Mathematical Literacy Grade 12 P1 North West Mock 2025 Memo

education Department: Education North West Provincial Government REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 et SSSR SR SSSR SSR RRR ES j * MATHEMATICAL LITERACY P1/ WISKUNDIGE GELETTERDHEID VI SEPTEMBER 2025 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 Symbol/Kode | Explanation/Verduideliking M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid Cc Conversion/Herleiding Ss Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule ie) Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding, ens. R Rounding off/Afronding No penalty for rounding/Geen penalisasie vir afronding nie AO Answer only/Slegs antwoord Method with consistent accuracy/Metode met volgehoue akkuraatheid Rounding consistent with accuracy/ Afronding met volgehoue akkuraatheid These marking guidelines consist of 12 pages/ Hierdie nasienriglyne bestaan uit 12 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 NOTE: LE If a candidate answers a question TWICE, only mark the FIRST attempt. If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. if the candidate presents any extra solution when reading from the graph, table, layout plan and map, then penalise for any extra item presented. Rounding is an independent mark. General principle of marking, if the candidate makes one mistake one mark is deducted. A conclusion mark can only be awarded if relevant calculations of at least ; of the maximum mark of the sub-question has been awarded. No penalty for rounding (NPR) if the first decimal is correct, except questions involving money. T WEL: As 'n kandidaat 'n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na. As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, sien die doodgetrekte (gekanselleerde) poging na. Volgehoue akkuraatheid (CA) word in ALLE aspehte van die nasienriglyne toegepas, dit hou op by die tweede berekeningsfout of ‘breakdown’. Wanneer ‘n kandidaat aflesings vanaf ‘n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra item. Afrondings tel as ‘n afsonderlike punt. Die algemene beginsel van merk as’n leerder cen fout maak, word een punt afgetrek. ‘n Gevolgtrekkingspunt kan slegs gegee word indien relevante berekeninge van ten minste ; van die maksimumpunt van die subvruag toegeken is. Geen penalisering vir ronding (NPR) as die eerste desimaal korrek is nie, behalwe as vrae geld insluit. QUESTION/VRAAG 1 [30 MARKS/PUNTE] ANSWER ONLY FULL MARKS Q/V_| Solution/Oplossing Explanation/Verduideliking | T&L F 1.1.1 | A South African Citizen/‘n Suid-Afrikaanse burger VR. 2A answer Ll (2)|E OR/OF VVA Permanent resident or Refugee at the time of application/ Permanente inwoner of vlugteling met die tyd van aansoek F 1.1.2 | R259 300 000 000 YWA 2A answer LI Q)|E YMA IMA correct value divided | F 1.1.3 | Monthly threshold = R92 520 + 12 by 12 LI =R7710 VM 1A answer E (2) F 1.1.4 | RIL 180 VWA 2A answer LI (2) |E Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 Q/V_| Solution/Oplossing Explanation/Verduideliking | T&L F 1.1.5 | R2190 + R20 1MA adding correct values | LI =R2210 “MA 1MA subtract R2 100 from M "2% the correct answer = R2210 — R2100 “MA 1A answer “R110 WA @) YA P. 1.2.1 | Stacked bar graph/ 2A compound stacked bar LI Stapelgrafiek graph E (2) VVA D 1.2.2 | Survey, Observation/Opname, Observasie 2A Survey LI (2) |E VVA D 1.2.3 | Day 5/Dag 5 2A Day 5 Ll (2) |M D 1.2.4 | number of medals = 5 + 6 +7 YMA IMA adding correct values | LI = 18 medals/medaljes 1A 18 medals E 2) ¥MA D 1.2.5 | 40: 126YMA 1A correct values Ll IMCA