Maths LIT Grade 12 NSC P2 MEMO September 2025 Free State

_ education Department of Education FREE STATE PROVINCE PREPARATORY EXAMINATION VOORBEREIDENDE EKSAMEN GRADE/GRAAD 12 MATHEMATICAL LITERACY P2 WISKUNDIGE GELETTERDHEID V2 SEPTEMBER 2025 MARKS/PUNTE: 150 MARKING GUIDELINES/NASIENRIGLYNE Symbol/Kode | Explanation/Verduideliking M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid Cc Conversion/Herleiding S Simplification/ Vereenvoudiging Reading from a table/a graph/document/diagram/Lees vanaf tabel/'n grafiek/dokument/ diagram Correct substitution in a formula/Korrekte vervanging in 'n formule Opinion/Explanation/Opinie/Verduideliking Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding ens. Rounding off/Afronding No penalty for correct rounding/Geen penalisasie vir korrek afronding nie Answer only/Slegs antwoord Method with constant accuracy/Metode met volgehoue akkuraatheid No penalty for unit/Geen penalisasie vir eenheid nie These marking guidelines consist of 12 pages. Hierdie nasienriglyne bestaan uit 12 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne NOTE: If a candidate answers a question TWICE, only mark the FIRST attempt. If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented. General principle of marking: If the candidate makes one mistake, he/she loses one mark. LET WEL: As 'n kandidaat 'n vraag TWEE KEER beantwoord, merk slegs die EERSTE poging. As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, merk die doodgetrekte (gekanselleerde) poging. Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou op by die tweede berekeningsfout. Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra item. Die algemene beginsel van merk: as ‘n leerder een fut maak verloor hy/sy een punt. QUESTION/VRAAG 1 [28 MARKS/PUNTE]| ANSWER ONLY FULL MARKS Q/V_| Solution/Oplossing Explanation/Verduideliking T&L MP LL. | CYVA 2A explanation Ll E A plan that shows the length and width of an object.” ~ (2) M 1.1.2) HYVYA 2A explanation si The maximum amount that a container can hold¥ ¥ (2) M 1.1.3) GY¥VA 2A explanation Ll The base unit of mass in the metric B system is equal to 1 000 grams. Vv ¥ Q) 7 M J l.l4) DYWA 2A explanation Ll E The amount of matter or material in an object. ¥¥ (2) M L1S|EVVA 2A explanation LI The length of the space E between two places or points. VY (2) Copyright reserved/Kopiereg voorbehou

FS/VS/September 2025 Marking Guidelines/Nasienriglyne QIV | Solution/Oplossing Explanation/Verduideliking T&L p i M 1.2.1 | The area of the room is 22 m?. VV”A 2A explanation Ll Die opperviak van die kamer is 22 m? (2) P 1.2.2 | 0% OR/OF zero percent VV A 2A correct probability Ll NPU E, Q) MP 1.2.3 | Floor plan/Vioerplan VV A 2A correct answer dal E OR/OF (2) Layout plan/Uitlegplan VV A MP 1.2.4 | 325VVA 2A correct room number LI _ QE 1.2.5 | The one has a double bed and the other one | 2A correct difference MP has two single beds./Die een het ‘n LI dubbelbed en die ander twee E enkelbeddens, VA OR/OF First room can accomodate one person, the second room can accomodate two people./Eerste kamer kan een persoon akkomodeer. Die tweede kamer kan twee persone akkomodeer. VV A OR/OF The one has one study table, and the other one has two./Die een het een studietafel en die ander een het twee. VV A OR/OF The one has one chair and the other one has two chairs./Die een het een stoel en die ander evn het twee. VV A OR/OF The one has one sidelamp and the other one has two sidelamps./Die een het een lampie en die ander een het twee. VV A (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne Q/V | Solution/Oplossing Explanation/Verduideliking | T&L M 1.3.1) 2x 1000 “MA IMA multiplied by 1000 Ll E =2000mvA 1A correct answer NPU (2) MP 1.3.2 | True/Waar VV A 2A correct answer LI (2) | E M 1.3.3 | 19:49V¥VA 2A correct time format tt (2) | M M 1.3.4 | 24-7VY¥MA IMA subtracting correct LI values E =17minvA 1A correct answer NPU (2) [28] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne QUESTION/VRAAG 2 [25 MARKS/PUNTE] Q/V_| Solution/Oplossing Explanation/Verduideliking | T&L MP 211) 2vVvA 2A correct answer LI MP 2.1.2 | Nelspruit VV A 2A correct town L2 (2) |E YRT MP 2.1.3 | 28 km+ 18 km + 3,5 km YMA IRT correct values L2 1MA adding values D = 49,5 km VCA 1CA no of kilometres NPU @) MP 2.1.4 | MachadodorpY “A 2A name of the toll plaza Ll (2) |E vA vA - 1A Ist road MP 2.1.5 | R539 and/en R36 | Aecept: R53 1A 2nd road Ll (2) |M MP 2.2.1 | 3 or three/of drie VW A 2A number of windows LI (2)|M MP 2.2.2 | Falsc/Onwaar YW A 2A correct answer L4 (2)|M MP 2.2.3 | Measured length/gemete fengte L2 = 125 mmvA 1A measured value (accept D 120 mm to 125 mm) 125 mm = 11,5 m “MCA 1MCA correct order of the ¥C ratio 0,125: 11,5 1C conversion 1:92 VCA 1CA unit ratio (4) MP 2.2.4 | There is no wall between the kitchen and 2A opinion L4 the living/lounge/dining/sitting room/Daar M is geen muur tussen die kombuis en die sitkamer/eetkamer nie. ¥V A (2) MP 2.2.5 | An elevation plan shows the side view of _ | 2A explanation Ll (a) | the outside of the building./n Aansigplan M toon die sy-aansig van_'n gebou.YV A (2) MP 2.2.5 | South Elevation/Suidaansig VV A 2A correct elevation L2 (b) (2)|M

FS/VS/September 2025 Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3 [26 MARKS/PUNTE] Explanation Q/V | Solution/Oplossing Verduideliking T&L M 3.1.1 | Thermometer/Termometer VV A 2A correct instrument | L1 Accept: Thermostat (2)|M M 3.1.2 | 440 mm — (4 mm = 2) WMA 1MA subtracting L2. double thickness M = 432 mm YCA ICA simplification AO (2) CA from 3.1.2 M 3.1.3 | Diameter/Middellyn: 432 mm = 0,432 m YC 1C conversion(mm to | L4 m) D Height/Hoogte: 1325 mm — 4 mm = 132) mmv A =1,321m 0,432 Radius = =0,216VYCA Volume = 3,142 x (radius)? * height/Aoogte = 3,142 x (0,216 m)* x 1,321 m WSF ¥CA = 0,19364 m3 x 1000 YC = 193,659 C Then/Dan: 98% x 193,659 € ™MCA = 189,78 CYCA His claim is not correct./Sy stelling is nie korrek nie.¥O OR/OF — 185 3 185 (=7 om = 0,185 m3 ¥ : 0,432 Radius = = 0,216 YCA 1A height 1CA radius 1SF substitution into the formula 1CA answer 1C conversion (m° to 0) 1MCA calculating percentage 1CA number of litres 10 opinion 1C conversion (£ to m*) ICA radius Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne Volume = 3.142 * (radius) x height/hoogte 0,185 m? = 3.142 x (0,216)? x h WSF 1SF substitute into — __ 8185 ws YMA formula : Berane ms 1MA changing the h + 1,262 m ¥CA subject of the formula . : . ICA simplification The given height of the geyser is Height/Hoogte: 1325 mm - 4 mm = 1321 mm =1,321mvA 1A determine height so: = x 1,321 m YMCA IMCA calculating 98% = 1,294 VCA of the height 1CA simplify height The statement is not correct. “O 10 correct opinion (9) 3.1.4 | °9F—32°=(1.8 < °C) M 1SF correct substitution | L2 140° F — 32 = (1,8 x °C) “SF M 1MA changing the 108 = 1,8 x °C subject of the formula oC = 108 YMA 1CA simplification 18 (3) =60°CVCA VVA M 3.2.1 | The total length around the rib cage of the cat./Die | 2A explanation Ll totale lengte rondom van die kat se ribbekas. (2) M 3.2.2 | BMI/LMIV VA 2A correct answer Ll (2) |E M 3.2.3 | BMI/LM/ = eo 2 5 1 om WSE 1SF substitution L2 0,6466 — 0,9156 D = ~ — vo F : : 34,43-—8,57—5,1 4S 1S simplification = 43,77 CA 1CA answer ah ig init Obese/vetsugtig VO 10 opinion NPR (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne Q/V_| Solution/Oplossing Explanation/Verduideliking | T&L M 3.2.4 | Reduce the amount of food./Verminder die 20 opinion L4 hoeveetheid kos. VV O E OR/OF Give low-calorie/healthy food./Gee lae kaloriekos/gesonde kos. OR/OF Cut back on treats./Verminder lekkernye. OR/OF Take the cat for walks/Gaan stap met die kat. (2) [26] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 [38 MARKS/PUNTE] Q/V_| Solution/Oplossing Explanation/Verduideliking | T&L M 4.1.1 | Perimeter = 2 x (length + width)/ L2 Omtrek = 2 x (lengte + breedte) E =2 x (1,525 m+ 2,74 m)“ SF 1SF correct substitution = 8,53 mv CAVA 1CA correct answer 1A unit NPR AO Q) ¥MA M 4.1.2 | Length/Lengte = 0,153 m x 2+ 1,525 m 1MA multiplied by 2 L2 ¥MA 1MA adding M = 0,306 m + 1,825 m 1CA correct answer NPU = 1,831 m4“CA NPR AO @) YRT M 4.1.3 | 0,76: 0,153 “A 1RT correct values L2 1A order M 1:0,201IVCA 1CA answer NPR AO GQ) L2 4.1.4 | 0,76m = 760 mm YC 1C conversion M E 760 mm — 100 mm “YMA 1MA subtraction 660 mm = 0,7 m or/of 0,66 m or/of 0,67 mv A A correct answer OR/OF 100 mm = 0,1 mV¥C 1C conversion 0,76 m—0,1 m 1MA subtraction = 0,66 m = 0,7 m or/of 0,66 m or/of'0,67 mv A A correct answer NPU NPR fe) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou 2 A Explanation Q/V | Solution/Oplossing Verduideliking T&L Pp 4.1.5 | Boys/Seuns = 12V A 1A number of boys L2 (a) E Girls/Meisies = 09VA 1A number of girls 12 -09=03 YCA 1CA answer more players were boys/meer spelers was AO seuns fe) vA CA Total from 4.1.5(a) P 4.1.5) 2 _ 1A numerator L2 = =0,095238095YCA ‘ (b) 21 1A denominator M vhs 1CA answer as decimal number NPR a (3) Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne A 5 Explanation QIV | Solution/Oplossing Verduideliking T&L M 4.2.1 | Container/Houer | L4 M Volume = length x width = height Volume = lengte x breedte x hoogte = 3,5 in x 2 in x 9,5 in WSF 1SF correct substitution = 66,5 in’ YCA 1CA correct answer Container/Houer 2 Volume = 7t * radius? x height/hoogte 1SF substitution = 3,142 x (5 +2) x 9.5 WSF 1A radius vA = 3,142 x 2,5° x 9,5 1CA answer = 186,56 inv CA Container 2/Cylinder/Houer 2/Silinder VO 10 opinion NPU NPR (6) L3 4.2.2 | SA=2 x m x radius x height + 7 = radius” M BO =2 x 2% radius < hoogte + 2 * radius? M =2 x 3,142 x 2,5 x 9,5 + 3,142 x (2,5) WSF 1SF substitution = 149,245 + 19,6375 VS 1S simplification = 168,8825 in? VWCA 1CA answer NPU NPR QB) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne Explanation Qrv Balsrtlompioskng Verduideliking T&L M 4.2.3 | 1 inch/dm = 25,4 mm L2 (a) M 2? =40mm — 40mm /_ IMA dividing 25,4mm = 1,57 indm ¥CA 1CA correct answer NPU AO (2) 4.2.3 | CONTAINER 1/HOUER 1 CA from 4.2.3(a) (b) L4 ‘ 25 IMA dividin MP —v = 055 Vv ig Height/Hoogte ce MA = 6,050955 VCA ICA answer D 5 =O¥YR IR rounding down Width/breedte: 157 =1,27 #1 355 Length//engte: — = 2,22 ae 2VCA 1CA correct answer No. that can be packed/Aantal wat gepak kan word: YMCA I1MCA multiplying 6x1x2 = =12 balls/balle¥CA 1CA no of balls CONTAINER 2/HOUER 2 . 95 _ Height/Hoogte: coe 6 Diameter/Middellyn: = =3VCA ICA answer No that can be packed/Aantal wat gepak kan word: 6 x 3 =18 balls/balle VWCA ICA no of balls Statement NOT VALID/Stelling is NIE WAAR | 16 conclusion NIE ¥O (9) [38] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Marking Guidelines/Nasienriglyne FS/VS/September 2025 | QUESTION/VRAAG 5 [33 MARKS/PUNTE] T i q Explanation Q/F | Solutien/Oplossing Verduideliking * MP 5.1.1. | Lesotho ¥WA 2A name of the country LI @lE ¥YRT MP 5.1.2. | 30355 x 14.1% YMA IRT total area 2 E = 4 280,055 km? 1MA multiplying by % ~4 280 km? YR 1R correctly rounded area NPU AO (3) MP 5.1.3 | Bar ScalevA 1A name of the scale L2 vA M When the map enlarges/reduces the scale also | 1A advantage enlarges/reduces. Grafiese skal Wanneer die kaart vergroot/verklein sal die (2) skaal ook vergroot/verklein. MP 5.1.4 | Two million one hundred and twenty five Ll thousand two hundred and sixty eight./Twee 2A correct answer E miljoen een honderd en vyf en twintig duisend twee honderd agt en sestig. VV A (2) MP 5.1.5 | South East/SE/Suidoos/SO VV A 2A direction L2 (2) |M M 5.1.6 | Before noon/Voormiddag VV A 2A correct answer oy (a) _. : (2) |E Accept: Time in the morning M 5.1.6 | Driving time/Rytyd = 8 hrs and 19 min 3 (b) v¥MA IMA adding duration to M 09:00 + 8 hrs and 19 min correct beginning time =17:19VCA ICA correct final time Breaks/Stoppe = 65 min + 45 min + 49 min Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne = 159 min ¥CA 1CA total time for breaks 159 __ a 2,65 = 2 hrs/uur and/en 39 min YC 1C conversion Arrival time/Aankomstyd: =17: inv’ 17:19 +2 hrs and 39 minw MCA IMCA adding = 19:58 VCA ICA arrival time OR/OF Total time/totale tyd ¥M =8 hrs 19 min + 65 min + 45 min + 49 min TMsarldingy tame: =8 hrs 178 min “CA ICA answer 178 min = 2 hrs 58 min WC 1C conversion +. Total time = 10 hrs $8. min “CA Teast ime 1MCA adding to correct beginning time 1CA arrival time 09:00 + 10 hrs 58 min ™MCA = 19:58 ¥CA OR/OF 1M adding to correct beginning time 1M adding time ¥M v¥M 9:00 + 8:19 + 0:65 + 0:45 + 0:49 =17: in V¥ 17:178 mn 1CA answer 178 min = 2 hrs 58 min iGiconversion 17:00 +2 hrs 58 min ™MCA IMGs adding =19:58VCA 1CA total time (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne T ‘ 5 Explanation Q/V | Solution/Oplossing Verduideliking * '5.2 | Inland cost/binnelandse koste F L4 = 80 litres x R22,86 ICA calculating amounts M (R1 828,80 and R1 765,60) =RI 828,80 VCA Coastal cost/Kuskoste = 80 litres x R22,07 =RI1 765,60 YMCA . _, R1828,80—R1 765,60 1MCA numerator % diff/verskil =" Y ; ca iE vershil R1 828,80 * 100% 1MCA denominator ¥MCA ICA correct % =3,46%VYCA NOT VALID/NIE GELD/G NIE VO 10 conclusion OR/OF vA R22,86~R22,07 % diff/verskil ==" 100% vMA | !A numerator R22,86 1A denominator vA 1MA multiplied by 100% =3,46%VCA 1CA correct % 10 conclusion NOT VALID/NIE GELDIG NIE VO OR/OF VA 1A numerator 1765,60 | 100% YMA 1A denominator 1828,80 IMA multiplied by 100% vA = 96,54 100% - 96,54 ICA correct % = 3,46%YCA 10 conclusion NOT VALID/NIE GELDIG NIE ¥O OR/OF 1A numerator 1A denaminator

FS/VS/September 2025 Marking Guidelines/Nasienriglyne 22,07 —— x 100% YMA 22,86 vA = 96,54% 100% - 96,54 ICA correct % = 3,46%YCA 10 conclusion NOT VALID/NIE GELDIG NIE VO 65) M 5.3.1 | Driving time/Reistvd = 2hr 20 min — 15 min 1.3: M =2 hr 05 minvA 1A driving time 2 br +2 60 ~ 2.083333...” IC conversion 121 km = speed * 2,083333.....WSF LSE"Substitition 121.km Speed/Spoed =F oaaaxs, ’ MA IMA changing the subject = 58,08 km/h YCA ICA average speed NPR (5) Copyright reserved/Kopiereg voorhbchou Please turn over/8/aai om asseblief

FS/VS/September 2025 Marking Guidelines/Nasienriglyne Fi ‘ Explanation Q/V | Solution/Oplossing Verduideliking T&L F 5.3.2 | R23 887,50 = 97,5% 12 ? = 100% D Original amount/Oorspronklike bedrag 1MA multiply with correct a 100 VA Taeammeeior RES EIS 97.5 as 1A denominator = R24 500 VCA 1CA amount OR/OF 100% — 2,5% = 97,5% = 0,975 YMA IMA correct % Original amount/Oorspronklike bedrag v _ R23 887,50 A 1A numerator “0975 YA 1A denominator = R24 500,00 YCA 1CA amount OR/OF 1 —0,025 = 0,975 YMA 1MA difference Original amount/Oorspronklike bedrag R23 887,50 VA 1A numerator ~ "9,975 vA 1A denominator = R24 500,00 YCA 1CA amount (4) [33] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou