NW Maths Literacy P2 Memo Eng SEPTEMBER 2019 hlayiso.com

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P2 SEPTEMBER 2019 MARKING GUIDELINES These marking guidelines consist of 12 pages. Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 2 NW/September 2019 NSC-Marking guidelines Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy MCA Method with constant accuracy A Accuracy C Conversion S Simplification RT / RG / RD Reading from a table / graph / diagram SF Correct substitution in a formula O Opinion / Example / Definition / Explanation R Rounding-off NPR No penalty for rounding or omitting units AO Answer only, full marks J Justify KEY TO TOPIC SYMBOL: F = Finance; M = Measurement; MP = Maps, Plans and other representations; DH = Data Handling; P = Probability

Downloaded from hlayiso.com Mathematical Literacy/P2 3 NW/September 2019 NSC-Marking guidelines Q1 ANSWER EXPLANATION LEVEL 1.1.1 Actual volume = 95% x 50 mℓü 1M for multiplying by 95% = 47,5 mℓü 1A answer M2 OR [2] 5% of 50 mℓ = 2,5 mℓ 1M for subtracting Actual volume = 50 – 2,5 mℓü 1A answer = 47,5 mℓü 1.1.2 50 x 1 000 = 50 000 mℓü 1C conversion to mℓ ℓ 1M dividing by 47,5 mℓ Number of bottles = , ℓ ü 1CA answer M3 [3] =1 052 bottlesü OR 1C conversion to ℓ 47,5 ÷ 1 000 = 0,0475 ℓü 1M dividing by 0,0475 ℓ 1CA answer Number of bottles = , ℓ ü =1 052 bottlesü 1.1.3 Fixed costs = Property Rental + Electricity + Printing machine rental F2 1MA for adding [2] Fixed costs = R3 800 + R 1 000 + R575,42ü 1A correct answer = R5 375,42 ü 1.1.4 Number of rolls of self-adhesive paper 1MA for dividing M2 1A answer = 1 000 ÷ 50ü [2] = 20 rollsü 1.1.5 VAT exclusive price = ü 1M for dividing by 1,15 F3 , [4] 1A answer = R6 004,35ü 1M subtraction VAT = R6 905 – R6 004,35ü 1CA answer = R900,65ü OR ü 1A numerator VAT = × 6 905ü 1A denominator ü 1M multiplying by = R900,65ü R6 905 1CA answer Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 4 NW/September 2019 NSC-Marking guidelines Q1 ANSWER EXPLANATION LEVEL 1.1.6(a) Cost per litre for 50ℓ cylinder F4 1MA dividing by 50ℓ [5] = ü 1A answer ℓ =R1 160 per litre ü Cost per litre for 30ℓ cylinder 1MA dividing by 30ℓ = ü 1A answer ℓ =R1 175 per litreü 1O for correct ∴ 50 ℓ will be cheaper. ü conclusion 1.1.6(b) Cost for labels = R65 × 20 1A cost for labels F3 = R1 300ü [6] Cost of bottles = R370.50 × 10 1A cost for bottles = R3 705ü Total cost = Fixed costs + labels + bottles + 50 ℓ cylinder of perfume = R5 375,42 + R1 300,00 + R3 705,00 + R58 000,00 1MCA addition ü 1CA answer = R68 380,42 ü 1O opinion ∴ His claim is valid.ü 1J justification The total cost is less than R70 000.ü 1.2.1 , 1A numerator F2 Cost = üü 1A denominator [2] 1.2.2 Total income = R47 × number of perfumes 2A correct formula F2 [2] 1.2.3 1A starting pointü F3 1A : 400ü [4] 1A : 700ü 1A : 800ü Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 5 NW/September 2019 NSC-Marking guidelines Q1 ANSWER EXPLANATION LEVEL INCOME AND EXPENDITURE GRAPHS 45000 45 000 INCOME 40000 40 000 EXPENDITURE 35000 35 000 ü AMOUNT IN RANDS 30 000 30000 25 000 25000 ü 20 000 20000 ü 15 000 15000 10 000 10000 5 000 5000 00 ü 0 200 400 600 800 1000 NUMBER OF PERFUME BOTTLES 1.2.4 A point where the income of R18 800 equals to the 2O F2 expenditure of R18 800. üü (4) A point where 400 bottles = R18 800. üü 2A correct values CA from 1.2.3 1.3.1 2D = 100% – ( 23% + 19% + 18 % + 