correct order M 20:63VA ICA simplified as a ratio G3) F 13.1/G “VA 2A correct answer Ll Accept:The rate of increase in prices over a given period of E time./Aanvaar: Die styging in die prysvlakke oor ‘n gegewe dperk, tydp' Q) D 13.2)/E VVA 2A correct answer Ll Accept: IQR = Q3 — Q;/Aanvaar: IKO = K3 — K, (2) |E F 133}C ¥VA 2A correct answer Ll Accept: The point at which the total cost and total revenue are E equal./ Aanvaar: Die punt waar die totale uitgawes en die totale inkomste gelyk is. (2) D 134/A VVA 2A correct answer Ll Accept: The middle value of an arranged set of data/ E Aanvaar: Die middelwaarde van ‘n geordende datastel. Q) [30] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 QUESTION/VRAAG 2 [35 MARKS/PUNTE]| Rolling tennis ball basket/Tennisbalmandjies met wiele R12 792,08 Rackets/Rakeite (6~-1= 15) 4 for free/] verniet R2 099 x 15 R31 485 YMCA ¥MA Racket bags/Raketsakke R8 097,01 Total cost/Totale koste YMCA R14 940 + R12 792,08 + R31 485 + R8 097,01 R67 314,09 YCA 1CA correct answer 1A correct value 15 IMCA multiplying by R2.099 1CA correct answer IMCA adding all costs 1CA correct cost (7) | Q/V_ | Solution/Oplossing Explanation/Verduideliking | T&L YMA F 2.1.1 | 30x 8 = 240 balls/balle 1MA multiply 30 with 8 L2 YMA 1MA dividing answer by4_ | E 240 +4 = 60 containers/houers V A 1A correct answer @) F 2.1.2 | Amount VAT excluded/Bedrag BTW uitgesluit “ YRT v¥MA 1RT correct value iis icin Te IMA divide with 115%/1,15 = R7 040,88 VA 1A correct answer = R7 040,88 +3 YMCA IMCA divide by 3 = R2 346,96 VCA 1CA simplification OR/OF YRT \ R8.097,01x 209 “MA RE same VAIE: 115 IMA multiplying with ac = R7 040,88 VA 1A correct answer = R7 040,88 +3 YMCA IMCA divide by 3 = R2 346,96 YCA 1CA simplification (5) CA from number of balls F 2.1.3 | Tennis balls/Tennishalle from 2.1.1 L3 YMA an M 60 x R249 IMCA multiplying correct = R14940 VA value with 60 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 Q/V | Solution/Oplossing Explanation/Verduideliking | T&L YY RT FE 2.2.1 | Two options 2RT correct answer Ll (2) | E YRT F 2.2.2 | R59515x ¥A IRT correct value L2 =RI78 54¥A IMA multiply by 3 E 1A correct answer GB) CA from 2.2.2 FE 2.2.3 raz 701,76MC4 YMA IMCA correct fraction L2 REEBYS IMA multiplying by 100% | M = % CA zs oe 0 1CA simplification omeR IR rounded answer (4) FE 2.2.4 | Interest paid/rente betaal L4 D Year 1/Jaar 1 / R59 515 x 112,5% YMA = R66 954,375. YMA Year 2/Jaar 2 R66 954,375 X 112,5% = R75 323,67188 YMA 12,5% x == 6,25% “MA R75 323,67188 x 6,25% = R4 707,729492 YCA R75 323,67188 + R4 707,729492 = R80 031,40137 YMCA = R80 031,40137—59515 YMCA = R20 516,40 ¥CA vO Lorenzo's statement is CORRECT. Lorenzo's hewering is KORREK. IMA calculating percentage IMA first year final amount IMA second year final amount IMA calculating percentage 1CA 6 months interest amount IMCA correct final amount IMA subtract 59 515 from final amount 1CA correct answer 10 conclusion Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 OR/OF Year 1/Jaar I R59 515 x 12,5% YMA = R7 439,38 (A) = R7 439,38 + R59 515 YCA = R66 954,375 VA Year 2/Jaar 2 R66 954,375 x 12,5% = R8 369,30 (B) = R8 369,30 + R66 954,375 = R75 323,67188 “MA 12,5% x == 6,25% YMA R75 323,67188 X 6,25% = R4 707,729492 (C) ¥CA R75 323,67188 + R4 707,729492 = R80 031,40137 =A+B+C YMCA = R7 439,38 + R8 369,30 + R4 707,729492 = R20 516,40 VCA vo Lorenzo’s statement is CORRECT. Lorenzo's bewering is KORREK. OR/OF Interest paid/rente betaal ¥Y¥MC YMCA VYMCA R59 515 X 112,5% x 112,5%xX 106,25% — 59 515 YMCA YMCA = R80 031,40137 — 59 515 =R20 516,40 YMCA vO IMA multiply with 12,5% 1MCA adding correct values 1A year | correct amount IMA second year final amount 1MA calculating percentage 1CA 6 months interest amount 1MCA adding correct values 1CA correct answer 10 conclusion (9) Lorenzo’s statement is CORRECT. Lorenzo's bewering is KORREK. F 2.2.5 | To avoid paying interest/Om die betaal van rente te vermy. 