Mathematics Grade 11 P1 North West November 2025 QP & Memo

[oor POW IMOAMED TLONT STATMMOL EPI STCS. COM ns i i | education | ' ‘ i Department: i i Education i i North West Provincial Government ‘ i REPUBLIC OF SOUTH AFRICA i i ‘ 4 i i 4 i ‘ MATHEMATICS P1 i i 4 " TY] 4 i ¥ NOVEMBER 2025 z i i 1 rr i 4 w 7] 4 i Pee eee eee Pee eee eee eee Pee OPPO eee eee ha ‘ | MARKS: 150 i | TIME: 3 hours | ‘ 4 4 i This question paper consists of 9 pages and 1 information sheet. ‘ i Copyright reserved Please turn over i Beane Treen cavers CrP UEr ER ruOREG Orava RE TRUER RH RFORP SDN > PEP PIN PS R RRDNRPIOSE

Mathematics/P1 Downloaded from Stanmorephysics.com 2 NW/November 2025 Grade 11 INSTRUCTIONS AND INFORMATION Read the following instructions carefully before answering the questions. 1 2; 10. This question paper consists of NINE questions. Answer ALL the qu sstions. Number the answers correctly according to the numbering system used in this question paper. Clearly show ALL caleulations, diagrams, graphs, etc. that you have used in determining your answers. Answers only will NOT necessarily be awarded full marks. You may use an approved scientific calculator (non-programmable and non-graphical), unless stated otherwise. If necessary, round off answers to TWO decimal places, unless stated otherwise. Diagrams are NOT necessarily drawn to scale. An information sheet with formulae is included at the end of the question paper. Write neatly and legibly. Copyright reserved Please turn over

Downloaded from Stanmorephysics.com 3 Mathematics/P1 NW/November 2025 Grade 11 QUESTION 1 1.1 Solve for x: Ld x? -11y=-24 GB) 1.1.2 5x2—x—80 (correct to TWO decimal places) (3) 1:13 42 >x? Hx (4) 4. 10 1 1.1.4 5 = a x -6 x42 (6) 1.2 Solve for x and y simultaneously: 2x-y-1=0 and x?—2xy+2x-y’? =0 (6) 1.3 Given: kx +5x+k=0. For which integer values of k will the roots of the equation be rational? (4) 1.4 Calculate the value of x, without using a calculator. x= 30+ 30+ 30+ ¥30+ 30+... (5) [31] QUESTION 2 2.1 Simplify fully, without using a calculator: 273 3.9" 2 x-2 (3) 2.2 Solve for x, without the use of a calculator: 3 221 5 =-8 (2) 2.2.2 4°-9.2* =-8 (6) y+ 2.3 If it is given that: = 1796" , calculate the values of xand y. (5) [16] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com 4 Mathematics/P1 NW/November 2025 Grade 11 QUESTION 3 Given the finite linear pattern: 1; 3; 53; .... 3 119 Sol Determine T, , the formula for the n term of the pattern. (2) 3.2 Determine the 20" t ; of the pattern. (2) 33 Determine the a3 f terms in the pattern. (2) 3.4 Hence, determine the number of terms in the following pattern: (0/110 -3:10:5:10:...:10: 119: 00 (2) 3.5 The linear pattern: 1; 3; 5; .... forms the row of first differences of a quadratic number pattern. Q,,, term 99 of the quadratic pattern, is 9632. Determine the value of Q,,, term 98 of the quadratic number pattern. QUESTION 4 Consider the quadratic sequence: —7; —22; —35; —46; ... 4.1 Write down the fifth term of the sequence. 4.2 Determine T, , the n" term of the quadratic sequence. 