Mathematical Literacy Grade 12 P2 EC June 2019 Memo (Eng)

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 JUNE 2019 MATHEMATICAL LITERACY P2 MARKING GUIDELINE MARKS: 100 SYMBOL EXPLANATION M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table OR reading from a graph OR diagram OR from map a OR a plan F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason AO Answer only NPR No penalty for rounding O Opinion D Define This marking guideline consists of 9 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P2 (EC/JUNE 2019) NOTE:  If a candidate answer a question TWICE, only mark the FIRST attempt.  If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version.  Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error.  If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra incorrect item presented. QUESTION 1 [23 MARKS] Ques. Solution Explanation Level 1.1.1 Amount overdue 1 RT Correct values L2 = R26 263,55 – M R25 754,61 RT 1M Subtracting F = R508,94 OR OR 1 RT Correct values Amount overdue 1M Subtracting = R2 696,94 – M R2 188,00 RT = R508,94 (2) 1.1.2 Probability L2  1A Numerator P = 1A Denominator  = 0,18  CA 1CA Rounding (3) 1.1.3 EBUS 2715 fees 1 RT All correct values L4 = 2 696,94 + (3 715 × 7) + (4 280 × 2) + 3 510 1M Adding values F + 1 020 + 25,21 + 14,40 + 210 – 2 188 RT MM 1M Subtracting 2188 = 39 853,55 1M Subtracting from = 45 198,55 – 39 853,55 M 45 198,55 = R5 345 1 CA Difference Difference = 5 345 – 3 715 1O Not valid = R1 630 CA Statement is not valid O (6) 1.1.4  1RT Correct values L2 % Registration fee = x 100 M 1M Multiplying by 100 F , = 3,96%CA OR 4% 1CA Percentage NPR (3) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2019) MATHEMATICAL LITERACY P2 3 1.2.1  CA from 1.1.3 L3 Semester 1 = 1M Adding all values D  1M Dividing by 6 = R4 080,83 CA 1CA Mean Semester 2 = 1CA Mean semester 2 = R3 787  CA 1M Subtract Difference = R4 080,83 – R3 787 M 1CA Difference = R293,83 CA (6) 1.2.2 Amount for 2017 = 4280 MM 1M Multiplying by 100 L2 1M Dividing by 105 F = R4 076,19 CA 1CA Amount OR OR Amount for 2017 = MM 2M Dividing by 1,05 , = R4 076,19 CA 1CA Amount (3) [23] Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P2 (EC/JUNE 2019) QUESTION 2 [29 MARKS] Ques. Solution Explanation Level 2.1.1 Distance from Vanrhynsdorp to Garies 1 RT Correct values L4 = 433 – 289 RT OR = 258 – 114 RT 1A Distance M&P = 144 km A OR = 144 km A Distance from Kamieskroon to Springbok = 547 – 479 OR = 68 – 0 1A Distance = 68 km A OR = 68 km 1O Incorrect Incorrect O 1O Reason Strip chart not drawn to scale R (5) 2.1.2 Distance = (289 – 52) + 121 M 1M Add correct L2 = 358 km CA distances M&P OR 1CA Distance L3 Distance = 65 + 44 + 53 + 75 + 121 M M = 358 km CA Distance = Speed Time 1SF Substitution 358 = 95 Time SF 1M Change subject of = Time M formula Time = 3,76842 hours 1C Convert to minutes Minutes = 0,76842 60 1M Adding times = 46 minutes C 1CA Time Time of arrival = 7:00 + 0:45 + 3:46 M = 11:31 CA (7) 2.2.1 Area of rectangle = length x width 1C Convert to mm L3 = 150 120 CSF 1SF Substitution M = 18 000 mm2 A 1A Area of rectangle 1A Radius Area of a circle = radius 1CA Area of circle = 3,142 40 mm 40 mm A 1M Subtraction of the = 5 027,2 mm2 CA two areas 1CA Area without a Area without the photo = 18 000 – 5 027,2 M photo = 12 972,8 mm2 CA (7) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2019) MATHEMATICAL LITERACY P2 5 2.2.2 Surface area L3 = 2(length width + width height + length height) 1SF Substitution M = 2(390 270 + 270 300 +390 300)SFA 1A Correct values = 2(105 300 + 81 000 + 117 000) S 1S Simplification = 606 600 cm2 CA 1CA Surface area. (4) 2.3 Company A 1RT Correct values L3 IQR = 3 500 – 1 400 RT 1CA IQR (A) Data = 2 100 CA 1A Range (A) Range = 5 300 – 800 = 4 500 A Company C IQR = 5 800 – 3 900 1CA IQR (C) =1 900 CA 1CA Range (C) Range = 6 300 – 2 800 = 3 500 CA Both IQR and range are higher for Company A than 1O Finding Company C O OR Both IQR and range are smaller for company C than Company A O (6) [29] Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P2 (EC/JUNE 2019) QUESTION 3 [18 MARKS] Ques. Solution Explanation Level 3.1.1 Value of A = 6 3 + 1 6 M 1MA Matches won and drawn L2 = 18 + 6 1A Value of A D = 24 A 1M Subtracting and dividing by 3 Value of B = 19 – 4 1A Value of B = M = 5 A (4) 3.1.2 CA from 3.1.1 L2 Probability = AA 1A Numerator P 1A Denominator (2) 3.1.3 Points = 2 3 + 1 CA from 3.1.1 L4 =7 A 1A Points D Total = 21 + 7 = 28 MA 1MA Total points Difference = 28 – 24 1MA Difference = 4 MA Statement not valid O 1O Not valid (4) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2019) MATHEMATICAL LITERACY P2 7 3.2.1 School A = 45 2 3 = 270 M 1M No. of minutes L4 45 2 = 90 M Total = 270 + 90 = 360 minutes MA 1M Total no. of minutes Hours = 1C Convert to hours = 6 h C School B = 30 8 + 30 = 240 + 30 = 270 minutes 1CA No of hours for school B 1O Conclusion Hours = = 4,5 h CA School B is CAPS compliant O (5) 3.2.2 1MA Concept of ratio L3 Ratio = MA D = 31 Grade 10 = 31 4 = 124 1MA Total for Grade 10 and MA Grade 11 Grade 11 = 31 3 = 93 1CA Total Total books = 62 + 124 + 93 = 279 CA (3) [18] Copyright reserved Please turn over

