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SENIOR CERTIFICATE/
NATIONAL SENIOR CERTIFICATE
GRADE 12
MATHEMATICS P2
NOVEMBER 2020
MARKS: 150
TIME: 3 hours
This question paper consists of 14 pages, 1 information sheet
and an answer book of 24 pages.
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Mathematics Grade 12 P2 NSC November 2020 QP (Eng)
Grade 12 Mathematics Paper 2 question paper from the NSC November Exam 2020 (English), 15 pages. Read online or download the free PDF.
Mathematics · Grade 12 · NSC November Exam · 2020. Question paper, 15 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 12
- Document type
- Question paper
- Year
- 2020
- Exam period
- NSC November Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 15
- File size
- 411.6 KB
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This exam
NSC November Exam 2020
Questions in this paper
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Mathematics/P2 2 DBE/November 2020
SC/NSC
INSTRUCTIONS AND INFORMATION
Read the following instructions carefully before answering the questions.
1. This question paper consists of 10 questions.
2. Answer ALL the questions in the SPECIAL ANSWER BOOK provided.
3. Clearly show ALL calculations, diagrams, graphs, etc. that you have used in
determining your answers.
4. Answers only will NOT necessarily be awarded full marks.
5. You may use an approved scientific calculator (non-programmable and
non-graphical), unless stated otherwise.
6. If necessary, round off answers correct to TWO decimal places, unless stated
otherwise.
7. Diagrams are NOT necessarily drawn to scale.
8. An information sheet with formulae is included at the end of the question paper.
9. Write neatly and legibly.
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Mathematics/P2 3 DBE/November 2020
SC/NSC
QUESTION 1
A Mathematics teacher was curious to establish if her learners' Mathematics marks influenced
their Physical Sciences marks. In the table below, the Mathematics and Physical Sciences marks
of 15 learners in her class are given as percentages (%).
MATHEMATICS
26 62 21 33 53 76 32 59 43 33 49 51 19 34 85
(AS %)
PHYSICAL
34 67 28 46 65 76 26 73 50 39 57 51 24 41 80
SCIENCES (AS %)
SCATTER PLOT
90
80
PHYSICAL SCIENCES (%)
70
60
50
40
30
20
10
0
0 10 20 30 40 50 60 70 80 90
MATHEMATICS (%)
1.1 Determine the equation of the least squares regression line for the data. (3)
1.2 Draw the least squares regression line on the scatter plot provided in the ANSWER
BOOK. (2)
1.3 Predict the Physical Sciences mark of a learner who achieved 69% for Mathematics. (2)
1.4 Write down the correlation coefficient between the Mathematics and Physical
Sciences marks for the data. (1)
1.5 Comment on the strength of the correlation between the Mathematics and Physical
Sciences marks for the data. (1)
1.6 What trend did the teacher observe between the results of the two subjects? (1)
[10]
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Mathematics/P2 4 DBE/November 2020
SC/NSC
QUESTION 2
The number of aircraft landing at the King Shaka International Airport and the Port Elizabeth
Airport for the period starting in April 2017 and ending in March 2018, is shown in the double
bar graph below.
Number of aircraft landing at the King Shaka
International airport and the Port Elizabeth Airport for
the period April 2017 to March 2018
3000
Number of aircraft landing
2500
2000
1500
King Shaka
1000
Port Elizabeth
500
0
Apr May Jun Jul Aug Sep Oct Nov Dec Jan Feb Mar
Months in the period 2017/2018
[Source: http://www.airports.co.za/airports/statistics/aircraft]
2.1 The number of aircraft landing at the Port Elizabeth Airport exceeds the number of
aircraft landing at the King Shaka International Airport during some months of the
given period. During which month is this difference the greatest? (1)
2.2 The number of aircraft landing at the King Shaka International Airport during these
months are:
2 182 2 323 2 267 2 334 2 346 2 175
2 293 2 263 2 215 2 271 2 018 2 254
Calculate the mean for the data. (2)
2.3 Calculate the standard deviation for the number of aircraft landing at the King Shaka
International Airport for the given period. (2)
2.4 Determine the number of months in which the number of aircraft landing at the King
Shaka International Airport were within one standard deviation of the mean. (3)
2.5 Which ONE of the following statements is CORRECT?
A. During December and January, there were more landings at the Port
Elizabeth Airport than at the King Shaka International Airport.
B. There was a greater variation in the number of aircraft landing at the King
Shaka International Airport than at the Port Elizabeth Airport for the given
period.