4.3 Which term of the sequence has a value of 29? 4.4 Determine which two consecutive terms of the quadratic sequence differ with 29. (3) [11] () (4) (4) (3) [12] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com 5 Mathematics/P1 NW/November 2025 Grade 11 QUESTION 5 . 4 Given: f(x) =——~ +1 x+2 5.1 ns of the asymptotes of /. 52 ercept of f. 5.3 itercept of /. 5.4 f . Clearly label ALL the intercepts with the (3) 5.5. Write down the domain of /. (2) 5.6 Determine the equation of the axis of symmetry of f in the form y=mx+c, for m<0. (3) [13] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com 6 Mathematics/P1 NW/November 2025 Grade 11 QUESTION 6 Sketched below is the graph of g(x) = a.b* + q. The graph of g cuts the x —and y —axis at (1;0) and (0;—4) respectively. The line y =—8 is the asymptote of g. 6.1 Write down the value of q¢. (1) 6.2 Determine the values of a and b. (4) 6.3 Write down the range of g. (2) 6.4 Determine the equation of k, if k obtained when g is reflected about the x —axis and then shifted 2 units to the right. Write your answer in the form of k(x) =b* + p. (4) [11] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com 7 Mathematics/P1 NW/November 2025 Grade 11 QUESTION 7 Sketched below are the graphs of g(x) =—-x-5 and f(x)=x° +6x+5. e Dis the turning point of /. e E and F are the y=intercepts of f and g respectively. e Aand C are x —intereepts of f. e Aisalso the x — intercept of g. 71 Calculate the co-ordinates of D, the turning point of /. (3) 7.2 Calculate the length of: 7.2.1 EF (2) 7.2.2 AC (3) 73 The graphs intersect at A and B. 7.3.1. Determine the co-ordinates of B. (4) 7.3.2 Hence, determine the values of ¢ for which the equation (x+t)? +6(x+t)+5=-(x+1t)-5 has ONE positive and ONE negative root. (2) 74 It is further given that MN is parallel to the y —axis between A and B, with M a point on the graph of g and N a point on the graph of /. 7.4.1. Write down the length of MN in terms of x. (2) 7.4.2 Determine the maximum length of MN. (2) 7.4.3 Hence, or otherwise, find the values of k , for which f(x) +k = g(x) will have non-real roots. (2) 1:5 Use the graph to determine for what value(s) of x, will f(x).g(x) <0 (2) [22] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com 8 Mathematics/P1 NW/November 2025 Grade 11 QUESTION 8 8.1 Lethabo has TWO investment option offers: ¢ Option A: 8,2% p.a. compounded daily (365 days per year) ¢ Option B: 8,3% p.a. compounded monthly 8.1.1 Calculate the effective interest rate of Option A. (2) 8.1.2 Which investment option is better for Lethabo to take? Justify your answer with the necessary calculations. (2) 8.2 Sam wins R300000 in a lottery and decides to invest the full amount in to buy a car for each of his two sons when they turn 21. e His first son, Peter, turns 21 exactly 2 years after the investment was made. On Peter’s 21" birthday, Sam withdraws R175 000 to buy Peter a car. ¢ The investment earns 9% p.a, compounded quarterly for the first four years. « After that, the interest rate changes to 8.5% p.a, compounded monthly. ¢ The second son turns 21 six years from Sam’s initial investment. 