2A opinion L4 (2) |M [35] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 QUESTION/VRAAG 3 [26 MARKS/PUNTE]| | Q/V | Solution/Oplossing Explanation/Verduideliking | T&L D 3.1 Australia/Australié YA 2A correct country Ll Q)|E D 3.2 Shooter 2/Doel2. VA 1A correct shooter Ll E South Africa/Suid-Afrika VA 1A correct country Q) D 3.3. | 100 %A 1A 100 L2 91 YA 1A 91 M so YA 1A 89 G3) IMA arranging data in D 3.4 71, 78, 82, 89, 91,|91, 92}, 92, 93, 100, 100, 100 vMA ascending order L2 Median/Mediaan = (91+92) +2. “MA IMA concept of median M =91,54CA 1CA correct median GB) D 3.5.1 | New Zeeland/ Nieu-Seelani YMA _ [Ls 67, 79, |80, 89}, 89, [91. 91], 92, 194, 96, 100, 100 1MA arrange correct data in | M ascending order 80 +89 Ql= 2 vMA 1MA correct quartile 1 Ql=845 VA 1A answer Q2=91 94 +96 a= VA 1A quartile 3 Q3 =95 YMA + IOR=Q3-QI YA 1A correct formula = 95 - 84,5 1CA subtracting values =10,5% “CA 1CA simplification (7) YCA vvVO D 3.5.2 | Australia, smaller IQR indicates more consistency ICA correct country 14 Australie, die kleiner IKO toon meer konsekwentheid aan 20 SoneIisiOn @) D VVA D 3.6 Player was injured/ill/disqualified/tired/replaced/substituted 2A any one reason L4 Speler was beseer/siek/gediskwalifiseer/moeg/vervang E Q) YMA 1MA correct numerator P 3.7 - x% 100 YMA 1MA correct denominator L3 48 MA 1MA % calculation M IR rounding = 15,56% YR (4) [26] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 UESTION/VRAAG 4 [29 MARKS/PUNTE] | Q/V | Solution/Oplossing Explanation/Verduideliking | T&L D 4.1.1 | Daniil Medvedey YRT 1RT Daniil Medvedev Ll E 198m VRT IRT 1,98 m (2) YMA IMA concept of mean D 4.1.2 | Range = Highest — Lowest/ Omvang = Hoogste - Laagste IMA subtracting correct L2 =38-20 ~MA values E =18 VA 1A answer (3) 4.1.3 vA ¥MA F/D $10,3 million + $12,2 million + $11,7 million + 1A correct 5 values L2 $11,6 million + $7,3 million IMA adding the values E = $53,1 million VCA 1CA correct answer QB) VVA F 4.1.4 | The value of one currency for the purpose of conversion to 2A correct definition Ll (a) another/Die koers waarteen een geldeenheid vir ‘n ander E omgeruil sal word. - (2) YMA F 4.1.4 | $32 million + $23 million = $55 milKon 1MA adding correct values | L2 (b) 1A answer M $55 million x 0,8996 YMCA IMCA multiply with 0,8996 ¥CA = €49 478 000/€49,478 million 1CA answer in euros (4) F/D 4.1.5 | Percentage female earnings/Persentasie vroulike inkomste L4 $27,1 million + $26,7 million + $14,6 million + $13,7 million D = $82,1 millionWA 1A correct total values $82,1 million 190%” MCA IMCA divided by 245,7 MOK 1MCA percentage = 33,41473341% “CA i =33,415% VYCA : OR/OF $27100 000 +$26 700 000 + $14 600 000 + $13 700 000 = $82 100 000VA $82 100 000 x 100% YMCA $245 700 000 ¥MCA wi = 33,41473341% CA may YOA 1CA correct rounded answer 1A correct total values 1MCA divided by 245,7 1MCA percentage calculation 1CA answer VON nnn nk nee And nee eee