C. The standard deviation of the number of landings at the Port Elizabeth
Airport will be higher than the standard deviation of the number of landings
at the King Shaka International Airport. (1)
[9]
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Mathematics/P2 5 DBE/November 2020
SC/NSC
QUESTION 3
1
∆TSK is drawn. The equation of ST is y = x + 6 and ST cuts the x-axis at M. W(–4 ; 4)
2
lies on ST and R lies on SK such that WR is parallel to the y-axis. WK cuts the x-axis at
V and the y-axis at P(0 ; –4). KS produced cuts the x-axis at N. TŜK = .
y
T
W(–4 ; 4)
M V x
N O
S P(0 ; –4)
R
K
3.1 Calculate the gradient of WP. (2)
3.2 Show that WP ⊥ ST. (2)
3.3 If the equation of SK is given as 5y + 2x + 60 = 0, calculate the coordinates of S. (4)
3.4 Calculate the length of WR. (4)
3.5 Calculate the size of . (5)
3.6 Let L be a point in the third quadrant such that SWRL, in that order, forms a
parallelogram. Calculate the area of SWRL. (4)
[21]
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Mathematics/P2 6 DBE/November 2020
SC/NSC
QUESTION 4
M(–3 ; 4) is the centre of the large circle and a point on the small circle having centre O(0; 0).
From N(–11 ; p), a tangent is drawn to touch the large circle at T with NT is parallel to the
y-axis. NM is a tangent to the smaller circle at M with MOS a diameter.
y
M(–3 ; 4)
T
O x
N(–11 ; p)
S
4.1 Determine the equation of the small circle. (2)
4.2 Determine the equation of the circle centred at M in the form
(x − a )2 + ( y − b)2 = r 2 (3)
4.3 Determine the equation of NM in the form y = mx + c (4)
4.4 Calculate the length of SN. (5)
4.5 If another circle with centre B(–2 ; 5) and radius k touches the circle centred at M,
determine the value(s) of k, correct to ONE decimal place. (5)
[19]
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Mathematics/P2 7 DBE/November 2020
SC/NSC
QUESTION 5
f (x ) = − cos x and g (x ) = sin( x + 30) , for the interval x 0 ; 180 , are
1
The graphs of
2
drawn below. A(130,9° ; 0,33) is the approximate point of intersection of the two graphs.
y
g
A(130,9° ; 0,33)
x
0° 90° 150° 180°
f
5.1 Write down the period of g. (1)
5.2 Write down the amplitude of f (1)
5.3 Determine the value of f (180) – g(180) (1)
5.4 Use the graphs to determine the values of x, in the interval x [0° ; 180°], for
which:
5.4.1 f ( x − 10) = g ( x − 10) (1)
5.4.2 3 sin x + cos x 1 (4)
[8]
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Mathematics/P2 8 DBE/November 2020
SC/NSC
QUESTION 6
6.1 In the diagram, P(–5 ; 12) and T lies on the positive x-axis. PÔT =
y
P(−5 ; 12)
<
x
T
Answer the following without using a calculator:
6.1.1 Write down the value of tan (1)
6.1.2 Calculate the value of cos (3)
6.1.3 S(a ; b) is a point in the third quadrant such that TÔS = + 90 and
OS = 6,5 units. Calculate the value of b. (4)
6.2 Determine, without using a calculator, the value of the following trigonometric
expression:
sin 2 x. cos(− x) + cos 2 x. sin( 360 − x)
(5)
sin(180 + x)
6.3 Determine the general solution of the following equation:
6 sin 2 x + 7 cos x − 3 = 0 (6)
1 1
6.4 Given: x + = 3 cos A and x 2 + 2 = 2
x x
Determine the value of cos 2A without using a calculator. (5)
[24]
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Mathematics/P2 9 DBE/November 2020
SC/NSC
QUESTION 7
A landscape artist plans to plant flowers within two concentric circles around a vertical light
pole PQ. R is a point on the inner circle and S is a point on the outer circle. R, Q and S lie in
the same horizontal plane. RS is a pipe used for the irrigation system in the garden.
• The radius of the inner circle is r units and the radius of the outer circle is QS.
• The angle of elevation from S to P is 30°.