8.2.1. How much money will Sam have available at the end of six years, when his second son turns 21? (5) 8.2.2 The average inflation rate over this period is 8% p.a. Would Sam be fair and consistent towards his two sons if the same amount calculated in QUESTION 8.2.1 is used for his second son's car? Justify your answer with the necessary calculations. (4) 8.2.3. Peter sells his car after 4 years for R79 120. What is the annual rate of depreciation, if calculated using the reducing balance method? (4) [17] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Mathematics/P1 9 Grade 11 QUESTION 9 9.1 Baobab High School has 100 Grade 12 learners. Of these, 35 take Mathematics, 30 take Accounting, and 20 take both subjects. 9.1.1. Are the events "taking Mathematics” (M) and "taking Accounting” (A) mutually exelusive events? Motivate your answer. 9.1.2 Are the events "taking Mathematics” (M) and "taking Accounting” (A) independent? Justify your answer with the appropriate calculations. 9.1.3. Draw a Venn-diagram representing the above information. 9.1.4. Use the Venn-diagram to determine P((not M) or A). 9.2 A bag contains a total of 25 balls, which are red or blue. The exact number of each colour is unknown. However, it is known that the probability of drawing a red ball, setting it aside, and then drawing another red ball is = Determine how many red and how many blue balls are in the bag. (Hint: Let the number of red balls be x.) TOTAL: Copyright reserved NW/November 2024 (2) (4) (3) (2) (6) [17] 150

Downloaded from Stanmorephysics.com Mathematics/P1 NW/November 2025 Grade 11 INFORMATION SHEET: MATHEMATICS GR11 ee be? -4ac 2a A=P(l+ni) A= P(l-i)" M % +X Ni +Y2 2° 2 y=mx+ YY, =mM(x-x,) inddne: 2. 222” a? =b? sinA sinB_ sinC +c? —2be.cos A area ABC = sab. sinC = tit n P(A)= ra) P(A or B) = P(A) + P(B) — P(A and B) Copyright reserved

MARKS/PUNTE: 15 PCC UReCeP OOOO OCOCOCOUCOCOUOCO CCC e CPE Pee eee eee ee ee e See eee eee EERE ORO O ROR U POOR ORE EEO E RRO R ECR EEE prwwmmmnmmmnwwwwwnn nn PYLON OAIE FLOM STAMMNOTEPNYSTCS. CONT 0 education Department: Education North West Provincial Government REPUBLIC OF SOUTH AFRICA PROVINCIAL ASSESSMENT/ PROVINSIALE ASSESSERING [ GRADE 11/GRAAD 11 | , a \ ie he * a MATHEMATICS P1/WISKUNDE V1 " “ NOVEMBER 2025 : " MARKING GUIDELINES/NASIENRIGLYNE " ll 1" . “« 0 These marking guidelines consist of 12 pages. Hierdie nasienriglyne bestaan uit 12 bladsye.

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 2 Grade/Graad 11 — Marking Guidelines /Nasienriglyne NW/November 2025 NOTE: e Ifacandidate answered a question TWICE, only mark the FIRST attempt. ¢ Consistent accuracy applies in ALL aspects of the marking guideline. LET WEL: 5 e Indien ’n kandidaat *n e Volgehoue akkuraathei toegepassing. g TWEE keer beantwoord het, sien slegs die EERSTE poging na. DEURGAANS op ALLE aspekte van die nasienriglyne van QUESTION/ VRAAG 1 1.1.1 x? — 11x =-24 Y standard form/stdvorm x? =1ix+ 24=0 * (x —8)(«— 3) =0 Answer only: 3/3 ¥ factors/faktore ¥ both answers/beide antwe x =8 or |ofx=3 (3) 1.1.2 5x*-x-8=0 aye Pen. rounding (only | mark) 7 sabstitation ~(-1)+y (-1)?