NATIONAL
SENIOR CERTIFICATE
GRADE 11
NOVEMBER 2025
MATHEMATICS P1
MARKS: 150
TIME: 3 hours
This question paper consists of 11 pages, including an information sheet.
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Mathematics Grade 11 P1 Eastern Cape November 2025 QP (Eng)
Grade 11 Mathematics Paper 1 question paper from the Eastern Cape November Exam 2025 (English), 11 pages. Read online or download the free PDF.
Mathematics · Grade 11 · Eastern Cape November Exam · 2025. Question paper, 11 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 11
- Document type
- Question paper
- Year
- 2025
- Exam period
- Eastern Cape November Exam
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 11
- File size
- 616.5 KB
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Eastern Cape November Exam 2025
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2 MATHEMATICS P1 (EC/NOVEMBER 2025)
INSTRUCTIONS AND INFORMATION
Read the following instructions carefully before answering the questions.
1. This question paper consists of NINE questions. Answer ALL the questions.
2. Clearly show ALL calculations, diagrams, graphs, et cetera that you have used in
determining your answers.
3. You may use an approved scientific calculator (non-programmable and non-
graphical), unless stated otherwise.
4. Answers only will NOT necessarily be awarded full marks.
5. If necessary, round off answers to TWO decimal places, unless stated otherwise.
6. Diagrams are NOT necessarily drawn to scale.
7. Number the answers correctly according to the numbering system used in this question
paper.
8. An information sheet with formulae is included at the end of the question paper.
9. Write neatly and legibly.
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(EC/NOVEMBER 2025) MATHEMATICS P1 3
QUESTION 1
1.1 Solve for x:
1.1.1 x ( 2 x + 6) = 0 (2)
1.1.2 4x2 = 9 − 3x (correct to TWO decimal places) (4)
1.1.3 x( x − 4) + 2(4 − x) 0 (4)
x +14
1.1.4 Given: f ( x) =
x+2
(a) For which value(s) of x will f ( x ) be real? (2)
(b) Solve for x , if f ( x ) = 1 (4)
1.2 Solve simultaneously for x and y:
x − 3y = 1
x 2 − 2 xy + 9 y 2 = 17 (6)
1.3 Determine the value of x that will satisfy the equation (without the use of a
calculator and show all your working)
10
1+ =7
1
1+
1
1+
x (5)
[27]
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4 MATHEMATICS P1 (EC/NOVEMBER 2025)
QUESTION 2
2.1 Simplify the following expression:
125x . 54 x − 2
3
512 x + 6 .5x (4)
2.2 Solve for x :
3
2.2.1 6 x = 482
(3)
1 1
2.2.2 x − 3x + 2 = 0
2 4
(4)
2.3 Given: The area of a rectangle is (16 x − 100 ) cm2 and the breadth is ( 4 x + 10 ) cm .
Determine the length of the rectangle in terms of x. (4)
2.4 The difference between the squares of two consecutive integers is 45. Determine the
value of the square of the sum of these two consecutive integers.
Hint: Let the smaller integer be x. (4)
[19]
QUESTION 3
3.1 Consider the following linear number pattern: 5,5 ; 5,0 ; 4,5 ; . . .
3.1.1 Write down the next TWO terms in the number pattern. (2)
3.1.2 Calculate the general term of the number pattern, in the form
Tn = bn + c (2)
3.1.3 Which term in the number pattern is the first to be less than −113,5 ? (2)
3.2 The constant difference of a linear number pattern is 5 and the 38th term is 192.
Determine the value of the first term. (3)
[9]
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(EC/NOVEMBER 2025) MATHEMATICS P1 5
QUESTION 4
4.1 Given the nth term of the quadratic number pattern: Tn = n 2 − 12n + k
4.1.1 If T62 = 3132 , determine the value of k . (2)
4.1.2 Determine the first THREE terms of the first difference number pattern. (2)
4.1.3 Calculate the value of n for which the quadratic number pattern will have a
minimum. (2)
4.1.4 Determine Tn −1 , in terms of n. (2)
4.1.5 Between which two consecutive terms of the quadratic number pattern, will
the difference be 149? (3)
4.2 In a quadratic number pattern, the second term is 4, the third term is three times the
first term and the fourth term is 18.
Determine the value of T3 (3)
[14]
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6 MATHEMATICS P1 (EC/NOVEMBER 2025)
QUESTION 5
a x
The graphs of f ( x ) = + q and g ( x ) = + c are drawn below. C ( 3; − 1) is the point of
x+ p 3
intersection between the asymptotes of f. A and B are x- and y-intercepts of f and g
respectively. E(4 ; 2) is a point on f in the first quadrant.
5.1 Write down the value of p. (1)
5.2 Determine the equation of f. (3)
5.3 Determine the coordinates of A and B. (3)
5.4 Write down the domain of h , if h ( x ) = f − ( x − 4 ) (3)
5.5 Determine the value of x , for which f ( x ) .g ( x ) 0 (2)
5.6 Calculate the area of ABE if the length AB = 2 10 units. (5)
[17]
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(EC/NOVEMBER 2025) MATHEMATICS P1 7
QUESTION 6
The graphs of f ( x ) = − x2 − 6 x and g ( x ) = ax2 + bx are drawn below. g is the reflection of
f along the x-axis. A and B ( −5;n ) are symmetrical on f along x = − p , i.e. the axes of
symmetry.