8% ) ü 1M addition DH3 2D = 32%ü 1A answer [5] ∴D = 16%ü 1CA dividing by 2 Number of Fantasy perfume = 16% × 12 000ü 1MCA percentage = 1 920 perfumesü concept 1CA answer 1.3.2 Number of perfumes sold in May DH4 = 1 920 – 689 – 550 ü 1M subtraction [3] = 681ü 1A answer His claim is NOT valid. ü 1J justification [44] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 6 NW/September 2019 NSC-Marking guidelines Q2 ANSWER EXPLANATION LEVEL 2.1.1 199,5 = üü 1A sum DH3 1A mean concept 2 394 = 2 019 + 2 1S difference 2 = 2 394 − 2 019ü 1A answer 375 = 2 ü 1CA [5] = 187,5 ü Accept 187 500 2.1.2(a) Range = Max value – Min valueü 1A correct formula DH2 67,6 = S – 163,8ü 1SF for substitution [4] S = 67,6 + 163,8ü 1S simplification = 231,4ü 1A answer Accept 231 000 2.1.2(b) 163,8; 191,3; 191,5; 199,7; 201,2; 201,9; 205,0; 213,4; CA from 2.1.2(a) DH3 218,7; 226,7; 230,8; 231,4 ü 1MA for arranging [4] 1M Median concept , , 1A adding correct values Median = üü 1CA = 203,5 thousands ü OR 203 500 ü 2.1.2(c) Q1 = , , CA from 2.1.2 (b) DH4 ü 1MA adding correct [6] = 195,6 ü values 1A answer , , 1M adding correct values Q3 = ü 1A answer = 222,7ü IQR = Q3 - Q1 = 222,7 – 195,6 = 27,1 thousand ü 1CA answer ∴ It is greater than 27 000. ü 1O 2.1.3 Mean of cars sold in 2017 CA from 2.1.2(a) DH4 , 1M addition [6] = üü 1M mean concept = 206,3 thousandü 1CA answer = 206 300 1A correct value Mean in 2018 = 199,5 thousand ü = 199 500 1O conclusion 1J reason The claim is invalid.ü 6 800 more cars were sold in 2017 than in 2018. ü [No penalty for omitting thousands] 2.1.4 Mean üü 2A answer DH2 [2] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 7 NW/September 2019 NSC-Marking guidelines Q2 ANSWER EXPLANATION LEVEL 2.2.1 1RG F3 üü 100% + 4,9% = 104,9% ü 1M addition [5] Price of bread in February 2018 1A answer = 13,99 × ü 1M multiplying by 100 , and dividing by 104,9 = 13,34 ü 1CA 2.2.2 The price of meat has decreased by 0,5% from 2O Explanation F4 February 2018 to February 2019. [2] [34] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 8 NW/September 2019 NSC-Marking guidelines Q3 ANSWER EXPLANATION LEVEL 3.1.1. South East or SE or South Easterly 2A correct answer MP2 [2] 3.1.2 · From Polokwane, head South on N1ü 1A for South MP2 · Pass Mokopane, Mookgophong, Modimolle and 1A mentioning 1 town Bela-Belaü 1A Witbank [5] · After passing Pretoria, turn left into N4ü 1A turning to N4 · Proceed straight on N4 and pass Witbankü 1A position of Middelburg · Then you will reach Middelburg at the intersection of N4 and N11ü OR · From Polokwane, head South on N1ü 1A for South · At Mokopane, turn left into N11 ü 1A turning left into N11 · Proceed and pass Marble Hall, Groblersdal, ü 1A mentioning 1 town Damwal, Loskop, Botshabelo ü 1A mentioning 1 town or · After passing Botshabelo, Middleburg will be at the landmark intersection of N4 and N11 ü 1A position of Middelburg 3.1.3 · Driving at high speedüü 2O for correct pinion MP2 · No robots and stop signsüü · Less trafficüü [2] · No potholes (Any acceptable answer) 3.1.4 Bar length = 2,6 cmü 1A correct value MP 3 Measured distance = 10,6 cmü 1M correct value [7] , 1CA Actual distance = ü× 100 kmü , = 407,70 kmü 1M for correct fraction 1C conversion to miles , × 1CA answer ∴ , ü = 254,8 milesü (Accept values from 389 km – 408 km) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 9 NW/September 2019 