-4(5)(-8) Answer only: 3/3 25) VY each answ/elke antw (3) «x= 1,37 or| of x= -1,17 T,b3 42>x7 +x x? 4+x%+42<0 (x+7)(x-6) <0 Y standard form/vorm Y critical values 7 6 kritiese waardes vv answer/antw -7<x<6 OR/OF 42>x? +x -x?-x+42>0 (x+7)(6-—x) <0 —7<x<6 Y standard form/vorm Y critical values kritiese waardes vv answer/antw (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 3 Grade/Graad 11 — Marking Guidelines /Nasienriglyne NW/November 2025 Integer values for which A is perfect square: Heelgetalle waarvoor A ‘n volkome vierkant is: k =0; +2 OR/OF Answer only: 0/4 1.1.4 4 10 1 x -4 x? -x-6 x+2 4 0 (x=2)(x+2) (x-3)(x+2) (x +2) vv factors/faktore A(x —3) —10(x=2) = (x-3)(x-2) v¥ x LCM/KGV 4x-12-1042¢ 20 x? —5x4+6 (eliminating denominator) x? 4x-250/ ¥ standard form (x +2)(x= )) =0 | Y factors/faktore x=—2) gt or/of x=1 F answerlante (6) 1.2 25 — PT — Oereeeerscey x? -2xyt+2x-y? Y y subject/onderwerp (3 pH 2s equation) sub. equ. (3) into equ. (2) Y substitution x? —2x(2x—1)+2x—(2x-1)? =0 = Ax + xt Da Ax" + Ax gala Y standard form/std vorm -7x? +8x-1=0 Tx* -8x+1=0 (1x-1)(x-1) =0 Y factors/faktore x= L or/of x=1 7 Y both x-values/beide x-w 1 5 = {>) =L= a a Aa 2()-1=1 Y both y-values/beide y-w 6 2™ mistake: BD ©) Last mark independent of # mistakes Leading to linear: Max. 2/6 13 ke +5x+k=0 A=b’ —4ac Y substitution (5)? — 4(k)(k) = (5)? —4(k)(k (5) ( Mk) 425-442 =25-4k? v A Perfect square “k=0; £2 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 4 Grade/Graad 11 — Marking Guidelines /Nasienriglyne NW/November 2025 kx? +5x+k=0 A2=0 and Ais perfectsquare Vv (5) —4(k\(k) > 0 b4acie0 V (5—2k)(5 + 2k) >0 (5)’ —4(k)(k) > 0 25-4k? >0 pF tA eee. KER (5 —2k)(5 +2k)s 23 es! “k='0; £2 ~<ncdle 2 4ai7 (4) k=0;442 | 1k 20; Bim 14 : iin Y square both sides/kwadreer Y substitution of ‘’ x”’ x= is0+ {30+ 30+ V¥30+ ¥30+... ¥ standard form/stdvorm a =30+ 1304304, 30+ 304+ 30+... factors x? =304+x V¥x=6 x#-5 x’? -x-30=0 (5) (x -6)(x +5) =0 Answer only: 0/5 x=6; x#-5 [31] QUESTION/VRAAG 2 2d Y Factorize/faktoriseer 2P33.2") _ 2421=3.28271 _ 2427 =3.24j ¥simpl & + exp/vereenv & 2° a a e207? +eksp 3-3 i v 26 (3) we AG 1 2 4 3 221 | 2 __g s Answer only: 2/2 Y power/mag 5 3 3 v -32 (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 5 NW/November 2025 Grade/Graad 11 — Marking Guidelines /Nasienriglyne 222 4° 9.2" =-8 v 4*=2 2?* 9.2" 4+8=0 Y standard form/std vorm (2* -8)(2* -1)=0 Y factors/faktore 2° =8=2' orfof 2*=1=2° Y both equation/beide vgl x=3 or/of $= ven eel (6) PB} 37 ~ aa D5 * Y prime bases/priem od A grondtalle (2)3.3)"" = (2)7.8)s" Y exponential laws/ekspwette 5= 5 ne Y equating exponents/ eksp = 2 ¥x=-2 x=-2 vy =-2 (5) yt+l=—x y+1=+(2) 2 y=-2 [16] QUESTION/VRAAG 3 3.1 13: 35: Sse, 119 T, =dn+c=2n+e v 2n 1=2(l)+e VY c=-l c=-1=> T, =2n-1 2) 3.2 Tyg = 2(20) -1=39 Y substitution 7 Answer only: 2/2 v 39 (2) 3.3 =2n- Y substituti tinal Answer only: 2/2 substation n=60 ¥n=60 (2) 3.4 10; 1; 10; 3; 10; 5; 10; ... ; 10; 119; 10. v +61 Original sequence/oorspronklike ry: 13335; .... 3119 Vv 121 (2) Number of terms in the combined sequence/aantal terme in gekombineerde reeks: 60 +61 =121 Answer only: 1/2 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 6 NW/November 2025 Grade/Graad 11 — Marking Guidelines /Nasienriglyne 3.5 Ty, = 2(98) -1=195 Y substitution T,, = 2(98) —1 Qys = 9632 —195 = 9437 Vv 195 Y 9437 @) 5 [11] QUESTION/VRAAG 4 4.1 y —7 ; —22; -35; -46; ... IstD/leV: ©» ‘-15 ; -13 ; -11 2ndD/2eV: 2 2 Ts=— 55 vo -55 (1) 4.2 2a=2 Answer only: 1/4 a=1 Va=l 3a+b=-5 3(l) +b =-15 bani b=-18 a+b+c=-7 1+-18+c=-7 ¥ c=10 c=10 YT, =n* -18n+10 (4) T, =n’ -18n+10 a T, =n? -18n +10 =29 Vn’ —18n +10 = 29 n> —18n-19=0 Y standard form/std vorm (n-19)(n+1)=0 Y factors/faktore n=19 n#-l Vslegs n=19 n¥-l1 (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 7 NW/November 2025 Grade/Graad 11 — Marking Guidelines /Nasienriglyne 44 ¥2n-17 —15; —13; -11.... 2n-17 =29 Y substitution 2n —17 = 29 n=23 Yanswer/antw T,, &T,; (3) BetweenT,, and T,, OR/OF ~~ Tate oa my y (n +1)? —18(1 + 1)+10-(n? -18n +10)=29 n? +2n4+1—18n-18+10—n? +18n-10 = 29 2n-17=29 + n=23 Between T,, and T,, [12] QUESTION/VRAAG 5 5.1 x =-2 and/en y=1 v¥ each answer/elke antw (2) $.2 v f(0)= as +1=3 «.(0; 3) NB must be coordinates BRaEH ERENT @ + Moet koGrdinate wees 5.3 vy=0 0= 4 +1 ¥ x+2 Vvx=-6 -x-2=4 x=-6 @) 5.4 nly ¥ both intercepts/beide H afsnitte ¥ both asymptotes /beide (03) asimptote ee. a aren; Y shape/vorm (6:0) \ 29) @) 5.5 x#-2,xeER ¥x#-2 VxeER Answer only: 2/2 (x # —2) or/of OR/OF x € (—00;-2) or/of (-2; 0) ¥v each()/elke hakie (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 8 NW/November 2025 Grade/Graad 11 — Marking Guidelines /Nasienriglyne 5.6 y=-xt+e (-2;)) v m=-l = ¥ subs (—2; 1) Len re Answer only: 3/3 Y equation/vgl c=-l GB) y=-x-l i [13] QUESTION/VRAAG 6 _ 1 x 6.1 q=-8 ¥q=-8 (dl) 6.2 -~4=ab°-8 Y substitution (0; — 4) =4 ¥ a=4 a Y substitution (1; 0) g(x) =4.b* -8 Answer only: 2/4 0=45'-8 “p=2 b=2 (4) g(x) = 4.2" -8 63 Ye 8, YER Answer only: 2/2 (y >-8) vy>-8vyeR Q) 64 k(x) = -g(x-2) k(x) =-4.2°? +8 A(x) =-27.2"? +8 k(x) =-2" +8 Answer only: 4/4 ¥-4&+8 Y exponent x—2 ¥ exponential laws/eksp wette Y answer/antw (4) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 9 NW/November 2025 Grade/Graad 11 — Marking Guidelines /Nasienriglyne QUESTION/VRAAG 7 Y 3 Ss {2} x uM B D F i 7A Vv x=-3 vib eam Y substitution: /(-3) SE3)=C3y #6(-3)45=-4 ot 5p D(-3; -4) (3) 72.1 E(0; 5) & F(O; —5) VY E&F EF = 5 — (—5) = 10 units/eenhende v answer/antw (2) 7.2.2 |For/Vir A & C:x?+6x+5=0 (x +5)(x+ 1) =0 v y=0 X,=—-5 orlof x¢=-1 Y x=-5 & x=-l AC = —1— (—5) = 4 units/eenhende v AC=4 @) 731 ge) =f) Y equating/gelykstel —x-5=x°+6x45 x? +7x+10=0 Y factors/faktore Orb Ae? Y choose x = —2 /kies x = -2 x, =-5 x, =-2 Ye = 8(-2)=-(-2)-5=-3 Yvya3 (4) B(-2; -3) 132. -5<t<—2 Y interval Y notation/notasie (2) TAL | MN= g(x) — f(x) =-x-5—(a? + 6x45) ¥ a(x)— £0) v /antw =~»? _7x=10 answer Q) TA2 ae Vx=-3,5 x= BO -3,5 2(-1) 2 P Vo—= Max.