• RQ̂S = 2 x and PQ = 3r
P
r Q
2x 30°
R
S
7.1 Show that QS = 3r (3)
7.2 Determine, in terms of r, the area of the flower garden. (2)
7.3 Show that RS = r 10 − 6 cos 2 x (3)
7.4 If r = 10 metres and x = 56, calculate RS. (2)
[10]
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Mathematics/P2 10 DBE/November 2020
SC/NSC
QUESTION 8
8.1 O is the centre of the circle.. KOM bisects chord LN and MN̂O = 26. K and P
ˆ P = 32°. OP is drawn.
are points on the circle with NK
L
K O 1
1 2
1 3 2 M
32° 2
26°
N
P
8.1.1 Determine, giving reasons, the size of:
(a) Ô 2 (2)
(b) Ô1 (4)
8.1.2 Prove, giving reasons, that KN bisects OK̂P. (3)
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Mathematics/P2 11 DBE/November 2020
SC/NSC
8.2 In ∆ABC, F and G are points on sides AB and AC respectively. D is a point on
GC such that D̂1 = B̂ .
A
G
1
F 2
1
D
2
C
B
8.2.1 If AF is a tangent to the circle passing through points F, G and D, then
prove, giving reasons, that FG || BC. (4)
AF 2
8.2.2 If it is further given that = , AC = 2x – 6 and GC = x + 9, then
FB 5
calculate the value of x. (4)
[17]
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Mathematics/P2 12 DBE/November 2020
SC/NSC
QUESTION 9
9.1 In the diagram, O is the centre of the circle. Points S, T and R lie on the circle.
Chords ST, SR and TR are drawn in the circle. QS is a tangent to the circle at S.
R
T
O
Q
S
Use the diagram to prove the theorem which states that QŜT = R̂. (5)
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Mathematics/P2 13 DBE/November 2020
SC/NSC
9.2 Chord QN bisects MN̂P and intersects chord MP at S. The tangent at P meets
MN produced at R such that QN || PR. Let P̂1 = x .
R
N
1 3
2
M 2
1
S x
1
2
3
P
1
2
Q
9.2.1 Determine the following angles in terms of x. Give reasons
(a) N̂ 2 (2)
(b) Q̂2 (2)
MN MS
9.2.2 Prove, giving reasons, that = (6)
NR SQ
[15]
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Mathematics/P2 14 DBE/November 2020
SC/NSC
QUESTION 10
In the diagram, a circle passes through D, B and E. Diameter ED of the circle is produced
to C and AC is a tangent to the circle at B. M is a point on DE such that AM ⊥ DE.
AM and chord BE intersect at F.
C D M E
1 2 1 2
4 1
F
3 2
1
2
B 3
A
10.1 Prove, giving reasons, that:
10.1.1 FBDM is a cyclic quadrilateral (3)
10.1.2 B̂ 3 = F̂1 (4)
10.1.3 CDB ||| CBE (3)
10.2 If it is further given that CD = 2 units and DE = 6 units, calculate the length of:
10.2.1 BC (3)
10.2.2 DB (4)
[17]
TOTAL: 150
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Mathematics/P2 DBE/November 2020
SC/NSC
INFORMATION SHEET
− b b 2 − 4ac
x=
2a
A = P(1 + ni ) A = P(1 − ni ) A = P(1 − i) n A = P(1 + i) n
Tn = a + (n − 1)d Sn =
n
2a + (n − 1)d
2
Tn = ar n−1 Sn =
(
a r n −1 )
; r 1 S =
a
; −1 r 1
r −1 1− r
F=
x (1 + i) n − 1 P=
x 1 − (1 + i) − n
i i
f ( x + h) − f ( x )
f / ( x) = lim
h →0 h
x + x 2 y1 + y 2
d= (x2 − x1 )2 + ( y2 − y1 )2 M 1 ;
2 2
y 2 − y1
y = mx + c y − y1 = m( x − x1 ) m= m = tan
x 2 − x1
(x − a )2 + ( y − b)2 = r 2
a b c
In ABC: = =
sin A sin B sin C
a 2 = b 2 + c 2 − 2bc. cos A
1
area ABC = ab. sin C
2
sin( + ) = sin cos + cos sin sin( − ) = sin cos − cos sin
cos( + ) = cos cos − sin sin cos( − ) = cos cos + sin sin
cos 2 − sin 2
cos 2 = 1 − 2 sin 2 sin 2 = 2 sin cos
2 cos2 − 1
n
x=
x (x − x )
i
2
n 2 = i =1
n
n( A )
P(A) = P(A or B) = P(A) + P(B) − P(A and B)
n(S)
yˆ = a + bx b=
(x − x )( y − y )
(x − x )
2
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