NSC-Marking guidelines Q3 ANSWER EXPLANATION LEVEL 3.1.5 Distance M4 Time = [6] Average Speed 407,7 km 1SF Substitution = ü 120 km/h 1A answer = 3,3975 hours ü Converting to Minutes 1C minutes 0,3975 x 60 = 23,85 minutes ü For stopping twice 1M Subtraction 1A answer 3 hours and 23,85 minutes – 40 minutes ü = 2 hours and 43,85 minutes ü 1J Reason Her claim is Invalid / Incorrect ü 3.2.1 · For fuelüü 2O for correct opinion MP2 · For the maintenance of the busüü · For entertainment üü [2] (Accept any sensible reason except for the basic need.) 3.2.2 65% of R13 500ü 1M for multiplying by F3 R8 775 ü 65% × 1A correct answer [4] Money deposited = ü , 1C conversion to LRD = 96 428,571 LRDü 1CA answer Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 10 NW/September 2019 NSC-Marking guidelines Q3 ANSWER EXPLANATION LEVEL 3.3.1 P3 ü ü M RTM [3] ü B RTB 1A 2nd branch T M RPM 1A 3rd branch P B RPB R Meal M DTM 1A outcomes T D B DTB M DPM P B DPB 3.3.2 1A numerator P3 Probability ℎ = = ü 1A denominator ü [2] [33] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 11 NW/September 2019 NSC-Marking guidelines Q4 ANSWER EXPLANATION LEVEL 4.1.1 (a) To allow for expansion üü 2O for reason M4 [2] (b) Cylindrical ü bottle, because it looks broader than the 1O for pyramid M2 rectangular bottle. ü 1J for justification [2] OR Rectangular ü bottle, because it looks taller than the cylindrical bottle. ü (c) Height of a rectangular bottle = = 4,5 ü 1C for conversion M4 1SF substitution in the Volume of a rectangular bottle = ℓ× × formula [8] = 5 cm × 2 cm × 4,5 cmü 1A correct answer = 45 cm3ü Radius of cylindrical bottle = = 3 ü 1A radius calculation Volume of a cylindrical bottle = ×( ) × 1SF substituting correct = 3,142 × (3) × 1,6 ü values = 45,2 ü 1A correct answer ≈ 45 ü 1R rounded answer 1 O conclusion ∴ The volume of the bottles is the same. ü 4.1.2 Volume of a cylindrical bottle = ×( ) × M4 = , ×( , ) × ü 1SF correct substitution = , ü 1A correct answer [5] = × , 1CA correct answer = , ü 1A comparing units 589,125 cm3 = 589,125 g cm3 ü 1O for conclusion 589,125 cm3 ˂ 600 cm3 ∴ The bath salts granules will fit, as the bottle is bigger. ü Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P2 12 NW/September 2019 NSC-Marking guidelines Q4 ANSWER EXPLANATION LEVEL 4.1.3 95% 45 = 42,75 ü 1A correct answer M4 [6] Concentration of perfume oil in EDT 1M concept of ratio = × 42,75 mℓü 1CA answer = 2,1375 mℓü Concentration of perfume oil in EDP = × 42,75 mℓ ü 1CA correct answer = 5,13 mℓ ü 1CA for the difference Difference = 5,13 mℓ − 2,1375 mℓ = 2,9925 mℓ ü ≈ 3 1O for conclusion ∴ His claim is valid. ü 4.1.4 Probability = üü 1A numerator P3 1A denominator [3] = 0.17ü 1C answer 4.2.1 Pension fund = 7,5% × R312 000ü 1MA multiplying by F4 = R23 400ü 7.5% 1A correct answer [5] Non- taxable income = R23 400 + R46 800ü = R70 200ü 1MCA addition 1CA answer Taxable income = R338 000 – R70 200ü = R267 800 1M subtraction 4.2.2 Medical credits = (R310 + R310 + R209) ü × 12ü 1M adding medical F2 = R9 948ü credits 1M multiplying by 12 [3] 1A correct answer 4.2.3 Taxable income before rebates 1RT correct tax bracket F3 = 35 253 + 26% (267 800 – 195 850) üü 1SF, substituting = 53 960ü 267 800 [5] 1A answer Income tax = 53 960 – 9 948 – 14 067ü = 29 945ü 1M subtracting rebates and medical credits 1CA answer [39] TOTAL: 150 Copyright reserved Please turn over