Mathematics Grade 11 KwaZulu Natal June 2022 Paper & Memo

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com s.co m si c st an mor ep hy om fr oa de d do wn l

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com s.co m si c st an mor ep hy om fr oa de d do wn l

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com

Downloaded Downloaded f rom St anmorephysics. com from hlayiso.com

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com

Downloaded from hlayiso.com Downloaded f rom St anmorephysics. com NATIONAL SENIOR CERTIFICATE GRADE 11 MATHEMATICAL LITERACY COMMON TEST JUNE 2022 MARKING GUIDELINE MARKS: 100 SYMBOL EXPLANATION M Method MA Method with accuracy CA Consistent accuracy A Accuracy (Answer) C Conversion S Simplification RT/RG/RD Reading from a table/ graph/ diagram NPR No penalty for units/rounding SF Correct substitution in a formula O Opinion/ reason/deduction/example J Justification R Rounding off F deriving a formula E Explanation U Units AO Answer only full marks This marking guideline consists of 5 pages. Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy 2 Common Test June 2022 Downloaded f rom St NSC – anmorephysics. Marking Guideline com QUESTION 1 [20 MARKS] QUE SOLUTION EXPLANATION L/T 1.1.1 Rands = 103,42 M 1M, Conversion dividing by 100 L1 100 1CA,Answer F = R1,0342CA Accept R1,03 NPR (2) 1.1.2 L1 Cost = R1,0342 ×348,2kwh M 1M, Multiplying by Rate F = R360,108 =R360,11 CA 1CA, Answer in rands OR Accept R358,65 Cost = 103,42 ×348,2kwh M OR =36 010.844 cents CA 1M, Multiplying by rate 1CA, Answer in cents (2) 1.1.3 M L1 Block 1 tariff = 87,5 ×103,42 1M, Multiplying rate by percentage F 100 =90,4925 centsA 1A, Answer NPR (2) 2A, Answer L1 1.2.1 Number scaleA (2) MP 1.2.2 One unit on the map represents twenty thousand units in 2E, Explanation L1 reality/actual groundE MP OR The map is 20 000 times smaller than the actual ground. E (2) 1.2.3 Meters = 20 000cm 1MA, Dividing by 100 L1 100 MA MP = 200 A 1A, Answer (2) 1.3.1 10 km RT 2RT, Answer L1 (2) M&P 1.3.2 25 km RT 2RT, Answer L1 (2) M&P 1.3.3 Saddle Path RT 2RT, Answer L1 (2) M&P 1.3.4 Woodcutters Trail RT 1RT, Answer L1 Block House RT 1RT, Answer M&P (2) [20] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Mathematical Literacy 3 Common Test June 2022 Downloaded f rom St NSC – anmorephysics. Marking Guideline com QUESTION 2[30 MARKS] QUE SOLUTION EXPLANATION L/T 2.1.1 05 March 1998 A 2A, Answer L1 Accept 980305 OR 05/03/1998 (2) F 2.1.2 Service Period = 14 months L2 12 M 1M, Dividing by 12 M = 1,166666666 1year 2months A 1A, Correct years and months (2) 2.1.3 1M, Multiplying R7200 by 1% L2 A= × R7200M F 1A, Answer = R72 A (2) 2.1.4 CA from 2.1.3 L2 B = R22 +R250 +R72 +R680M 1M, Adding correct values F = R1024 CA 1CA, Answer M C =R7200 – R1024 1M,Subracting Correct values =R6176 CA 1CA, Answer (4) 2.1.5(a) L3 UIF benefit = R86400 × 60% A SF 1A, Annual gross F 365 1SF, Correct substitution =R142,03 CA 1CA, Answer His statement is incorrect J 1J,Justification (4) 2.1.5(b) A L4 Agree, All UIF claims that are within 5years are 1A, Answer F payable irrespective of nature of departure. R 2R, Reason (3) 2.2.1 Duration = M 1M, Dividing by 60 L2 1A, Answer M = 1 hourA (2) 2.2.2 R120RT 2RT, Answer L1 (2) F 2.2.3 Daily cost(0-5days) = R688 M 1M,Dividing by 5 days L3 5 days F =R137,60A 1A, Daily rate of R137,60 Difference = R137,60-R54M =R83,60 1M, Difference Her statement is correctJ 1J, Justification (4) 2.2.4 Step graphA 2A, Answer L1 (2) F 2.2.5 L2 A 1A, Numerator P(above R90) = P A 1A, Denominator = CA 1CA, Simplification OR OR P (above R90) = 1 - MA 1M, Probability concept 1A, Correct fraction 1CA, Simplification = CA (3) [30] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Mathematical Literacy 4 Common Test June 2022 Downloaded f rom St NSC – anmorephysics. Marking Guideline com QUESTION 3 [30 MARKS] QUE SOLUTION EXPLANATION L/T 3.1.1 Total Distance = 60 + 33 + 27 MA 1MA, Adding all correct distances L2 = 120km A 1A,Answer (2) M&P 3.1.2 L3 Average speed = SF 1SF, Correct substitution M 1C, Conversion to hours = C = 60km/h A U 1A, Answer 1U, Units (4) 3.1.3 Distance = 460 – 280 OR 684 – 504 L3 = 180km M M 1M, Measuring distance Scale = 2.5cm : 180km M 1M, Concept of scale = 2.5 : 18 000 000 C 1C, Conversion = 1: 7 200 000 CA 1CA, Answer (4) 3.1.4 CA from 3.1.3 L4 Measured distance = 5cm M 1M, Measured distance M Scale = 1 : 7 200 000 Actual distance = 5 x 7 200 000 CA 1CA, Using scale = 36 000 000 = 360km  CA 1CA, Distance The distance given is incorrect O 1O, Deduction (4) 3.1.5  High traffic volumes O L4 OR 2O, Opinion M&P  Poor road condition OR (2)  Delays caused by traffic officials OR  Road accidents OR Any other valid reason 3.2.1 South East RT 2RT,Answer L1 (2) MP 3.2.2(a) L2 Ratio = : MA 1MA, Dividing by 55 both sides M = 1 mile :1,61kmA 1A, Correct answer (2) 3.2.2(b) Duration = 17:30 -05:30 M 1M, Subtracting times L2 = 12hoursA 1A, Answer M AO (2) 3.2.3 Because the starting point of the marathon is at the L4 highest point above sea levelO MP OR 2O, Reason The finishing point is at the lowest height above sea levelO (2) 3.2.4 Male athletes = × 11 000M 1M, Percentage concept L2 1A, Correct answer MP AO (2) = 6050A Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Mathematical Literacy 5 Common Test June 2022 Downloaded f rom St NSC – anmorephysics. Marking Guideline com QUE SOLUTION EXPLANATION L/T 3.2.5 In order to disqualify incompetent athletesO L4 OR MP In order to manage broadcasting times for other programmes. O 2R, Reason OR Athletes won’t run for the rest of the day. O OR (2) Any other valid reason 3.2.6 1RT, Correct distance difference L3 Distance = 74km – 45kmRT 1CA, Answer MP = 29kmCA Accept 26km to 32km (2) [30] QUESTION 4 [20 MARKS] QUE SOLUTION EXPLANATION L/T 4.1.1 Compound bar graphA 1A, Correct graph L1 Heading A 1A, Answer DH (2) 4.1.2 No of hats = 54 – 10MA 1MA, Correct values subtracted L3 = 44 hatsA 1A,Answer DH (2) 4.1.3 Shoes = 29+20+14+10+4+12 M 1M, Adding values L2 =89CA 1CA, Number of shoes DH (2) 4.2.1 Survey A 2A, Answer L1 (2) DH 4.2.2 Mean = M L2 350+999+450+280+350+720+192+800+450+220+280 1M,Adding values DH 11 =5091 1MA,Dividing by 11 11MA =R462,82CA 1CA, Answer. (3) 4.2.3 R39,R39.20,R49.90;R52;R52;R55,R69,90;R89,90;R92; L4 R99;R409 M 1M, Arranging prices DH VAT (median) = 15% ×R55CAMA 1CA,Correct median =R8,25 1MA, Calculating vat by15% Incorrect statement. J 1J, Justification (4) 4.2.4 Range = R999- R192MA 1MA, Range concept L2 =R807 A 1A,Answer DH AO (2) 4.2.5 A E 1A,Answer L4 Mode, mode is not affected by outliers/ the modal price 2E,Explanation DH will indicate the most favourable item by customers. (3) [20] TOTAL MARKS: 100 Copyright Reserved Please Turn Over