NW/September 2025 (5) | Q/V | Solution/Optossing Explanation/Verduideliking | T&L ¥ RT D 4.1.6 Mean/Gemiddeld = (10,3412,2411,6+0,3+7,3+3,9+6,7)MM YMA 1RT correct values L2 6 1MA concept of mean M 45,6 MM 3 (YMA IMA divided by 6 vA = 7,6 million (MM) OR/OF 7 600 000 1A answer in millions (4) F 42.1 |2+5+7=14 Ll E 7_1VA 1A adding ratio (14) os x 2 1A answer OR/OF : ; vVA Half of the amount/Helfte van die bedrag 2A correct answer (2) CA denominator from F 4.2.2 vA 4.2.1 L4 = x £175000 YMA 1A correct ratio M 1MA multiplying with = £62500 V¥ CA £175 000 . . vO 1CA correct answer His statement is CORRECT/Sy bewering is KORREK. 10 conclusion (4) [29] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 QUESTION/VRAAG 5 | 30 MARKS/PUNTE]| | Q/V | Solution/Oplossing Explanation/Verduideliking | T&L YMA F 5.1.1 | 2025 — 1959 IMA subtracting two correct | L1 * 66 yearsi/jare VA years E 1A correct answer AO (2) YRT YMCA # 5.1.2 | $256 800 x 35% IRT correct rate L2 YCA IMCA multiplied by 35% E =$ 89 880 1CA correct answer (If no dollar unit penalise with one mark/indien geen doller (3) eenheid penaliseer met een punt) 5.1.3. | Total medical credit/Totale mediese korting F L2 ¥MA YMA we = (R364 x 2) + (R246 x 7) IMA multiplying R364 by 2 | M =R728+R172 IMA multiplying R246 by 7 YMCA 1MCA calculating annual =R2 450 x 12 antiouitit = R29 400 vor 1CA correct answer a (4) CA from 5.1.2 and 5.1.3 F 5.1.4 | Tax payable in South Africa / L3 M Belasting betaalbaar in Suid-Afrika YMA $256 800 x 17,1232 = R4 397 237,76 VA YRT vs R644 489 + 45% (4 397 237,76 — 1 817 000) = R644 489 + 45% (2 580 237,76) = R644 489 + 1 161 106,992 ¥CA =RI1 805 595,992 — 29 400 YMCA =RI1 776 195,992 — (17 235 + 9 444) =RI1 749 516.99 YCA Tax payable in U.S / Belasting betaalbaar in VSA YMCA $ 89 880 x 17,1232 R1 539 033,22 VCA vo John McEnroe will pay less tax in the U.S/John McEnroe sal IMA multiply by 17,1232 1A correct answer IRT correct tax bracket 1S substitution of correct value ICA simplification 1MCA subtracting medical credit and rebate 1CA correct answer IMCA multiply by 17,1232 1A correct answer 10 conclusion

NW/September 2025 Q/V | Solution/Oplossing Explanation/Verduideliking | T&L OR/OF Tax payable in South Africa / CA from 5.1.2 and 5.1.3 Belasting beiaalbaar in Suid-Afrika ¥MA IMA multiply by 17,1232 $256 800 x 17,1232 1A correct answer = R4 397 237,76 VA YRT WS 1RT correct tax bracket R644 489 + 45% (4 397 237,76 — 1 817 000) 1S substitution of correct = R644 489 + 45% (2 580 237,76) vale = R644 489 + 1 161 106,992 ICA simplification ¥CA 1MCA subtracting medical =RI1 805 595,992 — 29 400 YMCA credit and rebate =RI1 776 195,992 — (17 235 + 9 444) 1CA correct answer =RI1 749 516.99 VCA IMCA divide by 17,1232 R1 749 516,99 + 17,1232” MCA lcntnnelanawes = $102 172,32 VCA Tax payable in U.S / Belasting betaalbaar in VSA $ 89 880 vO John McEnroe will pay less tax in the U. S/John McEnroe sal minder belasting betaal in die VSA 10 conclusion (10) YRT IRT correct value D 5.2.1 | 44775 — 16 337 YRT IRT correct value L2 =28 438 VA 1CA simplification E GB) 5.2.2 oA Differences 2021 sales —2020 sales x 100% D 2020 sales L2 ¥MA “SF D = ee x 100% 1MA correct formula 1SF substitution _ 206 563 *aaaeo7 * 100% en vs 1S simplification (3) = 168,492% = 168% Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 QV | Solution/Oplossing Explanation/Verduideliking | T&L 5.2.3 YRT 1RT correct numerator P sl IRT correct denominator L3 2a RP M =025 YCA 1CA correct decimal G) 5.2.4 YA D From March 2021 there was a strong decline in the sales for 2 | 10 strong decline L4 mn 10 rapid incline E months but in June and July increased rapidly/ Van Maart 2021 was daar ‘n sterk vermindering in verkope, maar van Junie en Julie was daar ‘n skielike stvging in verkope. 2) [30] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou