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NATIONAL
SENIOR CERTIFICATE
GRADE 12
JUNE 2019
MATHEMATICAL LITERACY P1
MARKING GUIDELINE
MARKS: 100
Symbol Explanation
M Method
MA Method with accuracy
CA Consistent accuracy
A Accuracy
C Conversion
S Simplification
RT/RG/RM Reading from a table/Reading from a graph/Reading from a map
F Choosing the correct formula
SF Substitution in a formula
J Justification
P Penalty, e.g. for no units, incorrect rounding off etc.
R Rounding Off/Reason
AO Answer only
NPR No penalty for rounding
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Mathematical Literacy Grade 12 P1 EC June 2019 Memo (Eng)
Grade 12 Mathematical Literacy Paper 1 memorandum from the EC June 2019 (English), 8 pages. Read online or download the free PDF.
Mathematical Literacy · Grade 12 · EC June · 2019. Memorandum, 8 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2019
- Exam period
- EC June
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 8
- File size
- 255.6 KB
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EC June 2019
Questions in this paper
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2 MATHEMATICAL LITERACY P1 (EC/JUNE 2019)
NOTE:
If a candidate answers a question TWICE, only mark the FIRST attempt.
If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the
solution, mark the crossed out (cancelled) version.
Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however
it stops at the second calculation error.
If the candidate presents any extra solution when reading from a graph, table, layout
plan and map, then penalise for every extra incorrect item presented.
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(EC/JUNE/2019) MATHEMATICAL LITERACY P1 3
QUESTION 1 [22 MARKS] INTEGRATED QUESTION
Question Solution Explanation/Marks
AO: FULL MARKS Topic/L
1.1 1.1.1 DM Row Travel Agency RT 2 RT correct agency F
(2) L1
1.1.2 Reference Number: 0674582 RT 2 RT correct Voucher no. F
(2) L1
1.1.3 3 nights RT 2RT correct no of nights F
(2) L1
1.1.4 3 × R1 440,00 M 1M×1 440,00 F
= R4 320,00 CA 1CA simplification (2) L1
1.2 1.2.1 250 + 330 + 450 + 500 + 1 000 + 1500 + 2 000 1M addition all values M
= 5 580 mℓ M L1
1CA dividing and
= 5,58 ℓ CA simplifying
OR
0,25 + 0,33 + 0,45 + 0,5 + 1 + 1,5 + 2 l MA
= 5,58 l CA (2)
1.2.2 M 1M division correct values M
No. of A containers= = 6CA 1CA No of A containers L1
(2)
1.3 1.3.1 42,2 km RT 2 RT distance M&P
(2) L1
1.3.2 Difference in height above sea level 1RT correct values M&P
= 46 – 35 RT L1
=11 m CA 1CA difference (2)
1.4 1.4.1 Mode = 61 RT 2RT mode D
= 47 (2) L1
1.4.2 Range = 86 – 18 MA 1MA subtracting correct
= 68 CA values D
1CA range (2) L1
1.4.3 Raw mark = 150 MA 1MA % of 150 D
L1
= 129 CA 1CA raw mark
OR
Raw mark = 0,86 x 150 MA
= 129 CA (2)
[22]
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4 MATHEMATICAL LITERACY P1 (EC/JUNE 2019)
QUESTION 2 [29 MARKS] FINANCE
Question Solution Explanation/Marks Topic
AO: FULL MARKS /L
2.1 2.1.1 Total amount = 1 200 × 60 M 1M multiplication F
= R72 000 CA 1CA amount (2) L1
2.1.2 20 000 R6 000 M CA 1M multiplication of correct
values
OR
1CA simplification (2)
School’s contribution = 0,3 x 20 000 M F
= R6 000 CA L1
2.1.3 Ratio 2 000 : 20 000 MA A 1MA for ratio and 2000 F
1 : 10 1A for 20 000 (2) L1
2.1.4 Balance = 2 000 – (10 50 1M balance after sale of 10 T
= R1 500 M shirts
= 50 M 1M division
1CA total number of T-shirts
Total T-Shirts = 50 + 10 F
= 60 CA (3) L2
2.2 2.2.1 D = 24 901 – 23 901 M 1M subtracting values F
= 1000 kwh A 1A simplifying (2) L1
2.2.2 Costs = 100 132,70+50 155,30 M 1M multiplication and
= 13 270 + 7 765 addition
= 21 035 M 1M simplification
CA 1CA dividing by 100
F
= R210,35 (3) L2
2.2.3 VAT amount= 210,35 M 1M multiplication of 15% by
210,35 F
= R31,55 A
1A simplification (2) L1
2.3 2.3.1 Inflation is the increase in price of goods and 2 Explanation
F
services e.g. the price of petrol increases with
L1
time. O (2)
2.3.2 Price increase = 16,21 – 16,02 M 1M subtraction of values
