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PROVINCIAL ASSESSMENT
GRADE 10
MATHEMATICAL LITERACY P2
NOVEMBER 2019
MARKING GUIDELINES
MARKS: 75
Codes Explanation
M Method
MA Method with Accuracy
CA Consistent Accuracy
A Accuracy
C Conversion
D Define
J Justification/Reason/Explain
S Simplification
RT Reading from a table OR a graph OR a diagram OR a map OR a plan
F Choosing the correct formula
SF Substitution in a formula
O Opinion
P Penalty, e.g. for no units, incorrect rounding off, etc.
R Rounding Off
AO Answer only
NPR No penalty for rounding off OR omitting units
These marking guidelines consist of 6 pages.
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Mathematical Literacy Grade 10 P2 2019 Memo (Eng)
Grade 10 Mathematical Literacy Paper 2 memorandum from the North West November 2019 (English), 7 pages. Read online or download the free PDF.
Mathematical Literacy · Grade 10 · North West November · 2019. Memorandum, 7 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 10
- Document type
- Memorandum
- Year
- 2019
- Exam period
- North West November
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 7
- File size
- 540.5 KB
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North West November 2019
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Mathematical Literacy/P2 2 NW/November 2019
NSC– Grade 10 – Marking Guidelines
KEY TO TOPIC SYMBOL:
F = Finance; M = Measurement; MP = Maps, Plans and other
Representations DH = Data Handling; P = Probability
QUESTION 1 [12 MARKS]
Q Solution Explanation Topic
&
Level
1.1.1 Purchases for the month M 2M Adding purchases F
= 476,00 + 135,50 + 99,50 + 77,50 + 129,50 + 57,00 1A Total purchases L2
= R975,00 A (3)
1.1.2 1M Divide by 12 F
Interest per month = 0,31 M
12 L3
= 0,025833333 A 1A Monthly interest
Interest on outstanding amount
= 0,025833333× 1215,80 M 1M Multiply by
= R31,40816667 1215,80
≈ R31,41 CA 1CA Interest amount
OR
31 1M Multiply by
Interest payable = 100 × 1215,80 M 1215,80
376 M 1A Annual interest
= 1M Divide by 12
12 M
≈ R31,41 M 1CA Interest amount
(4)
1.1.3 327,34 MA
1MA Numerator and F
Percentage = 1636,71 × 100% M denominator L2
1M Multiply by 100
= 19,9998778 % 1CA Percentage (3)
= 20 % CA
1.2 It cannot be said with certainty, because the days of the P
week are not given in the graph.O 2O Opinion (2) L4
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Mathematical Literacy/P2 3 NW/November 2019
NSC– Grade 10 – Marking Guidelines
QUESTION 2 [23 MARKS]
Q Solution Explanation Level
2.1.1 MP
24 1RT Total nr
Number of screws =
6 1M divide by nr of chair
= 4 A
1A answer (3) L2
RT RT MP
2.1.2 Chair seat and stretcher 1 RT chair
seat
2A stretcher (3) L2
AAAA
M
2.1.3 1A multiply by 42
Area = 41 × 42 cm
1A answer
= 1772 cm2
1A unit L3
(3)
2.2 M
(a) 94 + 2 × 1 2D explanation
= 96 cm
(b) 42 + 2 × 1 1A multiply by 10
= 44 cm 1A answer
(4) L3
Dimension = 96 × 44 = 4224
2.3 The screw got a hole in the back where you fit the 2A explanation M
Allen key to fasten or loosen the screw. (2) L2
2.4.1 Material needed = 6 × 1,1 1A multiply by 1.1m M
= 6,6 m 1 A answer
(2) L2
2.4.2 1A Multiplication F
Cost of material needed = 6,6 × R64,50 1A answer
= R450,70
(2)
L2
2.4.3 Labour = 6 × R75 1M × R75 F
= R450,00 1A answer
Total cost = (R450,00) + R425,70 1Madding
= R875,70 1A answer (4) L3
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Mathematical Literacy/P2 4 NW/November 2019
NSC– Grade 10 – Marking Guidelines
QUESTION 3 [23 MARKS]
Q Solution Explanation Topic
&
Level
3.1 Guests to invite = 112 – 2 M 1RD Number of seats MP
= 110 guests CA 1M Subtract 2 L3
OR 1CA Number of
13 x 8 = 104 + 6 guests (3)
= 110
3.2 For easy movement. A 2O Reason MP
OR L4
Uncomfortable to sit on the short side. A
Accept any other logical reason. (2)
3.3 A 1A Pass dance floor MP
Walk pass the dance floor, pass the podium and turn 1A Direction L4
left. A
OR
Accept any other logical explanation. (2)
3.4 Probability of guest sitting at table with even number P
L4
= 1 M
7 1CA Answer to 3
= 0,142857142 decimal places (2)
= 0,143 CA Answer must not be
greater than 1
3.5 Floor Area of hall = length × width M
= 16 m × 12 m SF 1SF Substitution L4
= 192 m2 1CA Floor Area
Area of Dance floor = 1 × 192 m2 1M × by 1÷4
4 1CA Area of dance
= 48 m2 floor
(4)
3.6 Hiring of the venue: CA from 3.1.1 F
R6 500,00 1M R6500 L4
Draping and décor: R7 750,00 1M R7750
Cost for DJ = R350 × 7 hours 1CA Cost for DJ
= R2 450 CA 1MA 350 × 100 and
Catering = (R350 × 100 guests) + (R200 × 12) MA 200 × 13
= R35 000 + R2 400 1CA
= R37 400 CA
Total cost
= R6 500,00 + R7750 + R2450 + R37 400 M 1M Adding all values
= R54 100 CA 1CA Total cost
Statement invalid MA 1O Invalid
(10)
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Mathematical Literacy/P2 5 NW/November 2019
NSC– Grade 10 – Marking Guidelines
QUESTION 4 [18 MARKS]
Q Solution Explanation Level
4.1.1 25; 29; 30; 30; 32; 35; 35; 38; 56; 56; 58; 58; 58; 67; 67; 70; 1A correct central values
74; 76; 84; 85 M 1M dividing
56 58 1CA conclusion
Median = M
2
= 57% A L3
(3)
4.1.2 Range = 85% – 25% M 1M subtracting min and
= 60% CA max values
1CA solution
(2) L2
4.1.3 Mode = 58% A
2A Correct mode (2) L3
4.2.1 P = 0 RT 1A Read
from table
Q = 6 RT 2A Read L2
from table
(2)
4.2.2 M M 1M writing probability
1M multiplying by
7 × 100 100
P=
1CA answer
20 L2
(3)
= 35%CA
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Mathematical Literacy/P2 6 NW/November 2019
NSC– Grade 10 – Marking Guidelines
Q Solution Explanation Level
4.2.3 NUMBER OF LEARNERS PER LEVEL
7
7
6
6
CA
5
5 1CA correct
FREQUENCY
4 plotting of
4 A L2
3
23 1CA correct
plotting of
12 L3
CA
01 1A correct
Level 1 Level 2 Level 3 Level 4 Level 5 Level 6 Level 7
plotting of
0
L6
LEVEL
LEVEL
(3) L3
A
4.2.4 Share = 3 of R500 1A using
5 ratio
= R300 A 1A
simplifying
R300
Each learner’s share =
2
1CA answer
= R150 A
(3) L4
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Mathematical Literacy/P2 7 NW/November 2019
NSC– Grade 10 – Marking Guidelines
PROVINCIAL ASSESSMENT MATHEMATICAL LITERACY P2
GRADE 10 PAPER 2
QUESTION NO. MEASUREMENT DATA HANDLING PROBABILITY
FINANCE MAPS/PLANS
LEVEL 2 LEVEL 3 LEVEL 4
1.1.1 3 3
1.1.2 4 4
1.1.3 3 3
1.2.1 2 2
TOTAL 6 4 2 10 0 0 2
2.1.1 3 3
2.1.2 3 3
2.1.3 3 3
2.2 4 4
2.3 2 2
2.4.1 2 2
2.4.2 2 2
2.4.3 4 4
TOTAL 15 8 6 12 5 0 0
3.1 3 3
3.2 2 2
3.3 2 2
3.4 2 2
3.5 4 4
3.6 10 10
TOTAL 9 14 10 4 7 0 2
4.1.1 3 3
4.1.2 2 2
4.1.3 2 2
4.2.1 2 2
4.2.2 3 3
4.2.3 3 3
4.2.4 3 3
TOTAL 10 5 3 26 15 12 18 4
GRAND 31 26 19 26 15 12 18 4
TOTAL
TOTAL 75
% 41 35 25 40% 31% 11% 15% 4%
FINANCE MEASUREMEN MAPS/PLANS DATA 25% ± PROBABILIT
35% ± 5% T 20% ± 5% 15% ± 5% 5% Y MIN 5%
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