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Mathematical Literacy Grade 12 P1 EC June 2019 Memo (Eng)

MemorandumMathematical LiteracyGrade 1220198 pages

Grade 12 Mathematical Literacy Paper 1 memorandum from the EC June 2019 (English), 8 pages. Read online or download the free PDF.

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Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 JUNE 2019 MATHEMATICAL LITERACY P1 MARKING GUIDELINE MARKS: 100 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table/Reading from a graph/Reading from a map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason AO Answer only NPR No penalty for rounding This marking guideline consists of 8 pages.
Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/JUNE 2019) NOTE:  If a candidate answers a question TWICE, only mark the FIRST attempt.  If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version.  Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error.  If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra incorrect item presented. Copyright reserved Please turn over
Downloaded from hlayiso.com (EC/JUNE/2019) MATHEMATICAL LITERACY P1 3 QUESTION 1 [22 MARKS] INTEGRATED QUESTION Question Solution Explanation/Marks AO: FULL MARKS Topic/L 1.1 1.1.1 DM Row Travel Agency  RT 2 RT correct agency F (2) L1 1.1.2 Reference Number: 0674582  RT 2 RT correct Voucher no. F (2) L1 1.1.3 3 nights  RT 2RT correct no of nights F (2) L1 1.1.4 3 × R1 440,00  M 1M×1 440,00 F = R4 320,00  CA 1CA simplification (2) L1 1.2 1.2.1 250 + 330 + 450 + 500 + 1 000 + 1500 + 2 000 1M addition all values M = 5 580 mℓ M L1 1CA dividing and = 5,58 ℓ  CA simplifying OR 0,25 + 0,33 + 0,45 + 0,5 + 1 + 1,5 + 2 l MA = 5,58 l CA (2) 1.2.2 M 1M division correct values M No. of A containers= = 6CA 1CA No of A containers L1 (2) 1.3 1.3.1 42,2 km  RT 2 RT distance M&P (2) L1 1.3.2 Difference in height above sea level 1RT correct values M&P = 46 – 35  RT L1 =11 m  CA 1CA difference (2) 1.4 1.4.1 Mode = 61  RT 2RT mode D = 47  (2) L1 1.4.2 Range = 86 – 18  MA 1MA subtracting correct = 68 CA values D 1CA range (2) L1 1.4.3 Raw mark = 150  MA 1MA % of 150 D L1 = 129  CA 1CA raw mark OR Raw mark = 0,86 x 150 MA = 129  CA (2) [22] Copyright reserved Please turn over
Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/JUNE 2019) QUESTION 2 [29 MARKS] FINANCE Question Solution Explanation/Marks Topic AO: FULL MARKS /L 2.1 2.1.1 Total amount = 1 200 × 60  M 1M multiplication F = R72 000  CA 1CA amount (2) L1 2.1.2 20 000 R6 000 M  CA 1M multiplication of correct values OR 1CA simplification (2) School’s contribution = 0,3 x 20 000  M F = R6 000  CA L1 2.1.3 Ratio 2 000 : 20 000 MA A 1MA for ratio and 2000 F 1 : 10 1A for 20 000 (2) L1 2.1.4 Balance = 2 000 – (10 50 1M balance after sale of 10 T = R1 500 M shirts = 50 M 1M division 1CA total number of T-shirts Total T-Shirts = 50 + 10 F = 60 CA (3) L2 2.2 2.2.1 D = 24 901 – 23 901 M 1M subtracting values F = 1000 kwh A 1A simplifying (2) L1 2.2.2 Costs = 100 132,70+50 155,30 M 1M multiplication and = 13 270 + 7 765 addition = 21 035 M 1M simplification CA 1CA dividing by 100 F = R210,35 (3) L2 2.2.3 VAT amount= 210,35 M 1M multiplication of 15% by 210,35 F = R31,55 A 1A simplification (2) L1 2.3 2.3.1 Inflation is the increase in price of goods and 2 Explanation F services e.g. the price of petrol increases with L1 time.  O (2) 2.3.2 Price increase = 16,21 – 16,02 M 1M subtraction of values = 19c OR R0,19 A 1A difference (with units cents F or Rands) (2) L1 Copyright reserved Please turn over
