Physical Sciences Grade 11 P1 March Test 2017 Paper & Memo

Downloaded from hlayiso.com testpapers.co.za

Physical Sciences / P1 Downloaded from hlayiso.com 2 March 2017 Common Test NSC INSTRUCTIONS AND INFORMATION TO CANDIDATES 1. 10. 11. 12. Write your name on the ANSWER BOOK. This question paper consists of FOUR questions. Answer ALL the questions in the ANSWER BOOK. Start EACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. Leave ONE line between two subsections, for example between QUESTION 2.1 and QUESTION 2.2. You may use a non-programmable calculator. You may use appropriate mathematical instruments. You are advised to use the attached DATA SHEET. Show ALL formulae and substitutions in ALL calculations. Round off your final numerical answers to a minimum of TWO decimal places. Give brief motivations, discussions, et cetera where required. Write neatly and legibly. Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences / P14 3 March 2017 Common Test NSC QUESTION 1: MULTIPLE- CHOICE QUESTIONS Four options are provided as possible answers to.the following questions. Each question has only ONE correct answer. Write only the letter (A - D) next to the question number (1.1 — 1.4) in the ANSWER BOOK, for example 1.5 D. 1.1. Which ONE of the following forces ALWAYS acts perpendicular to the surface on which an object is placed. A normal force B tension force Cc frictional force D gravitational force (2) 1.2. Two objects of masses m and 2m are arranged as shown in the diagram below: q ~< > Which ONE of the changes below wil! produce the GREATEST increase in the gravitational force exerted by the one mass on the other. halve the smaller mass. double the larger mass. halve the distance between the masses. double the distance between the masses. (2) uO WD > 1.3. Two forces R and S are applied simultaneously on an object Q as shown in the sketch | below: Ss R Q \ To obtain a maximum resultant force the angle, ©, between force R and force S must be... 4 A 180° B 120° Cc 60° D 0° (2) Copyright Reserved Please Turn Over |

Downloaded from hlayiso.com Physical Sciences / P41 4 March 2017 Common Test NSC 1.4 Apoint P, is kept in equilibrium by three forces, F, G and H, as shown in the diagram below: F Which ONE of the following statements is NOT TRUE with reference to the three forces? A B Cc D all three forces lie in the same plane. the resultant of the three forces is zero. H is the resultant of F and G acting together. the sum of the components of all three forces in any chosen direction is zero. (2) [8] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences / P14 March 2017 Common Test NSC QUESTION 2 An object of mass 44,65 kg is suspended vertically in the air by TWO forces Fy | and F2 as shown in the sketch below: Fp Fy oo 60° 44,65 kg F, makes an angle of 60° with the vertical as shown, ; | 2.1 F; and F2 are classified as vectors. Define a vector. (2) | 2.2 The object can be suspended vertically by a SINGLE FORCE instead of Fy and Fe. 2.2.1 Provide a suitable name for this single force that can replace F, 7 and Fo. : (1) 2.2.2 Calculate the magnitude of this single force. (3) yt 2.3. The vertical component of F; has a magnitude of 262, 54 N. Calculate the magnitude of Fz. (5) [11] Copyright Reserved Please Turn Over Ve

Downloaded from hlayiso.com Physical Sciences / P4 6 March 2017 Common Test NSC QUESTION 3 3.1. State Newton’s Second Law of motion, in words. (2) 3.2 The diagram below shows two blocks, each of mass 8 kg and 12 kg respectively, joined by an inelastic string of negligible mass. The string runs over a frictionless pulley. The 12 kg block is on a rough horizontal surface while the 8 kg block is suspended as shown in the diagram below. string 12 kg string Both the 12 kg and 8 kg blocks move with constant velocity. 3.2.1 Draw a labelled free body diagram to show ALL the forces that act on the 8 kg block. (2) 3.2.2 By means of a calculation, show that the tension in the string that joins the TWO blocks together is 78,40 N. (2) 3.2.3 Draw a labelled free body diagram to show ALL the forces that act on the 12 kg block as it moves with constant velocity. (4) 3.2.4 Write down the magnitude of the net force acting on the 12 kg block. (1) 3.2.5 Define frictional force. (2) 3.2.6 Calculate the co-efficient of kinetic friction between the 12 kg block and the surface. (4) 3.2.7 If the 12 kg block had a larger surface area in contact with the surface, how would this affect the co-efficient of kinetic friction calculated in 3.2.6 above. Assume that the rest of the system remains unchanged. Only write down, INCREASES, DECREASES or REMAINS THE SAME. Give a reason for the answer. (2) [19] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences / P1 March 2017 Common Test NSC QUESTION 4 A body of mass 16 kg and radius 0.10 m is placed a distance “x” m, from another body of mass 48 kg and radius 0,15 m as shown in the sketch below: | xm 16 kg 48 kg | 4.1. State Newton's Law of Universal Gravitation, in words. (2) 4.2 Give reason why Newton’s Law of Universal Gravitation is said to be UNIVERSAL. (1) 4.3 It is observed that the 16kg body exerts a force of magnitude 2,30 x 10° N on the 48kg body when they are placed as shown in the sketch above. 4.3.1 Write down the magnitude of the force that the 48 kg body exerts on the 16 kg body. Give a reason for the answer. (3) 4.3.2 Calculate the distance, x. (6) [12] TOTAL: 50 Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences / P1 March 2017 Common Test NSC DATA FOR PHYSICAL SCIENCES GRADE 11 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE (FISIKA) GRAAD 11 VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE Acceleration due to gravity 2 Swaartekragversnelling 9 9,8ms Universal gravitational constant 1 rate 2 Swaartekragkonstante G 6.67 x 107) Nim™kg TABLE 2: FORMULAE/TABEL 2: FORMULES FORCE/KRAG Frot = Ma Fy = mg F< mime r 7" =p.N fy = UyN Copyright Reserved