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P2 (EC/JUNE 2019) QUESTION 4 [30 MARKS] Ques. Solution Explanation Level 4.1.1 There are emergency exit points between row 8 L4 and row 9 A 2A Reason (2) M&P 4.1.2 Seats in the economy class 1MA Seats per row L2 = 18 MA 6 MA 1MA Total rows M&P = 108 A 1A Total no of seats (3) 4.1.3 There is more space R 2R Reason L4 OR M&P Service is better R OR It is more relaxing R Any other relevant reason. (2) 4.2.1 Quarter finals = (1 412 2) + (4 249 2) RT 1RT Correct values for L4 = 2 824 + 8 498 MA both matches 2 F = $11 322 CA 1MA Adding 1CA Total 1RT Correct values for Finals = (2 186 2) + (5 538 2) MA both matches 2 = 4 372 + 11 076 1CA Total for final = $15 448 CA 1M Adding 1CA Total in dollars Total amount = 11 322 +15 448 M 1O Valid = $26 770 CA Statement is valid O (8) 4.2.2 % change = 100% RTMM 1RT Correct values L2 1M Correct F denominator = 41,35% CA 1M Multiplying by 100 OR 1CA Percentage % change = 100% RTMM = 115,29% CA (4) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2019) MATHEMATICAL LITERACY P2 9 4.2.3 Year 1 = 20 000 1,065 M 1M Increasing by 6,5% L3 = $21 300 CA 1CA Amount for F year 1 Year 2 = 21 300 1,065 1CA Amount for = $22 684,50 CA year 2 1A Interest rate for Rate for 9 months = 6,5% 9 months = 4,875% A Year 3 = 22 684,50 1,04875 1CA Final amount = $23 790,37 CA OR Final amount = 20 000 1,065 M 1,065 M 1,04875AA = $23, 79037 CA (5) 4.2.4 Men play more vigourously R 2R Reason L4 OR F Men’s matches attract more spectators R OR Performance/Skills better R Any other relevant reason (2) 4.2.5 Ticket prices increase from day 1 to the final 2O Trend L4 day O D 2R Reason for Competition gets tougher and therefore matches trend become more interesting to watch. R (4) [30] TOTAL: 100 Copyright reserved Please turn over

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