Downloaded from hlayiso.com (EC/JUNE/2019) MATHEMATICAL LITERACY P1 5 2.3.3 M 1CA from 2.3.2 Distance = 5 50 2 500 km M 1M distance for a day (50 2) Fuel used = M 40 CA 1M distance for 5 days , 1M division by 12,5 Increase in fuel cost= 40 0,19 = R7,60 CA 1CA simplification 1CA increase OR Distance = 50 x 2  = 100 km for a day Fuel used = =8ℓ , Increase in cost of fuel for 1 day = 8 x 0,19 = R1,52  Increase in cost of fuel for 5 days = R1,52 x 5  = R7,60  OR 2 x 50 x 5 = 500 km  Petrol used = = 40 ℓ  , Cost of fuel after increase = 40 x 16,21 = R648,40  Cost of fuel before increase = 40 x 16,02 = R640,80  F Increase = R648,40 – R640,80 = R7,60  (5) L3 2.4 2.4.1 Balance = R13 502,64 RT 2 RT F (2) L1 2.4.2 Fee = 42,37+17,47+100,88 = R160,72  RTCA 1 RT adding correct values 1 CA simplification F (2) L1 [29] Copyright reserved Please turn over
Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/JUNE 2019) QUESTION 3 [20 MARKS] MEASUREMENT Ques. Solution Explanation/Marks AO: FULL MARKS Level 3.1.1 M 1M Addition of correct Total distance = 6,3 + 13,02 + 5,04 values M = 24,36 km CA 1CA Simplification (2) L1 3.1.2 M 1M distance around Perimeter = 120 × 2 + 90 × 2 1A simplification M = 420 m (or 0,42 km) A (2) L1 3.1.3 , 1 RT value of 1,6 km No of rounds = RT M 1 M Division C 1 C Conversion = 3,81 CA 1 CA simplification Completed rounds =3 R 1 Rounding to completed rounds M (5) L2 3.1.4 : % % 1M substitution 1CA simplification (NPR) = 100%M M = 97,65%CA (2) L2 3.1.5 M 1M conversion to m , 1M division Distance = M 1CA simplification = 0,6665 CA M 1CA rounding (4) = 0,67m CA L2 3.2.1 V πr h 1M substituting radius M 1M substituting height V = 3,142 2.5 12,75 1CA simplification M = 250,38 cm CA (NPR) (2) L2 3.2.2 100 mℓ : 211 KJ M 1Mconcept of ratio 250,38 : ? 1M method multiplication of correct , values and dividing by ?= M = 528,30 KJCA 100 M 1CA simplification (3) L2 [20] Copyright reserved Please turn over
Downloaded from hlayiso.com (EC/JUNE/2019) MATHEMATICAL LITERACY P1 7 QUESTION 4 [11 MARKS] MAPS AND REPRESENTATIONS Ques. Solution Explanation/Marks AO: FULL MARKS Level 4.1 South RT 2RT correct direction M&p (2) L1 4.2 RT 1RT measuring scale 2,5 cm : 20 km 1M conversion from 1.6 : 10 1000 100 M km to cm 1CA expressing in 1 : unit ratio , 1 : 800 000 CA OR 2,5 cm : 20 km 1 cm : 8 km x 1000 000 M &p 1 : 800 000 (3) L2 4.3 2,5 cm : 20 km 1CA from 4.2 6,5 cm : ? (distance from Queenstown CBD and Whittesea)M 1M measuring M distance on map , distance = M , 1M multiplication of = 52 km CA values 1M division by 2,5 OR 1CA simplification (4) 1 : 800 000 (CA from 4.2) 6,5 : 800 000 6,5cm MM 1M measuring , distance on map Distance = M 1M multiplication 1M conversion to km = 52 km CA 1CA simplification (Accept 6,2 – 6,7 cm) M &p (Accept 49,6 – 53,6 km) (4) L2 4.4 Numeric scale  A 2A Correct scale Representative scale / Ratio scale A M &p Verbal scale / Word scale A (2) L1 [11] Copyright reserved Please turn over
Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P1 (EC/JUNE 2019) QUESTION 5 [18 MARKS] DATA HANDLING Ques. Solution Explanation/Marks AO: FULL MARKS Level 5.1 Gauteng RT 2RT correct province D (2) L1 5.2 1 145 861; 2 745 590; 3 509 953; 4 039 939; 5 404 868; 2RT arranging all D values starting with L1 5 822 734; 6 562 053; 10 267 300; 12 272 263 RT smallest. (2) 5.3 Limpopo RT 2RT middle position D CA from 5.2 and L1 check province (2) 5.4 5.4.1 Free State and North West CA CA from 5.2 D 1 mark for each L1 province (2) 5.4.2 Eastern Cape and KwaZulu-Natal CA CA from 5.2 D 1 mark for each L1 province (2) 5.5 IQR represents 50% A 2A D (2) L1 5.6 No. of listeners in NW = 3 509 953M 1M 90 % of the D population L2 = 3 158 957,71S 1S simplification = 3 158 958CA 1CA (Rounded to the nearest whole number people cannot be decimals) (3) 5.7 % Mean = M 1M adding the D percentages L2 1M dividing by 9 = M 1CA simplification (NPR) = 89,78% CA (3) [18] TOTAL: 100 Copyright reserved Please turn over

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