Write down the equation of f in the turning point form, i.e. y = a ( x + p ) + q
2
6.1 (3)
6.2 Determine the coordinates of A. (3)
6.3 Determine the length of OE if CD = 14 units. (5)
6.4 Determine the value(s) of k for which:
6.4.1 f ( x ) = − x 2 − 6 x + k will have non-real roots. (2)
6.4.2 f ( x + k ) will have two real roots that have different signs. (3)
[16]
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8 MATHEMATICS P1 (EC/NOVEMBER 2025)
QUESTION 7
x +1
1
7.1 Given: f ( x ) = −3
3
7.1.1 Write down the equation of the asymptote of f (1)
7.1.2 Calculate the coordinates of the intercepts of f (3)
7.1.3 Sketch the graph of f. Indicate the horizontal asymptote as well as the
intercepts with the axes. (3)
7.1.4 Determine the value of x for which f ( x ) 0 (2)
7.2 An exponential function with equation h ( x ) = a . k x + r has the following properties:
• The range is y ( −2; )
• The points ( 0;0 ) and ( 2;6 ) lie on the graph
Determine the equation of h, in the form y = . . . (4)
[13]
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(EC/NOVEMBER 2025) MATHEMATICS P1 9
QUESTION 8
8.1 A motorbike costs R250 000 and depreciates by 13% p.a. annually, calculated on the
reducing balance method.
Calculate what the motorbike will be worth after 6 years. (3)
8.2 Convert an annual effective rate of 7,5% per annum to a nominal rate per annum
compounded quarterly. (3)
8.3 Rodney starts an investment with a deposit of R25 000. Two years later, he deposits
another R10 000. Exactly four years after he started the investment, he withdraws R5 000.
For the first two years, the interest is calculated at 4% per annum, compounded monthly
and thereafter it is calculated at 7% per annum, compounded semi-annually.
What is the accumulated amount of the investment exactly five years after the initial
deposit? (5)
8.4 Brian borrows R x at an annual interest rate of 12% p.a. He has two options to repay the
loan.
OPTION 1: Pay R5 000, 2 years after the loan was granted and the remaining amount, 4
years after the loan was granted. The interest is compounded annually.
OPTION 2: Pay R3 000, 1 year after the loan was granted and the remaining amount, 3
years after the loan was granted. The interest is compounded semi-
annually.
If the total amount paid in both options is the same, calculate the value of x. (6)
[17]
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10 MATHEMATICS P1 (EC/NOVEMBER 2025)
QUESTION 9
9.1 A and B are independent events. It is further given that:
• P(A) = 0,3
• P(B) = 0,6
9.1.1 Are the events, A and B mutually exclusive? Motivate your answer. (2)
9.1.2 Represent the information on a Venn diagram. (3)
9.1.3 Calculate P (not A and not B). (2)
9.2 The contingency table below represents 106 athletes’ responses regarding jogging on the
sand.
Male Female Total
Enjoy jogging on sand 26 30 56
Do not enjoy jogging on sand 16 34 50
Total 42 64 106
9.2.1 If an athlete from this group is chosen randomly, what is the probability that it is
a male? (1)
9.2.2 Is the event “enjoy jogging on sand” independent of the gender? (4)
9.3 During the summer season in South Africa, the probability of sunny weather on any
given day is 0,7. If it is sunny, the probability that a person uses sunscreen is x . If it is
not sunny, the probability of using sunscreen is 0,2x.
9.3.1 Draw a tree diagram, clearly labelling the branches and indicating the outcomes. (3)
9.3.2 If it is given that the overall probability of using sunscreen on a randomly
selected day is 0,62 , determine the value of x. (3)
[18]
TOTAL: 150
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(EC/NOVEMBER 2025) MATHEMATICS P1 11
INFORMATION SHEET: MATHEMATICS
−b b 2 − 4ac
x=
2a
A = P(1 + ni) A = P(1 − ni) A = P(1 − i) n A = P(1 + i) n
n
Tn = a + (n − 1)d Sn = (2a + (n − 1)d )
2
Tn = ar n −1 Sn =
( ) ; r 1
a r n −1 S =
a
; −1 r 1
r −1 1− r
F=
x (1 + i ) − 1
n
x 1 − (1 + i)−n
P=
i i
f ( x + h) − f ( x )
f ' ( x) = lim
h→ 0 h
x + x2 y1 + y 2
d = ( x2 − x1 )2 + ( y2 − y1 )2 M 1 ;
2 2
y 2 − y1
y = mx + c y − y1 = m( x − x1 ) m= m = tan
x 2 − x1
( x − a) + ( y − b) = r2
2 2
a b c
In ABC: = =
sin A sin B sin C
a2 = b2 + c2 − 2bc.cos A
1
area ABC = ab.sin C
2
sin ( + ) = sin . cos + cos .sin sin ( − ) = sin . cos − cos .sin
cos( + ) = cos . cos − sin . sin cos( − ) = cos . cos + sin . sin
cos 2 − sin 2
cos 2 = 1 − 2 sin 2 sin 2 = 2 sin . cos
2 cos 2 − 1
n
( x − x )
2
x=
x 2 = i =1
i
n n
n( A)
P ( A) = P(A or B) = P(A) + P(B) – P(A and B)
n (S )
yˆ = a + bx b=
(x − x )( y − y )
(x − x) 2
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