30 + 31 + 3 MA 1MA adding correct days
= 116 A
1A simplification
It is not valid./Dit is nie geldig nie. O
OR/OF 1O verification
131 days is more than 4 months (3)
It is not valid
131 dae is meer as 4 maande
Dit is nie geldig nie
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Mathematical Literacy/P2/Wiskundige Geletterdheid/V2 20 DBE/2019
SC/SSE/NSC/NSS – Marking Guidelines/Nasienriglyne
Q/V Solution/Oplossing Explanation/Verduideliking T&L
F
5.3 Accept one of the following L4
The insurance company believes the claim is not valid.
They suspect it is a fraudulent claim.
They don't believe the item was specified.
Under insured / Unpaid premiums
Too many claims to date O
Negligence on the side of the client
Die versekeringsmaatskappy glo dat die eis nie geldig is nie
Hulle vermoed dat dit 'n oneerlike eis is. 2O reason
Hulle glo nie dat die item gespesifiseer is nie
Onder verseker / Onbetaalde premies
Te veel keer ge-eis tot datum
Nalatigheid aan die kant van die eiser.
OR/OF
Any other valid reason/Enige ander geldige rede
(2)
[30]
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