4JONQ WNL aseeld (2) {2) or (e) {2) Downloaded from hlayiso.com fbl=zxp $e] VOWED J 107 yore (0 10 2). Dalqo Sif Jo SSEU SH OF euOHOdEN pUe S10] SU} 0} (euoHOdon SUF Ul B}Es9/2008 III" JOSlqo ey} ‘algo Ue UO sjoe soiO} JOUAUEYINSE E UsYY |". Pentesey 1yBukdog 7AaesB Jo s0i0j/8010} feuonennesBaysiem/64 AB010$ [PWOUN4 VoEe SIP UOPEIS|SOOE Ue Je S040} By 40 UoTOSUI € NOILSaND. AN9O'SE = oy ey _ “ goo = z ‘4 s iar = 009 S00 NeO'S4L = fey LS' Ley = Rey + -AvS'Z97 ALS‘ Ley = key + M4 8% —~_ nusiey = /(B'6\go'ry) = bus 84 OY ze fqueyNsal POS 7/7 UORSSIIP PUE SpnyUBEW sey yeuy AQuenb jeoskydy 1-Z Z NOLLSAND 7AO FL 77a eb crO SE SAMY VE LNOLLSAND wnpueiowe, — OSN z SeOUaIDS [eOIskYd JOAQUIN] SSeelg “seed y Jo s}sIsuco wnpueiowsU SIUL ‘S'N ALVOlSILYAD YOINAS TWNOILVN Zboc HOV 4SaL NOWAOD INNGNVYONAIN Voldsv HLNOS 40 OMand3ay uoneonps Jo Juewiyedag jeyen-ninzemy uoneonpy

peniasey wSuAdog JOAQ WIN asealqt feu (2) (2) = ) ° 2) —_ & <= @ 0S WLOL £ () fe) [zu ) < @ Pw ee'| = v1 =— ATO OO ,6r) = x xe) w6r, = 4 ()) - oye 5, ormoez ce} @r)ODG | OL 29'9) 78" © r a 2 * tuig 4 c zer s {e) “Apog By gp ey} uo syiexe Apog By gp ey} IYI 2010} ayy 0} apnyuBeW ul penbe si Apog By Sp au] UO fo} sexe Apog By 91 SYN TEU S010} Bly _pUOHOW Jo MET PIU SLOMAN 0} BUIPICDNY QO AN e Dl X 087 LEY (1) A SSIBAUN Ou} UI eseyMKue paydde aqueo = Zy @ (0.40 2) » SaHUSS Jou] USSMTSG SOUEISIP SU} JO SI ‘SUF OF FeUOHOdGK A(SSIBAUI pue » SSSSCU TSU JO FNPOI SUy OF feuoipodoid Ajsealip si Ten BOIO} JEUORERIAEIB e ipim Apog seujo Arona sjoeme esieniun ayy ui Apog Aleag Ly vNOILSAND uMpUBJOWe — ISN ye UOUON Z40z YUE + @ / “Pasn sjeuayjeu jo adAj ay} uo Ajuo spuadep uoKoLy oBeULy Jo JUSIOWJS-0o Sy yO 7 PEO Ul SeSJe SOBLINS 84} Jo juepuadeput SI LOROLY DBEULY JO JUS!OIJS-O9 OU / “SWeS aU] SUIEWIOY p90 = 1 yeL = AOL) ad owt peuo hue Ay = Nua o} = GM) + 4 ew = youd (ee NOLLSSND NOUS ONDANVW SALLISOd) :49018 OM ZL. SHL OS (0.40 Z) » “soeyins ‘9u} 0} Jayfesed sjoe Yorum pue ,j~alqo ue Jo UOHOW ey] sesoddo yeLR aaJ0} 7NO 7 Maes6 Jo 3010378010} feuogenaesBaybromy64 UOROUY Buus ul eor0yUOIsUP | ABOIO} [BULOUYN NOOSA = 4 AGAR) = L 0 = d-) + Bw euo kue =< eur = a + 64 eu = youy panesey yyBuAdoQ LTE gee GCE vee eee po by geutos ZTE umnpuesowayy — SN, Saouelng [eaIsAYyd $e] VOWNUIOD 2102 YoEW e saouaps jeo1sAyd