= 19c OR R0,19 A 1A difference (with units cents F
or Rands) (2) L1
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(EC/JUNE/2019) MATHEMATICAL LITERACY P1 5
2.3.3 M 1CA from 2.3.2
Distance = 5 50 2 500 km M 1M distance for a day (50 2)
Fuel used = M 40 CA 1M distance for 5 days
,
1M division by 12,5
Increase in fuel cost= 40 0,19 = R7,60 CA 1CA simplification
1CA increase
OR
Distance = 50 x 2 = 100 km for a day
Fuel used = =8ℓ
,
Increase in cost of fuel for 1 day = 8 x 0,19
= R1,52
Increase in cost of fuel for 5 days = R1,52 x 5
= R7,60
OR
2 x 50 x 5 = 500 km
Petrol used = = 40 ℓ
,
Cost of fuel after increase = 40 x 16,21 = R648,40
Cost of fuel before increase = 40 x 16,02 = R640,80 F
Increase = R648,40 – R640,80 = R7,60 (5) L3
2.4 2.4.1 Balance = R13 502,64 RT 2 RT F
(2) L1
2.4.2 Fee = 42,37+17,47+100,88 = R160,72 RTCA 1 RT adding correct values
1 CA simplification F
(2) L1
[29]
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6 MATHEMATICAL LITERACY P1 (EC/JUNE 2019)
QUESTION 3 [20 MARKS] MEASUREMENT
Ques. Solution Explanation/Marks
AO: FULL MARKS Level
3.1.1 M 1M Addition of correct
Total distance = 6,3 + 13,02 + 5,04 values M
= 24,36 km CA 1CA Simplification (2) L1
3.1.2 M 1M distance around
Perimeter = 120 × 2 + 90 × 2 1A simplification M
= 420 m (or 0,42 km) A (2) L1
3.1.3 , 1 RT value of 1,6 km
No of rounds = RT M
1 M Division
C 1 C Conversion
= 3,81 CA 1 CA simplification
Completed rounds =3 R 1 Rounding to completed
rounds M
(5) L2
3.1.4 : % % 1M substitution
1CA simplification
(NPR)
= 100%M
M
= 97,65%CA (2) L2
3.1.5 M 1M conversion to m
, 1M division
Distance = M
1CA simplification
= 0,6665 CA M
1CA rounding (4)
= 0,67m CA L2
3.2.1 V πr h 1M substituting radius
M 1M substituting height
V = 3,142 2.5 12,75 1CA simplification M
= 250,38 cm CA (NPR) (2) L2
3.2.2 100 mℓ : 211 KJ M 1Mconcept of ratio
250,38 : ? 1M method
multiplication of correct
, values and dividing by
?= M = 528,30 KJCA
100 M
1CA simplification (3) L2
[20]
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(EC/JUNE/2019) MATHEMATICAL LITERACY P1 7
QUESTION 4 [11 MARKS] MAPS AND REPRESENTATIONS
Ques. Solution Explanation/Marks
AO: FULL MARKS Level
4.1 South RT 2RT correct direction M&p
(2) L1
4.2 RT 1RT measuring scale
2,5 cm : 20 km 1M conversion from
1.6 : 10 1000 100 M km to cm
1CA expressing in
1 : unit ratio
,
1 : 800 000 CA
OR
2,5 cm : 20 km
1 cm : 8 km x 1000 000 M &p
1 : 800 000 (3) L2
4.3 2,5 cm : 20 km 1CA from 4.2
6,5 cm : ? (distance from Queenstown CBD and Whittesea)M 1M measuring
M distance on map
,
distance = M
, 1M multiplication of
= 52 km CA values
1M division by 2,5
OR 1CA simplification (4)
1 : 800 000 (CA from 4.2)
6,5 : 800 000 6,5cm MM 1M measuring
,
distance on map
Distance = M 1M multiplication
1M conversion to km
= 52 km CA 1CA simplification
(Accept 6,2 – 6,7 cm) M &p
(Accept 49,6 – 53,6 km) (4) L2
4.4 Numeric scale A 2A Correct scale
Representative scale / Ratio scale A M &p
Verbal scale / Word scale A (2) L1
[11]
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8 MATHEMATICAL LITERACY P1 (EC/JUNE 2019)
QUESTION 5 [18 MARKS] DATA HANDLING
Ques. Solution Explanation/Marks
AO: FULL MARKS Level
5.1 Gauteng RT 2RT correct province D
(2) L1
5.2 1 145 861; 2 745 590; 3 509 953; 4 039 939; 5 404 868; 2RT arranging all D
values starting with L1
5 822 734; 6 562 053; 10 267 300; 12 272 263 RT smallest.
(2)
5.3 Limpopo RT 2RT middle position D
CA from 5.2 and L1
check province (2)
5.4 5.4.1 Free State and North West CA CA from 5.2 D
1 mark for each L1
province (2)
5.4.2 Eastern Cape and KwaZulu-Natal CA CA from 5.2 D
1 mark for each L1
province (2)
5.5 IQR represents 50% A 2A D
(2) L1
5.6 No. of listeners in NW = 3 509 953M 1M 90 % of the D
population L2
= 3 158 957,71S
1S simplification
= 3 158 958CA
1CA (Rounded to the
nearest whole number
people cannot be
decimals)
(3)
5.7 % Mean = M 1M adding the D
percentages L2
1M dividing by 9
= M 1CA simplification
(NPR)
= 89,78% CA (3)
[18]
TOTAL: 100
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