=—(-3,5)? — 7(-3,5) —10 = - = 2,25 4 aes (2) 743 9 v Vanswer/antw k>— 4 (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com 10 Mathematics P1/Wiskunde V1 NW/November 2025 Grade/Graad 11 — Marking Guidelines /Nasienriglyne 1S k>-1 or/of k=-5 Vvk>-1 Vvk=-5 (2) [21] QUESTION/VRAAG 8 _ > Tt Y substitution in correct 8.1.1 , = 6 1 ent = (a rs: formula . 4 082) 365 Vig 9 As 1+ iogp =(1 +22)” = 1,085445813 i= 854% (2) igre = 0,085445813 = 854% ‘ 7° 12 a ty 812 | Bt Figg = (14+ 2%)” = 1,086231401 — ¥B (2) ie¢p = 0,086231401 = 8,62% - Bis better/beter 8.2.1 To Ti T2 T3 T4 Ts To 300 000 (175 000) 6 ¥ 300000, 1+ 22 9% p.a. comp quat 35% p.a. c.month 4 Money from investment/Geld van belegging: 0.085)! A=P(1+i)" «(140% } 16 24 A= 300004 + 1) ( _ } 0.09. 4 12 175004 + oe) 0,09)'(, 0,085)" \ = 75009 + oe ( + oe 7 4 12 Ay « 0085) 1+—— = R259 652,50 12 OR/OF V R259 652,50 o/of 8 v AtT,: A= 300004 + | —175000 = 183449,34 , sooonr{ 1+ °°) —175000 0,09)°(, 0,085)" AtT; : A=18344gay{14+ 7 ic = } ¥ 183449 34 = R259 652,50 8 v1 8349.41 + a”) 24 “( ‘ ass) 12 V R259 652,50 (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics P1/Wiskunde V1 11 Grade/Graad 11 — Marking Guidelines /Nasienriglyne NW/November 2025 8.2.2 A= P(i+i)" vi & n indep. of formula A = 175000(1 + 0,08)* = 238 085,57 ¥ substitution in correct Difference = 259 652,50 — 238 085,57 = R21 566,93 formula Not fair, younger brother gets effectively more Y¥ R238 085,57 Nie regverdig nie, jonger broer kry effektief meer Y conclusion/gevolgtrekking (4) 8.2.3 A=P(Q=i)” ¥ substitution in correct formula/subst in regte form 79 120 = 175 000(1 — i)# 79120 © ei) y 19120 =(1-i)' 175000 175000 4/ 79120 . Py Ree va 7120 a - 175000 (2s - t= 0,180003389 = 18% Y answer/antw (4) [17] QUESTION/VRAAG 9 9.1.1 | No, M and A are NOT mutually exclusive/ Nee, M en A is NIE VY No/Nee onderling uitsluitend nie ¥ reason/rede b P(M dae a tozee cause P(M and A) = Too Ee (2) 9.1.2 = BS.xgy 80 — P(M) x P(A) = 100 * 100 ~ 0,105 GED g AD! ¥ 0,105 100 100 P(M and A) = 0,2 v¥ 0,2 0,2 + 0,105 - Mand Aare not independent events/nie onafhanklik nie v . . conclusion/gevolgtrekking (4) M A v 15 9.1.3 Cu) 55 ¥ 10 v55 (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai asseblief om

Downloaded from Stanmorephysics.com Mathematics/Wiskunde/P1/V1 12 NW/November 2025 Grade/Graad 11 Marking Guidelines / Nasienriglyne 9.1.4 , v 85 P(M’ or Ay = 20410455 _ 85 _17 _o95 100 100 20 Y answer/antw OR/OF OR/OF P(M’ or A) = P(M’)+ P(A)— P(M’ and A) = 65 + 30 10 _ 0,85 | “ Substitution in correct 100 100 100 formula OR/OF Answer only: 2/2 Y answer/antw P(M/ or A) = 1 — P(Mand A’) = 1-—~ = 0,85 OR/OF (aa Y substitution in correct formula Y answer/antw (2) 9.2 | Let numberr of red balls be = x/ Stel aantal rooi balle = x x x-l - 25 24 PR = Bh 25 24 60 ll 2 Y prod = — x “Kot po 60 600 60 “¥ fa -—x-110=0 actors/faktore (x-11)(x +10) =0 v 11 red balls/rooi balle x=l1 x#-10 ¥ 14 blue balls/b/ou balle. 11 red balls/rooi balle and 14 blue balls/blou balle. (6) Answer only: 0/6 [17] TOTAL: 150 TOTAAL : 150 Copyright reserved/Kopiereg voorbehou